By going through these Maharashtra State Board 12th Science Chemistry Notes Chapter 6 Chemical Kinetics students can recall all the concepts quickly.

## Maharashtra State Board 12th Chemistry Notes Chapter 6 Chemical Kinetics

→ For a reaction, aA + bB → cC + dD

Average rate = \(-\frac{1}{a} \frac{\Delta[\mathrm{A}]}{\Delta t}=-\frac{1}{b} \frac{\Delta[\mathrm{B}]}{\Delta t}=-\frac{1}{c} \frac{\Delta[C]}{\Delta t}=-\frac{1}{d} \frac{\Delta[\mathrm{D}]}{\Delta t}\)

→ Rate law : Rate = k [A]^{a} x [B]^{b}

→ k = \(\frac{2.303}{t}\) log_{10} \(\frac{[\mathrm{A}]_{0}}{[\mathrm{~A}]_{\mathrm{t}}}\) (For first order reaction)

→ t_{1/2} = \(\frac{0.693}{k}\) (For first order reaction)

→ k = \(\frac{[\mathrm{A}]_{0}-[\mathrm{A}]_{t}}{t}\) (For zero order reaction)

→ t_{1/2} = \(\frac{[\mathrm{A}]_{0}}{2 k}\)(For zero order reaction)

→ k = Ae^{-Ea/RT} (Arrhenius equation)

→ log_{10}k =log_{10}A – \(\frac{E_{a}}{2.303 R \mathrm{~T}}\)

→ log_{10}\(\frac{k_{2}}{k_{1}}=\frac{E_{a}\left(T_{2}-T_{1}\right)}{2.303 R \times T_{1} \times T_{2}}\)