Balbharti Maharashtra Board Class 5 Maths Solutions Chapter 16 Preparation for Algebra Problem Set 55 Textbook Exercise Important Questions and Answers.

## Maharashtra State Board Class 5 Maths Solutions Chapter 16 Preparation for Algebra Problem Set 55

Question 1.

Say whether right or wrong.

(1) (23 + 4) = (4 + 23)

Answer:

27 = 27 is right

(2) (9 + 4) > 12

Answer:

13 > 12 is right

(3) (9 + 4) < 12

Answer:

13 < 12 is wrong

(4) 138 > 138

Answer:

Wrong

(5) 138 < 138

Answer:

Wrong

(6) 138 = 138

Answer:

right

(7) (4 × 7) = 30 – 2

Answer:

28 = 28 is right

(8) \(\frac{25}{5}\) > 5

Answer:

5 > 5 is wrong.

(9) (5 × 8) = (8 × 5)

Answer:

40 = 40 is right

(10) (16 + 0) = 0

Answer:

16 + 0

= 16

16 = 0 is wrong

(11) (16 + 0) = 16

Answer:

16 = 16 is right.

(12) (9 + 4) = 12

Answer:

13 = 12 is wrong.

Question 2.

Fill in the blanks with the right symbol from <, > or =.

(1) (45 ÷ 9) [ ] (9 – 4)

Answer:

45 ÷ 9 = 5,

9 – 4 = 5 5

= 5

so, (45 + 9) = (9 – 4)

(2) (6 + 1) [ ] (3 × 2)

Answer:

6 + 1 = 7,

3 x 2 = 6

7 > 6

so, (6 + 1) > (3 x 2)

(3) (12 × 2) [ ] (25 + 10)

Answer:

12 x 2 = 24,

25 + 10 = 35

24 < 35

so, (12 x 2) < (25 + 10)

Question 3.

Fill in the blanks in the expressions with the proper numbers.

(1) (1 × 7) = ( [ ] × 1)

Answer:

1 x 7 = 7,

7 x 1 = 7

so, (1 x 7) = ( 7 x 1)

(2) (5 × 4) > (7 × [ ] )

Answer:

5 x 4 = 20, 7 x ………… must be less than 20.

7 x 2 = 14

so, (5 x 4) > ( 7 x 2)

(3) (48 ÷ 3) < ( [ ] × 5)

Answer:

48 – 3 = 16,

5 x 4 = 20

5 x 3 = 15

16 > 15 and 16 < 20 so, (48 + 3) <(4 x 5)

(4) (0 + 1) > (5 × [ ] )

Answer:

0 + 1 = 1,

5 x 1 = 5

5 x 0 = 0

1 < 5 and 1 > 0 so, (0 + 1) > (5 x Q)

(5) (35 ÷ 7) = ( [ ] + [ ] )

Answer:

35 ÷ 7 = 5,

3 + 2 = 5 so, (35 + 7) = (3 + 2)

(6) (6 – [ ] ) < (2 + 3)

Answer:

6 – < 2 + 3 = 5

5 > 6 – 2

so, (6 – 2) < (2 + 3)

Using letters

Symbols are frequently used in mathematical writing. The use of symbols makes the writing very short. For example, using symbols, ‘Division of 75 by 15 gives us 5’ can be written in short as ‘75 ÷ 15 = 5’. It is also easier to grasp.

Letters can be used like symbols to make our writing short and simple.

While adding, subtracting or carrying out other operations on numbers, you must have discovered many properties of the operations.

For example, what properties do you see in sums like (9 + 4), (4 + 9)?

The sum of any two numbers and the sum obtained by reversing the order of the two numbers is the same.

Now see how much easier and faster it is to write this property using letters.

- Let us use a and b to represent any two numbers. Their sum will be ‘a + b’.

Changing the order of those numbers will make the addition ‘b + a’. Therefore, the rule will be : ‘For all values of a and b, (a + b) = (b + a).’

Let us see two more examples.

- Multiplying any number by 1 gives the number itself. In short, a × 1 = a.
- Given two unequal numbers, the division of the first by the second is not the same as the division of the second by the first.

In short, if a and b are two different numbers, then (a ÷b) ≠ (b ÷a).

Take the value of a as 8 and b as 4 and verify the property yourself.

**Preparation for Algebra Problem Set 54 Additional Important Questions and Answers**

Say whether right or wrong.

(1) (15 ÷ 3) =5

Answer:

5 = 5 is right.

(2) (2 x 1) = 1

Answer:

2 = 1 is wrong.

(3) (16 ÷ 8) = (2 x 2)

Answer:

2 = 4 is wrong.

(4) (13 – 7) = 6

Answer:

6 = 6 is right.

(5) (1 x 0) = 1

Answer:

1 = 1 is wrong.

(6) (1 + 0) = 1

Answer:

1 = 1 is right.

Fill in the blanks with the right symbol from <, >, or =.

(1) (12 + 6) (10 X 2)

Answer:

12 + 6 = 18,

10 x 2 = 20

18 < 20

so, (12 + 6) < (10 x 2)

(2) (4 X 5) (10 X 2)

Answer:

4 x 5 = 20,

10 x 2 = 20

20 = 20

so, (4 x 5) = (10 x 2)

(3) (7 + 3) ………….. (3 X 3)

Answer:

7 + 3 = 10,

3 x 3 = 9

10 > 9

so, (7+ 3) > (3 x 3)

Fill in the blanks in the expressions with the proper numbers.

(1) (8 + ………….. ) = (8 x 1)

Answer:

8 + ……………. = 8,

8 x 1 = 8

8 + 0 = 8

so, (8 + 0) = (8 x 1)

(2) (5 x 6) > (14 x ……….. )

Answer:

5 x 6 = 30,

14 x 1 = 14

14 x 2 = 28

14 x 3 = 42

30 >28

so, (5 x 6) >(14 x 2)

(3) (6 X 7) < ( x 5)

Ans.

6 x 7 = 42,

9 x 5 = 45

42 < 45, 50, 55

so, (6 x 7) < (9 x 5)