Balbharti Maharashtra Board Class 5 Maths Solutions Chapter 5 Fractions Problem Set 21 Textbook Exercise Important Questions and Answers.

## Maharashtra State Board Class 5 Maths Solutions Chapter 5 Fractions Problem Set 21

Question 1.

Subtract the following.

\(\text { (1) } \frac{5}{7}-\frac{1}{7}\)

Answer:

\(\text { (2) } \frac{5}{8}-\frac{3}{8}\)

Answer:

\(\text { (3) } \frac{7}{9}-\frac{2}{9}\)

Answer:

\(\text { (4) } \frac{8}{11}-\frac{5}{11}\)

Answer:

\(\text { (5) } \frac{9}{13}-\frac{4}{13}\)

Answer:

\(\text { (6) } \frac{7}{10}-\frac{3}{10}\)

Answer:

\(\text { (7) } \frac{9}{12}-\frac{2}{12}\)

Answer:

\(\text { (8) } \frac{10}{15}-\frac{3}{15}\)

Answer:

Question 2.

\(\frac{7}{10}\) of a wall is to be painted. Ramu has painted 410 of it. How much more needs to be painted?

Solution:

To be painted – painted

Answer:

\(\frac{3}{10}\) more needs to be painted.

Addition and subtraction of unlike fractions

Example (1) Add : \(\frac{2}{3}+\frac{1}{6}\)

First let us show the fraction \(\frac{2}{3}\) by coloring two of the three equal parts on a strip.

You have learnt to add and to subtract fractions with common denominators. Here, we have to add the fraction \(\frac{1}{6}\) to the fraction \(\frac{2}{3}\).

So let us divide each part on this strip into two equal parts. \(\frac{4}{6}\) is a fraction equivalent to \(\frac{2}{3}\). Now, as 16 is to be added to \(\frac{2}{3}\) i.e. to \(\frac{4}{6}\), we shall colour one more of the six parts on the strip. Now, the total coloured part is \(\frac{5}{6}\).

Therefore,

That is,

Example (2) Add : \(\frac{1}{2}+\frac{2}{5}\)

Here, the smallest common multiple of the two denominators is 10. So, we shall change the denominator of both fractions to 10.

Example (3) Add : \(\frac{3}{8}+\frac{1}{16}\)

Here, 16 is twice 8. So, we shall change the denominator of both fractions to 16.

Example (4) Subtract : \(\frac{3}{4}-\frac{5}{8}\)

Let us make 8 the common denominator of the given fractions.

Example (5) Subtract : \(\frac{4}{5}-\frac{2}{3}\)

The smallest common multiple of the denominators is 15. So, we shall change the denominator of both fractions to 15.

**Addition and Subtraction Problem Set 13 Additional Important Questions and Answers**

\(\text { (1) } \frac{9}{14}-\frac{3}{14}\)

Answer:

\(\text { (2) } \frac{5}{6}-\frac{3}{6}\)

Answer:

\(\text { (3) } \frac{9}{16}-\frac{5}{16}\)

Answer:

\(\text { (4) } \frac{7}{8}-\frac{3}{8}-\frac{1}{8}\)

Answer:

(5) \(\frac{7}{9}\) part of the work done by Neha and Supriya together. \(\frac{5}{9}\) part of this work was done by Neha. How much work done by Supriya?

Solution:

Total work done – work done by Neha = work done by Supriya

Answer:

\(\frac{2}{9}\) work done by Supriya

(6) Mr. Sharma is \(\frac{14}{9}\) m tall. Mrs. Sharma is \(\frac{4}{9}\) shorter than him. What is Mrs. Sharma’s height?

Solution:

Mrs. Sharma’s height

Answer:

Mrs. Sharma’s height = \(\frac{10}{9}\)