10th Standard Maths 2 Practice Set 5.2 Chapter 5 Co-ordinate Geometry Textbook Answers Maharashtra Board
Balbharti Maharashtra State Board Class 10 Maths Solutions covers the Practice Set 5.2 Geometry 10th Class Maths Part 2 Answers Solutions Chapter 5 Co-ordinate Geometry.
Class 10 Maths Part 2 Practice Set 5.2 Chapter 5 Co-ordinate Geometry Questions With Answers Maharashtra Board
Question 1.
 Find the co-ordinates of point P if P divides the line segment joining the points A (-1, 7) and B (4, -3) in the ratio 2:3.
 Solution:
 Let the co-ordinates of point P be (x, y) and A (x1, y1) B (x2, y2) be the given points.
 Here, x1 = -1, y1 = 7, x2 = 4, y2 = -3, m = 2, n = 3
 ∴ By section formula,
 
 ∴ The co-ordinates of point P are (1,3).
Question 2.
 In each of the following examples find the co-ordinates of point A which divides segment PQ in the ratio a : b.
 i. P (-3, 7), Q (1, -4), a : b = 2 : 1
 ii. P (-2, -5), Q (4, 3), a : b = 3 : 4
 iii. P (2, 6), Q (-4, 1), a : b = 1 : 2
 Solution:
 Let the co-ordinates of point A be (x, y).
 i. Let P (x1, y1), Q (x2, y2) be the given points.
 Here, x1 = -3, y1 = 7, x2 = 1, y2 = -4, a = 2, b = 1
 ∴ By section formula,
 
 ∴ The co-ordinates of point A are (\(\frac { -1 }{ 3 } \),\(\frac { -1 }{ 3 } \)).
ii. Let P (x1,y1), Q (x2, y2) be the given points.
 Here, x1 = -2, y1 = -5, x2 = 4, y2 = 3, a = 3, b = 4
 By section formula,
 
 ∴ The co-ordinates of point A are (\(\frac { 4 }{ 7 } \),\(\frac { -11 }{ 7 } \))
iii. Let P (x1, y1), Q (x2, y2) be the given points.
 Here,x1 = 2,y1 = 6, x2 = -4, y2 = 1, a = 1,b = 2
 ∴ By section formula,
 
 ∴ The co-ordinates of point A are (0,\(\frac { 13 }{ 3 } \))
Question 3.
 Find the ratio in which point T (-1, 6) divides the line segment joining the points P (-3,10) and Q (6, -8).
 Solution:
 Let P (x1, y1), Q (x2, y2) and T (x, y) be the given points.
 Here, x1 = -3, y1 = 10, x2 = 6, y2 = -8, x = -1, y = 6
 ∴ By section formula,
 
 ∴ Point T divides seg PQ in the ratio 2 : 7.
Question 4.
 Point P is the centre of the circle and AB is a diameter. Find the co-ordinates of point B if co-ordinates of point A and P are (2, -3) and (-2,0) respectively.
 Solution:
 Let A (x1, y1), B (x2, y2) and P (x, y) be the given points.
 Here, x1 = 2, y1 =-3,
 x = -2, y = 0
 
 Point P is the midpoint of seg AB.
 ∴ By midpoint formula,
 
 ∴ The co-ordinates of point B are (-6,3).
Question 5.
 Find the ratio in which point P (k, 7) divides the segment joining A (8, 9) and B (1,2). Also find k.
 Solution:
 Let A (x1, y1), B (x2, y2) and P (x, y) be the given points.
 Here, x1 = 8, y1 = 9, x2 = 1, y2 = 2, x = k, y = 7
 ∴ By section formula,
 
 ∴ Point P divides seg AB in the ratio 2 : 5, and the value of k is 6.
Question 6.
 Find the co-ordinates of midpoint of the segment joining the points (22, 20) and (0,16).
 Solution:
 Let A (x1, y1) = A (22, 20),
 B (x2,y2) = B (0, 16)
 Let the co-ordinates of the midpoint be P (x,y).
 ∴ By midpoint formula,
 
 The co-ordinates of the midpoint of the segment joining (22, 20) and (0, 16) are (11,18).
Question 7.
 Find the centroids of the triangles whose vertices are given below.
 i. (-7, 6), (2,-2), (8, 5)
 ii. (3, -5), (4, 3), (11,-4)
 iii. (4, 7), (8, 4), (7, 11)
 Solution:
 i. Let A (x1, y1) = A (-7, 6),
 B (x2, y2) = B (2, -2),
 C (x3, y3) = C(8, 5)
 ∴ By centroid formula,
 
 ∴ The co-ordinates of the centroid are (1,3).
ii. Let A (x1 y1) = A (3, -5),
 B (x2, y2) = B (4, 3),
 C(x3, y3) = C(11,-4)
 ∴ By centroid formula,
 
 ∴ The co-ordinates of the centroid are (6, -2).
iii. Let A (x1, y1) = A (4, 7),
 B (x2, y2) = B (8,4),
 C (x3, y3) = C(7,11)
 ∴ By centroid formula,
 
 ∴ The co-ordinates of the centroid are (\(\frac { 19 }{ 3 } \),\(\frac { 22 }{ 3 } \))
Question 8.
 In ∆ABC, G (-4, -7) is the centroid. If A (-14, -19) and B (3, 5), then find the co-ordinates of C.
 Solution:
 G (x, y) = G (-4, -7),
 A (x1, y1) = A (-14, -19),
 B(x2, y2) = B(3,5)
 Let the co-ordinates of point C be (x3, y3).
 G is the centroid.
 By centroid formula,
 
 ∴ The co-ordinates of point C are (-1, – 7).
Question 9.
 A (h, -6), B (2, 3) and C (-6, k) are the co-ordinates of vertices of a triangle whose centroid is G (1,5). Find h and k.
 Solution:
 A(x1,y1) = A(h, -6),
 B (x2, y2) = B(2, 3),
 C (x3, y3) = C (-6, k)
 ∴ centroid G (x, y) = G (1, 5)
 G is the centroid.
 By centroid formula,
 
 ∴ 3 = h – 4
 ∴ h = 3 + 4
 ∴ h = 7
 
 ∴ 15 = -3 + k
 ∴ k = 15 + 3
 ∴ k = 18
 ∴ h = 7 and k = 18
Question 10.
 Find the co-ordinates of the points of trisection of the line segment AB with A (2,7) and B (-4, -8).
 Solution:
 A (2, 7), B H,-8)
 Suppose the points P and Q trisect seg AB.
 ∴ AP = PQ = QB
 
 ∴ Point P divides seg AB in the ratio 1:2.
 ∴ By section formula,
 
 Co-ordinates of P are (0, 2).
 Point Q is the midpoint of PB.
 By midpoint formula,
 
 Co-ordinates of Q are (-2, -3).
 ∴ The co-ordinates of the points of trisection seg AB are (0,2) and (-2, -3).
Question 11.
 If A (-14, -10), B (6, -2) are given, find the co-ordinates of the points which divide segment AB into four equal parts.
 Solution:
 Let the points C, D and E divide seg AB in four equal parts.
 
 Point D is the midpoint of seg AB.
 ∴ By midpoint formula,
 
 ∴ Co-ordinates of D are (-4, -6).
 Point C is the midpoint of seg AD.
 ∴ By midpoint formula,
 
 ∴ Co-ordinates of C are (-9, -8).
 Point E is the midpoint of seg DB.
 ∴ By midpoint formula,
 
 
 ∴ Co-ordinates of E are (1,-4).
 ∴ The co-ordinates of the points dividing seg AB in four equal parts are C(-9, -8), D(-4, -6) and E(1, – 4).
Question 12.
 If A (20, 10), B (0, 20) are given, find the co-ordinates of the points which divide segment AB into five congruent parts.
 Solution:
 Suppose the points C, D, E and F divide seg AB in five congruent parts.
 ∴ AC = CD = DE = EF = FB
 
 ∴ co-ordinates of C are (16, 12).
 E is the midpoint of seg CB.
 By midpoint formula,
 
 ∴ co-ordinates of E are (8, 16).
 D is the midpoint of seg CE.
 
 ∴ co-ordinates of F are (4, 18).
 ∴ The co-ordinates of the points dividing seg AB in five congruent parts are C (16, 12), D (12, 14), E (8, 16) and F (4, 18).
Maharashtra Board Class 10 Maths Chapter 5 Co-ordinate Geometry Intext Questions and Activities
Question 1.
 A (15, 5), B (9, 20) and A-P-B. Find the ratio in which point P (11, 15) divides segment AB. Find the ratio using x and y co-ordinates. Write the conclusion. (Textbook pg. no. 113)
 Solution:
 Suppose point P (11,15) divides segment AB in the ratio m : n.
 By section formula,
 
 ∴ Point P divides seg AB in the ratio 2 : 1.
 The ratio obtained by using x and y co-ordinates is the same.
Question 2.
 External division: (Textbook pg. no. 115)
 Suppose point R divides seg PQ externally in the ratio 3:1.
 
 Let the common multiple be k.
 Let PR = 3k and QR = k
 Now, PR = PQ + QR … [P – Q – R]
 ∴ 3k = PQ + k
 ∴ \(\frac { PQ }{ QR } \) = \(\frac { 2k }{ k } \) = \(\frac { 2 }{ 1 } \)
 ∴ Point Q divides seg PR in the ratio 2 : 1 internally.
 Thus, we can find the co-ordinates of point R, when co-ordinates of points P and Q are given.
Maharashtra State Board Class 10 Maths Solutions Part 2
- Co-ordinate Geometry Practice Set 5.1 Class 10 Maths Solutions
 - Co-ordinate Geometry Practice Set 5.2 Class 10 Maths Solutions
 - Co-ordinate Geometry Practice Set 5.3 Class 10 Maths Solutions
 - Co-ordinate Geometry Problem Set 5 Class 10 Maths Solutions
 - Trigonometry Practice Set 6.1 Class 10 Maths Solutions
 - Trigonometry Practice Set 6.2 Class 10 Maths Solutions
 - Trigonometry Problem Set 6 Class 10 Maths Solutions
 - Mensuration Practice Set 7.1 Class 10 Maths Solutions
 - Mensuration Practice Set 7.2 Class 10 Maths Solutions
 - Mensuration Practice Set 7.3 Class 10 Maths Solutions
 - Mensuration Practice Set 7.4 Class 10 Maths Solutions
 - Mensuration Problem Set 7 Class 10 Maths Solutions