Mass Media and History Question Answer Class 10 History Chapter 5 Maharashtra Board

Std 10 History Chapter 5 Question Answer Mass Media and History Maharashtra Board

Balbharti Maharashtra State Board Class 10 History Solutions Chapter 5 Mass Media and History Notes, Textbook Exercise Important Questions and Answers.

Class 10 History Chapter 5 Mass Media and History Question Answer Maharashtra Board

History Class 10 Chapter 5 Question Answer Maharashtra Board

Question 1.
(A) Choose the correct option from the given options and complete the statement.

(1) The first English newspaper in India was started by ………………………….. .
(a) James Augustus Hickey
(b) John Marshall
(c) Allen Hume
Answer:
(a) James Augustus Hickey

Maharashtra Board Solutions

(2) Television is an ………………………….. medium.
(a) visual
(b) audio
(c) audio-visual
Answer:
(c) audio-visual

(B) Identify and write the wrong pair in the following set.
(1) ‘Prabhakar’ – Acharya P.K. Atre
(2) ‘Darpan’ – Balshastri Jambhekar
(3) ‘Deenbandhu’ – Krishnarao Bhalekar
(4) ‘Kesari’ – Bal Gangadhar Tilak
Answer:
(1) Wrong Pair: ‘Prabhakar’ – Acharya P.K. Atre

Mass Media And History Class 10 Question 2.
Write short notes :
(1) The role of newspaper in the Indian struggle for independence
Answer:
Newspapers played an important role in the Indian independence struggle. It is as follows

  • Newspapers served as an important medium to create awareness during those times.
  • They described greatness of Indian culture and history to gather support of masses for the freedom movement.
  • They supported social, political and religious movements and opposed imperialism.
  • They discussed various social and political issues.
  • The ideas of social reformers and various organisations active in independence struggle reached people through newspapers.

(2) Why do we need mass media?
Answer:
Mass media includes print and electronic and various new media.

  • It facilitated free flow of information to all strata of the society and brought the world closer.
  • Editorials, various columns and supplements are essential parts of newspapers.
  • Readers also get a platform to voice their opinions. In fact, newspapers can help to make democracy stronger.
  • Akashrani broadcasted various programmes of the government as well entertainment.
  • Awareness creating programmes. It fulfill the need of the government to connect with people.
  • Television is an Audio-Visual medium which has made it possible to cross the inherent limitations of newspapers.
  • Radio to show the actual visuals of an event to people.
  • Mass Media is very important as it plays an important role to strengthen democracy.

(3) Mass Media and professional opportunities.
Answer:
There are many professional opportunities available in printed, electronic and digital media.

  • Writers, columnists, editors are required to write articles, columns and editorials in news-papers.
  • Newspapers also require reporters to gather news and technicians to work in the press.
  • There is requirement of actors and technicians in electronic media.
  • Artists are required to present programmes on television, in the same way news presenters, anchors are required.
  • If the articles, columns and programmes are based on history, an expert in history is required.

Mass Media And History Class 10 Question Answer Question 3.
Explain the following statements with reasons.
(1) Any information received through mass media needs to be reviewed critically.
Answer:

  • Information provided in the media may not represent the exact truth. We need to scan it carefully.
  • We have to understand idealistic and investigative motives of newspapers, government policies and prevailing social conditions behiid the newspiece.
  • The information received through Mass Media might be prejudiced or give a one-sided idea.
  • ‘Stern’, a German weekly magazine, purchased and published a number of so called handwritten diaries of Hitler.
  • It then sold them to a number of publication companies.
  • However, later it was proved that those diaries were forged. Hence it is essential to verily the information received through Mass Media.

(2) Knowledge of history is essential for newspaper articles.
Answer:

  1. In order to unfold the background of an event in the news, we have to resort to history.
  2. Some columns are based on historical events. These columns provide historical information about economical, social and political events in the past.
  3. Newspapers publish supplements in addition to the regular edition or special issues to mark the completion of 50 or 100 years of an event. On such occasions, one has to review history of that particular event.
  4. Even while writing columns like what happened in history on this day it is necessary to know past event. Hence, the knowledge of history is essential for writings of such type.

(3) Television is the most popular medium.
Answer:

  • Television being an audio-visual medium brings us into contact with events in an exciting and clarifying way.
  • It crossed the inherent limitations of newspapers and radio to show actual visuals.
  • It becomes possible for people to watch all the national and international events sitting at home.
  • Social problems, discussion on education and economics and political events are viewed by people.
  • In 1991, Indian government granted permission to private, national and international channels to telecast in India.
  • Television became a treasure house of entertainment.

Therefore, the television is the most popular medium.

Class 10 History Chapter 5 Questions And Answers Ssc Board Question 4.
Read the following extract and answer the questions.
Radio: ‘Indian Broadcasting Company’ (IBC), a private radio company was the first one to broadcast daily programmes. Later the same company was taken over by the British Government and named as, ‘Indian State Broadcasting Service (ISBS). On 8th June 1936 it was renamed, as ‘All India Radio (AIR)’.

After Independence, AIR became an integral part of the Ministry of Information and Broadcasting (India). Initially, it broadcasted Governmental programmes and schemes. It was named as ‘Akashvani’ on the suggestion of the famous poet Pandit Narendra Sharma. Akashvani broadcasts various entertainment, awareness creating and literary programmes. It also broadcasts special programmes for farmers, workers, the youth and women. The ‘Vividh Bharati’ programmes are broadcasted in 24 regional languages as well as 146 dialects of Indian languages. Lately, various new channels like ‘Radio Mirchi’ are providing radio services.

(1) Akashavani (AIR) is an integral part of which ministry?
Answer:

  1. Indian Broadcasting Company, a private radio company was taken over by the British Government in 1927 and named ‘Indian State Broadcasting Service (ISBS)’. On 8th June 1936, it was renamed as ‘All India Radio (AIR)’.
  2. AIR became integral part of the Ministry of Information and Broadcasting after independence. It was renamed Akashvani on the suggestion of Pandit Narendra Sharma.
  3. Initially it used to broadcast Government’s programmes and schemes. Later it started broadcasting various entertainment, awareness creating and literary programmes.
  4. Akashvani started ‘Vividh Bharati1 programmes. It broadcasts special programmes for farmers, workers, the youth and women.
  5. Vividh Bharati Programmes are broadcast in 24 regional languages and 146 dialects.

(2) What was the new name of IBC?
Answer:
Indian Broadcasting Company (IBC) was taken over by the British Government. It was named as the Indian State Broadcasting Services. (ISBS). On 8th June 1936, it was renamed as ‘All India Radio’ (AIR).

(3) In how many regional languages and local dialects are ‘Vividh Bharati’ programmes broadcasted?
Answer:
People get access to news through social media like Twitter, Instagram, Facebook, YouTube and from web news portals, web channels. This information is available in English and many other languages.

(4) How AIR was named ‘Akashavani’?
Answer:
AIR was named as Akashvani on the suggestion of the famous poet Pandit Narendra Sharma.

Question 5.
Complete the following concept chart.

NewspapersRadioTelevision
Beginning/Background
Nature of information/programmes
Functions

Answer:

NewspapersRadioTelevision
Background/BeginningJames Augustus Hickey started Calcutta General Advertiser or Bengal Gazette on 29th January, 1780. It was the first newspaper in English.A private radio station was started known as Indian Broadcasting Company.First Doordarshan centre was started in Delhi.
Information ProgrammesNews, articles, columns, opinions of the people, editorials, advertisements etc. are published.Along with entertainment programmes, have literary, informative programmes on farmers, women and educative values.Events around the world, movies, music, information about environmental and historical places, sports are shown either live or recorded.
Functions(1) Report daily news
(2) Public awareness and mass education.
(3) Provide information and strengthen democracy.
(4) Oppose injustice and give publicity to developmental work.
(1) Provide news from different sectors.
(2) Entertain through music, dramas, songs, etc.
(3) Present social problems and educate the masses about it.
(4) Conduct discussions on various issues ranging from the environment to culture.
(1) Telecast daily events and entertain.
(2) Educate the masses.
(3) Publicise programmes which are for social benefit.
(4) Bring about social awakening opposing evil traditions and practices.

Project
Write a review of a historical serial that you have watched.

Memory Map
Maharashtra Board Class 10 History Solutions Chapter 5 Mass Media and History 1

Question 6.
Complete the sentences by choosing a correct option:
(a) ………………….. is the first newspaper in Marathi.
(a) Deenbandhu
(b) Prabhakar
(c) Darpan
(d) Kesari
Answer:
(c) Darpan

(b) 6th January is celebrated as ………………….. day in Maharashtra.
(a) Periodical Day
(b) Newspaper Day
(c) Printing Day
(d) Journalist Day
Answer:
(d) Journalist Day

(c) The letters ‘Shatpatre1 published in Prabhakar were written by ………………….. .
(a) Lokmanya Tilak
(b) Lokhitvadi
(c) Mahatma Gandhi
(d) Justice Ranade
Answer:
(b) Lokhitvadi.

(d) The honour of printing illustrations for the first time in an Indian newspaper goes to ………………….. .
(a) Dnyanoday
(b) Darpan
(c) Prabhakar
(d) Kesari
Answer:
(a) Dnyanoday

(e) Deenbandhu was started by ………………….. who was a close associate of Mahatma Phule.
(a) Dr. Babasaheb Ambedkar
(b) Lokmanya Tilak %
(c) Narayan Meghaji Lokhande
(d) Krishnarao Bhalekar
Answer:
(d) Krishnarao Bhalekar

(f) ………………….. newspaper was started by Agarkar and Lokmanya Tilak.
(a) Deenbandhu and Induprakash
(b) Darpan and Prabhakar
(c) Dnyanoday and .Digdarshan
(d) Kesari and Maratha
Answer:
(d) Kesari and Maratha

(g) Balshastri Jambhekar started ………………….. the first monthly magazine in Marathi.
(a) Digdarshan
(b) Prabhakar
(c) Darpan
(d) Dnyanoday
Answer:
(a) Digdarshan

(h) ………………….. was acknowledged as the fourth pillar of democracy.
(a) Representatives
(b) Periodicals
(c) Newspaper
(d) Books
Answer:
(c) Newspaper.

(i) The first English news bulletin was broadcast on 23rd July, 1927 from the …………………… radio station.
(a) Kolkata
(b) Madras
(c) Mumbai
(d) Dblhi
Answer:
(c) Mumbai

(j) Dr. Rajendra Prasad, the first President of India inaugurated the …………………… Doordarshan centre.
(a) Mumbai
(b) Bangalore
(c) Lucknow
(d) Delhi
Answer:
(d) Delhi

(k) Newspapers published special supplements or a special issue to commemorate occasions like completion of seventy-five years of …………………… in 2017.
(a) Khilafat Movement
(b) Non Co-operation Movement
(c) Civil Disobedience Movement
(d) Quit India Movement
Answer:
(d) Quit India Movement

(l) ……………………, a German weekly magazine, had purchased a number of so called handwritten diaries that were later proved forged.
(a) Time Magazine
(b) Statesman
(c) Stern
(d) Reuters
Answer:
(c) Stern

(m) Akashvani has preserved recordings of all speeches delivered by the …………………… on 15th August.
(a) President
(b) Wee President
(c) Prime Minister
(d) Army General
Answer:
(c) Prime Minister

(n) Akashwani comes under the Ministry of …………………… of the Indian Government.
(a) Social welfare
(b) Human Resource and Development
(c) Information and Broadcasting
(d) Education Technology
Answer:
(c) Information and Broadcasting.

Question 7.
Identify the wrong pair in the following and write it:

NewspaperEditor
(1)  Prabhakar

(2)  Darpan

(3)  Deenbandhu

(4)  Kesari

(a)   Acharya R K. Atre

(b)   Balshastri Jambhekar

(c)  Krishnarao Bhalekar

(d)   Bal Gangadhar Tilak

Answer:
Wrong pair: Prabhakar – Acharya R K. Atre

(2)

NewspaperIssues
(1)  Prabhakar

(2)  Induprakash

(3)  Deenbandhu

(4)  Kesari

(a)   History of French revolution

(b)  Advocated widow re­marriage

(c)  Information on Telegraph

(d)   Voiced social and political problems.

Answer:
Wrong pair Deenbandhu – Information on Telegraph

(3)

Newspaper/Magazine/BookEditor
(1) Pragati(a) Tryambak Shankar Shejwalkar
(2) Digdarshan(b) Narendra Sharma
(3) Deenbandhu(c) Krishnarao Bhalekar
(4) Discovery of India(d) Pandit Nehru

Answer:
Wrong pair: Digdarshan – Narendra Sharma

Question 8.
Do as directed:
(a) Complete the graphical description

Answer:

(2)

Answer:

(b) Show the progress of Indian television Time-line:

Answer:

Question 9.
Explain the following concepts:

(a) Electronic or Digital Journalism or Web Journalism.
Answer:

  1. In the modem times, the computer and internet have become indispensable parts of printing and publishing process. Computer technology has led to the widespread practice of digital journalism.
  2. Websites run by newspapers are basically extensions of newspapers themselves. Modern periodicals are part of electronic or digital journalism.
  3. People get access to news through social media like Twitter, Instagram, Facebook, YouTube and from web news portals, web channels. This information is available in English and many other languages.
  4. Journalists working in this area today have to have many more skills than in the past when writing was the only requirement. Information available on these mediums should be reviewed critically and used with utmost care.

(b) E-newspapers
Answer:

  1. In recent times, e-newspapers have got prominent place in mass media.
  2. E-newspaper is not exactly like the printed one. In e-newspapers, news comes in sequence and not based on the nature and the importance of the news, like in printed newspaper e.g.. Front page news. Headline or Last page news.
  3. The news which we want to read has to be clicked and then it appears on the screen in detail.
  4. There is space provided for opinion of readers. In 1992, the first edition of the e-newspaper was published by ‘Chicago Tribune1.
  5. At present, almost all newspapers are available as e-newspapers and people can read them anytime, anywhere using the Internet or computer, tab, laptop or mobile.
  6. In recent times many newspapers have introduced e-newspapers. The e-newspapers are being received well by the readers.
  7. Learn to read e-newspapers with the help of your teachers.

Question 10.
Write short notes:
(a) Bengal Gazette:
Answer:

  • Bengal Gazette is the first newspaper which was started in India.
  • It was started by James Augustus Hickey, an Irish national.
  • It was first published on 29th January, .1780. It was also called “Calcutta General Advertiser’.
  • Bengal Gazette laid the foundation of newspaper in India.

(b) News printed in ‘Darpan’:
Answer:
The ‘Darpan newspaper started by Balshastri Jambhekar printed all types of news like political, economic, social and cultural. Some of them are mentioned below:

  • The Accounts of Expenditure from the Three Administrative Divisions of the East India Company.
  • The Danger of Russian Attack on the Nation.
  • Appointment of a Committee for Cleanliness of the City.
  • Remarriage of Hindu Widows.
  • The Inception of Theatre at Calcutta.
  • Achievements of Raja Ram Mohan Roy in England. All these reports published in the paper throw light on various situations/events of those days.

(c) Television:
Answer:

  • The first President of India, Dr. Rajendra Prasad inaugurated Delhi Doordarshan Centre.
  • Mumbai Doordarshan started to telecast its programmes on 2nd October, 1972.
  • Colour television started on 15th August, 1982. The Indian government granted permission to private, national and international channels in 1991 to telecast in India.

Question 11.
Explain the following sentences with reason:
(a) Newspaper is an important medium of education and information.
Answer:

  • Newspapers report events which are interesting to the public. But the importance of newspaper stretches far beyond a passing humari interest in events.
  • It covers a miscellany of topical issues. News would involve matters of higher importance like war, global warming, education, national elections or trivial issues such as scandals, gossips and debates on minor controversies.
  • Newspapers have contributed significantly to the spread of literacy and the concept of human rights and democratic freedoms.
  • They are integral to the development of democracy. In fact, they can help in making the democracy stronger.
  • Newspapers not only report the events but continue to shape opinions in the global village.

(b) 6th January is observed as ‘Patrakar Din’ or ‘Journalist Day’ in Maharashtra.
Answer:

  • Balshastri Jambhekar started the first newspaper in Marathi on 6th January, 1832 in Mumbai.
  • He is referred to as the ‘First Editor’ as he was the first editor.
  • He laid the foundation of Marathi newspaper by starting Darpan. As 6th January is his birth date, it is observed as ‘Patrkar Din’ or ‘Journalists’ Day’ in Maharashtra.

(c) Television and history are closely related.
Answer:

  1. Television plays a major role in developing interest in history. While producing shows and serials based on history and mythology, it is essential to have an accurate knowledge of history and know the minute details.
  2. ‘Bharat Ek Khoj’, Raja Shivchhatrapati, Ramayana, Mahabharata are among the few popular serials based on history and mythology. While producing these serials.
  3. It was essential to know the prevalent social conditions, outfits, lifestyle, weaponry, lingual expressions of the people. Historians who had knowledge on these subjects are required.
  4. While making programmes, based on sportsmen, literature, war, historical events, forts and animal life, it is important to give history of their development in that particular period.
  5. While conducting discussions on television on topics like social problems, education, economics, health, it is important to give references from the past.

This shows that the knowledge of history is required in the making many of programmes on Television. Hence Television and history are closely related.

Question 12.
Answer the following question in 25-30 words:
(a) Explain the objectives of newspapers.
Answer:
The main objectives of newspapers are as follows:

  • Newspapers provide various local, national and international news to the people and inform them about daily events.
  • They narrate political, economic, cultural and social history of the country.
  • Newspapers fulfill their role as the fourth column of democracy by creating public awareness and becoming a medium of mass education.
  • They even condemn the anti-social elements in the society and support the weaker section.

(b) How is history helpful in the planning of the Akashvani programmes ?
Answer:
Akashvani broadcasts all types of programmes from celebration of independence day to entertainment programmes. In planning these programmes, the knowledge of history is essential.

  1. Akashvani invites historians as experts for discussions while presenting programmes on various occasions such as the anniversaries of births and deaths of national leaders, anniversaries of historical events; speeches of all Prime Ministers/Presidents.
  2. Programmes like ‘On This Day in History’ is a daily programme which highlights importance of that day and date in history.
  3. Information has to be verified by historians before it reaches the people. Lectures on the contributions of various national leaders need to be supported by historical information. In the following ways history is helpful in the planning of Akashvani programmes.

(c) How were the message conveyed to the people in olden days?
Answer:
The following were a few means used to convey messages to the people in olden days:

  • A town crier would run on the streets beating drums and crying out important news according to the orders of the king.
  • So, the news would spread among people by word of mouth.
  • Inscriptions with royal decrees were placed at public places.

Question 13.
Read the following passages and answer the questions:”
(a) Which programmes are broadcasted by Akashvani?
Answer:

  • Initially, Akashvani broadcasted government programmes and schemes.
  • Later it broadcasted various entertainment and literary programmes.
  • Akashvani presents various programmes for creating awareness.
  • Special programmes are also broadcasted for farmers, workers, youth and women.

(a) On which book is the serial ‘Bharat Ek Khoj’ based on?
Answer:
The Serial Bharat Ek Khoj is based on ‘Discovery of India’, a book written by Pandit Jawaharlal Nehru.

(b) Who directed the serial ‘Bharat Ek Khoj’?
Answer:
The serial was directed by Shyam Benegal.

(c) Which factors/aspects of Indian history are depicted in ‘Bharat Ek Khoj’? OR Why was ‘Bharat Ek Khoj’ a serial telecasted by Doordarshan admired in all parts of India?
Answer:
The television serial ‘Bharat Ek Khoj’ presented social, political and economic life from ancient to the modem period in India.

  1. It portrayed various aspects of Indian history like Harappan civilisation, Vedic history and the interpretation of epics like Mahabharata and Ramayana.
  2. It used the technique of dramatisation effectively to recreate the Mauryan period and show the impact of Turk-Afghan invasions.
  3. The Mughal period and their contributions which have long-lasting effect on social and cultural fabric of India is shown. The rise of Bhakti movement, role of Chhatrapati Shivaji Maharaj in getting swarajya is portrayed.
  4. The last episodes (finale) of the serial narrate social movements and India’s freedom struggle in modem period.

Thus, the serial effectively portrayed the journey of India from Harappan civilisation to the modern period and therefore was admired in all parts of India.

Question 14.
Answer the following questions in detail:
(a) What were the different means of communication known around the world before the advent of newspaper?
Answer:
The following means of communication were used to convey news before the advent of newspaper:

  1. Inscriptions with royal decrees placed at public places was a custom in Egypt. Emperor Ashoka followed the sam method to reach out to his subjects.
  2. In the Roman Empire, roytil decrees were written on papers and those were distribute’d in all regions. It also contained information of various events taking place in the nation and its capital.
  3. During, the reign of’ Julius Caesar ‘Acta Diurna’, meaning acts of everyday used to be placed at public places in Rome.
  4. In the 7th century C.E., in China, royal dictates were distributed among people at public places.
  5. In England handouts were distributed occasionally among people at public places giving information about war or any important events.
  6. Travellers arriving from different faraway places would add spice to stories from those places and narrate the same to local people. The ambassadors of a king posted at various places would send back important news to the royal court.

(b) Write information on Periodicals based on its types.
Answer:
Magazines and journals which are published at regular intervals are known as Periodicals.
Types:

  • They are categorised as weekly, biweekly, monthly, bimonthly, quarterly, six monthly and annual.
  • There are some chronicles which are published at no fixed time.

Classification: Periodicals can be classified as popular and scholarly.

  • If a periodical aims at specialists and researchers, it is a ‘journal1. Articles are generally written by experts in the subject.
  • Popular periodicals are magazines published with variety of content. They can be on fashion, sports, entertainment and films.
  • Bharatiya Itihas ani Sanskruti and Marathwada Itihas Parishad Patrika are periodicals of present times. Periodicals are an important source to study history.

(c) Write about the important role of newspaper in the freedom struggle.
Answer:

  1. The press was the chief instrument for carrying out the political tasks and propagation of nationalist ideology.
  2. Both English and Vernacular press started by prominent “leaders like Gopal Ganesh Agarkar and Lokmanya Tilak acted as catalyst to the freedom struggle. They started ‘Kesari’ and ‘Maratha’ in 1881.
  3. Newspapers played a great role in building up an increasingly strong national sentiment and consciousness among people. It was an instrument to arouse, train, mobilise and consolidate nationalist public opinion.
  4. The newspapers were an effective tool in the hands of social reformers. They exposed social evils such as child marriage, ban on remarriage of the widows, inhuman institution as untouchability, caste fetters, etc. It became a weapon in their hands to educate masses.
  5. A comparative study was presented in newspaper on western education, knowledge and national education.
  6. Newspapers also discussed political institutions in India and the west. The main aim of these newspapers was not to gain profit but to serve the people.

(d) Give a short account of the development of Indian television.
Answer:

  1. Television service started in India in 1959. Dr. Rajendra Prasad, the first Indian President, inaugurated the Delhi Doordarshan centre.
  2. Mumbai centre began to telecast its programmes on 2nd October 1972. Colour television was introduced in India on 15th August 1982.
  3. The national telecast began in 1983. Doordarshan started Channels like DD Sports, DD Metro, news, etc. along with 10 regional channels.
  4. In the year 1991, the Indian government gave permission to private, national and international channels to telecast in India.
  5. Presently there are more than 800 national and regional channels. Some of them are exclusive news, sports, music, movies and religious channels which telecast programmes 24 hours a day.

(e) Distinguish between Newspapers and Magazines.
Answer:
Newspapers and magazines differ in their format, objectives and duration of getting published. The differences are noted below:

NewspapersMagazines
1. Newspapers document the current events.1. Magazines give no importance to current news.
2. News, articles, columns, editorials have importance in a newspaper.2. Magazines give preferences to particular subject and publish articles on it.
3. Newspapers are also called ‘Dailies’ as they are published every day.3. Duration of publication of magazine varies. Some are published weekly, fortnightly, monthly and annually.
4.. The main purpose of newspaper is to report local, national and international news.4. Instead of providing news, their content is entertaining and knowledge-based.
5. Newspapers make the people aware of the events happening in the society. They do not stick to any one subject.5. Magazines are about a specific topic. On the basis of their appearance, size, readability, content and audience, magazines differ from newspapers.
6. Newspapers mostly write about current news. Whatever happens in the world appears in the newspaper within a span of 24 hours. It shapes public opinion and keep people updated about the activities of the government.6, As magazines have lot of detailed information on specific topics they are considered as historical source.

Brain Teaser

Across:

  • Referred to as the ‘First Editor’.
  • A newspaper representing masses of the Indian society (Bahujan Samaj).
  • Tryambak Shankar Shejwalkar edited this journal.
  • Letters by Lokhitvadi.

Down:

  • The history of French Revolution was published in this newspaper.
  • Newspaper started by James Augustus Hickey.
  • First monthly magzine in Marathi.
  • Pandit Narendra Sharma suggested this name for AIR.Maharashtra Board Class 10 History Solutions Chapter 5 Mass Media and History 10

Class 10 History Textbook Solutions Answers

Historiography Development In The West Question Answer Class 10 History Chapter 1 Maharashtra Board

Std 10 History Chapter 1 Question Answer Historiography Development In The West Maharashtra Board

Balbharti Maharashtra State Board Class 10 History Solutions Chapter 1 Historiography Development in the West Notes, Textbook Exercise Important Questions and Answers.

Class 10 History Chapter 1 Historiography Development In The West Question Answer Maharashtra Board

History Class 10 Chapter 1 Question Answer Maharashtra Board

Question 1.
(A) Choose the correct option from the given options and complete the statement.
(1) It may be said that …….. was the founder of modern historiography.
(a) Voltaire
(b) Rene Descartes
(c) Leopold Ranke
(d) Karl Marx
Answer:
(a) Voltaire

Maharashtra Board Solutions

(2) ………… wrote the book entitled ‘Archaeology of Knowledge’.
(a) Karl Marx
(b) Michel Foucault
(c) Lucien Febvre
(d) Voltaire
Answer:
(b) Michel Foucault

(B) Identify and write the wrong pair in the following set.
(1) Georg Wilhelm Friedrich Hegel – ‘Reason in History’
(2) Leopold von Ranké – ‘The theory and Practice of History’
(3) Herodotus – ‘The Histories’
(4) Karl Marx – ‘Discourse on the Method’
Answer:
(1) Right pair: Georg Wilhelm Friedrich Hegel – ‘Reason in History’
(2) Right pair: Leopold von Ranké – ‘The theory and Practice of History’
(3) Right pair: Herodotus – ‘The Histories’
(4) Wrong pair: Karl Marx – Discourse on the Method.

Question 2.
Explain the following concepts.
(1) Dialectics
Answer:

  • In order to understand the true nature of an event, one needs to know its opposite for e.g. True — False, Good — Bad, etc.
  • A German philosopher, Georg Wilhelm Friedrich Hegel had put forward this method of analysis of history.
  • A theory called ‘Thesis’ is proposed at the beginning. It is followed by another theory called Antithesis’ which is, contrary to ‘Thesis’.
  • After a thorough logical discussion of both new thesis is proposed having gist of both (Thesis and Antithesis).
  • This process of orriving at a new thesis is called Synthesis.
  • This method of analysis of history which is based on opposites is known as ‘Dialectics’.

(2) Annales School
Answer:

  • At the dawn of the twentieth century, the writing ¿f history got a new direction.
  • Along with political events, kings, great leaders, the study of climate, local people, agriculture, trade, technology, means of communication, social divisions and their collective psychology of a group was also considered important in the study of history.
  • This new school of thought is known as Annales School. Annales School was started by French historians.

Question 3.
Explain the following with its reason.
(1) Historical research was driven to focus in depth on various aspects of women’s life.
Answer:

  • Initially, there was a lot of dominance of male perspective on historical writing. Simone de Beauvoir, a French scholar, insisted on inclusion of women perspective in historiography.
  • She emphasised on the inclusion of women in the process of writing history.
  • She insisted on rethinking of the male dominated perspective of history.
  • Because of her efforts historical research was driven to focus in depth on various aspects of women’s lives their employment, their role in trade unions, institution working for their cause, and their family life.

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(2) Foucault called his method, ‘the archaeology of knowledge’.
Answer:

  • According to Michel Foucault, the prevailing method of arranging historical events in a chronological order was not right.
  • He threw light on the fact that archaeology does not strive to reach the ultimate historical truth.
  • It attempts to explain various transitions in the past.
  • Foucault gave more importance for explaining the transitions in history. Hence, his method is called ‘the archaeology of knowledge’.

Question 4.
Complete the concept chart.
Maharashtra Board Class 10 History Solutions Chapter 1 Working of the Constitution 12
Answer:
Maharashtra Board Class 10 History Solutions Chapter 1 Working of the Constitution 7

Question 5.
Answer the following in detail.
(1) Explain Karl Marx’s ‘Class Theory’.

Answer:
In the latter part of nineteenth century, German thinker, Karl Marx put forward ‘Class Theory’ in his book ‘Das Kapital’.

According to him:

  1. History i not about abstract ideas but living people. The fullillment of basic needs of people depends on the nature of prevalent means of production and the ownership.
  2. All the different strata of the society do not get equal access to these means of production which causes the division of the society into classes. It rešults into class struggle.
  3. The class which owns means of production $ economically exploits the rest of the classes. Human history, according to him, is the history of class struggle.

(2) What are the four characteristics of modern historiography?
Answer:
The following are the four characteristics of modern historiography:

  1. Its method is based on scientific principles and begins with formation of relevant questions.
  2. These questions are anthropocentric i.e. they are about ancient human societies and their deeds in that period of time. No interrelation between the divine and human needs is suggested.
  3. Answers to these questions are supported by reliable evidence and they are presented in a logical order.
  4. History presents a graph of man’s progress with the help of his deeds in the past.

(3) What is feminist historiography?
Answer:

  • Feminist historiography means writing history with women perspective. There was a lot of dominance of male perspective on historical writing.
  • Simone de Beauvoir, a French scholar, insisted on rethinking on the male dominated perspective and including the women’s perspective in historiography.
  • The idea of feminist historiography was accepted.
  • Because of her efforts various aspects of women’s lives like their employment, their role in trade unions and their family life became part of historiography.

(4) Explain Leopold von Ranké’s perspective of history?
Answer:
Leopold’s view on ways to write history throws light on his perspective of history:

  1. He spoke about the critical method of historical research. He gave importance to information gathered through original documents.
  2. He also stated that all types of original documents related to the historical event should be examined in detail and with great care.
  3. He believed that with this method it was possible to reach the historical truth. He was critical of imagination in narration of history.

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Historiography : Development In The West Questions And Answers Pdf Project
Obtain detailed information on your favourite subject and write its history. For example :
– History of Pen
– History of Printing technology
– History of Computers
Answer:

Memory Map
Maharashtra Board Class 10 History Solutions Chapter 1 Working of the Constitution 4
Maharashtra Board Class 10 History Solutions Chapter 1 Working of the Constitution 5

Question 6.
Choose the correct option from the given options and complete the sentences:

(a) A scholar who writes critical historical narratives is known as ………………………… .
(a) an archaeologist
(b) a historian
(c) a social scientist
(d) a language expert
Answer:
(b) a historian

(b) The earliest inscription in the world is displayed at Louvre museum in ………………………… .
(a) England
(b) France
(c) Germany
(d) Portugal
Answer:
(b) France

(c) The tradition of recording historical events can be traced back to ………………………… civilization in Mesopotamia.
(a) Sumer
(b) Egyptian
(c) Arab
(d) Mohenjodaro
Answer:
(a) Sumer

(d) The tradition of modern historiography has its roots in the writings of ………………….. historiAnswer:
(a) Roman
(b) Greek
(c) German
(d) French
Answer:
(b) Greek

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(e) ………………….., a Greek historian of the fifth century B.C.E., had used the term ‘History’ for the first time for his book entitled, ‘The Histories’.
(a) Leopold Ranke
(b) Georg Hegel
(c) Michel Foucault
(d) Herodotus
Answer:
(d) Herodotus

(f) In 1737 C.E., the ………………….. university in Germany had an independent department for history.
(a) Oxford
(b) Cambridge
(c) Gottingen
(d) Stanford
Answer:
(c) Gottingen

(g) Historiography of the nineteenth century was greatly influenced by the thoughts of …………………..
(a) Karl Marx
(b) Voltaire
(c) Georg Hegel
(d) Leopold von Ranke
Answer:
(d) Leopold von Ranke

(h) A new school of historiography arose in France known as ………………….. school.
(a) Translation
(b) Annales
(c) Nationalism
(d) Communist
Answer:
(b) Annales

(i) The method of analysis which is based on opposites is known as …………………. .
(a) Numismatics
(b) Arithmetic
(c) Polynomial
(d) Dialectics
Answer:
(d) Dialectics

(j) ………………….. considered subjects like psychological disorders, science of medicine, prison administration for historical analysis.
(a) Michel Foucault
(b) Leopold Ranke
(c) Karl Marx
(d) Voltaire
Answer:
(a) Michel Foucault

(k) After 1990, ………………….. were considered as an independent social class.
(a) labourers
(b) women
(c) men
(d) farmers
Answer:
(b) women

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(l) According to ………………….., historical realities should be presented in a logical manner.
(a) Georg Hegel
(b) Voltaire
(c) Simone de Beauvoir
(d) Herodotus
Answer:
(a) Georg Hegel

(m) According to ………………….., one should never accept anything as the truth till all the doubts are solved.
(a) Rene Descartes
(b) Karl Marx
(c) Voltaire
(d) Herodotus
Answer:
(a) Rene Descartes.

Question 7.
Identify the wrong pair in the following and write it:
(1)

ThinkerBook
(1) Georg Wilhelm Friedrich Hegel(a) Reason in History
(2) Leopold von Ranke(b) The Theory and Practice of History
(3) Herodotus(c) The Histories
(4) Karl Marx(d) Discourse on the Method

Answer:
Wrong pair: Karl Marx – Discourse on the Method.

(2)

HistorianCountry
(1) HerodotusGreece
(2) Simone de BeauvoirGermany
(3) Michel FoucaultFrance
(4) Rene DescartesFrance

Answer:
Wrong pair: Simone de Beauvoir Germany.

(3)

Thoughts/OpinionHistorian
(1) All aspects of human life is important in the historiographyVoltaire
(2) He criticized imaginative narration.Leopold von Ranke
(3) History is not about abstract ideas but about living people.Rene Descartes
(4) Emphasized the rethinking of the male-dominated perspective of history.Simone de Beauvoir

Answer:
Wrong pair: History is not about abstract ideas but about living people – René Descartes.

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Question 8.
Complete the concept chart

Maharashtra Board Class 10 History Solutions Chapter 1 Working of the Constitution 8
Answer:
Maharashtra Board Class 10 History Solutions Chapter 1 Working of the Constitution 9

Maharashtra Board Class 10 History Solutions Chapter 1 Working of the Constitution 10
Answer:
Maharashtra Board Class 10 History Solutions Chapter 1 Working of the Constitution 11

Question 9.
Prepare a flow chart on the given topic:
Stages of historiography
Answer:
Maharashtra Board Class 10 History Solutions Chapter 1 Working of the Constitution 12

Question 10.
Write short notes:

(1) Georg Wilhelm Friedrich Hegel:
Answer:

  • Georg Hegel was a German philosopher.
  • He was of the view that the historical realities should be presented in a logical manner. According to him, Timelme was indicative of progress.
  • He believed that presentation of history is bound to change as time passes because new evidence surfaces.
  • His philosophy convinced many scholars that historical methods were not of lesser quality, though they differed from the scientific method.
  • His lectures and articles are published in a book called ‘Encyclopaedia of Philosophical Sciences’.
  • His book ‘Reason in History’ is well known. He devised a method of analysis based on opposites known as Dialectics’.

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(2) Karl Marx:
Answer:

  1. Karl Marx was a German thinker in the nineteenth century. He wrote the world famous treatise Das Kapital’. According to him, history was not about abstract ideas but about living people.
  2. He believed that human relationships are shaped by the fundamental needs of people and the ownership of prevalent ineczns of production to meet those needs.
  3. He stated that unequal accessibility to the means of production creates à division in socièty leading to class struggle. His theory of class struggle is considered significant all over the world.
  4. According to Marx, human history is the history of class struggle because the class which owns the means of production economically exploits the rest of the classes.

(3) Michel Foucault:
Answer:

  • Michel Foucault was a twentieth century historian from France.
  • He wrote the book ‘Archaeology of Knowledge’.
  • In this book, he insisted that the prevailing practice of arranging historical events in a chronological order is not right.
  • He gave importance to explaining the transitions that took place in history.
  • He acknowledged the role of subjects such as science of medicine, psychological disorders, prison.
  • Administration in historical analysis. This was not acknowledged by earlier historiAnswer:

(4) Leopold von Ranke:
Answer:

  1. Leopold von Ranke, a German philosopher, laid emphasis on utmost importance of information gathered through original documents.
  2. In order to reach historical truth, it was necessary to examine all documents related to historical event. He critcised the imaginative narration of history.
  3. Collection of his articles are published in two books, entitled ‘The Theory and Practice of History’ and ‘The Secret of World History’.
  4. Ranke had great influence on historiography of nineteenth century.

Question 11.
Give reasons:
(a) In historical research, it may not be possible to use the method of experiments and observation.
Answer:

  1. In physical and natural sciences, experiment and observation method is used to establish laws that remain true irrespective of the time and space.
  2. These laws can be tested and proved again and again.
  3. In historical research, the events had already taken place in the past and we were not present in the historical time and space.
  4. Moreover, these events cannot be recreated in the present time and space. Hence, experiment and observation method may not be used in historical research.

(b) Historiography in the 18th century gave importance to objectivity in history.
Answer:

  • A remarkable progress was achieved in the fields of Philosophy and Science till the eighteenth century in Europe.
  • It was believed that by applying scientific methods it was possible to study social and historical truths.
  • In the later period, history and historiography witnessed a lot of philosophical discussion.
  • This eliminated the imaginative and divine context in history and gave importance to objectivity.

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Question 12.
Answer the following in 25-30 words:
(a) What is Historiography?
Answer:

  1. The writing of critical historical narrative is called Historiography. A person who writes it is known as ‘Historian’. The following steps are helpful in writing historical narrative:
  2. Information related to history is collected and analyzed.
  3. The various sources are critically examined to understand the references regarding time and space in the given information as well as the conceptual framework used.
  4. After examining the references of historical information, relevant questions related to these historical references are framed and hypotheseis are formulated.
  5. In short, writing of critical historical narrative by following this method is known as historiography.

(b) What did Rene Descartes insist upon?
Answer:
French Philosopher Rene Descartes insisted on the following in writing historiography:

  1. ‘Never to accept anything as true till all grounds of doubt are excluded’.
  2. Hence, the reliability of a source like historical documents should be verified by critically examining them while writing history.

(c) Why is Voltaire said to be the founder of modern historiography?
Answer:
Voltaire, a french scholar, opined that it was important to consider the following aspects while writing history:

  1. objective truth and chronology of events;
  2. prevalent social traditions, agriculture, trade and economic system. It was because of his view that all aspects of human life was considered for history writing. Therefore, he is said to be the founder of modern historiography.

(d) What are the objectives of writing history?
Answer:
History is researched and written down with following objectives:

  • To analyse the events in the past.
  • To verify information about the historical events and their interconnections.
  • To study in detail and remove imaginative element and bring forth the truth.
  • To put the past events in chronological order.

(e) What progress was achieved in historiography in the eighteenth century?
Answer:
The following progress was achieved in historiography in the eighteenth century:

  • Scientific methods were applied to study social and historical truths.
  • Philosophical discourses revolving around divine phenomena were given less importance.
  • Philosophical discussions focused more on the objectivity in history and historiography.
  • Since the universities got an independent department of history, they became centres of historical studies.

Question 13.
Head the given passage carefully and answer the questions given below:
(a) Who is called a Historian?
Answer:
A scholar who writes critical historical narratives is called a Historian.

(b) Complete the concept chart.
Factors which determined historian’s
Maharashtra Board Class 10 History Solutions Chapter 1 Working of the Constitution 1
Answer:
Factors which determined historian’s
Maharashtra Board Class 10 History Solutions Chapter 1 Working of the Constitution 2

(c) How did the people in ancient societies preserve the events in the past?
Answer:
The ancient people preserved the events in the past so that they can pass them to the next generation. They used various means to do this:

  • Narrating the stories of valour of ancestors to the next generation.
  • Stories of their life preserved through cave paintings.
  • Adopting story telling technique.
  • Singing songs and ballads to impress events upon the minds of the new generation.

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Question 14.
Answer the following questions in detail:
(a) Which experts do we need in order to prove the reliability of historical documents?
Answer:
The following experts are required to prove the reliability of historical documents:

  • Language expert who can decipher the language and meaning of the document or the script on the inscription.
  • One who can recognise the type of paper used and the period in which it was used.
  • One who can understand the lettering style and the writing style of the author.
  • Expert who has knowledge of different seals, i.e. stamps of authority used by the rulers.
  • Historian who can interpret and do a comparative study of the references given in the document.

(b) Write Hegel’s view on history.
Answer:

  • Georg Wilhelm Friedrich Hegel was a German philosopher.
  • He was of the view that the historical realities should be presented in a logical manner.
  • He believed that presentation of history is bound to change as time passes because new evidence surfaces.
  • He proposed a method of analysis based on opposites known as ‘Dialectics’.
  • Hegel’s philosophy convinced many scholars that historical methods were not of lesser quality, though they differed from scientific methods.
  • His lectures and articles are published in a book called ‘Encyclopaedia of Philosophical Sciences’. His book ‘Reason in History’ is well known.

Question 15.
Observe the inscription in the picture and write information it:
Maharashtra Board Class 10 History Solutions Chapter 1 Working of the Constitution 13
Answer:

  1. A fragment of the earliest inscription is shown in the above picture. It dates back to 4500 BCE.
  2. It is displayed at the Louvre museum in France.
  3. The inscriptions have names of Sumerian kings and stories of battles fought by them.
  4. It shows a forward marching file of soldiers holding shields and spears. The General is in the front.
    Brain Teaser
    Hints:
    Down:

    • He used the word ‘History’ for the first time
    • He wrote the book ‘Discourse on the Method’
    • Presented Theory of ‘Dialectics’
    • He called his method ‘Archaeology of Knowledge’

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Across:

  • founder of modern historiography
  • Criticised imaginative narration of history. Articles published in ‘The Secret of World History’
  • Her writings helped in establishing the fundamentals of feminism
  • He wrote ‘Das Kapital’
    Maharashtra Board Class 10 History Solutions Chapter 1 Working of the Constitution 14

Class 10 History Textbook Solutions Answers

Political Parties Question Answer Class 10 Political Science Chapter 3 Maharashtra Board

Std 10 Political Science Chapter 3 Question Answer Political Parties Maharashtra Board

Balbharti Maharashtra State Board Class 10 Political Science Solutions Chapter 3 Political Parties Notes, Textbook Exercise Important Questions and Answers.

Class 10 Political Science Chapter 3 Political Parties Question Answer Maharashtra Board

Political Science Class 10 Chapter 3 Question Answer Maharashtra Board

Question 1.
Choose the correct option from the given options and complete the sentences.
(1) When people come together and participate in electoral process, to acquire political power, such organisations are called ………………………….. .
(a) Government
(b) Society
(c) Political parties
(d) Social organisations
Answer:
(c) Political parties

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(2) National Conference is a party in ………………………….. this region.
(a) Odisha
(b) Assam
(c) Bihar
(d) Jammu and Kashmir
Answer:
(d) Jammu and Kashmir

(3) Justice Party- a non-Brahmin movement was transformed into ………………………….. Political Party.
(a) Assam Gan Parishad
(b) Shivsena
(c) Dravid Munnetra Kazhagam
(d) Jammu and Kashmir National Conference
Answer:
(c) Dravid Munnetra Kazhagam

Question 2.
State whether the following statements are true or false. Give reasons for your answer.
(1) Political parties act as a link between government and people.
Answer:
The above statement is True.

  • The political parties convey the demands and complaints of the people to the government.
  • Information about various government policies and schemes are conveyed to the people by the political parties.
  • People’s reaction to the policies and their expectations are conveyed to the government too by the parties. In this way, political parties act as a link between government and the people.

(2) Political parties are social organisations.
Answer:
The above statement is True.

  • People who have similar views come together voluntarily and form a party, so it can be said that political parties are an integral part of our society.
  • The political parties try to solve the problems of the people.
  • Some political parties represent the role of a particular community in society, its ideology and work to achieve it. Hence it can be said that political parties are social organizations.

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(3) Coalition politics leads to instability.
Answer:
The above statement is False.

  • As no single party got majority after the elections held in 1989, coalition government came to power at the centre and many states.
  • Parties had to set aside their policies and programmes and concentrate on a common agenda to run the government.
  • Both Congress Party and the Bharatiya Janata Party made an experiment of establishing a coalition government.
  • The National Democratic Alliance formed by BJP and its partners and the Democratic Front government formed by Congress and its partners ruled at the centre and state level effectively.

Therefore, the belief that the coalition government brings instability was proved wrong.

(4) Shiromani Akali Dal is a national party.
Answer:
The above statement is False.
The Election Commission of India recognises a political party as National or Regional party on the basis of specific criteria namely:

  • The number of seats secured in Parliament and Legislative Assembly or percentage of votes secured.
  • Shiromani Akali Dal does not meet the criteria listed above.
  • As its influence is limited to the state of Punjab and not in any other state.
  • The Election Commission has given recognition to it as regional party.

Question 3.
Explain the following concepts.
(1) Regionalism
Answer:

  • India is a vast country with great physical diversity. People belonging to different regions have their own language, culture and traditions.
  • Along with the physical diversity, we find diversity in literature, education, history and movements.
  • Each one feels an affinity for his language, traditions and history of social reforms. This gives rise to linguistic identity.
  • This affinity towards all the above-mentioned aspects develops into identity consciousness and gives rise to excessive regional pride.
  • People start giving preference only to the development of their language and region.
  • This is known as Regionalism.

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(2) National Parties
Answer:
A party which functions at the national level is known as National Party.

  1. The Election Commission has laid certain criteria for a party to get recognised as a Political party. The political party should secure at least f 6% valid votes in four or more states in the earlier Lok Sabha. OR
  2. State Assembly elections and minimum four members should be elected in the Lok Sabha from any state or states in the earlier elections. OR
  3. The candidates of a party should be elected from a minimum three states or should be elected from a minimum 2% constituencies of the total Lok Sabha constituencies. OR
  4. It is important to get recognition as a state party in at least four states.

Question 4.
Answer the following questions in brief.
(1) What are the major characteristics of political parties?
Answer:
The main features of political parties are as follows:

  • Political parties aim at securing power by contesting elections.
  • Every political party has some ideology.
  • Every party has an agenda. It is based on the party’s ideology.
  • The party that gets majority seats in election forms the government and the one that does not secure the majority act as opposition parties.
  • Political parties are a link between the people and the government and work to gain the support of the people.

(2) What changes have taken place in the nature of political parties in India?
Answer:
The following changes were seen in the party system in India:

  • Indian- National Congress was the only dominant party in states and at the centre after independence.
  • All other parties came together and formed a coalition in 1977 and defeated the Congress.
  • For the first time in history, the two-party system got importance over one-party system.
  • The one-party system came to an end after the 1989 elections.
  • Regional parties got importance and the coalition government was formed at the centre and in the states.

Project
(1) In a map of Maharashtra, point out the Loksabha constituency that includes the names of your parents.
(2) In a map of India, point out the places where national political parties have their influence.
Answer:

Memory Map
Maharashtra Board Class 10 Political Science Solutions Chapter 3 Political Parties 1

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Question 5.
Choose the correct option from the given options and complete the sentences:
(a) The party which fails to secure majority is known as ………………………. party.
(a) Ruling
(b) Opposition
(c) Independent
(c) Coalition
Answer:
(b) Opposition

(b) ‘Bharatiya Janata Party’ which was formed in 1980 after a split with ………………………. a component of Janata Party.
(a) Jan Sangh
(b) Lok Dal
(c) Independent party
(b) Janata Dal
Answer:
(a) Jan Sangh.

(c) Social support received by a political party is called ………………………. .
(a) Democracy
(b) People’s rule
(c) Mass base
(d) Public relation
Answer:
(c) Mass base

(d) Promotion of the Marathi language is the objective of the ………………………. .
(a) Dravida Munnetra Kazhagam
(b) Shiromani Akali Dal
(c) Shiv Sena
(d) Assam Gana Parishad
Answer:
(c) Shiv Sena

(e) There are ………………………. recognised parties in India.
(a) five
(b) seven
(c) nine
(d) six
Answer:
(b) seven

(f) The main objective of the political party is to capture ………………………. and retain it.
(a) publicity
(b) victory
(c) power
(d) information
Answer:
(c) power

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(g) The ideology of the Communist Party of India is based on ………………………. Philosophy.
(a) Capitalist
(b) Marxist
(c) Democracy
(d) Imperialist
Answer:
(b) Marxist

(h) Shiromani Akali Dal is a prominent regional party in ………………………. state.
(a) Odisha
(b) Assam
(c) Punjab
(d) Jammu and Kashmir
Answer:
(c) Punjab

Question 6.
State whether the following statements are true or false. Give reasons for your answer:

(a) Political parties do not need support of the people.
Answer:
The above statement is False.

  • To secure power is the main aim of political parties.
  • Political parties have to implement various policies and programmes for the welfare of people and to gain the support of the people.
  • The party which solves the issues related to the welfare of the people get support.
  • Without the support of the people they can never get a mandate.

Hence, all political parties require support of the people.

(b) The Communist Party of India was split.
Answer:
The above statement is True.

  • The Communist Party of- India was established in 1925. The Communist Parties follow Marxist ideology.
  • In 1962, due to differences in the leadership a rift was created in the party.
  • The main reason for the split was about which political line to follow.

(c) Sometimes the sentiments of regionalism gets strengthened in the country.
Answer:
The above statement is True.

  1. A country like India has diversity of government language, region and culture. This diversity creates affinity towards a region.
  2. This affinity gives rise to excessive regional S pride and initiating movements to save it. The significance of such movements is claimed to be for preserving culture.
  3. Asserting to be rightful claimant of material resources, job opportunities and development of the region these movements strengthen the regional pride.
  4. Thus, this excessive regional pride turns morbid taking the form of regionalism.

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(d) Regional parties have no influence on National Politics.
Answer:
The above statement is False.

  • No single party got majority in the elections to Lok Sabha held in 1989.
  • The national parties formed coalition government at the centre taking help of regional parties.
  • As regional parties share power at the centre they have influence on national politics.

Question 7.
Explain the concept:
(a) Regional Parties:
Answer:

  1. The groups having a proud feeling about the different identity of their region and who compete to capture power to bring about regional development are ‘Regional Parties’.
  2. The influence of such parties are limited to their region. They give importance to regional problems. Development of one’s own region is the prime objective of these parties.
  3. Sometimes they demand for independent state or autonomy. They influence the national politics because of their dominance in the region.
  4. They have passed through various phases, from separatism to autonomy and have then merged with mainstream national politics.

(b) Political Party:
Answer:

  1. A Political Party is a kind of social organisation of like-minded people. The main aim of any political party is to contest election and secure power.
  2. The stand taken by various political parties on issues becomes their political ideology.
  3. In democracy, political parties are at the centre of all political activities. They are a link that connects common people, democracy, representation and elections.
  4. The party that secures a majority becomes the ruling party and the rest are known as the. opposition.

Question 8.
Write short note:
(a) Party System:
Answer:

  1. If one party remains in power in a country for a long period and no other party has any kind of influence the party system it is called ‘One- Party System’.
  2. When there are two equally strong parties which alternatively come to power. It is called ‘Two-Party System’.
  3. In a country where many political parties exist and compete with each other to capture power and have more or less influence in different states is called ‘Multi-Party System’.
  4. Democracy develops in Multi-Party System.

(b) Indian National Congress:
Answer:

  • The Indian National Congress was established in 1885.
  • The party represented the hopes and aspirations of Indians and led the freedom struggle.
  • Groups having diverse ideologies became part of the Congress to fight for freedom.
  • It believes in democratic socialism, social equality and international peace.
  • After independence, the Congress Party was a dominant party for almost four decades and ruled at the centre and in the states.

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(c) Communist Party of India:
Answer:

  • The Communist Party of India was established in 1925. The Communist Party follows the Marxist ideology.
  • The party aims at working to protect the interests of workers and labourers.
  • The main objective of this party is to oppose capitalism and protect the interests of workers.
  • The party split due to ideological differences in 1964. Those who walked out of the party formed Communist Party (Marxist).

(d) Nationalist Congress Party:
Answer:

  • Nationalist Congress Party (NCP) is the splinter or breakaway party from the Congress Party.
  • It considers the values like democracy, equality and secularism important.
  • It became part of United Progressive Alliance (UPA) and came to power in Maharashtra.
  • It was in power in Maharashtra from 1999 to 2014 and at the centre from 2004 to 2014.

(e) Trinamool Congress:
Answer:

  • All India Trinamool Congress was established in 1998.
  • The Election Commission of India gave it recognition in 2016.
  • Democracy, Secularism and protection of the weaker sections of the society are some of the policies of the party.
  • Presently (April 2019), this party is in power in the state of West Bengal.

(f) Shiv Sena:
Answer:

  1. The Shiv Sena was founded in 1966.
  2. The main objective of the party was to fight for the cause of Marathi-speaking people and preservation of Marathi language.
  3. They resisted the people from other regions.
  4. In 1995, it became the ruling party with BJP in Maharashtra and its strategic tie-up with BJP helped it to enter national politics.
  5. It was in power at the centre with BJP from 1998 to 2004. Again it has shared power with the BJP at the centre and state since 2014.

(g) Shiromani Akali Dal:
Answer:

  • Shiromani Akali Dal was formed in 1920.
  • It is a dominating party in Punjab.
  • It gives preference to nurture religious and for the regional pride.
  • The party has retained power in Punjab for many years.

(h) Dravid Munnetra Kazhagam:
Answer:

  • Justice party, a non-Brahmin movement, started in 1920. In 1944, it transformed into a political party called Dravid Kazhagam.
  • In 1949, a group within the party got split and formed Dravid Munnetra Kazhagam (DMK).
  • The party works for the protection of Tamil identity.
  • This party implemented many policies for welfare of the people and therefore has support from all the sections of society.
  • Another group separated from it in 1972 and formed All India Dravid Munnetra Kazhagham.
  • It remained in power for a long time in Tamil Nadu and for sometime at the centre.

Maharashtra Board Solutions

Question 9.
Do as directed
(a) Complete the concept map:
Maharashtra Board Class 10 Political Science Solutions Chapter 3 Political Parties 2
Answer:
Maharashtra Board Class 10 Political Science Solutions Chapter 3 Political Parties 3

Maharashtra Board Class 10 Political Science Solutions Chapter 3 Political Parties 4
Answer:
Maharashtra Board Class 10 Political Science Solutions Chapter 3 Political Parties 5

Maharashtra Board Solutions

(3)
Maharashtra Board Class 10 Political Science Solutions Chapter 3 Political Parties 6
Answer:
Maharashtra Board Class 10 Political Science Solutions Chapter 3 Political Parties 7

(b) Complete the Time-line writing the name of the party or the year of establishment:
Maharashtra Board Class 10 Political Science Solutions Chapter 3 Political Parties 8
Answer:
Maharashtra Board Class 10 Political Science Solutions Chapter 3 Political Parties 9

Question 10.
Answer the following questions in brief:

(a) What is called “mass base”?
Answer:

  • Every political party is formed with some ideology.
  • Political parties take a certain stand towards public issues.
  • Their ideology and their stand towards public issues are conveyed to the people through various programmes.
  • If the people agree with their role and ideology, they get the support of the people.
  • Such social support received by a political – party is called ‘mass base’.

(b) Write about the policies of Indian National Congress.
Answer:
The policies of the Indian National: Congress are as follows:

  • Equal rights for the minorities and weaker sections of society.
  • Secularism, all-round development and social welfare are its objectives.
  • Introduction of socialist democracy.
  • Belief in values like international peace and social equality.

Maharashtra Board Solutions

(c) Explain the role of Bharatiya Janata Party.
Answer:
Bharatiya Janata Party was formed in 1980 with the following objectives:

  • To preserve Indian culture and traditions.
  • To create a strong and rich India.
  • To give importance to economic reforms for development of India.

(d) Write about the policies of Communist Party of India (Marxist).
Answer:
Communist Party of India (Marxist) was formed in 1964 with the following objectives:

  • The party advocates socialism, secularism and democracy.
  • The main policy of the party is to work for the welfare of farmers, landless labourers and workers.
  • The party opposes imperialism.

(e) Why was Bahujan Samaj Party formed?
Answer:
The Bahujan Samaj Party was formed in 1984 to achieve the following objectives:

  • To bring socialist ideology into practice.
  • To secure power for ‘majority’ comprising of scheduled castes, scheduled tribes and other backward classes.
  • To give power in the hands of ‘majority’.

(f) What do the regional parties give preference for?
Answer:
The regional parties give preference to the following issues:

  • Importance should be given to regional issues and bring about development.
  • Regional issues should be handled* at regional level.
  • The power rests in the hands of regional people. ‘
  • People living in that region should get preference in administration and jobs. .

(g) What changes are seen in the nature and role of regional parties?
Answer:
The role of regional parties changed over period of time. The changes are as follows:

  • After independence, regional identity gave rise to separatists movements and demands were put up by regional parties for separate state.
  • They wanted to break away from the Indian union and form a separate state.
  • The demands of the regional parties changed gradually and these parties started asking for autonomy.
  • In the later period, for the development of their region and people the parties demanded representation of their people in the state and central government.
  • Regional parties in the north eastern region also started demanding more autonomy after split up.
  • The journey of the regional parties began with a split up and then a demand for autonomy going on to share power in federation and then entry into mainstream national politics.

Maharashtra Board Solutions

(h) What are the objectives of Assam Gana Parishad?
Answer:
Assam Gana Parishad was formed in 1985 with the following objectives:

  • To preserve the uniqueness of Assam’s culture, language and social identity.
  • To make efforts for economical development of Assam.
  • To resolve problems of displaced people.

(i) What are the criteria for a regional party to get recognition?
Answer:

  • In the last general .elections to the State Assembly, the party should not secure less than 6% of the total number of valid votes polled.
  • At least 2 members to be elected to the Legislative Assembly (Vidhan Sabha).
  • 3% seats of the total seats of Legislative Assembly or at least 3 seats in Legislative Assembly.

(j) What work is done by political parties?
Answer:
The following work is done by political parties:

  • To propagate policies and programmes of the party and contest elections.
  • They implement various policies when they come to power.
  • If they fail to secure power, they act as opposition party and try to gain support of the people.
  • They communicate the demands and complaints of the people to the government and the policies and programmes of the government to the people.

Question 11.
Give your opinion:

(a) Imagine you are opposition party leader and you have observed that the ruling party has not done good work in the field of health. What will you do as a leader of opposition?
Answer:
As opposition leader, I will do the following to make the government realise its negligence in the health field:

  • I will question the government in Parliament and point out their shortcomings and ask about the prolonged projects.
  • I will create awareness among the people by writing articles in newspapers.
  • I will give interviews,on radio and television and criticize the government.
  • I will organise rallies and meetings to sensitize among the people.

(b) Think and write
What has to be done to bring partyless democracy in modern times?
Answer:

  • The recognition of all the parties should be cancelled. ‘
  • People should be given the right to make decisions.
  • In order to improve the decision-making power, people should be educated on political issues.
  • To improve the moral character of the people who want to take the leadership.
  • To initiate direct democracy and prepare the people for the same.
  • Stress should be given for decentralization.
  • Mahatma Gandhi, Vinoba Bhave and Jayprakash Narayan put forth the idea of partyless democracy.
  • What has to be done to bring such democracy in modern times?

Maharashtra Board Solutions

Question 12.
What do you understand by the following news in newspapers? Explain in brief.

(a) Opposition parties held a meeting in Mumbai to resist the Ruling party. Will take up the issue of farmers?
Answer:

  • The ruling party did not undertake any work for the welfare of farmers. Therefore all the opposition parties decided to trap the government on this issue.
  • The opposition parties have kept aside their differences and come together for this cause.
  • It is the duty of the opposition party to question the negligence of the government.
  • This news makes us aware of the line of action taken by the opposition.
  • Opposition parties held a meeting in Mumbai to resist the Ruling party. Will take up the issue of farmers?
  • Ruling party organised ‘Samvad Yatra’ in rural areas.

(b) Ruling party has organised ‘Samvad Yatra’ in rural areas.
Answer:

  • Political parties adopt different ways to popularise their party and influence the people.
  • As the means of communication are limited in rural areas they organise the Yatra.
  • It shows the efforts of the government to understand problems of people in rural areas.
  • It is essential to have dialogue with people to know their problems and opinions.
  • As the initiative is taken by the government, people will develop faith in government.
  • The news conveys to us that the ruling party is carrying out its duties properly.
  • The faith in government becomes profound when people feel that government is sensitive towards them.

Class 10 Political Science Textbook Solutions Answers

Practice Set 50 Class 7 Answers Chapter 14 Algebraic Formulae – Expansion of Squares Maharashtra Board

Algebraic Formulae – Expansion of Squares Class 7 Maths Chapter 14 Practice Set 50 Solutions Maharashtra Board

Balbharti Maharashtra State Board Class 7 Maths Solutions covers the 7th Std Maths Practice Set 50 Answers Solutions Chapter 14 Algebraic Formulae – Expansion of Squares.

Std 7 Maths Practice Set 50 Solutions Answers

Question 1.
Expand:
i. (5a + 6b)²
ii. \(\left(\frac{\mathrm{a}}{2}+\frac{\mathrm{b}}{3}\right)^{2}\)
iii. (2p – 3q)²
iv. \(\left(x-\frac{2}{x}\right)^{2}\)
v. (ax + by)²
vi. (7m – 4)²
vii. \(\left(x+\frac{1}{2}\right)^{2}\)
viii. \(\left(a-\frac{1}{a}\right)^{2}\)
Solution:
i. (5a + 6b)²
Here, A = 5a and B = 6b
(5a + 6b)² = (5a)² + 2 × 5a × 6b + (6b)²
…. [(A + B)² = A² + 2AB + B²]
∴ (5a + 6b)² = 25a² + 60ab + 36b²

ii. \(\left(\frac{\mathrm{a}}{2}+\frac{\mathrm{b}}{3}\right)^{2}\)
Here A = \(\frac { a }{ 2 }\) and B = \(\frac { b }{ 3 }\)
Maharashtra Board Class 7 Maths Solutions Chapter 14 Algebraic Formulae - Expansion of Squares Practice Set 50 1

iii. (2p – 3q)²
Here, a = 2p and b = 3q
(2p – 3q)² = (2p)² – 2 × (2p) × (3q) + (3q)²
…. [(a – b)² = a² – 2ab + b²]
∴ (2p – 3q)² = 4p² – 12pq + 9q²

iv. \(\left(x-\frac{2}{x}\right)^{2}\)
Here a = x and b = \(\frac { 2 }{ x }\)
Maharashtra Board Class 7 Maths Solutions Chapter 14 Algebraic Formulae - Expansion of Squares Practice Set 50 2

v. (ax + by)²
Here, A = ax and B = by
(ax + by)² = (ax)² + 2 × ax × by + (by)²
…. [(A + B)² = A² + 2AB + B²]
∴ (ax + by)² = a²x² + 2abxy + b²y²

vi. (7m – 4)²
Here, a = 7m and b = 4
(7m – 4)² = (7m)² – 2 × 7m × 4 + 4²
…. [(a – b)² = a² – 2ab + b²]
∴ (7m – 4)² = 49m² – 56m + 16

vii. \(\left(x+\frac{1}{2}\right)^{2}\)
Here a = x and b = \(\frac { 1 }{ 2 }\)
Maharashtra Board Class 7 Maths Solutions Chapter 14 Algebraic Formulae - Expansion of Squares Practice Set 50 3

viii. \(\left(a-\frac{1}{a}\right)^{2}\)
Here A = a and B = \(\frac { 1 }{ a }\)
Maharashtra Board Class 7 Maths Solutions Chapter 14 Algebraic Formulae - Expansion of Squares Practice Set 50 4

Question 2.
Which of the options given below is the square of the binomial
(A) \(64-\frac{1}{x^{2}}\)
(B) \(64+\frac{1}{x^{2}}\)
(C) \(64-\frac{16}{x}+\frac{1}{x^{2}}\)
(D) \(64+\frac{16}{x}+\frac{1}{x^{2}}\)
Solution:
(C) \(64-\frac{16}{x}+\frac{1}{x^{2}}\)

Hint:
= \(\left(8-\frac{1}{x}\right)^{2}=8^{2}-2 \times 8 \times \frac{1}{x}+\left(\frac{1}{x}\right)^{2}\) …[(a – b)² = a² – 2ab + b²]
= \(64-\frac{16}{x}+\frac{1}{x^{2}}\)

Question 3.
Of which of the binomials given below is the m²n² + 14mnpq + 49p²q² the expansion?
(A) (m + n) (p + q)
(B) (mn – pq)
(C) (7mn + pq)
(D) (mn + 7pq)
Solution:
(D) (mn + 7pq)

Hint:
Here, square root of the first term = mn
Square root of the last term = 7pq
∴ Required binomial = (mn + 7pq)²

Question 4.
Use an expansion formula to find the values of:
i. (997)²
ii. (102)²
iii. (97)²
iv. (1005)²
Solution:
i. (997)² = (1000 – 3)²
Here, a = 1000 and b = 3
(1000 – 3)² = (1000)² – 2 x 1000 x 3 + 3²
…. [(a – b)² = a² – 2ab + b²]
= 1000000 – 6000 + 9
= 994009
∴ (997)² = 994009

ii. (102)² = (100 + 2)²
Here, a = 100 and b = 2
(100 + 2)² = (100)² + 2 x 100 x 2 + 2²
…. [(a + b)² = a² + 2ab + b²]
= 10000 + 400 + 4
= 10404
∴ (102)² = 10404

iii. (97)² = (100 – 3)²
Here, a = 100 and b = 3
(100 – 3)² = (100)² – 2 x 100 x 3 + 3²
…. [(a – b)² = a² – 2ab + b²]
= 10000 – 600 + 9
= 9409
∴ (97)² = 9409

iv. (1005)² = (1000 + 5)²
Here, a = 1000 and b = 5 (1000 + 5)²
= (1000)² + 2 x 1000 x 5 + 5²
…. [(a + b)² = a² + 2ab + b²]
= 1000000+ 10000 + 25
= 1010025
∴ (1005)² = 1010025

Maharashtra Board Class 7 Maths Chapter 14 Algebraic Formulae – Expansion of Squares Practice Set 50 Intext Questions and Activities

Question 1.
Use the given values to verify the formulae for squares of binomials. (Textbook pg. no. 92)
i. a = -7, b = 8
ii. a = 11,b = 3
iii. a = 2.5,b = 1.2
Solution:
i. (a + b)² = (-7 + 8)²
= 1²
= 1
a² + 2ab + b² = (-7)² + 2 x (-7) x 8 + 8²
= 49 – 112 + 64
= 1
∴(a + b)² = a² + 2ab + b²
(a – b)² = (-7 – 8)²
= (-15)²
= 225
a² – 2ab + b² = (-7)² – 2 x (-7) x 8 + (8)²
= 49 + 112 + 64
= 225
∴(a – b)² = a² – 2ab + b²

ii. (a + b)² = (11 + 3)²
= 14²
= 196
a² + 2ab + b² = 11² + 2 x 11 x 3 + 3²
= 121 + 66 + 9
= 196
∴(a + b)² = a² + 2ab + b²
(a – b)² = (11 – 3)² = 8²
= 64
a² – 2ab + b² = 11² – 2 x 11 x 3 + 3²
= 121 – 66 + 9
= 64
∴(a – b)² = a² – 2ab + b²

iii. (a + b)² = (2.5 + 1.2)²
= 3.7²
= 13.69
a² + 2ab + b² = (2.5)² + 2 x 2.5 x 1.2 + (1.2)²
= 6.25 + 6 + 1.44
= 13.69
∴(a + b)² = a² + 2ab + b²
(a – b)² = (2.5 – 1.2)²
= 1.32
= 1.69
a² – 2ab + b² = (2.5)² – 2 x 2.5 x 1.2 + (1.2)²
= 6.25 – 6 + 1.44
= 1.69
∴(a – b)² = a² – 2ab + b²-

Class 7 Maths Solution Maharashtra Board

Heredity and Variation Class 9 Science Chapter 16 Questions And Answers Maharashtra Board

Std 9 Science Chapter 16 Heredity and Variation Question Answer Maharashtra Board

Balbharti Maharashtra State Board Class 9 Science Solutions Chapter 16 Heredity and Variation Notes, Textbook Exercise Important Questions and Answers.

Class 9 Science Chapter 16 Heredity and Variation Question Answer Maharashtra Board

Class 9 Science Chapter 16 Heredity and Variation Textbook Questions and Answers

1. Complete the following sentences by choosing the appropriate words from the brackets.
(Inheritance, sexual reproduction, asexual reproduction, chromosomes, DNA, RNA, gene)

a. Hereditary characters are transferred from parents to offsprings by …………………………….., hence they are said to be structural and functional units of heredity.
b. Organisms produced by …………………………….. show minor variations.
c. The component which is in the nuclei of cells and carries the hereditary characteristics is called ……………………………..
d. Chromosomes are mainly made up of ……………………………..
e. Organisms produced through …………………………….. show major variations.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

2. Explain the following.

a. Explain Mendel’s monohybrid progeny with the help of any one cross.
Answer:

  • Mendel brought about a cross between two pea plants with only pair of contrasting characters. This type of cross is called a monohybrid cross.
  • Tall pea plants and dwarf pea plants were used in this cross. Hence this is parent generation (P1).
    Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation 3
  • All the plants produced in F1 genration are tall, having genotype Tt. This indicates that the gene responsible for tallness in pea plants is dominant over the gene responsible for dwarfness.
  • When F1 plants are self pollinated they produce second filial generation (F2).
  • In F2 generation both tall and dwarf plants appeared in the ratio 3:1.
  • Thus, the genotypic ratio of F2 generation is 3 (Tall) : 1 (Dwarf) and the genotypic ratio is 1 TT : 2 Tt: 1 tt.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

b. Explain Mendel’s dihybrid ratio with the help of any one cross.
Answer:

  • In dihybrid cross, Mendel considered two pairs of contrasting characters.
  • He made a cross between a pea plant producing rounded and yellow couloured seeds and a pea plant with wrinkled and green coloured seeds.
    Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation 4
  • All the plants produced in F1 generation had rounded yellow seeds. This is because in pea plants, round shape of seed is dominant over wrinkled shape and yellow colour of seed is dominant over green colour.
  • When F1 plants are self pollinated, they produce four types of gamates – RY, Ry, rY, ry.
  • F2 plants formed by the fusion of four types of male gametes and four types of female gametes, had phenotypes such as round yellow, wrinkled yellow, round green and wrinkled green.
  • Also, F2 generation showed nine different types of genotypes such as RRYY, RRYy, RRyy, RrYY, RrYy, Rryy, rrYY, rrYy, rryy.
  • Phenotypic ratio of dihybrid cross is
    Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation 5
  • The genotypic ratio of dihybrid cross is
    Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation 6

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

c. Distinguish between monohybrid and dihybrid cross.
Answer:

Monohybrid crossDihybrid cross
(i) Cross involving a single pair of contrasting characters is called monohybrid cross.(i) Cross involving two pairs of contrasting characters is called a dihybrid cross.
(ii) F1 plants of monohybrid cross produce two types of gametes.(ii) F1 plants of dihybrid cross produce four types of gametes.
(iii) Monohybrid cross has a phenotypic ratio of 3 : 1 in F2 generation.(iii) Dihybrid cross has a phenotypic ratio of 9 : 3 : 3 : 1 in F2 generation.

d. Is it right to avoid living with a person suffering from a genetic disorder?
Answer:

  • No, it is not right to avoid living with a person suffering from a genetic disorder.
  • Genetic disorders are transmitted from parents to offsprings only and they are non-contagious, i.e., they do not spread from one person to another through contact.

3. Answers the following questions in your own words.

a. What is meant by ‘chromosome’. Explain its types.
Answer:

  • The structure in the nucleus of cells that carries the hereditary characteristics is called the chromosome.
  • It is made up mainly of nucleic acids and proteins.
  • Depending upon the position of the centromere, there are four types of chromosomes.
    Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation 7

(a) Metacentric: The centromere is exactly at the mid-point in this chromosome, and therefore, it looks like the English letter ‘V’. The arms of this chromosome are equal in length.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

(b) Sub-metacentric: The centromere is somewhere near the mid-point in this chromosome which, therefore, looks like the English letter ‘U. One arm is slightly shorter than the other.

(c) Acrocentric: The centromere is near one end of this chromosome which therefore looks like the English letter One arm is much smaller than the other.

(d) Telocentric: The centromere is right at the end of this chromosome making the chromosome look like the English letter ‘i’. This chromosome consists of only one arm.

b. Describe the structure of the DNA molecule.
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation 8

  • In 1953, Watson and Crick proposed a model of the DNA molecule.
  • As per their model, two parallel threads (strands) of nucleotides are coiled around each other to form a double helix structure. This structure can be compared with a coiled and a flexible ladder.
  • Each strand of DNA is made up of many small molecules known as nucleotides.
  • Each nucleotide is made up of a molecule of nitrogen base and phosphoric acid joined to a molecule of sugar.
  • There are four types of nitrogen bases-adenine, guanine, cytosine and thymine. Adenine and guanine are called as purines while cytosine and thymine are called as pyrimidines.
  • Nucleotides are arranged like a chain in the DNA.
  • The two threads (strands) of the DNA are comparable to the two rails of the ladder and each rail is made up of alternately joined molecules of sugar and phosphoric acid.
  • Each rung of the ladder is a pair of nitrogenous bases joined by hydrogen bonds. Adenine always pairs with thymine and cytosine always pairs with guanine.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

c. Express your opinion about the use of DNA fingerprinting.
Answer:

  • DNA fingerprinting is the technique in which the sequence of the genes in the DNA of a person, i.e., the genome of the person is identified.
  • This technique is useful to identify the lineage and to identify criminals because it is unique to every person.
  • It is also useful to identify paternity and maternity disputes etc.
  • This technique was developed by Professor of genetics Sir Alec Jeffreys.
  • A common method of collecting a reference sample, is in the use of a buccal swab. If this is not available, blood or saliva or hair sample may be used.
  • Just like your actual fingerprint, your DNA fingerprint is something that you are born with. It is unique to you.
  • DNA fingerprint is very useful in forensic science.

d. Explain the structure, function and types of RNA.
Answer:

  • Ribonucleic acid (RNA) is an important nucleic acid of the cell.
  • RNA is made up of ribose sugar, phosphate molecules and four types of nitrogenous bases adenine, guanine, cytosine and uracil.
  • The nucleotide i.e., smallest unit of the chain of the RNA molecule is formed by the combination of a ribose sugar, phosphate molecule and one of the nitrogen bases.
  • Large numbers of nucleotides are bonded together to form the macromolecule of RNA.
  • RNA performs the function of protein synthesis.
  • According to function, there are three types of RNA:
    (a) Ribosomal RNA (rRNA): It is the component of cellular organelle ribosome. Ribosomes perform the function of protein synthesis.(b) Messenger RNA (mRNA): It carries the information for protein synthesis from genes (i.e. DNA segment in the cell nucleus) to ribosomes (in the cytoplasm) which produce the proteins.(c) Transfer RNA (tRNA): It carries the amino acid up to the ribosomes as per the message of the mRNA.

e. Why is it necessary for people to have their blood examined before marriage?
Answer:

  • If people have their blood examined before marriage, the partners will know about the possible genetic diseases that their children might inherit. So they may decide not to have children or not to get married.
  • Blood tests before marriage are also done to check for any contagious disease in the partners. This will help to protect the partners from contagious diseases like STDs.

4. Write a brief note on each.

a. Down syndrome
Answer:

  • Down syndrome is the disorder arising due to chromosomal abnormality.
  • This is the first discovered and described the chromosomal disorder in human beings.
  • This disorder is characterized by the presence of 47 chromosomes. It is described as the trisomy of the 21st pair.
  • Infants with this disorder have one extra chromosome with the 21st pair in every cell of the body. Therefore, they have 47 chromosomes instead of 46. Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation
  • Children suffering from Down syndrome are usually mentally retarded and have a short lifespan. Mental retardation is the most prominent characteristic.
  • Other symptoms include short height, short wide neck, flat nose, short fingers, scanty hair, single horizontal crease on palm and a life expectancy of about 16-20 years.

b. Monogenic disorders
Answer:

  • Disorders occurring due to mutation in any single gene into a defective one are called monogenic disorders.
  • Approximately 4000 disorders of this type are now known.
  • Due to abnormal genes, their products are either produced in insufficient quantity or not produced at all.
  • It causes abnormal metabolism and may lead to death at a tender age.
  • Examples of monogenic disorders are Hutchinson’s disease, Tay-Sachs disease, galactosaemia, phenylketonuria, sickle cell anaemia, cyctic fibrosis, albinism, haemophilia, night blindness etc.

c. Sickle cell anaemia: symptoms and treatment.
Answer:

  • Sickle-cell anaemia is a hereditary disease caused due to mutation in a single gene. It is a monogenic disorder.
  • Normal haemoglobin has glutamic acid as the 6th amino acid in its molecular structure. However, if it is replaced by valine, the shape/structure of the haemoglobin molecule, changes.
  • Due to this, the erythrocytes (RBCs) which are normally biconcave become sickle-shaped. This condition is called sickle-cell anaemia. The oxygen-carrying capacity of haemoglobin in such individuals is very low.
  • In this condition, clumping and thereby, destruction of erythrocytes occurs most often. As a result, blood vessels are obstructed and the circulatory system, brain, lungs, kidneys, etc. are damaged.
  • Symptoms of sickle-cell anaemia are swelling of legs and hands, pain in joints, severe general body aches, frequent cold and cough, constant low-grade fever, exhaustion, pale face, low haemoglobin count.
  • A person suffering from sickle-cell anaemia should take a tablet of folic acid daily.

5. How are the items in groups A, B and C inter-releated?

6. Filling the blanks based on the given relationship.
a. 44 + X : Turner syndrome : : 44 + XXY: – ……………………………..
b. 3:1 Monohybrid : : 9:3:3:1 : ……………………………..
c. Women : Turner syndrome : : Men : ……………………………..
Answer:
a. Klinefelter syndrome
b. Dihybrid
c. Klinefelter syndrome

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

7. Complete the tree diagram below based on types of hereditary disorders.
Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation 1
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation 2

Class 9 Science Chapter 12 Study of Sound Intext Questions and Answers

Question 1.
How do specific traits or characteristics appear in organisms? (Can you tell; Textbook Page No. 180)
Answer:

  • Information necessary for synthesis of a particular protein is stored in the DNA.
  • The segment of DNA which contains all the information for synthesis of a particular protein is called a gene for that protein.
  • To understand how a specific trait is expressed, let us consider plant height as an example.
  • We know that there are growth hormones in plants. Increase in the height of plants depends upon the quantity of growth hormones.
  • The quantity of growth hormone produced by a plant depends upon the efficiency of the concerned enzyme.
  • Efficient enzymes produce a greater quantity of the hormone due to which the height of the plant increases.
  • However, if the enzymes are less efficient, a smaller quantity of hormone is produced leading to the stunting of the plant.
  • Thus, the expression of traits is controlled by the genes.

Question 2.
Show the monohybrid cross between (RR) and (rr) and write the phenotypic and genotypic ratio of F2 generation. (Use your brain power; Textbook Page No. 187)
Answer:
Parental Generation (P1)
Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation 9
Phenotypic ratio : 3 Round : 1 Wrinkled
Genotypic ratio : 1 RR : 2 Rr : 1 rr

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 3.
Why did the characteristic of the Rounded- Yellow seeds alone appear in the Fj generation but not the characteristic of the wrinkled- green seeds? (Use your brain power; Textbook Page No. 187)
Answer:

  • Rounded-Yellow seeds is a dominant characteristic whereas wrinkled-green seeds is a recessive characteristic.
  • Therefore only the characteristic of Rounded- Yellow seeds appeared in the F1 generation.

Question 4.
Do all boys and girls of your class look alike? (Think about it; Textbook Page No. 179)
Answer:

  • No, all the boys and girls of my class do not look alike.
  • There is a lot of variation among them.

Question 5.
Carefully observe your classmate’s earlobes. (Observe; Textbook Page No. 179)
Answer:

  • Most of the classmates have free earlobes while very few have attached ear lobes.
  • This shows that in humans free earlobes is a dominant characteristic whereas attached earlobe is a recessive characteristic.

Question 6.
Irrespective of all of us being humans, what difference do you notice in our skin colour? (Observe; Textbook Page No. 179)
Answer:

  • Irrespective of all of us being humans, there is a lot of variation in our skin colour. Some people are light-skinned while some are dark-skinned.
  • The difference in skin colour is due to the gene responsible for the production of the pigment melanin.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 7.
All of you are in std. IX. Why then are some students tall and some short? (Observe; Textbook Page No. 179)
Answer:
Our height is decided by gene. People who are tall have genes for tallness whereas people who are short have genes for shortness and hence the variation.

Class 9 Science Chapter 12 Study of Sound Additional Important Questions and Answers

Choose and write the correct option:

Question 1.
The similarities and differences are all the effect of
(a) Heredity
(b) Fertilization
(c) Evolution
(d) Natural selection
Answer:
(a) Heredity

Question 2.
Each chromosome appears midway during cell division.
(a) Circular
(b) Rod-shaped
(c) Dumbbell-shaped
(d) Bottle-shaped
Answer:
(c) dumbbell-shaped

Question 3.
The chromosome in which the centromere is exactly at the mid-point is called chromosome.
(a) sub-metacentric
(b) metacentric
(c) acrocentric
(d) telocentric
Answer:
(b) metacentric

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 4.
The chromosome in which the centromere is somewhere near the mid-point is called chromosome.
(a) metacentric
(b) acrocentric
(c) sub-metacentric
(d) telocentric
Answer:
(c) sub-metacentric

Question 5.
The chromosome in which the centromere is near one end of the chromosome is called chromosome.
(a) metacentric
(b) acrocentric
(c) sub-metacentric
(d) telocentric
Answer:
(d) telocentric

Question 6.
Sex chromosomes are called
(a) homologous chromosomes
(b) autosomes
(c) allosomes
(d) metacentric chromosomes
Answer:
(c) allosomes

Question 7.
Which of the following is absent in RNA?
(a) Adenine
(b) Uracil
(c) Cytosine
(d) Thymine
Answer:
(d) Thymine

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 8.
DNA was discovered by
(a) Watson and Crick
(b) Frederick Miescher
(c) Gregor Johann Mendel
(d) Robert Brown
Answer:
(b) Frederick Miescher

Question 9.
The double helix model of DNA was produced by
(a) Watson and Crick
(b) Frederick Miescher
(c) Gregor Johann Mendel
(d) Robert Hooke
Answer:
(a) Watson and Crick

Question 10.
The molecule of RNA which is a component of the ribosome organelle is called a
(a) mRNA
(b) tRNA
(c) rRNA
(d) DNA
Answer:
(c) rRNA

Question 11.
In a monohybrid cross, the phenotypic ratio of F, generation is
(a) 1 tall: 3 dwarf
(b) 2 tall: 2 dwarf
(c) 3 tall: 1 dwarf
(d) 3 tall: 2 dwarf
Answer:
(c) 3 talhl dwarf

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 12.
arises due to either inheritance of only X chromosome from parents or due to inactivation of the gender-related part of X-chromosomes.
(a) Down syndrome
(b) Turner syndrome
(c) Klinefelter syndrome
(d) Albinism
Answer:
(b) Turner syndrome

Question 13.
Progenies of normal man and sufferer woman for sickle-cell anaemia will be
(a) all normal
(b) 25% normal and 75% sufferer
(c) all carrier
(d) all sufferer
Answer:
(c) all carrier

Question 14.
is a mitochondrial disorder.
(a) Down syndrome
(b) Cleft palate
(c) Spina bifida
(d) Leber hereditary optic neuropathy
Answer:
(d) Leber hereditary optic neuropathy

Question 15.
is a monogenic disorder.
(a) Haemophilia
(b) Cleft palate
(c) Diabetes
(d) Spina bifida
Answer:
(a) Haemophilia

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 16.
is a recessive character of pea plant.
(a) Round shape of seeds
(b) White colour of flowers
(c) Green colour of pods
(d) Inflated shape of pods
Answer:
(b) White colour of flowers

Question 17.
is a dominant character of pea plant.
(a) Dwarf height
(b) Yellow colour of pod
(c) Yellow colour of seeds
(d) Terminal position of flower
Answer:
(c) Yellow colour of seeds

Question 18.
is a dominant character in human beings.
(a) Non-rolling tongue
(b) Attached ear lobe
(c) Absence of hair on arms
(d) Free ear lobe
Answer:
(d) Free ear lobe

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 19.
is a recessive character in human beings.
(a) Absence of hair on arms
(b) Black and curly hair
(c) Free earlobe
(d) Presence of hair on arms
Answer:
(a) Absence of hair on arms

Question 20.
If one parent is normal and one parent is carrier of sickle-cell anaemia, then the progenies will be
(a) all normal
(b) 50% normal and 50% carrier
(c) 50% carrier and 50% sufferer
(d) all carrier
Answer:
(b) 50% normal and 50% carrier

Question 21.
If one parent is carrier and one parent is a sufferer of sickle-cell anaemia, then the progenies will be
(a) 50% normal and 50% carrier
(b) all sufferers
(c) 50% carrier and 50% sufferer
(d) all carrier
Answer:
(c) 50% carrier and 50% sufferer

Find the odd man out:

Question 1.
Adenine, thymine, cytosine, uracil
Answer:
Adenine. It is a purine whereas the others are pyrimidines.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 2.
Axillary flower, green pod, green seed, inflated pod
Answer:
Green seed. It is a recessive character of pea plant whereas the others are dominant characters.

Question 3.
Constricted pod, purple flower, axillary flower, yellow seeds.
Answer:
Constricted pod. It is a recessive character of pea plant whereas the others are dominant characters.

Question 4.
Green seeds, wrinkled seeds, terminal flower, green pod.
Answer:
Green pod. It is a dominant character of pea plant whereas the others are recessive characters.

Question 5.
Attached ear lobes, brown and straight hair, non-rolling tongue, presence of hair on arms.
Answer:
Presence of hair on arms. It is a dominant characteristic of human beings whereas the others are recessive characters.

Question 6.
Cystic fibrosis, albinism, spina bifida, sicklecell anaemia.
Answer:
Spina bifida. It is a polygenic disorder whereas the others are monogenic disorders.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 7.
Fiutchinson’s disease, phenylketonuria, nightblindness, leber hereditary optic neuropathy.
Answer:
Leber hereditary optic neuropathy. It is a mitochondrial disorder whereas the others are monogenic disorders.

Complete the analogy:

a. Tall plant: Phenotype :: Tt:
b. Dominant trait : Axial position of flower :: Recessive trait:
c. Women : 44 + XX :: Men :
d. Adenine and Guanine : Purine :: Cytosine and Thymine :
Answer:
a. Genotype
b. Terminal position of flower
c. 44 + XY
d. Pyrimidine

Match the columns

Question 1.

Column 1Column 2Column 3
(1) Leber hereditary optic neuropathy(a) 44 + XXY(i) Pale skin, white hairs.
(2) Diabetes(b) 45 + X(ii) Men are sterile.
(3) Albinism(c) Mitochondrial disorder(iii) Women are sterile.
(4) Turner syndrome(d) Polygenic disorder(iv) This disorder arises during development of zygote.
(5) Klinefelter Syndrome(e) Monogenic disorder(v) Effect on blood- glucose level.

Answer:
(1 – c – iv),
(2 – d – v),
(3 – e – i),
(4-b- Hi),
(5 – a – ii)

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 2.

Column ‘A’Column ‘B’
(1) Yellow and rinkled(a) yyrr
(2) Green and round(b) YyRr
(3) Yellow and round(c) YYrr
(4) Green and wrinkled(d) yyRr

Answer:
(1 – c),
(2 – d),
(3 – b),
(4 – a)

Question 3.

Column ‘A’Column ‘B’
(1) Tay-Sachs disease(a) Multifactorial disorder
(2) Diabetes(b) Destruction of erythrocytes
(3) Sickle-cell anaemia(c) Absence of melanin
(4) Albinism(d) Monogenic disorder

Answer:
(1 – d),
(2 – a),
(3 – b),
(4 – c)

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

State whether the following statements are true or false. Correct the false statement:

Question 1.
Offsprings produced through asexual reproduction show greater variations as compared to those produced through sexual reproduction.
Answer:
False. Offsprings produced through asexual reproduction show minor variations as compared to those produced through sexual reproduction.

Question 2.
Information necessary for protein synthesis is stored in the RNA.
Answer:
False. Information necessary for protein synthesis is stored in the DNA.

Question 3.
The quantity of growth hormone produced by a plant depends upon the efficiency of the concerned enzyme.
Answer:
True

Question 4.
The chromosome in which the centromere is exactly at the mid-point is called telocentric chromosome.
Answer:
False. The chromosome in which the centromere is exactly at the mid-point is called metacentric chromosome.

Question 5.
RNA molecules are called master molecules.
Answer:
False. DNA molecules are called master molecules.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 6.
The pair of sex chromosomes are called autosomes.
Answer:
False. The pair of sex chromosomes is called allosomes.

Question 7.
In DNA, Adenine always pairs with thymine and cytosine always pairs with guanine.
Answer:
True

Question 8.
In humans there are 23 pairs of autosomes and one pair of allosomes.
Answer:
False. In humans, there are 22 pairs of autosomes and one pair of allosomes.

Question 9.
The phenotypic and genotypic ratios are not same.
Answer:
True

Question 10.
Phenotype means the pairs of genes responsible for the visible characteristics of organisms.
Answer:
False. Phentotype means external appearance of visible characteristics of organisms.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 11.
During gamete formation, in Pj generation the pair of gametes separate independently.
Answer:
True

Question 12.
Down syndrome is caused due to monosomy of X chromosome.
Answer:
False. Down syndrome is caused due to trisomy of 21st chromosome.

Question 13.
In Klinefelter syndrome, women are sterile.
Answer:
False. In Klinefelter syndrome, men are sterile as this disorder arises in men due to abnormality in sex chromosome.

Question 14.
If the father and mother are both sufferers or carriers of sickle-cell anaemia, their offsprings are likely to suffer from this disease.
Answer:
True

Question 15.
During fertilization, mitochondria is contributed by the sperm cell and egg cell(ovum).
Answer:
False. During fertilization, mitochondria is contributed by the egg cell (ovum) alone.

Question 16.
Polygenic disorders strictly follow Mendel’s principles of heredity.
Answer:
False. Polygenic disorders do not strictly follow Mendel’s principles of heredity.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 17.
Genetic material is transferred in equal quantity from parents to progeny.
Answer:
True

Give scientific reasons:

Question 1.
DNA molecules are called as ‘Master molecules’.
Answer:

  • Molecules of DNA are present in all organisms from viruses and bacteria to human beings.
  • These molecules control the functioning, growth and division (reproduction) of the cell.
  • Genes present in the DNA are also responsible for transfer of hereditary characteristics from parents to offsprings.
  • Therefore, DNA molecules are called as ‘Master molecules’.

Question 2.
Phenotypic and genotypic ratios are different.
Answer:

  • Phenotype means external appearance or visible characteristics of organisms whereas the genotype is the pairs of genes responsible for the visible characteristics.
  • The genes responsible for any particular character are present in pairs.
  • Though, there are two genes, the phenotype
    depends on the presence of the dominant gene, e.g. Genotype for tall height of the plant is TT or Tt.
  • Therefore, phenotypic and genotypic ratios are different.

Question 3.
A carrier or sufferer of sickle-cell anaemia should avoid marriage with another carrier or sufferer.
Answer:

  • Sickle-cell anaemia is a hereditary disease caused due to mutation of a single gene.
  • It is a monogenic disorder that occurs due to changes in a gene during conception.
  • If father and mother both are sufferers or carriers of sickle-cell anaemia, their offsprings are likely to suffer from the disease.
  • Therefore, a carrier or sufferer of sickle-cell anaemia should avoid marriage with another carrier or sufferer.

Question 3.
Mitochondrial disorders are inherited from the mother only.
Answer:

  • Mitochondrial DNA becomes defective due to mutation.
  • During fertilization, mitochondria are contributed by the egg cell (ovum) alone.
  • Hence, mitochondrial disorders are inherited from the mother only.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 4.
Tobacco smoking causes cancer.
Answer:

  • Tobacco smoke contains harmful chemicals like pyridine, ammonia, aldehyde furfural, carbon monoxide, nicotine, sulphur dioxide etc.
  • They cause uncontrolled cell division.
  • Tobacco smoke is full of minute carbon particles which cause normal tissue lining of the lung to transform into thickened black tissue. This leads to cancer.
  • Therefore, tobacco smoking causes cancer.

Define the following terms:

Question 1.
Gene
Answer:
The segment of DNA which contains all the information for synthesis of a particular protein is called a ‘gene’.

Question 2.
Chromosome
Answer:
The structure in the nucleus of the cells that carries the hereditary characteristics is called chromosome.

Question 3.
Genetics
Answer:
The branch of biology which studies the transfer of characteristics of organism from one generation to the next and genes in particular, is called genetics.

Question 4.
Heredity
Answer:
Transfer of characteristics from parents to offsprings is called heredity.

Question 5.
Homologous chromosomes
Answer:
If the pair consists of chromosomes are similar in shape and organization, they are called homologous chromosomes.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 6.
Heterologous chromosomes
Answer:
If the pair which consists of chromosomes are not similar in shape and organization, they are called heterologous chromosomes.

Question 7.
Genetic disorders
Answer:
Diseases or disorders occuring due to abnormalities in chromosomes and mutations in genes are called genetic disorders.

Distinguish between:

Question 1.
DNA and RNA
Answer:

DNARNA
(i) In DNA, the sugar present is deoxyribose.(i) In RNA, the sugar present is ribose.
(ii) In DNA, the nitrogen bases are adenine, guanine, cytosine and thymine.(ii) In RNA, the nitrogen base thymine is replaced by uracil.
(iii) DNA is double stranded.(iii) RNA is single-stranded.
(iv) DNA carries hereditary information(iv) RNA helps in protein synthesis.

Question 2.
Turner syndrome and Klinefelter syndrome.
Answer:

Turner syndromeKline fater syndrome
(i) It is due to monosomy of sex chromosome.(i) It is due to felter of sex chromosome.
(ii) Disorder in sex chromosome results in 44 + X condition.(ii) Disorder in sex chromosome results is 44 + XY condition.
(iii) Seen in women.(iii) Seen in men
(iv) Women suffering from this syndrome are sexually sterile.(iv) Men suffering from this syndrome are sexually sterile.
(v) There is presence of total 45 chromosomes instead of 46.(v) There is presence of total 47 chromosomes instead of 46.

Write short notes on:

Question 1.
Albinism
Answer:

  • Albinism is a monogenic disorder.
  • Our eyes, skin and hair have colour due to the brown pigment melanin. In this disease, the body cannot produce melanin. Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation
  • The skin becomes pale, hair are white and eyes are usually pink due to absence of melanin pigment in the retina and sclera.

Question 2.
Polygenic disorders.
Answer:

  • Polygenic disorders are caused due to mutations in more than one gene.
  • In most such cases, their severity increases due to effects of environmental factors on the foetus.’
  • Common examples of such disorders are cleft lip, cleft palate, constricted stomach, spina bifida (a defect of the spinal cord), etc. Besides diabetes, blood pressure, heart disorders, asthma and obesity are also polygenic disorders.
  • Polygenic disorders do not strictly follow Mendel’s principles of heredity.
  • These disorders arise from a complex interaction between environment, life style and defects in several genes.

Question 3.
Turner syndrome.
Answer:

  • Turner syndrome is a disorder arising in women due to abnormality in sex chromosomes.
  • Turner syndrome arises due to either inheritance of only one X chromosome from parents or due to inactivation of the gender- related part of X-chromosomes.
  • Instead of the normal 44 + XX condition, women suffering from Turner syndrome show a 44 + X condition.
  • Such women are sterile i.e. unable to have children due to improper growth of the reproductive organ.

Answer the following questions:

Question 1.
What are the main objectives of National Health Mission?
Answer:
The main objectives of National Health Mission are:

  • Strengthening of the rural and urban health facilities.
  • Controlling various diseases and illnesses.
  • Increasing public awareness about health.
  • Offering financial assistance to patients through various schemes.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 2.
Which were the seven pairs of contrasting characteristics studied by Mendel in pea plant?
Answer:
The seven pairs of contrasting characters studied by Mendel in pea plant were as follows:

CharactersDominantRecessive
Shape of the seedRound(R)Wrinkled (r)
Colour of the seedYellow (Y)Green (y)
Colour of the flowerPurple (C)White (c)
Shape of podInflated (I)Constricted (i)
Colour of podGreen (G)Yellow (g)
Position of flowerAxillary (A)Terminal (a)
Height of the plantTall (T)Dwarf (t)

Question 3.
Name some dominant and recessive characteristics seen in human beings.
Answer:
Some dominant and recessive characteristics of human beings.

DominantRecessive
Rolling tongueNon-rolling tongue
Presence of hair on armsAbsence of hair on arms
Black and curly hairBrown and straight hair
Free earlobeAttached earlobe

Question 4.
What is Klinefelter syndrome?
Answer:

  • Klinefelter syndrome is a disorder arising in men due to abnormalities in sex chromosomes.
  • In this disorder, men have one extra X chromosome, hence their chromosomal condition becomes 44 + XXY.
  • Such men are usually sterile because their reproductive organs are not well developed.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 5.
How is the diagnosis for sickle-cell anaemia made?
Answer:

  • Under the National Health Mission scheme, the ‘Solubility Test’ for diagnosis of sickle-cell anaemia is available at all district hospitals.
  • Similarly, the confirmatory diagnostic test – ‘Electrophoresis’ is performed at rural and subdistrict hospitals.

Question 6.
Find out the Phenotypic ratio of the following:
(a) Round-Yellow
(b) Wrinkled-Yellow
(c) Round-Green
(d) Wrinkled-Green
Answer:
(a) Round-Yellow: 9
(b) Wrinkled-Yellow: 3
(c) Round-Green: 3
(d) Wrinkled-Green: 1
Phenotypic ratio: 9:3:3:1

Question 7.
Find out the Genotypic ratio of the following:
(a) RRYY
(b) RRYy
(c) RRyy
(d) RrYY
(e) RrYy
(f) Rryy
(g) rrYY
(h) rrYy
(i) rryy
Answer:
(a) RRYY -1
(b) RRYy-2
(c) RRyy-1
(d) RrYY-2
(e) RrYy-4
(f) Rryy-2
(g) rrYY – 1
(h) rrYy – 2
(i) rryy – 1
Genotypic ratio: 1:2:1:2:4:2:1:2:1

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Draw neat and labelled diagrams of the following:

Question 1.
Structure of chromosome
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation 10

Question 2.
Types of RNA
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation 11

Answer the following questions:

Question 1.
What are the effects of tobacco consumption?
Answer:

  • Smoking of cigarettes and bidis adversely affects the process of digestion.
  • It causes a burning sensation in the throat and cough.
  • Excessive smoking causes instability and trembling of fingers.
  • It causes dry cough which leads to sleeplessness.
  • Tobacco consumption can lead to shortening of life span, chronic bronchitis, pericarditis, cancer of the lungs, mouth, larynx (voice box), pharynx, urinary bladder, lips or tongue.
  • The nicotine present in tobacco affects the central and peripheral nervous system. Arteries become hard i.e. it causes arteriosclerosis and hypertension.

Maharashtra Board Class 9 Science Solutions Chapter 16 Heredity and Variation

Question 2.
Complete the table for number of chromosomes in different organisms.
Answer:

OrganismNo. of Chromosomes
Crab200
Maize20
Frog26
Roundworm04
Potato48
Human46
Dog78
Elephant56
Fruit fly08
Mango40

Balbharati Maharashtra State Board 9th Std Science Textbook Solutions 

Energy Flow in an Ecosystem Class 9 Science Chapter 7 Questions And Answers Maharashtra Board

Std 9 Science Chapter 7 Energy Flow in an Ecosystem Question Answer Maharashtra Board

Balbharti Maharashtra State Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem Notes, Textbook Exercise Important Questions and Answers.

Class 9 Science Chapter 7 Energy Flow in an Ecosystem Question Answer Maharashtra Board

Class 9 Science Chapter 7 Energy Flow in an Ecosystem Textbook Questions and Answers

1. Complete the following table (Carefully study the carbon, oxygen and nitrogen cycles).

Bio-geo-chemical cycles Biotic processes Abiotic processes
1. Carbon cycle
2. Oxygen cycle
3. Nitrogen cycle

2. Correct and rewrite the following statements and justify your corrections.
a. Carnivores occupy the second trophic level in the food chain.
b. The flow of nutrients in an ecosystem is considered to be a ‘one-way’ transport.
c. Plants in an ecosystem are called primary consumers.

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

3. Give reasons.
a. Energy flow through an ecosystem is ‘one way’.
Answer:

  • The Sun is the most important source of energy in any ecosystem.
  • Green plants of the ecosystem store some amount of solar energy in the form of food.
  • Before reaching the decomposers, this energy is passed on from one trophic level to the next.
  • Decomposers dissipate some amount of energy in the form of heat.
  • However, no part of the energy ever returns to the Sun. Hence, energy flow through an ecosystem is ‘one way’.

b. Equilibrium is necessary in the various bio-geo-chemical cycles.
Answer:

  • The cyclic flow of nutrients within an ecosystem is called bio-geo-chemical cycles.
  • Nutrients, necessary for the growth of organisms are continuously transferred from abiotic to biotic factors and biotic to abiotic factors within an ecosystem.
  • Any imbalance in the cycles will break the link between the biotic and abiotic factors.
  • Therefore, equilibrium is necessary between bio-geo-chemical cycles.

c. Flow of nutrients through an ecosystem is cyclic.
Answer:

  • All organisms need nutrients for their growth.
  • The nutrients carbon, oxygen, nitrogen, iron, calcium etc. are circulated and recycled from the biosphere to living organisms and after their death back to the biosphere.
  • Nutrients are taken up by plants and then passed on to the consumers.
  • Eventually, after their death, all types of consumers, are decomposed by decomposers like bacteria and fungi and the nutrients are again released into the biosphere and are, used again by living organisms.

Therefore, the flow of nutrients through an ecosystem is cyclic.

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

4. Explain the following cycles in your own words with suitable diagrams.
a. Carbon cycle.
7 Energy Flow In An Ecosystem Exercises
Answer:

  • The circulation and recycling of carbon from the atmosphere to living organisms and after their death back to the atmosphere is called the carbon cycle.
  • Abiotic carbon atoms are circulated and recycled into biotic form mainly through photosynthesis and respiration.
  • Hence, the carbon cycle is one of the important bio-geochemical cycles.
  • Plants convert carbon dioxide into carbohydrates by the process of photosynthesis.
  • Similarly, they produce carbon compounds like proteins and fats, too.
  • Carnivores feed upon herbivores. In this way, biotic carbon is transported from plants to herbivores, from herbivores to carnivores and from carnivores to apex consumers.
  • Main processes in the carbon cycle
    Energy Flow In An Ecosystem Class 9 Questions And Answers
  • Eventually, after death, all types of consumers, are decomposed by decomposers like bacteria and fungi and carbon dioxide is released again into the atmosphere and is used again by living organisms.
  • In this way, carbon is continuously passed on from one living organism to another. After the death of living organisms, carbon goes to the atmosphere and is again taken up by living organisms.

b. Nitrogen cycle.
Answer:
Class 9 Science Chapter 7 Energy Flow In An Ecosystem

  • Nitrogen forms 78% i.e. the maximum portion of the atmosphere. It is necessary for the maintenance of the cycle of nature.
  • The circulation and recycling of nitrogen gas into the form of different compounds through various biotic and abiotic processes in nature is called the nitrogen cycle. Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem
  • All organisms participate in the nitrogen cycle. It is an important component of proteins and nucleic acids.
  • As compared to other elements, it is inactive and does not easily combine with other elements. Most organisms cannot use the free form of nitrogen.
  • Important processes of nitrogen cycle:
    (a) Nitrogen fixation: Conversion of nitrogen into nitrates and nitrites through atmosphere, industrial and biological processes.
    (b) Ammonification: Release of ammonia through the decomposition of dead bodies and excretory wastes of organisms.
    (c) Nitrification: Conversion of ammonia into a nitrite and then nitrate.
    (d) Denitrification: Conversion of nitrogen compounds into gaseous nitrogen.

c. Oxygen cycle.
Answer:
Energy Flow In An Ecosystem Class 9 Exercise 1

  1. Oxygen forms 21% of the atmosphere. It is also present in the hydrosphere and lithosphere. The circulation and recycling of oxygen within the biosphere is called the oxygen cycle.
  2. This cycle, includes both the biotic and abiotic components. Oxygen is continuously produced as well as used up in the atmosphere. Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem
  3. Oxygen is highly reactive and it readily reacts with other elements and compounds.
  4. As oxygen is found in various forms like molecular oxygen (Oz), water (H,0), carbon dioxide (C02), inorganic compounds etc, the oxygen cycle of the biosphere is extremely complex.
  5. Oxygen is released in the process of photosynthesis, whereas it is used up in processes like respiration, combustion, decomposition, corrosion, rusting, etc.

5. What would you do to help maintain the equilibrium in the various bio-geochemical cycles? Explain in brief.
Answer:

  • Bio-geo-chemical cycles always involve the achievement of equilibrium, i.e., a balance in the cycling of the nutrients between the spheres.
  • Human activities that are known to be environmentally unfriendly can disrupt this balance.
  • We should avoid deforestation as trees play an important role in maintaining the balance.
  • We should avoid overuse of fertilizers. The fertilizers get washed away in the nearby water bodies disrupting the balance.
  • Avoid burning of fossil fuels as these fuels release a large amount of carbon in the form of carbondioxide, thus disrupting the balance.
  • Vehicular emissions is another contributor to the disruption in balance of the various cycles.
  • These emissions release oxides of nitrogen and carbon and other hazardous air pollutants.
  • So, we must use better quality fuel like CNG or ethanol to reduce vehicular emissions.

6. Explain in detail the inter-relationship between the food chain and food web.
Answer:

  • Interaction go on continuously between producers, consumers and decomposers.
  • There is a definite sequence in these interactions which is called the food chain.
  • Each chain consists of four, five or more links.
  • An ecosystem consists of many food chains that are interconnected at various levels. Thus, a food web is formed.
  • An organism may be the prey for many other organisms.
  • For example, an insect feeds upon leaves of various plants but the same insect is the prey for different animals like frog, wall lizard, birds, etc.
  • Thus, many food chains interconnected together form an intricate web called as food web.

7. State the different types of bio-geochemical cycles and explain the importance of those cycles.
Answer:

  • The different types of bio-geo-chemical cycles are nitrogen, oxygen, carbon, water vapour, iron, calcium, phosphorus, etc.
  • Nutrients, necessary for the growth of the organisms are continuously transferred from abiotic to biotic factors and biotic to abiotic factors within an ecosystem.
  • These cycles operate continuously through the medium of the biosphere formed by the lithosphere, atmosphere and hydrosphere. Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem
  • (iv) The recycling of biological, geological and chemical sources of nutrients takes place through these cycles.
  • Nutrients from the biosphere enter the bodies of plants and animals. Eventually, after death, all types of consumers are decomposed by decomposers like bacteria and fungi and they are again released into the biosphere and are used again by living organisms.
  • Therefore, these cycles help in maintaining the flow of nutrients and energy through ecosystem and maintaining the equilibrium in the ecosystem.

8. Explain the following with suitable examples.
a. What type of changes occur in the amount of energy during its transfer from plants to apex consumers?
Answer:

  • Plants of the ecosystem store some of the solar energy in the form of food.
  • Before reaching the decomposers, this energy is passed on from one trophic level to the next.
  • At every trophic level, some amount of energy is used by the organism for its own life processes and some amount of energy is lost to the surroundings.
  • Decomposers dissipate some amount of energy in the form of heat.
  • However, no part of the energy ever returns to the Sun. Hence, such passage of energy is referred to as ‘one way’ transport.
  • Therefore, energy is maximum at the base of the pyramid and is least at the apex, e.g.
  • phytoplanktons which form the base of the pyramid have 10,000 kcal of energy while humans at the apex have 10 kcal of energy.

b. What are the differences between flow of matter and of energy in an ecosystem? Why?
Answer:

Flow of matterFlow of energy
(i) It involves the circulation and recycling of nutrients in a cyclic manner within the biosphere.(i) It involves the flow of energy from one trophic level to another in a unidirectional or non-cyclic manner.
(ii) There is no dissipation of matter at any level.(ii) There is the dissipation of energy at every level.
(iii) Biosphere is the source of nutrients.(iii) The Sun is the most important source of energy.

Class 9 Science Chapter 7 Energy Flow in an Ecosystem Intext Questions and Answers

Can you recall?

7 Energy Flow In An Ecosystem Exercises  Question 1.
What is meant by nitrogen fixation?
Answer:
The process of conversion of Nitrogen into nitrates and nitrites is called Nitrogen fixation.

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Energy Flow In An Ecosystem Class 9 Questions And Answers Question 2.
Which microbes bring about the process of nitrogen fixation?
Answer:
Rhizobium present in the root nodules of the leguminous plant bring about the process of nitrogen fixation.

Class 9 Science Chapter 7 Energy Flow In An Ecosystem Question 3.
What is meant by ‘ecosystem’?
Answer:
An ecosystem includes all of the living things like plants, animals and other organisms in a given area, interacting with each other and also with non-living environmental factors like weather, earth, sun, soil, climate and atmosphere.

Energy Flow In An Ecosystem Class 9 Exercise 1Question 4.
Which are different types of ecosystems?
Answer:
Class 9 Science Chapter 7 Energy Flow In An Ecosystem Exercise

Class 9 Science Chapter 7 Energy Flow In An Ecosystem Exercise Question 5.
How do interactions take place between biotic and abiotic factors of an ecosystem?
Answer:

  • Abiotic factors include non-living factors such as soil, water etc. and biotic factors include all living organisms.
  • Both these abiotic and biotic ecosystems are connected through various bio-geo-chemical cycles.
  • These connections/interactions are important for the flow of matter and flow of energy.

Class 9 Science Chapter 7 Energy Flow in an Ecosystem Additional Important Questions and Answers

Choose and write the correct option:

Question 1.
An intricate network of food chains is called
(a) Biosphere
(b) Food web
(c) Energy pyramid
(d) Ecosystem
Answer:
(b) food web

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Question 2.
Fungi and other microbes are called
(a) Producers
(b) Consumers
(c) Decomposers
(d) Omnivores
Answer:
(c) decomposers

Question 3.
Oxygen forms of the atmosphere.
(a) 78%
(b) 21%
(c) 10%
(d) 90%
Answer:
(b) 21%

Question 4.
Microbes which do not need oxygen are called
(a) Producers
(b) Aerobes
(c) Anaerobes
(d) Decomposers
Answer:
(c) anaerobes

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Question 5.
The pattern of energy exchange in an ecosystem is called a
(a) Food chain
(b) Food web
(c) Pyramid of energy
(d) Trophic levels
Answer:
(c) Pyramid of energy

Question 6.
Carbon atoms are circulated and recycled through
(a) Nitrification and denitrification
(b) Photosynthesis and respiration
(c) Respiration and nitrification
(d) Photosynthesis and ammonification
Answer:
(b) photosynthesis and respiration

Question 7.
Conversion of ammonia into a nitrite and then nitrate is called
(a) Nitrogen fixation
(b) Denitrification
(c) Nitrification
(d) Ammonification
Answer:
(c) nitrification

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Question 8.
The conversion of nitrogen compounds into gaseous nitrogen is called
(a) Nitrogen fixation
(b) Denitrification
(c) Ammonification
(d) Nitrification
Answer:
(b) denitrification

Question 9.
is an important component of proteins and nucleic acids.
(a) Carbon
(b) Nitrogen
(c) Phosphorus
(d) Oxygen
Answer:
(b) Nitrogen

Question 10.
Amount of matter and energy from the lowest level to the highest level.
(a) decreases
(b) increases
(c) remains the same
(d) multiplies
Answer:
(a) decreases

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Question 11.
is the most important source of energy in any ecosystem.
(a) The Sun
(b) The Moon
(c) Producers
(d) Decomposers
Answer:
(a) The Sun

Question 12.
Flow of energy in an ecosystem is
(a) cyclical
(b) two way transport
(c) o ne way transport
(d) to and fro transport
Answer:
(c) one way transport

Question 13.
The Indian Institute of Ecology and Environment, Delhi, has published
(a) Invasive species in a changing Environment
(b) Encyclopaedia of Ecology and Environment
(c) Environment and Ecology Magazine
(d) Biodiversity and Disaster Management
Answer:
(b) Encyclopaedia of Ecology and Environment

Question 14.
Oxygen is released in the process of
(a) Respiration
(b) Decomposition
(c) Combustion
(d) Photosynthesis
Answer:
(d) photosynthesis

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Question 15.
cycle is a gaseous cycle.
(a) Carbon
(b) Phosphorus
(c) Calcium
(d) Iron
Answer:
(a) Carbon

Question 16.
is a sedimentary cycle.
(a) Carbon
(b) Nitrogen
(c) Oxygen
(d) Calcium
Answer:
(d) Calcium

Question 17.
is a primary consumer.
(a) Elephant
(b) Frog
(c) Owl
(d) Tiger
Answer:
(a) Elephant

Question 18.
is a secondary consumer.
(a) Grasshopper
(b) Elephant
(c) Frog
(d) Human
Answer:
(c) Frog

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Question 19.
Tiger is a /an
(a) Producer
(b) Primary consumer
(c) Apex consumer
(d) Secondary consumer
Answer:
(c) apex consumer

Question 20.
Carbon dioxide is released into the atmosphere through
(a) burning of fossil fuels
(b) volcanic activity
(c) respiration
(d) all of these
Answer:
(d) all of these

Question 21.
in 1942 studied the food chain and energy flow through it
(a) Linderman
(b) Darwin
(c) Calypso
(d) Chu win lee
Answer:
(a) Linderman

Question 22.
fter the death of apex consumers, energy becomes available to.
(a) Decomposers
(b) Producers
(c) Herbivores
(d) Carnivores
Answer:
(a) Decomposers

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Question 23.
Green plants of the ecosystem store in the form of food.
(a) Solar energy
(b) Chemical energy
(c) Thermal energy
(d) Electrical energy
Answer:
(a) Solar energy

Question 24.
Plants convert carbon dioxide into by the process of photosynthesis.
(a) Carbohydrates
(b) Proteins
(c) Fats
(d) Vitamins
Answer:
(a) Carbohydrates

Question 25.
Carnivores feed upon
(a) Decomposers
(b) Herbivores
(c) Producers
(d) Secondary producers
Answer:
(b) Herbivores

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Question 26.
is used up in the processes like respiration, combustion, decomposition, corrosion, rusting, etc.
(a) Nitrogen
(b) Oxygen
(c) Argon
(d) Helium
Answer:
(b) Oxygen

Question 27.
Nitrogen forms % of the atmosphere.
(a) 79
(b) 78
(c) 21
(d) 2
Answer:
(b) 78

Question 28.
Most organisms cannot use the free form of
(a) Oxygen
(b) Nitrogen
(c) Carbon dioxide
(d) Carbon monoxide
Answer:
(b) Nitrogen

Question 29.
first proposed the concept of Ecological Pyramid in 1927.
(a) Darwin
(b) Newton
(c) Elton
(d) Edison
Answer:
(c) Elton

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Question 30.
Ecological Pyramid is called
(a) Hills
(b) Mounts
(c) Eltonian
(d) Darwinism
Answer:
(c) Eltonian

Question 31.
is produced from oxygen through various atmospheric processes.
(a) Nitrogen dioxide
(b) Nitrites
(c) Ozone
(d) CFC
Answer:
(c) Ozone

Question 32.
Interactions between producers, consumers and saprophytes in a definite sequence is called
(a) Links
(b) Internet
(c) Food chain
(d) Connectors
Answer:
(c) Food chain

Question 33.
Many food chains interconnected at various levels is called
(a) Links
(b) Internet
(c) Connectors
(d) Food web
Answer:
(d) Food web

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Question 34.
Decomposers dissipate some amount of energy in the form of
(a) Light
(b) Electricity
(c) Sound
(d) Heat
Answer:
(d) Heat

Question 35.
The flow of nutrients in an ecosystem is
(a) Non- cyclic
(b) Mono directional
(c) Reverse directional
(d) Cyclical
Answer:
(d) Cyclical

Question 36.
The cyclical flow of nutrients within an ecosystem is called
(a) Biological cycle
(b) Chemical cycle
(c) Solar cycle
(d) Bio-geo chemical cycle
Answer:
(d) Bio-geo chemical cycle

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Question 37.
is an accumulation of the main abiotic gaseous nutrient materials found in the earth’s atmosphere.
(a) Gaseous cycle
(b) Water cycle
(c) Solar cycle
(d) Lunar cycle
Answer:
(a) Gaseous cycle

Question 38.
Oxygen is released into the atmosphere by the process of
(a) Photosynthesis
(b) Respiration
(c) Oxidation
(d) Decomposition
Answer:
(a) Photosynthesis

Question 39.
Charles Elton studied the of the Beer islands in England..
(a) Tundra ecosystem
(b) Mediterranean ecosystem
(c) Equatorial ecosystem
(d) Taiga ecosystem
Answer:
(a) Tundra ecosystem

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Question 40.
in 1942 studied the food chain and energy flow through it.
(a) Charles Elton
(b) Lindeman
(c) Robert Whittaker
(d) Eichler
Answer:
(b) Lindeman

Question 41.
After the death of apex consumers, energy becomes available to
(a) Primary consumer
(b) Secondary consumer
(c) Decomposer
(d) Sun
Answer:
(c) Decomposer

Question 42.
Nitrogen forms % of the atmosphere.
(a) 28%
(b) 78%
(c) 48%
(d) 82%
Answer:
(b) 78%

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Question 43.
first proposed the concept of the Ecological Pyramid in 1927.
(a) Charles Elton
(b) Lindeman
(c) Eichler
(d) John Muir
Answer:
(a) Charles Elton

Question 44.
Oxygen is released into the atmosphere by the process of
(a) respiration
(b) Photosynthesis
(c) Combustion
(d) All of these
Answer:
(b) Photosynthesis

Find the odd man out:

Question 1.
Photosynthesis, Respiration, Decomposition, Forest Fires
Answer:
Forest Fires

Question 2.
Combustion, Corrosion, rusting, formation of ozone, Photosynthesis
Answer:
Photosynthesis

Question 3.
Biological nitrogen fixation, ammonification, nitrification, denitrification, industrial nitrogen fixation
Answer:
Industrial nitrogen fixation

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Question 4.
Frog, Owl, Squirrel, Fox
Answer:
Squirrel

Question 5.
Grasshopper, squirrel, elephant, lion
Answer:
Lion

Question 6.
Nitrogen cycle, oxygen cycle, carbon cycle, phosphorus cycle
Answer:
Phosphorus cycle

Question 7.
Photosynthesis, Nitrification, Ammonification, Denitrification
Answer:
Photosynthesis

Find out the correlation:

1. Grasshopper : Primary consumer :: Tiger : ………………..
2. Owl : Secondary consumer :: Squirrel : ………………..
3. Flow of energy : One way :: Flow of nutrients : ………………..
4. Plants : Producers :: Bacteria and Fungi : ………………..
5. Nitrogen : Gaseous cycle :: Phosphorus : ………………..
6. Oxygen : 21% :: Nitrogen : ………………..
7. Photosynthesis: Carbon cycle:: Ammonification : ………………..
8. Respiration : Oxygen cycle :: Nitrification : ………………..
9. Respiration : Biotic process :: Combustion : ………………..
10. Microbes using oxygen : Aerobes :: Microbes not using oxygen : ………………..
Answer:
(1) Apex consumer
(2) Primary consumer
(3) Cyclic
(4) Decomposers
(5) Sedimentary cycle
(6) 78%
(7) Nitrogen cycle
(8) Nitrogen cycle
(9) Abioticprocess
(10) Anaerobes

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Q.l. (B) 3. Difference between:
(1) Azotobacter and Rhizobium
Answer:

AzotobacterRhizobium
Free-living nitrogen-fixing bacteriaSymbiotic nitrogen-fixing bacteria

(2) Biotic components and Abiotic component
Answer:

Biotic componentsAbiotic component
Living component of an ecosystemPhysical/Chemical non-living components of an ecosystem

(3) Producers and Herbivores
Answer:

ProducersHerbivores
They are present in the 1st trophic levelThey are present in the 2nd trophic level

(4) Carnivores and Herbivores
Answer:

CarnivoresHerbivores
They depend on Herbivores for nutritionThey depend on Producers for nutrition

(5) Phosphorus and Carbon
Answer:

PhosphorusCarbon
It cycles through the Sedimentary cycleIt cycles through the Gaseous cycle

(6) Food chain and Food web
Answer:

Food chainFood web
Interactions between producers, consumers and decomposers in a definite sequence is called as a food chain.The interconnection among different food chains in an ecosystem at various levels is called as a food web

State whether the following statements are true or false. Correct the false statements:

(1) Herbivores occupy the third trophic level in a food chain.
(2) Apex consumers use herbivores and carnivores as their food.
(3) Humans are apex consumers.
(4) Omnivores feed only on carnivores.
(5) A food chain has two links.
(6) The number of consumers in a food web is fixed.
(7) The amount of matter and energy goes on increasing at every level in a food chain.
(8) Robert Brown first proposed the concept of Ecological Pyramid.
(9) After the death of apex consumers, the energy becomes available to decomposers.
(10) The gaseous cycle is a speedier cycle than the sedimentary cycle. Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem
(11) Climatic changes and human activities seriously affect the speed, intensity and equilibrium of bio-geo-chemical cycles.
(12) Carbon dioxide is released in the atmosphere through photosynthesis.
(13) The equilibrium of oxygen and carbon dioxide gases is maintained by decomposers.
(14) The conversion of ammonia into a nitrite and then nitrate is called nitrogen fixation.
(15) Conversion of nitrogen compounds into gaseous nitrogen is called nitrogen fixation.
(16) Release of ammonia through decomposition of dead plants and excretory wastes of organisms is called ammonification.
(17) The cyclic flow of nutrients within an ecosystem is called Energy Pyramid.
Answer:
(1) False, herbivores occupy the second trophic level in a food chain as they are directly dependent on producers.
(2) True
(3) True
(4) False. Omnivores feed on both herbivores and carnivores.
(5) False. A food chain consists of four, five or more links.
(6) False. A food web can have many consumers.
(7) False. The amount of matter and energy goes on decreasing at every level in a food chain.
(8) False. Charles Elton first proposed the concept of Ecological Pyramid.
(9) True
(10) True
(11) True
(12) False. Carbon dioxide is released in the atmosphere through respiration, burning of fossil fuels and wood, forest fires and volcanic activity. (13) False. The equilibrium of oxygen and carbon dioxide gases is maintained by plants.
(14) False. The conversion of ammonia into a nitrite and then nitrate is called nitrification.
(15) False. Conversion of nitrogen compounds into gaseous nitrogen is called denitrification.
(16) True
(17) False. The cyclic flow of nutrients within an ecosystem is called bio-geochemical cycle.

Name the following:

Question 1.
The animals that feed on herbivores.
Answer:
Carnivores.

Question 2.
Organisms that feed on herbivores and carnivores.
Answer:
Omnivores.

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Question 3.
Two examples of primary consumers.
Answer:
Grasshopper, squirrel.

Question 4.
Two examples of secondary consumers.
Answer:
Frog, owl.

Question 5.
Two examples of Apex consumers.
Answer:
Lion, tiger.

Question 6.
Levels in the food chain.
Answer:
Trophic level.

Question 7.
Organisms that decompose the dead bodies of plants and animals.
Answer:
Decomposers.

Question 8.
Process which releases oxygen.
Answer:
Photosynthesis.

Question 9.
Release of ammonia through decomposition of dead bodies and excretory wastes of organisms.
Answer:
Ammonification.

Question 10.
Conversion of nitrogen into nitrates and nitrites through atmospheric, industrial and biological processes.
Answer:
Nitrogen fixation.

One line answers:

Question 1.
What is Food chain?
Answer:
Interactions between producers, consumers and decomposers in a definite sequence is called as a food chain.

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Question 2.
What is Food web?
Answer:
The interconnection among different food chains in an ecosystem at various levels is called as a food web.

Question 3.
What is Trophic level?
Answer:
A trophic level is the step at which the organism obtains its food in the chain.

Question 4.
What is Pyramid of energy?
Answer:
The pattern of energy exchange in an ecosystem is called a ‘Pyramid of energy’.

Question 5.
What is Bio-geo-chemical cycle?
Answer:
The cyclical flow of nutrients within an ecosystem is called bio-geo-chemical cycle.

Question 6.
What is Carbon cycle?
Answer:
The circulation and recycling of carbon from the atmosphere to living organisms and aher their death back to the atmosphere is called the carbon cycle.

Question 7.
What is Oxygen cycle?
Answer:
The circulation and recycling of oxygen within the biosphere is called as oxygen cycle.

Question 8.
What is Nitrogen cycle?
Answer:
The circulation and recycling of nitrogen gas into the form of different compounds through various biotic and abiotic processes in nature is called the nitrogen cycle.

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Question 9.
What is Nitrogen fixation?
Answer:
The process of conversion of free nitrogen gas of the atmosphere into nitrogen compounds is called of nitrogen fixation.

Distinguish between:

Question 1.
Gaseous Cycle and Sedimentary Cycle.
Answer:

Gaseous CycleSedimentary Cycle
(i)      It is an accumulation of the main abiotic gaseous nutrient materials found in the earth’s atmosphere.

(ii)    It includes nitrogen, oxygen, carbon dioxide, water vapour etc.

(i)     It is an accumulation of the main abiotic nutrient materials found in the soil, sediment and sedimentary rocks, etc. of the earth.

(ii)    It includes soil components like iron, calcium, phosphorus etc.

Question 2.
Carbon Cycle and Nitrogen Cyde.
Answer:

Carbon CycleNitrogen Cycle
(i) The circulation and recycling of carbon from the atmosphere to living organisms and after their death back to the atmosphere is called the carbon cycle.(i) The circulation and recycling of nitrogen into the form of different compounds through various biotic and abiotic processes in nature is called the nitrogen cycle.
(ii) Main processes involved in the carbon cycle are photosynthesis and respiration.(ii) Main processes involved in the nitrogen cycle are nitrogen fixation, ammonification, nitrification and denitrification.
(iii) Carbon in the form of carbon dioxide is directly absorbed by plants for photosynthesis.(iii) Nitrogen gas cannot be directly absorbed by plants. So nitrogen is fixed by the process of nitrogen fixation and then absorbed from the soil.

Complete the flow chart:

Question 1.
Energy Pyramid.
Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem 2

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem 3

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem
Question 3.
Nitrogen Cycle
Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem 4

Question 4.
Bio-Geo Chemical cycle
Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem 5

Write short notes on:

Question 1.
Trophic level.
Answer:

  • Each level in the food chain is called a trophic level.
  • A trophic level is the step at which the organism obtains its food in the chain.
  • The amount of matter and energy gradually decreases from producers at the lowest level to the top consumers at the highest level.

Question 2.
Food web.
Answer:

  • An ecosystem consists of many food chains that are interconnected at various levels. This is called food web.
  • An organism may be the prey for many other organisms.
  • For example, an insect feeds upon leaves of various plants but the same insect is the prey for different animals like wall lizards, birds etc. Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem
  • This forms an intricate web instead of a linear food chain. Such an intricate network is called as food web.
  • Generally food webs are formed everywhere in nature.

Question 3.
Energy Pyramid.
Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem 2
Answer:

  • Each level in the food chain is called a trophic level.
  • The amount of matter and energy gradually decreases from producers at the lowest level to the top consumers at the highest level.
  • The initial quantity of energy goes on decreasing at every level of energy exchange.
  • Similarly, the number of organisms also decreases from the lowest level to the highest level.
  • This pattern of energy exchange in an ecosystem is called a Pyramid of energy.

Explain the following statements

Question 1.
justify the statements
(a) Producers form the first trophic level in the food chain. Herbivores depend directly on producers.
(b) The flow of nutrients in an ecosystem is cyclic.
(c) Plants in an ecosystem are called autotrophs.
Answer:

  1. So herbivores form the second trophic level, whereas carnivores depend on herbivores, so they form the third trophic level in the food chain.
  2. The nutrients are circulated and recycled from the biosphere to living organisms and after their death back to the biosphere.
  3. They produce their own food by the process of photosynthesis. All animals in an ecosystem directly or indirectly depend on plants for food.

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Explain the diagram

Question 1.
Food chain in a forest ecosystem:
Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem 6
Answer:

  • In a forest ecosystem, grass is eaten by a deer, which in turn is eaten by a tiger.
  • The grass, deer and tiger form a food chain.
  • In this food chain, energy flows from the grass (producer) to the deer (primary consumer) to the tiger (secondary consumer).

Question 2.
Food chain in an aquatic ecosystem (Pond)
Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem 7
Answer:

  • In a aquatic ecosystem algae are eaten by insects.
  • Insects are eaten by small fish, small fish are in turn eaten by big fish.
  • And the big fish are eaten by fish eating birds.
  • In this food chain, energy flows from the algae (producer) to the insects (primary consumers) to the small fish (secondary consumers) to the big fish (tertiary consumer) and to the fish eating birds (apex consumer).

Question 3.
Carbon cycle
Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem 8
Answer:

  • The circulation and recycling of carbon from the atmosphere to living organisms and after their death back to the atmosphere is called carbon cycle.
  • Main processes involved in carbon cycle are photosynthesis and respiration.
  • Carbon in the form of carbon dioxide is directly absorbed by plants for photosynthesis

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Question 4.
Nitrogen cycle
Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem 9
Answer:
(i) The circulation and recycling of nitrogen into the form of different compounds through various biotic and abiotic processes in nature is called the nitrogen cycle.
(ii) Main processes involved in nitrogen cycle are nitrogen fixation, ammonification, nitrification and denitrification.
(iii) Nitrogen gas cannot be directly absorbed by plants. So nitrogen is fixed by the process of nitrogen fixation and then absorbed from the soil.

Question 5.
Oxygen cycle
Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem 10
Answer:

  1. Oxygen forms 21% of the atmosphere. It is also present in the hydrosphere and lithosphere.
  2. Circulation and recycling of oxygen within the biosphere is called the oxygen cycle.
  3. This cycle, includes both the biotic and abiotic components.
  4. Oxygen is continuously produced as well as used up in the atmosphere.
  5. Oxygen is highly reactive and it readily reacts with other elements and compounds.
  6. As oxygen is found in various forms like molecular oxygen (O2), water (H2O), carbon dioxide (CO2), inorganic compounds etc, the oxygen cycle of the biosphere is extremely complex.
  7. Oxygen is released in the process of photosynthesis, whereas it is used up in processes like respiration, combustion, decomposition, corrosion, rusting, etc.

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Answers based on figures.

Question 1.
Nitrogen Cycle
Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem 12+
Answer:

  • Oxygen forms 21% of the atmosphere. It is also present in the hydrosphere and lithosphere.
  • The circulation and recycling of oxygen within the biosphere is called the oxygen cycle.
  • This cycle, includes both the biotic and abiotic components.
  • Oxygen is continuously produced as well as used up in the atmosphere.
  • Oxygen is highly reactive and it readily reacts with other elements and compounds.
  • As oxygen is found in various forms like molecular oxygen (O2), water (H2O), carbon dioxide (CO2), inorganic compounds etc, the oxygen cycle of the biosphere is extremely complex.
  • Oxygen is released in the process of photosynthesis, whereas it is used up in processes like respiration, combustion, decomposition, corrosion, rusting, etc.

Answers based on figures.

Question 1.
Nitrogen Cycle

(i) Is nitrogen a reactive gas?
Answer:
Nitrogen in its atmospheric state non-reactive gas

(ii) Name process of nitrogen conversion from atmosphere to green plants.
Answer:
Nitrogen fixation is the process of nitrogen conversion atmosphere to green plants

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

(iii) Name the process of converting usable nitrogenous products into atmospheric inert nitrogen.
Answer:
Denitrification is the process of converting usable nitrogenous products into atmospheric inert nitrogen

(iv) Animals produce which product of nitrogen?
Answer:
Animals produce ammonia as a product of nitrogen

(v) Name two nitrifying organisms.
Answer:
Azotobacter and Rhizobium are the two nitrifying organisms

(vi) Which type of bio-geo-chemical cycles does nitrogen follow?
Answer:
Nitrogen follows gaseous and sedimentary bio-geo-chemical cycles

Question 2.
Carbon cycle
Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem 13

(i) Is carbon dioxide gas freely available in the atmosphere?
Answer:
Carbon dioxide gas is freely available in the atmosphere

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

(ii) How is carbon found in water?
Answer:
Carbon is found in water in the form of carbonates

(iii) How are we using carbon as a fuel?
Answer:
Fossil fuels are a form of carbon which are used as fuel by us

(iv) How to plants use carbon as their food source?
Answer:
Plants take up carbon in photosynthesis and convert it into starch which is their food source

(v) How do animals use carbon?
Answer:
Animals use carbon in form of organic compounds and inorganic compounds

(vi) Which type of bio-geo-chemical cycles does carbon follow?
Answer:
Carbon follows gaseous and sedimentary bio-geo-chemical cycles

Question 3.
Oxygen cycle
Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem 14

(i) Is oxygen gas freely available in the atmosphere?
Answer:
Oxygen gas is freely available in the atmosphere

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

(ii) How is oxygen used by animals?
Answer:
Oxygen is used in respiration by the animals

(iii) How are we using carbon as a fuel?
Answer:
Fossil fuels are a form of carbon which are used as fuel by us

(iv) How to plants use carbon as their food source?
Answer:
Plants take up carbon in photosynthesis and convert it into starch which is their food source

(v) How do animals use carbon?
Answer:
Animals use carbon in form of organic compounds and inorganic compounds

(vi) Which type of bio-geo-chemical cycles does carbon follow?
Answer:
Carbon follows gaseous and sedimentary biogeo-chemical cycles

Question 4.
Food web
Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem 15

(i) What is the basic unit of food web?
Answer:
The basic unit of food web is food chain

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

(ii) Which organisms are on the 1st level of this food web?
Answer:
Producers are p. the 1st level of this food web

(iii) What are the animals which depend on producers directly for nutrition called?
Answer:
The animals which depend on producers directly for nutrition are called Herbivores

(iv) What are the animals which eat any type of food for nutrition called?
Answer:
The animals which eat any type of food for nutrition are called Omnivore

(v) What will happen if one animal in the food chain goes extinct?
Answer:
If one animal in the food chain goes extinct the entire food chain collapse

(vi) What are the factors badly affecting the food web?
Answer:
Factors like hunting, pollution, deforestation, human-animal conflicts etc. are the factors badly affecting the food web

Complete the paragraph

(1) Elemental oxygen is normally found in the form of a diatomic molecule. However, in the upper reaches of the atmosphere, a molecule containing three atoms of oxygen is found. This would mean a formula of 03 and this is called ozone. Unlike the normal diatomic molecule of oxygen, ozone is poisonous and we are lucky that it is not stable nearer to the Earth’s surface. But it performs an essential function where it is found. It absorbs harmful radiations from the Sun. This prevents those harmful radiations from reaching the surface of the Earth where they may damage many forms of life.

Recently it was discovered that this ozone layer was getting depleted. Various man-made compounds like CFCs (carbon compounds having both fluorine and chlorine) which are very stable and not degraded by any biological process) were found to persist in the atmosphere. Once they reached the ozone layer, they would react with the ozone molecules. This resulted in a reduction of the ozone layer and recently they have discovered a hole in the ozone layer above the Antarctica. It is difficult to imagine the consequences for life on Earth if the ozone layer dwindles further, but many people think that it would be better not to take chances. These people advocate working towards stopping all further damage to the ozone layer.

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

(2) The utilisation of glucose to provide energy to living things involves the process of respiration in which oxygen may or may not be used to convert glucose back into carbon dioxide. This carbon dioxide then goes back into the atmosphere. Another process that adds to the carbon dioxide in the atmosphere is the process of combustion where fuels are burnt to provide energy for various needs like heating, cooking, transportation and industrial processes.

In fact, the percentage of carbon dioxide in the atmosphere is said to have doubled since the industrial revolution when human beings started burning fossil fuels on a very large scale. Carbon, like water, is thus cycled repeatedly through different forms by the various physical and biological activities. Heat is trapped by glass, and hence the temperature inside a glass enclosure will be much higher than the surroundings. This phenomenon was used to create an enclosure where tropical plants could be kept warm during the winters in colder climates. Such enclosures are called greenhouses.

Greenhouses have also lent their name to an atmospheric phenomenon. Some gases prevent the escape of heat from the Earth. An increase in the percentage of such gases in the atmosphere would cause the average temperatures to increase worldwide and this is called the greenhouse effect. Carbon dioxide is one of the greenhouse gases. An increase in the carbon dioxide content in the atmosphere would cause more heat to be retained by the atmosphere and lead to global warming.

(3) Nitrogen gas makes up 78% of our atmosphere and nitrogen is also a part of many molecules essential to life like proteins, nucleic acids (DNA and RNA) and some vitamins. Nitrogen is found in other biologically important compounds such as alkaloids and urea too. Nitrogen is thus an essential nutrient for all life-forms and life would be simple if all these life-forms could use the atmospheric nitrogen directly. However, other than a few forms of bacteria, life-forms are not able to convert the comparatively inert nitrogen molecule into forms like nitrates and nitrites which can be taken up and used to make the required molecules.

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

These nitrogen-fixing bacteria may be free-living or be associated with some species of dicot plants. Most commonly, the nitrogenfixing bacteria are found in the roots of legumes (generally the plants which give us pulses) in special structures called root nodules. Other than these bacteria, the only other manner in which the nitrogen molecule is converted to nitrates and nitrites is by a physical process. During lightning, the high temperatures and pressures created in the air convert nitrogen into oxides of nitrogen. These oxides dissolve in water to give nitric and nitrous acids and fall on land along with rain. These are then utilised by various lifeforms.

Read the paragraph and answer the questions:

(1) Nitrogen cycle
The nitrogen cycle is the biogeochemical cycle by which nitrogen is converted into multiple chemical forms as it circulates among the atmosphere, terrestrial, and marine ecosystems. The conversion of nitrogen can be carried out through both biological and physical processes. Important processes in the nitrogen cycle include fixation, ammonification, nitrification, and denitrification, The majority of Earth’s atmosphere (78%) is atmosphere nitrogen, making it the largest source of nitrogen.

However, atmospheric nitrogen has limited availability for biological use, leading to a scarcity of usable nitrogen in many types of ecosystems. The nitrogen cycle is of particular interest to ecologists because nitrogen availability can affect the rate of key ecosystem processes, including primary production and decomposition, Human activities such as fossil fuel combustion, use of artificial nitrogen fertilizers, and release of nitrogen in wastewater have dramatically altered the global nitrogen cycle. Human modification of the global nitrogen cycle can negatively affect the natural environment system and also human health.

(i) Why nitrogen cycle is called bio-geochemical cycle?
Answer:
Nitrogen cycle is called bio-geochemical cycle as it undergoes biological as well as geochemical processes.

(ii) Why is nitrogen cycle important to us?
Answer:
Nitrogen cycle is important to us as nitrogen availability can affect the rate of key ecosystem processes, including primary production and decomposition.

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

(iii) Name important process of nitrogen cycle.
Answer:
Important processes in the nitrogen cycle include fixation, ammonification, nitrification, and denitrification.

(iv) What can affect the nitrogen cycle negatively?
Answer:
Human modification of the global nitrogen cycle can negatively affect the natural environment system and also human health.

(v) Which human activities change the nitrogen cycle?
Answer:
Human activities such as fossil fuel combustion, use of artificial nitrogen fertilizers, and release of nitrogen in wastewater have dramatically altered the global nitrogen cycle.

(2) Food web
A food chain is a linear network of links in a food i web starting from producer organisms (such asgrass or trees which use radiation from the Sun to make their food) and ending at apex predator species (like grizzly bears or killer whales), detritivores (like earthworms or woodlice), ordecomposer species (such as fungi or bacteria), A food chain also shows how the organisms are related with each other by the food they eat. Each level of a food chain represents a different trophiclevel. A food chain differs from a food web, because the complex network of different animal’s feeding relations are aggregated and the chain only follows a direct, linear pathway of one animal at a time.

Natural interconnections between food chains make it a food web. A common metric usedto the quantify food web trophic structure is foodi chain length. In its simplest form, the length of a chain is the number of links between a trophici consumer and the base of the web and the meanchain length of an entire web is the arithmetic average of the lengths of all chains in a food web. The food chain is an energy source diagram. Many food webs have a keystone species. A keystonespecies is a species that has a large impact on thei surrounding environment and can directly affectthe food chain.

If this keystone species dies off it can set the entire food chain off balance. Keystonespecies keep herbivores from depleting all of thei foliage in their environment and preventing ai mass extinction. Food chains were first introduced by the Arab scientist and philosopher Al-Jahiz inthe 10th century and later popularized in a book I published in 1927 by Charles Elton, which also i introduced the food web concept.

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

(i) What is a food web?
Answer:
Food web is a linear network of links of food chains.

(ii) In a food web which organism are called producers?
Answer:
In a food web which organism which can produce food by photosynthesis are called producers.

(iii) What is the role of keystone species?
Answer:
Keystone species keep herbivores from depleting all of the foliage in their environment and preventing a mass extinction.

(iv) What is a keystone species?
Answer:
A keystone species is a species that has a large impact on the surrounding environment and can directly affect the food chain.

(v) What does each level of food chain represent?
Answer:
Each level of a food chain represents a different trophic level.

(3) Carbon cycle
The carbon cycle is the biogeochemical cycle by which carbon is exchanged among the biosphere, pedosphere, geosphere, hydrosphere, and atmosphere of the Earth. Carbon is the main component of biological compounds as well as a major component of many minerals such as limestone. Along with the nitrogen cycle and the water cycle, the carbon cycle comprises a sequence of events that are key to make Earth capable of sustaining life. It describes the movement of carbon as it is recycled and reused throughout the biosphere, as well as long-term processes of carbon sequestration to and release from carbon sinks.

The carbon cycle was discovered by Antoine! Lavoisier and Joseph Priestley, and popularised by Humphry Davy. Carbon in the Earth’satmosphere exists in two main forms carbon dioxide and methane. Both of these gases absorb and retain heat in the atmosphere and are partially responsible for the greenhouse effect. Methane produces a larger greenhouse effect per volume as compared to carbon dioxide, but it exists in much lower concentrations and is more short-lived than carbon dioxide, making carbon dioxide the more important greenhouse gas of the two.

Carbon dioxide is removed from the atmosphere primarily through photosynthesis and enters the terrestrial and oceanic biospheres. Carbon dioxide also dissolves directly from the atmosphere into bodies of water (ocean, lakes, etc.), as well as dissolving in precipitation as raindrops fall through the atmosphere. When dissolved in water, carbon dioxide reacts with water molecules and forms carbonic acid, which contributes to ocean acidity. It can then be absorbed by rocks through weathering. It also can acidify other surfaces it touches or be washed into the ocean.

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

(i) Which gas has greener house effect as compared to CO2?
Answer:
Methane gas CH4 has greener house effect as compared to CO2.

(ii) How does dissolved CO2 affect oceans?
Answer:
When dissolved in water, carbon dioxide reacts with water molecules and forms carbonic acid, which contributes to ocean acidity.

(iii) Why is carbon cycle called bio-geochemical cycle?
Answer:
The carbon cycle is the biogeochemical cycle by which carbon is exchanged among the biosphere, pedosphere, geosphere, hydrosphere, and atmosphere of the Earth.

(iv) How is carbon dioxide removed from atmosphere?
Answer:
Carbon dioxide is removed from the atmosphere primarily through photosynthesis and enters the terrestrial and oceanic biospheres.

(v) Who discovered the carbon cycle?
Answer:
The carbon cycle was discovered by Antoine Lavoisier and Joseph Priestley.

Answer the questions in detail:

Question 1.
Write the important processes of the nitrogen cycle.

Answer:

  • Nitrogen fixation: Conversion of nitrogen into nitrates and nitrites through atmospheric, industrial and biological processes.
  • Ammonification: Release of ammonia through decomposition of dead bodies and excretory wastes of organisms.
  • Nitrification: Conversion of ammonia into a nitrite and then nitrate.
  • Denitrification: Conversion of nitrogen components into gaseous nitrogen.

Make a concept diagram and explain.

Question 1.
Food chain
Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem 19
Answer:
According to the mode of nutrition the organisms are classified into producers, consumers, saprotrophs (saprophytes) and decomposers. Primary consumers are directly dependent on autotrophs (producers), e.g.: Grasshopper, squirrel, elephant) Secondary consumers use herbivores as their food, e.g.: Frog, owl, fox, etc. Apex or top consumers use herbivores and carnivores as their food. No animals feed on top consumers, e.g.: Tiger, lion, etc. Omnivores feed on herbivores and carnivores, e.g.: Humans, bear, etc. A continuous interaction between producers, consumers and decomposers in a definite sequence is called as food chain.

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Food chain, in ecology is the sequence of transfers of matter and energy in the form of food from organism to organism. Food chains intertwine locally into a food web because most organisms consume more than one type of animal or plant. Plants, which convert solar energy to food by photosynthesis, are the primary food source. In a predator chain, a plant-eating animal is eaten by a flesh-eating animal. In a parasite chain, a smaller organism consumes part of a larger host and may itself be parasitized by even smaller organisms. In a saprophytic chain, microorganisms live on dead organic matter.

Question 2.
Energy pyramid
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem 20
An energy pyramid is a model that shows the flow of energy from one trophic, or feeding, level to the next in an ecosystem. The model is a diagram that compares the energy used by organisms at each trophic level. The energy in an energy pyramid is measured in units of kilocalories (kcal). Energy pyramids are similar to biomass pyramids, another type of trophic pyramid that models the amount of biomass at each trophic level in an ecosystem, energy flow in ecosystems. The structure of an energy pyramid reflects the trophic structure of an ecosystem.

The pyramid is divided into trophic levels similar to those in a food chain. At the pyramid base are the producers, autotrophic organisms that make their own food from inorganic substances. All of the other organisms in the energy pyramid are consumers. These are heterotrophs, meaning that they get food energy by consuming other organisms. The consumers at each trophic level feed on organisms from the level below and are themselves consumed by organisms at the level above. Primary consumers are organisms that consume producers; thus, most primary consumers are herbivores, though some may be detrivores (organisms that feed on decaying organic matter).

Maharashtra Board Class 9 Science Solutions Chapter 7 Energy Flow in an Ecosystem

Secondary consumers are carnivores that feed on primary consumers and tertiary consumers are carnivores that eat secondary consumers. In rare instances, an ecosystem may have an additional trophic level composed of quaternary consumers camivores that consume tertiary consumers’ energy pyramid. The shape of an energy pyramid shows that the amount of food energy that enters each trophic level is less than the amount that entered the level below. Approximately 90 percent of the food energy that enters a trophic level is “lost” as heat when it is used by organisms to power the normal activities of life such as breathing and digesting food the remaining 10 percent is stored in the various organisms’ tissues.

It is this latter energy that is available to be passed to the next trophic level. Thus, the higher the trophic level on the pyramid, the lower the amounts of available energy ecosystem energy transfer through an ecosystem. The number of organisms at each level decreases relative to the level below because there is less energy available to support those organisms. The top level of an energy pyramid has the fewest organisms because it has the least amount of energy. Eventually there is not enough energy left to support another trophic level; thus most ecosystems only have four trophic levels.

Balbharati Maharashtra State Board 9th Std Science Textbook Solutions

Acids, Bases and Salts Class 9 Science Chapter 5 Questions And Answers Maharashtra Board

Std 9 Science Chapter 5 Acids, Bases and Salts Question Answer Maharashtra Board

Balbharti Maharashtra State Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts Notes, Textbook Exercise Important Questions and Answers.

Class 9 Science Chapter 5 Acids, Bases and Salts Question Answer Maharashtra Board

Class 9 Science Chapter 5 Acids, Bases and Salts Textbook Questions and Answers

1. Identify the odd one out and justify.

(a) Chloride, nitrate, hydride, ammonium
Answer:
Ammonium is the odd one out as it is a basic radical and rest all are acidic radicals. Generally, basic radicals are formed by the removal of electrons from the atom of metals such as Na+, Cu2+. But there are some exceptions, such as NH4+.

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

(b) Hydrogen chloride, sodium hydroxide, calcium oxide, ammonia
Answer:
Hydrogen chloride is the odd one out. It is acidic and rest all are basic.

(c) Acetic acid, carbonic acid, hydrochloric acid, nitric acid
Answer:
Carbonic acid is the odd one out. It is a dibasic acid and rest are all monobasic acids.

(d) Ammonium chloride, sodium chloride, potassium nitrate, sodium sulphate
Answer:
Ammonium chloride is the odd one out, as it is made up of a strong acid and weak base and rest all are formed from strong acid and strong base.

(e) Sodium nitrate, sodium carbonate, sodium sulphate, sodium chloride
Answer:
Sodium carbonate is the odd one out, as it is made up of a weak acid and strong base, and rest all are formed from strong acid and strong base.

(f) Calcium oxide, magnesium oxide, zinc oxide, sodium oxide.
Answer:
Zinc oxide is the odd one out, as it is an amphoteric oxide, and rest all are basic oxides.

(g) Crystalline blue vitriol, crystalline common salt, crystalline ferrous sulphate, crystalline sodium carbonate.
Answer:
Crystalline common salt is the odd one out, as it does not contain water of crystallisation. It is an ionic compound and ionic compounds are crystalline in nature and rest all have their crystalline structure because of their water of crystallization.

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

(h) Sodium chloride, potassium hydroxide, acetic acid, sodium acetate.
Answer:
Acetic acid is the odd one out. It is an acid, the rest are all salts.

2. Write down the changes that will be seen in each instance and explain the reason behind it.

(a) 50ml water is added to 50ml solution of copper sulphate.

Answer:

  • Copper sulphate solution is blue. It is a concentrated solution.
  • When 50 ml of water is added to this concentrated solution, it becomes a diluted solution.
  • The intensity of the blue colour is now different in this homogenous mixture.

(b) Two drops of the indicator phenolphthalein were added to 10ml solution of sodium hydroxide.

Answer:

  • Sodiumhy droxide is a base and phenolphthalein is a synthetic indicator.
  • Sodium hydroxide solution will turn pink if phenolphthalein is added to it.
  • It is a test for identifying bases.

(c) Two or three filings of copper were added to 10ml dilute nitric acid and stirred.
Answer:
When copper metal reacts with dilute nitric acid, the metal does not displace hydrogen from the acid like reaction with other metals. Instead the reaction produces nitric oxide, (NO).
Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts 39

(d) A litmus paper was dropped into 2ml dilute HCl. Then 2ml concentrated NaOH was added to it and stirred.
Answer:
Blue litmus Paper:

  • HCl is hydrochloric acid, so the blue litmus turns red.
  • When equal amount of NaOH is added the colour again changes to blue and remains the same.

Red litmus paper:

  • Red litmus paper shows no colour change in hydrochloric acid.
  • When some amount of NaOH is added the colour changes to blue initially but when the amount of NaOH is sufficient the blue colour dissappears.
  • Equal amounts of HC1 and NaOH results in the formation of NaCl, a salt, and the solvent water. This reaction is called the neutralization reaction.

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

(e) Magnesium oxide was added to dilute HCl and magnesium oxide was a added to dilute NaOH.
Answer:
(i) Magnesium oxide + dil HCl.
This is a neutralization reaction. Magnesium oxide is an insoluble base, it reacts with dilute HCl to produce a soluble salt MgCl2 and water H2O.
\(\mathrm{MgO}_{(\mathrm{s})}+2 \mathrm{HCl}_{(\mathrm{aq})} \longrightarrow \mathrm{MgCl}_{2(\mathrm{aq})}+\mathrm{H}_{2} \mathrm{O}_{(n)}\)

(ii) Magnesium oxide + NaOH.
No chemical reaction takes place between magnesium oxide and sodium hydroxide.

(f) Zinc oxide was added to dilute HCl and zinc oxide was added to dilute NaOH.
Answer:

  • Zinc oxide reacts with dilute hydrochloric acid to form zinc chloride and water. It is a neutralization reaction.
    \(\mathrm{ZnO}_{(\mathrm{s})}+2 \mathrm{HCl}_{(\mathrm{aq})} \longrightarrow \mathrm{ZnCl}_{2(\mathrm{aq})}+\mathrm{H}_{2} \mathrm{O}_{(\mathrm{l})}\)
  • Zinc oxide reacts with sodium hydroxide to form sodium zincate and water.
    \(\mathrm{ZnO}_{(\mathrm{s})}+2 \mathrm{NaOH}_{(\mathrm{aq})} \longrightarrow \mathrm{Na}_{2} \mathrm{ZnO}_{2(\mathrm{aq})}+\mathrm{H}_{2} \mathrm{O}_{(\mathrm{t})}\)

(g) Dilute HCl was added to limestone.
Answer:

  • When hydrochloric acid is added to limestone, carbon dioxide is liberated. Limestone is calcium carbonate.
    CaCO3 + 2 HCl → CaCl2 + CO2 + H2O
  • Carbon dioxide is prepared in the laboratory using these chemicals.

(h) Pieces of blue vitriol were heated in a test tube. On cooling, water was added to it.
Answer:

  • On heating, the crystalline structure of blue vitriol breaks down to form a colourless powder and water is released.
  • This water is part of the crystal structure of blue vitriol.
  • It is called water of crystallization.
  • On adding water to the white powder, a solution was formed which has the same colour as the copper sulphate salt solution.

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

(i) Dilute H2SO4 was taken in an electrolytic cell and electric current was passed through it.
Answer:

  • If pure water is used in the electrolytic cell, current does not flow even on putting on the switch.
  • Pure water is a bad conductor of electricity. Dilute H2SO4 is acidulated water.
  • The electrical conductivity of water increases on mixing with strong acid or base in it due to their dissociation and electrolysis of water takes place.
  • H2SO4 is fully dissociated in aqueous solution. \(\mathrm{H}_{2} \mathrm{SO}_{4} \longrightarrow 2 \mathrm{H}^{+}+\mathrm{SO}_{4}^{2-}\)
  • H2O is a weak electrolyte and is only slightly dissociated \(\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{H}^{+}+\mathrm{OH}^{-}\)
  • During electrolysis, the hydrogen ions migrate towards the cathode and are discharged there.

[H+ ions gains electrons and are converted to hydrogen gas]
\(2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{H}_{2(\mathrm{~g})}\)
Cathode reaction:
\(2 \mathrm{H}_{2} \mathrm{O}_{(\mathrm{i})}+2 \mathrm{e}^{-} \longrightarrow \mathrm{H}_{2(\mathrm{~g})}+2 \mathrm{OH}_{(\mathrm{aq})}^{-}\)
Anode reaction:
\(2 \mathrm{H}_{2} \mathrm{O}_{(\mathrm{l})} \longrightarrow \mathrm{O}_{2(\mathrm{~g})}+4 \mathrm{H}_{(\mathrm{aq})}^{+}+4 \mathrm{e}\)

  • For every hydrogen ion discharged at the anode, another hydrogen ion is formed at the cathode.
  • The net result is that the concentration of the sulphuric acid remains constant and electrolysis of water is overall reaction. \(2 \mathrm{H}_{2} \mathrm{O} \longrightarrow 2 \mathrm{H}_{2}+\mathrm{O}_{2}\)
  • The volume of the hydrogen gas formed near the cathode is double that of the oxygen gas formed near the anode.

3. Classify the following oxides into three types and name the types.
CaO, MgO, CO2, SO3, Na2O, ZnO, Al2O3, Fe2O3
Answer:
There are three types of oxides : Basic oxides, Acidic oxides and Amphoteric oxides.

Basic oxidesAcidic oxidesAmphoteric oxides
CaOCO2ZnO
MgOSO3Al2O3
Na2O
Fe2O3

Generally metal oxides are basic in nature.
Exception : Al2O3 and ZnO are amphoteric oxides.
Generally non-metal oxides are acidic in nature.

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

4. Explain by drawing a figure of the electronic configuration.

a. Formation of sodium chloride from sodium and chlorine.
Answer:

b. Formation of a magnesium chloride from magnesium and chlorine.
Answer:

5. Show the dissociation of the following compounds on dissolving in water, with the help of chemical equation and write whether the proportion of dissociation is small or large.
Hydrochloric acid, Sodium chloride, Potassium hydroxide, Ammonia, Acetic acid, Magnesium chloride, Copper sulphate.
Answer:
(a) Hydrochloric acid (HCl)

  • \(\mathrm{HCl}_{(g)} \frac{\text { Water }}{\text { dissociation }}>\mathrm{H}_{(\mathrm{aq})}^{+}+\mathrm{Cl}_{(\mathrm{aq})}^{-}\)
  • Hydrochloric acid is a strong acid, as on dissolving in water, it dissociates almost completely and the resulting aqueous solution contains mainly H ions and the concerned acidic radical.
  • The proportion of dissociation is large.

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

(b) Sodium chloride (NaC1)

  • \(\mathrm{NaCl}_{(s)} \frac{\text { Water }}{\text { dissociation }}>\mathrm{Na}_{(\mathrm{aq})}^{+}+\mathrm{Cl}_{\text {(aq) }}^{-}\)
  • When an ionic compound begins to dissolve in water, the water molecules push themselves in between the positive and negative ions of the compound and separate them from each other.
  • The proportion of dissociation is large.

(c) Potassium hydroxide (KOH)

  • \(\mathrm{KOH}_{(n)} \frac{\text { Water }}{\text { dissociation }} \mathrm{K}_{(\mathrm{aq})}^{+}+\mathrm{OH}_{(\mathrm{aq})}\)
  • Potassium hydroxide is a strong base, as on dissolving in water, it dissociates almost completely and the resulting aqueous solution contains mainly OH+ ions and the concerned basic radical.
  • The proportion of dissociation is large.

(d) Ammonia (NH3)
(i) \(\mathrm{NH}_{3(\mathrm{~g})}+\mathrm{H}_{2} \mathrm{O}_{(\mathrm{n}}-\frac{\text { Water }}{\text { uissociation }}>\mathrm{NH}_{4 \text { (aq) }}^{+}+\mathrm{OH}_{\text {(aq) }}^{-}\)
(ii) Ammonia dissolves in water to form NH4OH (ammonium hydroxide). NH4OH does not dissociate completely as it is a weak base. The aqueous solution contains a small proportion of OH ions and the concerned basic radical along with a large proportion of undissociated molecules of the base i.e. NH4OH.
(iii) The proportion of dissociation is small.

(e) Acetic acid (CH3COOH)

  • \(\mathrm{CH}_{3} \mathrm{COOH}_{(l)} \frac{\text { Water }}{\text { dissociation }} \mathrm{CH}_{3} \mathrm{COO}_{(\text {aq) }}+\mathrm{H}_{(a z)}+{ }^{+}\)
  • Acetic acid is a weak acid, on dissolving in water it does not dissociate completely, and the resulting aqueous solution contains H+ ion and the concerned acidic radical in small proportion along with large proportion of the undissociated molecules of the acid.
  • The proportion of dissociation is small.

(f) Magnesium chloride (MgCl2)

  • \(\mathrm{MgCl}_{2(\mathrm{~s})} \frac{\text { Water }}{\text { dissociation }}>\mathrm{Mg}^{2+} \text { (aq) }+2 \mathrm{Cl}^{-} \text {(aq) }\)
  • Magnesium chloride dissolves in water and forms magnesium ions and chloride ions. When an ionic compound begins to dissolve in water, the water molecules push themselves in between the ions of the compound and separate them from each other.
  • The proportion of dissociation is large.

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

(g) Copper sulphate (CuSO4)

  • \(\mathrm{CuSO}_{4(s)} \frac{\text { Water }}{\text { dissociation }}>\mathrm{Cu}_{(\mathrm{aq})}^{2+}+\mathrm{SO}_{4}^{2-}\)
  • When Copper sulphate is dissolved in water it forms copper ions and sulphate ions. When an ionic compound begins to dissolve in water, water molecules push themselves in between the ions of the compound and separate them from each other.
  • The proportion of dissociation is large.

6. Write down the concentration of each of the following solutions in g/L and mol/L.

a. 7.3g HCl in 100ml solution
b. 2g NaOH in 50ml solution
c. 3g CH3COOH in 100ml solution
d. 4.9g H2SO4 in 200ml solution
Answer:
To find : The concentration in g/L.
Solution:

7. Obtain a sample of rainwater. Add to it a few drops of universal indicator. Meausre its pH. Describe the nature of the sample of rainwater and explain the effect if it has on the living world.
Answer:

  • pH of rain water is 6.5 that means rain water is slightly acidic.
  • When we add universal indicator to rain water it turns orangish red, indicating pH value is between 0 to 7, which tells us that rain water is acidic in nature.
  • Most of the plants grow best when pH of soil is close to 7. If the soil is too acidic or too basic, it affects plant growth.

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

8. Answer the following questions.

a. Classify the acids according to their basicity and give one example of each type.
Answer:

  • Basicity of acids : The number of H+ ions obtainable by the dissociation of one molecule of an acid is called its basicity. The acids are classified as monobasic, dibasic and tribasic acids based on the number of H+ ions present.
  • Examples of monobasic acid : HCl, HNO3, CH3COOH
  • Examples of dibasic acid: H2SO4, H2CO3
  • Examples of tribasic acid: H3BO3, H3PO4

b. What is meant by neutralization? Give two examples from everyday life of the neutralization reaction.
Answer:

  • In neutralization reaction, an acid reacts with a base to form salt and water.
  • In a neutralisation reaction the acid dissociates to form H+ ions and base dissociates to form OH ions.
  • They combine to form H2O molecules which mixes with the solvent.

Examples in daily life:

  • When people suffer from acidity, they take some antacids to neutralise the acid in their stomach.
  • If an ant stings us the pain is due to formic acid. It is neutralised by rubbing moist baking soda which is basic in nature.

c. Explain what is meant by electrolysis of water. Write the electrode reactions and explain them.
Answer:
Electrolysis of water:

  • Electrolysis of water is the decomposition of water into oxygen and hydrogen gas due to an electric current being passed through acidified water.
  • Cathode reaction:
    \(2 \mathrm{H}_{2} \mathrm{O}_{(l)}+2 \mathrm{e}^{-} \longrightarrow \mathrm{H}_{2(\mathrm{~g})}+2 \mathrm{OH}_{(\mathrm{aq}}\)
  • Anode reaction:
    \(2 \mathrm{H}_{2} \mathrm{O}_{(l)} \longrightarrow \mathrm{O}_{2(\mathrm{~g})}+4 \mathrm{H}_{(\mathrm{aq})}^{+}+4 \mathrm{e}^{-}\)
  • It is found that the volume of gas formed near the cathode is double that of the gas formed near the anode.
  • Hydrogen gas is formed near the cathode and oxygen gas near the anode.
  • From this, it is clear that electrolysis of water has taken place and its constituent element have been released.

9. Give a reason for the following.

a. Hydronium ions are always in the form H3O+.
Answer:

  • Acids in water gives H+ ions. These H+ ions do not exist freely in water.
  • This is because H+ is a single proton, a hydrogen atom has only one proton and one electron.
  • If the electron is removed to make H+, all that is left is an extremely tiny positively charged nucleus.
  • This H ion will immediately combine with the surrounding water (H2O) molecules to form (H3O4) hydronium ion.

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

b. Buttermilk spoils if kept in a copper or brass container.
Answer:

  • Buttermilk contains an organic acid called as lactic acid.
  • The lactic acid reacts with copper and brass and forms toxic compounds which are not fit for consumption.
  • They are harmful and may cause food poisoning.
  • So it is not advisable to keep buttermilk in brass or copper containers.

10. Write the chemical equations for the following activities.

(a) NaOH solution was added to HCl solution.
Answer:
When NaOH reacts with HCl, it gives NaCl and water.

(b) Zinc dust was added to dilute H2SO4.
Answer:
When zinc reacts with dilute sulphuric acid, it forms zinc sulphate and hydrogen gas is liberted.
Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts 4

(c) Dilute nitric acid was added to calcium oxide.
Answer:
When dilute nitric acid reacts with calcium oxide, it forms calcium nitrate and water.

(e) Carbon dioxide gas was passed through KOH solution.

(f) Dilute HCl was poured on baking soda.

11. State the differences.

a. Acids and bases
Answer:

AcidsBases
(i) A substance which liberates H+ ions when dissolved in water is an acid
(ii) Blue litmus turns red in an acid.
(iii) The pH of an acid is less than 7.
(iv) Acids are sour to taste
(v) e.g. HCl, H2SO4
A substance which liberates OH ions when dissolved in water is called a base.
Red litmus turns blue in a base
The pH of a base is greater than 7.
Bases are bitter to taste,
e.g. NaOH, KOH.

b. Cation and anion
Answer:

CationsAnions
(i) Cations are ions with a net positive charge.Anions are ions with a net negative charge.
(ii) Cations are generally formed by metals. When metals donate electrons, they have excess of protons, hence they form cations.Anions are generally formed by non-metals. When non-metals accept electrons, they have excess of electrons, hence they form anions.
(iii) Cations are attracted towards the cathode which are negatively charged electrodes.Anions are attracted towards the anode which are positively charged electrodes.
(iv) e.g.: Na+, Ca2+, Mg2+, K+ etc.e.g.: O2 , S2-, Cl, Br etc.

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

c. the Negative electrode and the positive electrode.

Answer:

Negative ElectrodePositive Electrode
(i) Negatively charged electrodes are called as a cathode.Positively charged electrodes are called as Anode.
(ii) Positively charged cations move towards the cathode or negative electrode.Negatively charged anions move towards the anode or positive electrode.
(iii) Cathode accepts electrons from cationsAnode gives electrons to anions

12. Classify aqueous solutions of the following substances according to their pH into three groups : 7, more than 7, less than 7.

Common salt, sodium acetate, hydrochloric acid, carbon dioxide, potassium bromide, calcium hydroxide, ammonium chloride, vinegar, sodium carbonate, ammonia, sulphur dioxide.
Answer:

pH = 7pH > 7pH < 7
(a) common salt.sodium acetate.sulphur dioxide.
(b) potassium bromide.sodium carbonatehydrochloric acid.
(c)ammonia.carbon-dioxide.
(d)calcium hydroxide.ammonium chloride.
(e)vinegar

Class 9 Science Chapter 5 Acids, Bases and Salts Intext Questions and Answers

Question 1.
How are the following substances classified into three groups with the help of litmus?
Lemon, tamarind, baking soda, buttermilk, vinegar, orange, milk, lime, tomato, milk of magnesia, water, alum.
Answer:

Basic Substance: Turns Red Litmus BlueAcidic Substance: Turns Blue Litmus RedNeutral Substance: No change in the colour of litmus
Baking SodaLemonwater
LimeTamarind
Milk of MagnesiaButtermilk
Vinegar
Orange
Milk
Tomato
Alum

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 2.
Fill in the columns in the part of the following table:
Answer:

Question 3.
Complete the following table of the concentration of various aqueous solutions.
Answer:

Question 4.
Complete the following table of neutralization reactions and also write down the names of the acids, bases and salts in it.
Answer:

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 5.
What are the names of the following compounds? NH3, Na2O, CaO.
Answer:
NH3 : Ammonia
Na2O : Sodium oxide
CaO : Calcium oxide

Question 6.
Into which type will you classify the above compounds, acid, base or salt?
Answer:
NH3 : base
Na2O : base
CaO : base

Question 7.
ive examples of monobasic, dibasic and tribasic acids.
Answer:
Monobasic acid examples: HNO3, HCl, CH3COOH
Dibasic acid examples: H2SO4, H2CO3
Tribasic acid examples: H3BO3, H3PO4

Question 8.
Give the three types of bases with their examples.
Answer:
Types of bases:
Monoacidic base examples : NaOH, KOH, NH4OH
Diacidic base examples: Ca(OH)2, Ba(OH)2
Triacidic base examples: A(OH)3, Fe(OH)3

Question 9.
What are the colours of the following natural and synthetic indicators in acidic and basic solutions? Litmus, turmeric, jamun, methyl orange, phenolphthalein?
Answer:

IndicatorColour in Acidic SolutionColour in basic Solution
LitmusRedBlue
TurmericYellowRed
JamunRedBlue-Green
Methyl orangeRedYellow
PhenolphthaleinColourlessPink

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 10.
On mixing the substances as shown here, what are the resulting mixtures formed by mixing the following substances called?
(a) Water and salt
(b) Water and sugar
(c) Water and sand
(d) Water and sawdust
Answer:
(a) Water and salt – Homogeneous mixture
(b) Water and sugar – Homogeneous mixture
(c) Water and sand – Heterogeneous mixture
(d) Water and sawdust – Heterogeneous mixture

Question 11.
What would be the definition of an acid and a base with reference to the neutralization reaction?
Answer:

  • Acid: An acid is a substance which neutralises a base to form salt and water.
  • Base: A base is a substance which neutralises an acid to form salt and water.

Answer the following questions:

Question 1.
Take aqueous solution of sodium chloride, copper sulphate, glucose, urea, dil.H2SO4 and dil.NaOH in a beaker and test the electrical conductivity of the solutions. Answer the given below questions.

(a) With which solutions did the bulb glow?
Answer:
Solutions with which bulb glows: Aqueous solution of NaCl, CuSO4, H2SO4 and NaOH.

(b) Which solutions are electrical conductors?
Answer:
Solutions which are electrical conductors:
NaCl, CuSO4, H2SO4 and NaOH.

Question 2.
During electrolysis of copper sulphate, if electric current is passed through the electrolytic cell for a long time, what change would be seen at the anode?
Answer:

  • When electricity is passed for a long time through copper sulphate solution, the following reaction is seen at the anode: Anode Reaction: Cu(s) → Cu2+(aq) + 2e
  • All the copper atoms will get converted into copper ions and get deposited on the cathode. This process continues till the copper anode exists.

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 3.
Would water be a good conductor of electricity?
Answer:
Pure water is not a good conductor of electricity.

Answer the following questions:

Question 1.
(i) With which solutions did the bulb glow?
(ii) Which solutions are electrical conductors?

Answer:
(i) The bulbs glows when the wire are immersed in NaCl solution.
(ii)

SolutionResults
1g Copper Sulphate SolutionBulb glow
1g Glucose SolutionBulb does not glow
1g Urea SolutionBulb does not glow
5ml dil.H2SO4 SolutionBulb glows
5ml dil. NaOH SolutionBulb glows

Question 2.
What would be the definition of an acid and a base with reference to the neutralization reaction?
Answer:

  • Acid: An acid is a substance which neutralises a base to form salt and water.
  • Base: A base is a substance which neutralises an acid to form salt and water.

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 3.
Dissolve 2g salt in 500ml pure water. Take 250 ml of this solution in a 500ml capacity beaker. Connect two electrical wires to the positive and negative terminals of a power supply. Remove the insulating cladding from about 2cm portions at the other ends of the wires. These are the two electrodes. Fill two test tubes upto the brim with the prepared dilute salt solution. Invert them on the electrodes without allowing any air to enter. Start the electric current under 6V potential difference from the power supply. Observe what happens in the test tubes after some time.
(a) Did you see the gas bubbles forming near the electrodes in the test tubes?
(b) Are these gases heavier or lighter than water?
(c) Are the volumes of the gases collected over the solution in the two test tubes the same or different?
(d) Test the solutions in the two test tubes with litmus paper, what do you see?
(e) Repeat the activity by using dilute H2SO4 as well as dilute NaOH as the electrolyte.
Answer:
(a) Yes, gas bubbles can be seen forming near the electrodes in the test tube.
(b) These gases are lighter than water.

(c) The volumes of gases collected over the solution in the two test tubes are different.
(d) The solution in the cathode turns red litmus blue while solution in anode turns blue litmus red.
(e) When the above experiment is repeated with dil H2SO4 and dil NaOH, Hydrogen gas is liberated at cathodes and oxygen gas is liberated at anode.

Answer the following questions:

Question 1.
Cut a lemon into two equal parts. Take the juice of each part into two separate beakers. Pour 10 ml of drinking water in one beaker and 20 ml in the second. Stir the solutions in both the beakers and taste them. Is there any difference in the tastes of the solutions in the two beakers? What is that difference?
Answer:

  • In the above activity, the sour taste of the solutions is because of the solute, lemon juice in them.
  • The quantity of the lemon juice is the same in both the solutions. Yet their tastes are different.
  • The solution in the first beaker is more sour than the one in the second.
  • Although the quantity of the solute is the same in both the solutions, the quantity of the solvent is different.
  • Ratio of the quantity of the solute to the quantity of the resulting solution is different. This ratio is larger for the solution in the first beaker and therefore that solution tastes more sour.
  • On the other hand, the proportion of the lemon juice in the total solution in the second beaker is smaller and taste is less sour.
  • The taste of foodstuff depends upon the nature of the taste-giving ingredient and its proportions in the foodstuff.
  • Similarly, all the properties of a solution depend on the nature of the solute and solvent and also on the proportion of the solute in a solution
  • The proportions of a solute in a solution is called the concentration of the solute in the solution.

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 2.
Take a big test tube. Choose a rubber stopper in which a gas tube can be fitted. Take a few pieces of magnesium ribbon in the test tube and add some dilute HCl to it. Take a lighted candle near the end of the gas tube and observe. What did you observe?

Answer:

  • Magnesium metal reacts with dilute HCl and an inflammable gas, hydrogen, is formed.
  • During this reaction, the reactive metal displaces hydrogen from the acid to release hydrogen gas.
  • At the same time, the metal is converted into basic radical which combines with the acidic radical from the acid to form the salt.
    \(\mathrm{Mg}_{(\mathrm{s})}+2 \mathrm{HCl}_{(\mathrm{aq}) \longrightarrow} \underset{\rightarrow}{\mathrm{MgCl}_{2(\mathrm{aq})}}+\mathrm{H}_{2(\mathrm{~g})}\)

Question 3.
Take some water in a test tube and add a little red oxide (the primer used before painting iron articles) to it. Now add a small quantity of dilute HCl to it, shake the test tube and observe.
(a) Does the red oxide dissolve in water?
(b) What change takes place in the particles of red oxide on adding dilute HCl?
Answer:
(a) The chemical formula of red oxide is Fe2O3. It is insoluble in water.
(b) The water-insoluble red oxide reacts with HCl to produce a water-soluble salt FeCl3.

  • This gives a yellowish colour to the water.
  • The following chemical equation can be written for this chemical change.
    \(\mathrm{Fe}_{2} \mathrm{O}_{3(\mathrm{~s})}+6 \mathrm{HCl}_{(\mathrm{aq})} \longrightarrow 2 \mathrm{FeCl}_{3(\mathrm{aq})}+3 \mathrm{H}_{2} \mathrm{O}_{(\mathrm{l})}\)

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 4.
Fit a bent tube in a rubber cork. Take some lime water in a test tube and keep it handy. Take some baking soda in another test tube and add some lemon juice to it. Immediately fit the bent tube over it. Insert its other end into the lime water. Note down your observations of both the test tubes. Repeat the procedure using washing soda, vinegar and dilute HC1 properly. What do you see?
Answer:

  • In this activity, when limewater comes in contact with the gas released in the form of an effervescence, it turns milky.
  • This is a chemical test for carbon dioxide gas.
  • When lime water turns milky, we infer that the effervescence is of CO2.
  • This gas is produced on the reaction of acids with carbonate and bicarbonate salts of metals.
  • A precipitate of CaCO3 is produced on its reaction with the lime water Ca(OH)2.
  • This reaction can be represented by the following chemical equation.
    \(\mathrm{Ca}(\mathrm{OH})_{2(\mathrm{aq})}+\mathrm{CO}_{2(\mathrm{~g})} \longrightarrow \mathrm{CaCO}_{3(\mathrm{~s})}+\mathrm{H}_{2} \mathrm{O}_{(\mathrm{l})}\)
  • Washing soda is sodium carbonate Na2CO3. It will react same as baking soda (NaHCO3).
  • Vinegar and HCl are acids, they do not react chemically with lemon juice.

Class 9 Science Chapter 5 Acids, Bases and Salts Additional Important Questions and Answers

Select the correct option

Question 1.
…………………. acid is present in lemon.
(a) malic acid
(b) tartaric acid
(c) citric acid
(d) butyric acid
Answer:
(c) Citric acid

Question 2.
Tamarind contains …………………. acid.
(a) Lactic acid
(b) tartaric acid
(c) matlic acid
(d) butyric acid
Answer:
(b) tartaric

Question 3.
Butter milk contains …………………. acid.
(a) butyric acid
(b) Lactic acid
(c) matlic acid
(d) citric acid
Answer:
(a) Butyricacid

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 4.
If the basic radical is H+ the type of compound is ………………… .
(a) neutral
(b) base
(c) acid
(d) alkali
Answer:
(c) Acid

Question 5.
The name of compound NH3 is ………………… .
(a) nitric acid
(b) ammonium
(c) nitride
(d) ammonia
Answer:
(b) ammonia

Question 6.
The bases which are soluble in water are called as ………………… .
(a) indicators
(b) acids
(c) alkalis
(d) salts
Answer:
(c) alkalis

Question 7.
H3PO4 is a …………………. acid.
(a) monobasic
(b) tribasic
(c) tetrabasic
(d) dibasic
Answer:
(b) tribasic

Question 8.
According to pH scale pure water has a pH of ………………… .
(a) 6
(b) 7
(c) 5
(d) 8
Answer:
(b) 7

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 9.
With reference to neutralization, metallic oxides are ………………… in nature.
(a) basic
(b) neutral
(c) acidic
(d) saline
Answer:
(a) basic

Question 10.
Molecular formula of blue vitriol is ………………… .
(a) CuSO3 5H2O
(b) CuSO4 4H2O
(c) CUSO3 4H2O
(d) CUSO4 5H2O
Answer:
(d) CUSO4 5H2O

Question 11.
Molecular formula of crystalline alum is ………………… .
(a) KSO4, AISO4, 24H2O
(b) K2SO4, ALSO4, 24H2O
(c) K2SO4, AL2(SO4)3, 24H2O
(d) KSO4, Al2(SO4)3, 24H2O
Answer:
(c) K2SO4, AL2(SO4)3, 24H2O

Question 12.
Molecular formula for sodium oxide is ………………… .
(a) Na2O
(b) NaO2
(c) NaO
(d) Na2O2
Answer:
(a) Na2O

Question 13.
H2CO3 is …………………. acid.
(a) monobasic
(b) dibasic
(c) tribasic
(d) tetrabasic
Answer:
(b) dibasic

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 14.
Molecular formula of Red oxide is ………………… .
(a) Fe2O3
(b) CuO
(c) Fe3O4
(d) Na2O
Answer:
(a) Fe2O3

Question 15.
The positive terminal electrode is called as ………………… .
(a) anode
(b) cathode
(c) anion
(d) cation
Answer:
(a) anode

Question 16.
…………………. produced in stomach helps in digestion.
(a) Hydrochloric acid
(b) Oxalic acid
(c) Sulphuric acid
(d) Nitric acid?
Answer:
(a) Hydrochloric acid

Question 17.
The solution turns blue litmus red, its pH is likely to be ………………… .
(a) 7
(b) 4
(c) 14
(d) 9
Answer:
(b) 4

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 18.
An ionic compound NaCl is formed by ………………… .
(a) Na+ and Cl
(b) Na+ and Cl+
(c) Na and Cl
(d) Na and Cl+
Answer:
(a) Na+ and Cl

Question 19.
pH of strong acid is ………………… .
(a) 0
(b) 7
(c) 8
(d) 14
Answer:
(a) 0

Question 20.
HCl + NaOH → NaCl + H2O is a …………………. reaction.
(a) neutralization
(b) crystallisation
(c) electrolysis
(d) dissociation
Answer:
(a) neutralization

Question 21.
Adding water to acid is an …………………. reaction.
(a) endothermic
(b) exothermic
(c) neutralisation
(d) crystallisation
Answer:
(b) exothermic

Find the odd one out:

(a) Rose Petal, Turmeric, Phenolphthalein, Indigo.
Answer:
Phenolphthalein is odd one out as rest are natural indicators while phenolphthalein is a synthetic indicator.

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

(b) Lime water, Vinegar, Acetic acid, Tartaric acid.
Answer:
Lime water is odd one out as this is basic in nature while rest are acidic.

(c) NaHCO3, HCl, H2SO4, HNO3
Answer:
NaHCO3 is odd one out as it is base while rest are acids.

(d) Oxalic acid, Nitric acid, Citric acid, acetic acid.
Answer:
Nitric acid is odd one out as others are weak acids while Nitric acid is a strong acid.

(e) Crystalline, Liquid, Gases, Solid.
Answer:
Crystalline is odd one out as this is nature of a compound while others are physical states of compounds.

(f) Ca(OH)2, Mg (OH)2, NaOH, NH4OH.
Answer:
NaOH is odd one out even though all are bases but NaOH is highly soluble in water compared to others.

Name the following:

Question 1.
Name the three types of ionic compounds.
Answer:
The three types of ionic compounds are acids, bases and salts.

Question 2.
Name the two constituents of molecule of an ionic compound.
Answer:

  • Cation (positive ion/ basic radical)
  • Anion (negative ion/acidic radical).

Question 3.
Name any three acids with their molecular formula.
Answer:

  • Hydrochloric acid – HC1
  • Sulphuric acid – H2SO4
  • Nitric acid – HNO3

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 4.
Name any three bases with their molecular formula.
Answer:

  • Sodium hydroxide – NaOH
  • Potassium hydroxide – KOH
  • Calcium hydroxide – Ca(OH)2

Question 5.
Name any three salts with their molecular formula.
Answer:

  • Sodium chloride – NaCl
  • Potassium sulphate – K2 SO4
  • Calcium chloride – CaCl2

Question 6.
Name any two strong acids.
Answer:

  • Hydrochloric acid – HC1
  • Sulphuric acid – H2 SO4

Question 7.
Name any two weak acids.
Answer:

  • Acetic acid – CH3 COOH
  • Carbonic acid – H2 CO3

Question 8.
Name any two strong bases.
Answer:

  • Sodium hydroxide – NaOH
  • Potassium hydroxide – KOH

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 9.
Name a weak base.
Answer:
Ammonium hydroxide – NH4OH

Question 10.
Name any two alkalis.
Answer:

  • Sodium hydroxide – NaOH
  • Potassium hydroxide – KOH

Question 11.
Name any two acids with their basicity 1 (monobasic)
Answer:

  • Hydrochloric acid – HC1
  • Nitric acid – HNO3

Question 12.
Name any two acids with their basicity 2 (dibasic)
Answer:

  • Sulphuric acid – H2 SO4
  • Carbonic acid – H2CO3

Question 13.
Name any two acids with their basicity 3 (tribasic)
Answer:

  • Boric acid – H3BO3
  • Phosphoric acid – H3PO4

Question 14.
Name any two bases with their acidity 1 (monoacidic)
Answer:

  • Sodium hydroxide – NaOH
  • Potassium hydroxide – KOH

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 15.
Name any two bases with their acidity 2 (diacidic)
Answer:

  • Calcium hydroxide – Ca(OH)2
  • Barium hydroxide – Ba(OH)2

Question 16.
Name any two bases with their acidity 3 (triacidic)
Answer:

  • Aluminium hydroxide – Al(OH)3
  • Ferric hydroxide – Fe(OH)3

Question 17.
Name the two units to express the concentration of the solution.
Answer:

  • mass of solute in grams dissolved in one litre of the solution grams per litre, (g/L).
  • Number of moles of the solute dissolved in one litre of the solution. Molarity (M) of the solution.

Match the columns:

Question 1.

Column ‘A’Column ‘B’
(1) HNO3
(2) H3PO4
(3) CH3COOH
(4) H2CO3
(a) Acetic acid
(b) Carbonic acid
(c) Phosphoric acid
(d) Nitric acid

Answer:
(1-d),
(2- c),
(3 – a),
(4 – b)

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 2.

Column ‘A’Column ‘B’
(1) NH4OH
(2) Ca(OH)2
(3) Al(OH)3
(4) Ba(OH)2
(a) Aluminium Hydroxide
(b) Barium Hydroxide
(c) Calcium Hydroxide
(d) Ammonium Hydroxide

Answer:
(1-d),
(2- c),
(3 – a),
(4 – b)

Question 3.

Column ‘A’ SolutionColumn ‘B’ pH
(1)Milk(a)0
(2)Milk of Magnesia(b)14
(3)1 M HCl(c)10.5
(4)1 M NaOH(d)6.5

Answer:
(1-d),
(2- c),
(3 – a),
(4 – b)

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 4.

Column ‘A’Column’B’
(1) Urine
(2) Apples
(3) Orange
(4) Butter
(a) Butyric acid
(b) Uric acid
(c) Malic acid
(d) Citric acid

Answer:
(1 – b),
(2 – c),
(3 – d),
(4 – a)

Question 5.

Column ‘A’Column ‘B’
(1) Crystalline blue vitriol
(2) Crystalline green vitriol
(3) Crystalline
(4) washing soda Crystalline alum
(a) FeS04-7H20
(b) K2S04-A12(S04)3.24H20
(c) CuS04-5H20
(d) Na2CO310H2O

Answer:
(1-c),
(2- a),
(3 – d),
(4 – b)

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

State whether the following statements are true or false and if false. Correct the false statement:

(1) The separation of H and CI in HCI is in absence of water.
(2) \(\mathrm{NaOH}_{(\mathrm{s})} \frac{\text { Water }}{\text { dissociation }}>\mathrm{Na}_{(\mathrm{aq})}^{+}+\mathrm{OH}_{(\mathrm{aq})}^{-}\)
(3) H2SO4 is a strong acid.
(4) NaC1 is an ionic compound.
(5) Turmeric is synthetic indicator.
(6) Metal + Dilute acid forms salt and water.
(7) Copper oxide is called red primer.
(8) Oxide of non-metal + Acid → Salt + Water.
(9) Zinc oxide reacts with sodium hydroxide to form sodium zincate.
(10) Al2O3 is an amphoteric oxide.
(11) Blue vitriol ZnSO4. 7H2O.
(12) Molecular formula for crystalline Ferrous sulphate is Fe5O4. 5H2O.
(13) NaCl in water does not conduct electricity.
(14) Phenolphthalein is colourless in base.
Answer:
(1) False. The separation of H+ and Cl in HC1 is in presence of water.
(2) True
(3) True
(4) True
(5) False. Turmeric is a natural indicator.
(6) False. Metal + Dilute acid forms salt and hydrogen gas.
(7) False. Iron oxide is called red primer.
(8) False. Oxide of izan-metal + Base → Salt + Wafer.
(9) True
(10) True
(11) False. Blue Vitriol is CuSO4. 5H2O.
(12) False. Molecular formula for crystalline Ferrous sulphate is FeSO4. 7H2O.
(13) False. NaCl in water conducts electricity.
(14) False, Phenolphthalein is colourless in acid and pink in base.

Define the following:

Question 1.
Acid
Answer:
An acid is a substance which on dissolving in water gives rise to H ion as the only cation. For example, HC1, H2 SO4, H2CO3.Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts 1

Question 2.
Base
Answer:
A base is a substance which on dissolving in water gives rise to the OW ion as the only anion. For, NaOH, Ca(OH)2Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts 2

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 3.
Strong Acid
Answer:
On dissolving in water, a strong acid dissociates almost completely, and the resulting aqueous solution contains mainly H ions and the concerned acidic radical. e.g. HC1, HBr, HNO3, H2SO4.

Question 4.
Weak Acid
Answer:
On dissolving in water a weak acid does not dissociate completely, and the resulting aqueous solution contains H+ ion and the concerned acidic radical in small proportion along with large proportion of the undissociated molecules of the acid, e.g., H2CO3 (Carbonic acid), CH3COOH (Acetic acid)

Question 5.
Strong Base
Answer:
On dissolving in water, a strong base dissociates almost completely and the resulting aqueous solution contains mainly OH ions and the concerned basic radicals, e.g. NaOH, KOH, Ca(OH)2, Na2O.

Question 6.
Weak Base
Answer:
On dissolving in water, a weak base does not dissociate completely and the resulting aqueous solution contains a small proportion of OH ions and the concerned basic radical along with a large proportion of undissociated molecules of the base. e.g. NH4 OH.

Question 7.
Alkali
Answer:
The bases which are highly soluble in water are called alkali, e.g. NaOH, KOH, NH3. Here, NaOH and KOH are strong alkalis while NH3 is a weak alkali.

Question 8.
Basicity of acids
Answer:
The number of H+ ions obtainable by the dissociation of one molecule of an acid is called its basicity.

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 9.
Acidity of bases
Answer:
The number of OH ions obtainable by the dissociation of one molecule of a base is called its acidity.

Question 10.
Concentration of solute in the solution.
Answer:
The proportion of a solute in a solution is called the concentration of the solute in the solution.

Question 11.
Concentrated solution.
Answer:
When the concentration of a solute in its solution is high, it is a concentrated solution.

Question 12.
Dilute solution
Answer:
When the concentration of a solute in its solution is low, it is a dilute solution.

Question 13.
Neutralization
Answer:
A reaction in which an acid reacts with a base to form salt and water is called a neutalization reaction.
NaOH + HC1 → NaCl + H2O
Base + Acid → Salt + Water

Question 14.
Cathode
Answer:
The electrode connected to the negative terminal of a battery by means of a conducting wire is called a cathode.

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 15.
Anode
Answer:
The electrode connected to the positive terminal of a battery by means of a conducting wire is called an anode.

Question 16.
Cations
Answer:
Cations are positively charged ions which are attracted towards negative electrode (cathode) when electricity is passed into a solution of an ionic compound.

Question 17.
Anions
Answer:
Anions are negatively charged ions which are attracted towards the positive electrode (anode) when electricity is passed into a solution of an ionic compound.

Question 18.
Electrolytic cell
Answer:
An assembly that consists of a container with an electrolyte and the electrodes dipped in it, is called an electrolytic cell.

Question 19.
Molarity of a solution
Answer:
The number of moles of the solute dissolved in one litre of the solution is called the molarity of that solution. The molarity of a solute is indicated by writing its molecular formula inside a square bracket for example [NaCl] = 1

Question 20.
Acid – base indicators
Answer:
Some natural and synthetic dyes show two different colours in acidic and basic solution, and such dyes are acid base indicators.

Explain the following chemical reactions with the help of balanced equations:

Question 1.
Magnesium reacts with dilute hydrochloric acid.
Answer:
When magnesium reacts with dilute hydrochloric acid, it forms magnesium chloride and hydrogen gas is liberated.
Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts 3

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 2.
When copper reacts with nitric acid.
Answer:
When copper reacts with nitric acid, it forms copper nitrate and hydrogen gas is liberated.
Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts 5

Question 3.
When ferric oxide reacts with diluted hydrochloric acid.
Answer:
When Ferric oxide reacts with diluted hydrochloric acid, it forms ferric chloride and water.
Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts 9

Question 4.
When calcium oxide reacts with dilute hydrochloric acid.
Answer:
When calcium oxide reacts with dilute hydrochloric acid, it forms calcium chloride and water.
Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts 7

Question 5.
When Magnesium oxide reacts with dilute hydrochloric acid.
Answer:
When magnesium oxide reacts with dilute hydrochloric acid, it forms magnesium chloride and water.
Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts 8

Question 6.
When zinc oxide reacts with dilute hydrochloric acid.
Answer:
When zinc oxide reacts with dilute hydrochloric acid, it forms zinc chloride and water.
Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts 57

Question 7.
When aluminium oxide reacts with hydrogen fluoride
Answer:
When aluminium oxide reacts with hydrogen fluoride, it forms Aluminium fluoride arid water.
Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts 10

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 8.
When carbon dioxide reacts with sodium hydroxide.
Answer:
When carbon dioxide reacts with Sodium hydroxide, it forms Sodium carbonate and water.

Question 9.
When carbon dioxide reacts with potassium hydroxide.
Answer:
When carbon dioxide reacts with potassium hydroxide, it forms potassium carbonate and water.

Question 10.
When sulphur trioxide reacts with sodium hydroxide.
Answer:
When sulphur trioxide reacts with sodium hydroxide, it forms sodium sulphate and water.

Question 11.
When calcium hydroxide reacts with carbon dioxide.
Answer:
When calcium hydroxide reacts with carbon dioxide, it forms calcium carbonate and water.

Question 12.
When sodium carbonate reacts with hydrochloric acid.
Answer:
When sodium carbonate reacts with hydrochloric acid, it forms sodium chloride, carbon dioxide and water.

Question 13.
When sodium carbonate reacts with sulphuric acid.
Answer:
When sodium carbonate reacts with sulphuric acid, it forms sodium sulphate, carbon dioxide and water.

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 14.
When calcium carbonate reacts with nitric acid.
Answer:
When calcium carbonate reacts with nitric acid, it forms calcium nitrate, carbon dioxide and water.

Question 15.
When potassium carbonate reacts with sulphuric acid.
Answer:
When potassium carbonate reacts with sulphuric acid, it forms potassium sulphate, carbon dioxide and water.

Question 16.
When sodium bicarbonate reacts with hydrochloric acid. OR Dilute HC1 was poured on baking soda
Answer:
When sodium bicarbonate reacts with hydrochloric acid, it forms sodium chloride, carbon dioxide and water.

Question 17.
When potassium bicarbonate reacts with nitric acid.
Answer:
When potassium bicarbonate reacts with nitric acid, it forms potassium nitrate, carbon dioxide and water.

Question 18.
When sodium bicarbonate reacts with acetic acid.
Answer:
When sodium bicarbonate reacts with acetic acid, it forms sodium acetate, carbon dioxide and water.
Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts 21

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 19.
When copper sulphate is heated.
Answer:
When copper sulphate is heated it loses it’s water of crystallization to form white anhydrous copper sulphate.
Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts 58

Question 20.
When Ferrous sulphate is heated.
Answer:
When ferrous sulphate is heated it loses its water of crystallization to form white anhydrous ferrous sulphate.

Q.2. (B)-3. Complete the following table.

Question 1.
Complete the following table.
Answer:

Complete the following reactions.

Question 1.
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts 31

Question 2.
Metal + Dilute acid → Salt + Hydrogen
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts 32

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 3.
Metal oxide + Dilute acid → SaIt + Water
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts 33
Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts 34

Question 4.
Oxide of non-metal + base → salt + water
Answer:

Question 5.
Carbonate salt of metal + dilute acid → Another salt of metal + Carbon dioxide + water
Answer:

Question 6.
Bicarbonate salt of metal + dilute acid → Another salt of metal + carbon dioxide + water
Answer:

Give scientific reasons:

Question 1.
Ionic compound NaCl has very high stability.
Answer:

  • The outermost shell of both Na+ and Cl ions is a complete octet.
  • An electronic configuration with a complete octet indicates a stable state.
  • A molecule of NaCl has Na+ and Cl ions. An ionic bond is formed between these ions.
  • The force of attraction between them is very strong as it is formed between the oppositely charged Na+ and Cl ions.
  • Therefore NaCl, an ionic compound has very high stability.

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 2.
Ionic compound dissociates while forming an aqueous solution.
Answer:

  • On dissolving in water, an ionic compound forms an aqueous solution.
  • In the solid state, the oppositely charged ions in the ionic compound are sitting side by side.
  • When an ionic compound being to dissolve in water, the water molecules push themselves in between the ions of the compound and it separates them from each other, that is to say, an ionic compound dissociates while forming an aqueous solution.

Question 3.
Blue coloured copper sulphate crystals become colourless on heating.
Answer:

  • Copper sulphate crystals are blue in colour and crystalline in form due to presence of water of crystallisation.
  • Each molecule of crystalline copper sulphate contains five molecules of water of crystallisation (CuSO4.5H2O).
  • On heating, the copper sulphate crystals lose the water of crystallisation and turns into white amorphous powder called as anhydrous copper sulphate.
  • Therefore, blue coloured copper sulphate crystals become colourless on heating.

Question 4.
During electrolysis of water, a few drops of sulphuric acid are added to it.
Answer:

  • Pure water is a covalent compound and hence it is a non-electrolyte and does not conduct electricity.
  • When a few drops of sulphuric acid (H2SO4) are added to water.
  • Being a strong acid it dissociates almost completely in its solution forming H+ cations and \(\mathrm{SO}_{4}^{2-}\) anions.
  • The movement of these ions in the solution towards the respective electrodes amount to the conduction of electricity through the solution.
  • Therefore, during electrolysis of water, a few drops of sulphuric acid are added to it.

Question 5.
Glucose is a non-electrolyte.
Answer:

  • Glucose is a covalent compound
  • It does not form any ions in its aqueous solution.
  • Due to this aqueous solution of glucose does not conduct electronic current.
  • Hence, glucose is a non-electrolyte.

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 6.
Pure water is a poor conductor of electricity but aqueous solution of sodium chloride conducts electricity.
Answer:

  • Pure water does not contain any free ions.
  • Sodium chloride (NaCl) is an ionic compound made up of sodium cation (Na+) and chloride anion (Cl)
  • When sodium chloride is dissolved in water , these ions dissociates in its aqueous solution. ‘
  • These ions are free to move in the solution and conduct electricity.
  • Therefore, pure water is a poor conductor of electricity but aqueous solution of sodium Chloride conducts electricity.

Question 7.
When carbon dioxide gas is passed through freshly prepared lime water, the limewater turns milky.
Answer:

  • Limewater traditionally means a weak solution of the alkali calcium hydroxide Ca(OH)2.
  • When CO2 is passed through limewater, it reacts with calcium hydroxide to form insoluble particulates (precipitate of calcium carbonate (CaCO3).
  • Calcium carbonate is weak basic salt and this gives a milky white precipitate.
    Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts 38
  • Hence, lime water turns milky when CO2 gas is passed through it.

Q.3.1. Answer the following:

Question 1.
Write down chemical equations for
(a) Zinc oxide reacts with sodium hydroxide
(b) Aluminium oxide reacts with sodium hydroxide.
Answer:
(a) When zinc oxide reacts with sodium hydroxide, it forms sodium zincate and water
Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts 59

(b) When Aluminium oxide reacts with sodium hydroxide, it forms sodium aluminate and water.

Question 2.
Can we call Al2O3 and ZnO acidic oxides on the basis of above reactions.
Answer:

  • No, because they also react with acids to form their respective salts and water.
  • So, they show the properties of basic oxides also.

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 3.
Define ‘amphoteric oxides’ and give two examples.
Answer:

  • Amphoteric oxides are those oxides which react with both adds as well as bases to form their respective salts and water.
  • Amphoteric oxides show the properties of both acidic oxides as well as basic oxides. ZnO and Al2 O3 are amphoteric oxides.?

Question 4.
Take a solution of 1g copper sulphate in 50ml water in a 100 ml capacity beaker. Use a thick plate of copper as anode and a carbon rod as cathode. Arrange the apparatus as shown in the figure and pass an electric current through the circuit for some time. Do you see any changes?
Answer:

  • A thin film of copper metal is deposited on cathode which is immersed in solution. There is no change in colour of solution
  • The electrons from cathode combines with Cu2+ ion from the solution forming Cu atoms which were then deposited on the cathode.

Q.3.5. Answer in brief:

Question 1.
What are acids, bases and salts?
Answer:

  • Compounds having H+ as the basic radical in their molecules are called Acids.
  • Compounds having OH as the acidic radical in their molecule are called Bases.
  • Ionic compounds which have a basic radical other than H+ and an acidic radical other than OH are called salts.

Question 2.
What is an ionic bond?
Answer:

  • The molecule of an ionic compound has two constituents namely cation (positive ion / basic radical) and anion (negative ion / acidic radical).
  • There is a force of attraction between these ions as they are oppositely charged, and that is called the ionic bond.
  • The force of attraction between one positive charge on a cation and one negative charge on an anion makes one ionic bond.

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 3.
Give examples to show that proportions of H+ and OH ions in aqueous solution determines the properties of those solutions.
Answer:
The examples to show that proportions of H+ and OH ions in aqueous solution determines the properties of those solutions are :

  • The proportions of H+ and OH ions divides soil into the acidic, neutral and basic, types of soil.
  • It is necessary for blood, cell sap etc to have H+ and OH ions in certain definite proportions for their proper functioning.
  • Fermentation carried out with the help of micro-organisms, other biochemical processes and also many chemical processes require the proportion of H+ and OH ions to be maintained within certain limits.

Question 4.
What is pH scale?
Answer:

  1. In 1909, the Danish scientist Sorensen introduced a convenient new scale of expressing H+ ion concentration which is found to be useful in chemical and biochemical processes.
  2. It is the pH scale (pH: power of hydrogen). The pH scale extends from 0 to 14. According to this scale pure water has a pH of 7. pH 7 indicates a neutral solution. This pH is the midpoint of the scale.
  3. The pH of an acidic solution is less than 7 and?

Question 5.
Give the pH of following solutions.
Answer:

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 6.
What is universal indicator? Which is the most accurate method of measuring the pH of a solution?
Answer:

  • In the pH scale, the pH of solutions varies from 0 to 14 in accordance with the strength of the acid or base.
  • To show these variations in pH, a universal indicator is used.
  • A universal indicator shows different colours at different values of pH. A universal indicator is made by mixing several synthetic indicators in specific proportions.
  • The pH of a solution can be determined by means of a universal indicator solution or the pH paper made from it.
  • However, the most accurate method of measuring the pH of a solution is to use an electrical instrument called pH meter.
  • In this method, pH is measured by dipping electrodes into the solution.

Answer in detail:

Question 1.
Explain the Arrhenius theory of acids and bases.
Answer:
The Swedish scientist Arrhenius put forth a theory of acids and bases in the year 1887. This theory gives definitions of acids and bases as follows:
Acid : An acid is a substance which on dissolving in water gives rise to H ion as the only cation. For example, HCl, H2SO4, H2CO3

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts 61

Base: Abase is a substance which on dissolving in water gives rise to the OH ion as the only anion, For example, NaOH, Ca(OH)2
Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts 51

Question 2.
Write a short note on Neutralization.
Answer:

  • Take 10 ml of dilute HCl in a beaker, go on adding dilute NaOH drop by drop and record the pH.
  • Stop adding the NaOH when the green colour appears on the pH paper, that is when the pH of solution becomes 7.
  • Both HCl and NaOH dissociate in their aqueous solutions. Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts
  • Addition of NaOH to HCl solution is like adding a large concentration of OH ions to a large concentration of H+ ions.
  • However water dissociates into H+ and OH ions to a very small extent.
  • Therefore on mixing the excess OH ions combines with excess H+ ions and forms H2O molecules which mix with solvent water.
  • This change can be represented by the ionic equation shown as follows. H+ + Cl + Na+ + OH → Na+ + Cl + H2O
  • It can be observed that Na+ and CT ions are there on both the sides. Therefore the net ionic reaction is H+ + OH → H2O
  • As NaOH solution is added drop by drop to the HCl solution, the concentration of ff goes on decreasing due to combination with added OH ions, and that is how the pH goes on increasing.
  • When enough NaOH is added to HCl, the resulting aqueous solution contains only Na+ and Cl ions, that is, NaCl, a salt, and the solvent water. The only source of H+ and OH ions in this solution is a dissociation of water.
  • Therefore, this reaction is called the Neutralization reaction. The Neutralization reaction is also represented by the following simple equation.

Question 3.
Explain the water of Crystallization.
Answer:

  • Take some crystals of blue vitriol (CuSO4. 5H2O) in a test tube. Heat the test tube on a low flame of a burner.
  • It was observed that on heating, the crystalline structure of blue vitriol broke down to form a colourless powder and water came out.
  • This water was part of the crystal structure of blue vitriol. It is called water of crystallization.
  • On adding water to the white powder a solution

    was formed which had the same colour as the solution in the first test tube.
  • From this we come to know that no chemical change has occurred in the crystals of blue vitriol due to heating.
  • Losing water on heating blue vitriol, breaking down of the crystal structure, losing blue colour and regaining blue colour on adding water are all physical changes.
  • Similarly, ferrous Sulphate crystals also contain 7 molecules of water of crystallization which are lost on heating.
  • The reaction is represented as
  • Ionic compounds are crystalline in nature. These crystals are formed as a result of definite arrangement of ions.
  • In the crystals of some compounds, water molecules are also included in this arrangement.
  • That is the water of crystallization. The water of crystallization is present in a definite proportion of the chemical formula of the compound.

Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Question 4.
Explain the conduction of electricity through solutions of ionic compounds
Answer:

  1. Electrons conduct electricity through electrical wires, and ions conduct electricity through a liquid or a solution.
  2. Electrons leave the battery at the negative terminal, complete the electric circuit and enter the battery at the positive terminal.
  3. When there is a liquid or a solution in the circuit, two rods, wires or plates are immersed in it. These are called electrodes.
  4. Electrodes are made of conducting solid. The electrode connected to negative terminal of a battery by means of a conducting wire is called a cathode and the electrode connected to the positive terminal of a battery is called anode.
  5. We have seen that salts, strong acids and strong bases dissociates almost completely in their aqueous solutions.
  6. Therefore the aqueous solutions of all these three contain large number of cations and anions.
  7. A characteristic of liquid state is the mobility of its particles. Due to its mobility the positive charged ions of the solution are attracted to the negative electrode or cathode.
  8. On the other hand, the negative charged ions of the solution are attracted to the positive electrode or anode.
  9. The movement of ions in the solution towards the respective electrodes accounts to the conduction of electricity through the solution.
  10. From this we can understand that those liquids or solutions which contain a large number of dissociated ions conduct electricity. Maharashtra Board Class 9 Science Solutions Chapter 5 Acids, Bases and Salts

Balbharati Maharashtra State Board 9th Std Science Textbook Solutions

Substances in Common Use Class 9 Science Chapter 14 Questions And Answers Maharashtra Board

Std 9 Science Chapter 14 Substances in Common Use Question Answer Maharashtra Board

Balbharti Maharashtra State Board Class 9 Science Solutions Chapter 14 Substances in Common Use Notes, Textbook Exercise Important Questions and Answers.

Class 9 Science Chapter 14 Substances in Common Use Question Answer Maharashtra Board

Class 9 Science Chapter 14 Substances in Common Use Textbook Questions and Answers

1. Fill in the blanks.

a. The number of molecules of water of crystallization in washing soda is …………….…. .
b. The chemical name of baking soda is …………….…. .
c. …………….…. is used in treatment of hyperthyroidism.
d. The chemical name of Teflon is …………….…. .
Answer:
a. 10
b. Sodium bicarbonate
c. Iodine -123
d. Polytetra fluoroethylene (C2F4)n

Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use

2. Match the pairs

Group A Group B
1. Saturated brine a. sodium metal freed
2. Fused salt b. basic salt
3. CaOCl2 c. crystallization of salt
4. NaHCO3 d. oxidation of colour

Answer:
(1 – c),
(2 – a),
(3 – d),
(4 – b)

3. Write answers to the following

a. What is meant by radioactivity?
Answer:

  • Elements with a high atomic number such as uranium, thorium, radium have a property of spontaneously emitting invisible, highly penetrating and high energy radiation.
  • This property is called radioactivity.
  • A substance having this property is called a radioactive substance.

b. When is said to be the nucleus unstable?
Answer:

  • It is the balance of protons and neutrons in a nucleus which determines whether a nucleus will be stable or unstable.
  • Too many neutrons or protons upset this balance disrupting the binding energy from the strong nuclear forces making the nucleus unstable.

c. Which diseases are caused by artificial food colours?
Answer:
Diseases like ADHD (Attention Deficit Hyperactivity Disorder) can affect children due to excessive consumption of foods with added food colours.

d. Where in the industrial field is radioactivity used?
Answer:
Industrial field Radiography

  • Internal cracks and voids in cast iron articles and iron solder can be detected with the help of gamma rays.
  • For this purpose, isotopes like cobalt-60, iridium-192 are used in the radiography camera.
  • This technique is used for detecting flaws in metal work.

Measurement of thickness, density and level

  • It is necessary to maintain the required thickness in the manufacture of aluminium, plastic, iron sheets of differing thickness.
  • In the manufacturing process, a radioactive substance is placed on one side and an instrument to measure radiation on the other.
  • The radiation read by the measuring instrument varies with the thickness of the sheet.
  • Material inside a packing can also be examined by the same technique.

Luminescent paint and radio luminescence:

  • The radioactive substances radium, promethium, tritium with some phosphor are used to make certain objects visible in the dark, for example, the hands of a clock, and certain other objects.
  • Krypton-85 is used in HID (High-Intensity Discharge) lamps while promethium – 147 is used in portable X-ray units as the source of beta rays.

Use in Ceramic articles:

  • Luminous colours are used to decorate ceramic tiles, utensils, plates, etc.
  • Earlier uranium oxide was used in these paints.

e. Write down properties of teflon.
Answer:
Properties of teflon :

  • The atmosphere and chemical substances have no effect on Teflon.
  • Neither water nor oil will stick to Teflon coated articles.
  • High temperatures do not affect Teflon as its melting point is 327 °C.
  • Teflon coated articles are easy to clean.

f. What type of colours will you use to celebrate ecofriendly Rang Panchami? Why?
Answer:

  • We regularly use artificial colours on Rang Panchami.
  • The red colour used on Rang Panchami is very dangerous. It contains a high proportion of mercury in it.
  • This poses risks like blindness, skin cancer, asthma, itching of the skin, permanent blocking of sweat pores, etc.
  • Therefore, it is necessary to use eco-friendly colours.
  • We will prepare colours for Rang Panchami from natural resources such as beet root, flowers of flame of forest, spinach, flame tree (gulmohar) and protect your health by using these.

g. Why has the use of methods like Teflon coating become more common?
Answer:
The use of methods like Teflon coating became more common because of following properties of teflon:

  • The atmosphere, rain water and chemical substances have no effect on Teflon.
  • Neither water nor oil will stick to Teflon coated articles.
  • High temperatures do not affect Teflon as its melting point is 327 °C.
  • Teflon coated articles are easy to clean.
  • Teflon is a poor conductor of electricity.

4. Give a scientific explanation

a. Bleaching powder has the odour of chlorine.
Answer:

  • Bleaching powder undergoes slow decomposition due to the carbon dioxide in air and chlorine gas is released.
  • Bleaching powder gets its property because of this release of chorine gas.
    Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 7

b. The hard water of a well becomes soft on adding washing soda to it.
Answer:

  • The hard water from a well or a bore-well becomes soft on adding washing soda and we come to know this from the lather formed on it.
  • The hardness of water is due to the presence of chlorides and sulphates of calcium and magnesium in it.
  • Na2CO3 is added to it to soften such water and make it suitable for use.
  • The reaction with Na2CO3 causes the formation of insoluble carbonate salts of magnesium and calcium.
    MgCl2(aq) + Na2CO3(s) → MgCO3(s) + 2 NaCl(s)

c. Soap forms a precipitate in hard water.
Answer:

  • When soap is mixed with hard water, calcium and magnesium salts of fatty acids are formed.
  • These being water insoluble, they form a precipitate and that is why lather is not formed.

d. The particles of powder are given an electric charge while spraying them to form the powder coating.
Answer:

  • Powder coating is a method of applying a layer harder than paint on the surface of an iron object to prevent rusting.
  • In this method, a polymer resin, a pigment and some other ingredients are melt, mixed, cooled and ground into a uniform powder.
  • This powder is sprayed on the polished metal surface by electrostatic spray deposition (ESD).
  • In this method, the particles of the powder are given an electrostatic charge due to which a uniform layer of the powder sticks to the metal surface.
  • Then the object is heated in the oven along with the coating.
  • A chemical reaction occurs in the layer, resulting in the formation of long cross-linked polymeric chains.

e. The aluminium article is used as an anode in the anodising process.
Answer:

  • A protective layer is formed naturally on the surface of aluminium metal by reaction with oxygen in air.
  • In the anodizing process, this layer is made of the desired thickness. Anodizing is done by electrolysis.
  • Dilute Sulphuric acid is taken in the electrolytic cell and the aluminium article is dipped in it as the anode.
  • When an electric current is passed, hydrogen gas is released at the cathode and oxygen gas at the anode.
  • A reaction with oxygen occurs and a layer of hydrated aluminium oxide is formed on the anode. Therefore, aluminium article is used as an anode in the anodizing process.

f. When the radiation coming out from certain radioactive substance is passed through an electric field, marks are found at three places on the photographic plate placed in its path.
Answer:
(i) When the radiation coming out from certain radioactive substance is passed through an electric field, marks are found at three places on the photographic plate placed in its path. This is because the radiation coming out from radioactive substance are of three types Alpha rays, Beta rays and Gamma rays.

(ii) The rays which get deviated slightly towards negatively charged plate are called alpha rays. They get deviated towards negatively charged plate because they are made of positively charged particles, called as alpha particles (He++).

(iii) The rays which get deviated substantially towards the positively charged plate are called beta rays. They get deviated towards a positively charged plate because they are made of negatively charged particles called as beta particles (e-).

(iv) The rays which do not deviate at all are called gamma rays. They are uncharged electromagnetic radiation. Hence, marks are found at three places on the photographic plate. (For diagram refer Fig. 14 .2 from Q. 4(3))

g. A certain type of ceramic tiles are fixed on the outer layer of a space shuttle.
Answer:
(i) Each shuttle is covered by more than 24,000 of the six- by six-inch advance ceramic tiles. This tiles withstand high temperatures without decomposing. They are brittle, water-resistant and electrical insulator. Most of the tiles are made of silica fibres, which are produced from high-grade sand (SiO2).

(ii) Silica is an excellent insulator because it transports heat slowly. When the outer portion of a tile gets hot, the heat takes a long time to work its way down through the rest of the tile to the shuttle’s skin. The tiles keep the orbiter’s aluminium skin at 350 degrees or less.

(iii) The silica fibers are mixed with water and chemicals, and the mixture is poured into molds, which are zapped in microwave ovens at 2,350°C to fuse the silica fibres. Tiles are too brittle to attach to the orbiter directly.

(iv) The shuttle’s skin contracts slightly while in orbit, then expands during re-entry.

(v) In addition, the stresses of launch and re-entry cause the skin to flex and bend. Such motions could easily crack the tiles or shake them off. To keep them in place, workers glue the tiles to flexible felt-like pads, then glue the pads to the orbiter.

5. Write answers to the following

a. Write about artificial food colours, the substances used in them and their harmful effects.
Answer:
(a) Artificial food colour and substances in them.

  • Food colours are mixed in most soft drinks and foodstuffs available in the market.
  • These food colours are in the form of powders, gels and pastes.
  • Food colours are used in domestic as well as commercial products.
  • Certain colours and essences are added to ice cream, ice candies, sauce, fruit juices, cold drinks, pickles, jams and jelly.
  • Food colours are often found to be added to packaged meat (chicken, mutton), chilli powder, turmeric, sweets and other similar substances so as to give them a good colour.
  • Tetrazene, sunset yellow are artificial food colours used extensively.

(b) Harmful effects of artificial food colours

  1. Food colours added to pickles, jam and sauce contain small quantities of lead and mercury. These can be harmful for those who consume these products on a regular basis.
  2. Diseases like ADHD (Attention Deficit Hyperactivity Disorder) can affect children due to excessive consumption of foods with added food colours.

b. What is meant by water of crystallization? Give examples of salts with water of crystallization, and their uses.
Answer:
The exact number of water molecules which are chemically bonded to a molecule of a salt within a hydrated crystalline compound is called as water of crystallization are:

Some substances in our daily use which contain water of crystallization are:

  • Alum (Potash alum – K2SO4.Al2(SO4)3.24H2O)
  • Borax (Na2B4O7.10H2O)
  • Epsom salt (Magnesium sulphate MgSO4.7H2O)
  • Barium chloride (BaCl2.2H2O)
  • Sodium sulphate (Glauber’s salt Na2SO4.10 H2O)
  • Blue vitriol (Copper Sulphate – CuSO4.5H2O)

Uses of these salts are as given below:
(i) Alum (Potash alum – K2SO4.Al2(SO4)3.24H2O)

  • Alum is used in the process of water purification.
  • Because of the property of coagulation, the solid impurities in water come together, become heavy and settle to the bottom. As a result, the impure water or muddy above becomes clear.
  • Alum powder, found in the spice section of many grocery stores, may be used in pickling recipes as a preservative to maintain fruit and vegetable crispness.
  • Alum is used as the acidic component of some commercial baking powders.
  • Alum has been used as an after shave treatment.

(ii) Borax (Na2B4O7.10H2O)

  • Borax today is used for many cleaning purposes.
  • It is used to make homemade laundry detergent.
  • It is added as a cleaning boost to any other detergent.
  • It even keeps ants and other pests away.

(iii) Epsom salt (Magnesium sulphate MgSO4.7H2O)

  • Epsom salt is used as a relaxing magnesium bath soak.
  • To grow better vegetables – Add a tablespoon of Epsom salt to the soil below a vegetable plant to boost growth.

(iv) Barium chloride (BaCl2.2H2O)

  • In industry, Barium chloride is mainly used in the purification of brine solution in caustic chlorine plants.
  • It is also used in the manufacture of heat treatment salts.
  • It is used in hardening of steel.
  • It is used in the manufacture of pigments.

(v) Sodium sulphate (Glauber’s salt Na2SO4.10H2O)

  • In the laboratory, anhydrous Sodium sulphate is widely used as an inert drying agent, for removing traces of water from organic solutions.
  • Glauber’s salt, the decahydrate, is used as a laxative.

(vi) Blue vitriol (Copper sulphate CuSO4.5H2O)

  • Blue vitriol is used in the blood test for diagnosing anaemia.
  • Slaked Time is used with blue vitriol in the Bordeaux mixture which is used as a fungicide on fruits like grapes and musk melon.

c. Write briefly about the three methods of electrolysis of sodium chloride.
Answer:

  • When an electric current is passed through a saturated solution of sodium chloride (brine) it is electrolysed and hydrogen gas is released at the cathode while chlorine gas is released at the anode.
  • This method is used for production of chlorine gas. In this method an important basic compound NaOH is formed in the cell.
  • Chemical reaction
    2NaCl + 2H2O → 2NaOH + Cl2 ↑ + H2
  • When salt is heated to a high temperature (about 800 °C), it melts. This is called the fused state of the salt.

6. Write the uses.

a. Anodizing
b. Powder coating
c. Radioactive substances
d. Ceramic
Answer:
(a) Anodizing : Anodizing is done on aluminum cooking utensils like griddles and cookers.

(b) Powder coating : Powder coating is done on iron objects to prevent rusting. Also, on Plastic and Medium density fibre (MDF) board, to make them highly durable, hard and attractive.

(c) Radioactive substances:
(I) Industrial field:
(i) Industrial Radiography : Internal cracks and voids in cast iron articles and iron solder can be. detected with the help of gamma rays. For this purpose, isotopes like cobalt-60, iridium-192 are used in the radiography camera. This technique is used for detecting flaws in metal work.

(ii) Measurement of thickness, density and level: It is necessary to maintain the required thickness in the manufacture of aluminium, plastic, iron sheets of differing thickness. In the manufacturing process, a radioactive substance is placed on one side and an instrument to measure radiation on the other. The radiation read by the measuring instrument varies with the thickness of the sheet. Material inside a packing can also be examined by the same technique.

(iii) Luminescent paint and radioluminescence:
The radioactive substances radium, promethium, tritium with some phosphor are used to make certain objects visible in the dark, for example, the hands of a clock, and certain other objects. Krypton-85 is used in HID (High Intensity Discharge) lamps while promethium-147 is used in portable X-ray units as the source of beta rays.

Use in Ceramic articles – Luminous colours are used to decorate ceramic tiles, utensils, plates, etc. Earlier uranium oxide was used in these paints.

(II) Field of agriculture :

  • The genes and chromosomes that give seeds properties like fast growth, higher productivity, etc. can be modified by means of radiation.
  • The radioactive isotope cobalt-60 is used for food preservation.
  • Onions, potatoes are irradiated with gamma rays from cobalt-60 to prevent their sprouting.
  • Strontium-90 is used as a tracer in the research on various crops.

(III) Medical science:

  • Polycythemia : The red blood cell count increases in the disease polycythemia. Phosphorus- 32 is used in its treatment.
  • Bone cancer : Strontium-89, strontium-90, samarium-153 and radium-223 are used in the treatment of bone cancer.
  • Hyperthyroidism : Enlargement of thyroid gland, weight loss in spite of appetite, insomnia are the symptoms of hyperthyroidism.
  • It occurs due to overproduction of hormones by the thyroid gland. Iodine-123 is used in the treatment of hyperthyroidism.
  • Tumour detection : Boron-10, iodine-131, cobalt-60 are used in treatment of brain tumour, while arsenic-74 is used in detection of small tumours in the body.

(d) Ceramic : Pots made by a potter, Mangalore roofing tiles, construction bricks, pottery, terracotta articles are some examples of common ceramic articles that we see around.

7. Write the harmful effects

a. Artificial dye
b. Artificial food colour
c. Radioactive substances
d. Deodorant
Answer:
(a) Artificial dye:

  • Dyeing hair can have adverse effects like hair fall, damage to hair texture, burning of skin, adverse effect on eyes, etc.
  • Lipstick contains a dye named carmine. It does not affect lips but causes stomach disorders.
  • Excessive use of plants for making natural dyes results in deterioration of the environment.

(b) Artificial food colour:

  • Food colours added to pickles, jams and sauces contain small quantities of lead and mercury. These can be harmful for those who consume these products on a regular basis.
  • Diseases like ADHD (Attention Deficit Hyperactivity Disorder) can affect children due to excessive consumption of foods with added food colours.

(c) Radioactive substances :

  • The central nervous system is affected by radioactive radiations.
  • Hereditary defects are generated by bombardment of radiation on D.N.A in the body.
  • Radioactive radiation can penetrate the skin, and causes diseases like skin cancer, leukemia.
  • The radioactive pollutants created due to explosions enter the body through air and it is difficult to control them.
  • The radioactive pollutants released in the sea enter the bodies of fishes and through them enter the human body.
  • The radioactive paint on the watch can cause cancer.
  • The radioactive isotopes strontium-90 can enter the body through plants, fruits, flowers, cereals, milk, etc. and cause diseases like bone cancer, leukemia.

(d) Deodorant:

  • Aluminium – Zirconium compounds are the most harmful chemicals in the deodorant. Disorders like headache, asthma, respiratory disorders, heart disease are likely to occur without our knowledge.
  • There is a possibility of various skin disorders and also skin cancer due to the aluminium chlorohydrates.

8. Write the chemical formula Bleaching powder, common salt, baking soda, washing soda
Answer:

Common nameChemical name
Bleaching powderCaOCl2
Common saltNaCl
Baking sodaNaHCOs
Washing sodaNa2CO3.10 H2O

9. Explain what you see in the following picture
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 19
Powder coating
Answer:

  1. This picture shows powder coating of the given object. Powder coating is a method of applying a layer harder than paint on the surface of an iron object to prevent rusting.
  2. In this method, a polymer resin, a pigment and some other ingredients are melt mixed, cooled and ground into a uniform powder.
  3. This powder is sprayed on the polished metal surface by electrostatic spray deposition (ESD).
  4. In this method, the particles of the powder are given an electrostatic charge due to which a uniform layer of the powder sticks to the metal surface.
  5. Then the object is heated in the oven along with the coating.
  6. A chemical reaction occurs in the layer, resulting in the formation of long cross-linked polymeric chains.
  7. This powder coating is highly durable, hard and attractive. Powder coating can be done on plastic and medium density fibre (MDF) board in day to day use as well.

Class 9 Science Chapter 14 Substances in Common Use Intext Questions and Answers

Can you recall?

Question 1.
What are detergents?
Answer:

  • Detergent is a water-soluble cleansing agent which combines with impurities and dirt to make them more soluble, and differs from soap in not forming a scum with the salts in hard water.
  • Today, detergents are more likely to be a mixture of synthetic chemicals and additives cooked up in a huge chemical plant and, unlike traditional soap, they’re generally liquids rather than solids.
  • Detergents are used in everything from hair shampoo and clothes, washing powder to shaving foam and stain removers.
  • The most important ingredients in detergents are chemicals called surfactants – a word made from bits of the words surface-active agents.

Question 2.
What are the important substances that we use in day to day life? For what purposes do we use them?
Answer:
Some of the substances we use in our day to day life and the purpose of using them are as follows:

Toothpaste: for cleaning teeth and maintaining hygienic conditions of mouth.

Soap : for bathing and maintaining hygienic conditions of body.

Natural and artificial fibers : we wear them as clothes to protect our body and many other purposes.

Washing powder: for cleaning clothes. Vegetables, fruits and food grains : they provide us with necessary vitamins, minerals and carbohydrates required for proper functioning of body.

Water : very important for our survival and many other functions of day to day life.

Metals : for making buildings, bridges, roads, vehicles, trains, ships, airplanes, utensils etc.

Acids, bases and salts : used for various purposes, for example, Sodium chloride which is used as common salt, a very necessary ingredient of our daily food without which our food is tasteless.

Question 3.
How are the various substances in day to day use classified from the scientific point of view?
Answer:
The various substances in day to day use are classified from the scientific point of view as elements, compounds, mixtures, metals, non-metals, acids, bases and salts.

Question 4.
Which chemicals and apparatus will you use in the laboratory for making soap?
Answer:
For making soap in laboratory following chemicals and apparatus are used :
Chemicals : Vegetable oil (coconut oil, castor oil, soya bean oil etc.)
Sodium hydroxide (NaOH)
Salt (Sodium chloride NaCl)

Apparatus :
500 ml glass beaker
Burner
Flat glass tray
Knife

Soaps are essential to personal and public health. They safely remove germs, soils and other contaminants and help us to stay healthy and make our surroundings more pleasant. Soaps are made from fats and oils or their fatty acids.

Take about 20 ml of any vegetable oil (coconut oil, castor oil, soybean oil etc.) in a beaker. Put about 30 – 35 ml of NaOH in it and heat and stir the mixture till a paste is formed. Now add a little salt. Stir again and allow the mixture to cool in a flat glass tray, on cooling it solidifies. Take a knife and cut it in soap bars as per the size required.

Question 5.
What are salts?
Answer:

  • Inorganic substances occur naturally in the form of salts rather than acids or bases.
  • The ionic compounds which do not contain H+ and OH ions and contain only one kind of cation and anion are called simple salts.
  • For example, Na2SO4, K3PO4, CaCl2.
  • The sea is said to be a rich source of salts. In fact, the sea is a rich source of several salts of various elements such as chlorine, sodium, magnesium, potassium, calcium, bromine.
  • The important salts found in sea water are sodium chloride, magnesium chloride, magnesium sulphate, potassium chloride, calcium carbonate and magnesium bromide.

Answer the following questions:

Question 1.
How is it determined whether a substance is acidic, basic or neutral?
Answer:

  • In the pH scale, the pH of solutions varies from 0 to 14 in accordance with the strength of the acids or base.
  • The pH scale shows different colours at different values of pH. Colour from dark red to yellow or from pH value 0 to 6 indicates the substances are acidic.
  • Colour from light blue to violet or from pH value 8 to 14 indicates the substances are basic.
  • Green colour or pH value 7 indicates the substances are neutral.

Question 2.
A sweets shop looks attractive because of the colourful sweets displayed there. Which colours are used in these substances?
Answer:

  • Food colours and essences are used in sweets to make them colourful and tasty.
  • These food colour are in the form of powders, gels and pastes.
  • Food colours are natural as well as artificial.
  • The food colours prepared from seeds, beetroot, flowers and fruit concentrate are natural.
  • Tetrazene, sunset yellow are artificial food colours used extensively.

Question 3.
Make a list of substances in day to day use in accordance with their pH value (O to 14).
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 18

Question 4.
A doctor gives you medicines when you fall ill. What are the medicines made from?
Answer:

  • Long before pure chemicals were manufactured in labs, people used plants for medicine.
  • There are over a hundred active ingredients derived from plants for use as drugs and medicines.
  • The emergence of synthetic chemistry in the 1800s opened up new avenues for scientific research into drugs.
  • Many chemists tried to locate medically active ingredients in plants (for instance the important malaria remedy quinine), and subsequently tried to make those substances in the laboratory in order to become independent of plant supplies.
  • At the same time, a new industry developed as scientists developed processes to synthesise new chemicals on a large scale.
  • New production methods developed in the late 1800s and early 1900s made it easier to standardise, package and transport medicines.

Question 5.
What problems do you get after playing colours on Rang Panchami? Why?
Answer:

  • After playing colours on Rang Panchami we may get problems such as risks of blindness, skin cancer, asthma, itching of the skin, permanent blocking of sweat pores etc.
  • This is because the colours used in rang panchami specially the red colour is very dangerous.
  • It contains a high proportion of mercury in it.

Question 6.
Which colours will you use to prevent the occurrence of these problems?
Answer:

  • To prevent the occurrence of these problem, instead of using artificial colours, natural colours should be used.
  • Natural colours are prepared from natural resouroes such as beet root, flowers of flame of forest, spinach, flame tree (gulmohar).

Question 7.
What problem do you have on painting the house and furniture?
Answer:

  • On painting the house and furniture with artificial colours which are dangerous, we may get problems such as risks of blindness, skin cancer, asthma, itching of the skin, permanent blocking of sweat pores, etc.
  • This is because the colours contain a high proportion of mercury in it.

Question 8.
What is the property of Teflon because of which it is used in non-stickware?
Answer:
Following are the properties of teflon because of which it is used in nonstick cookware.

  • The atmosphere and chemical substances have no effect on Teflon.
  • Neither water nor oil will stick to Teflon coated non-stickware.
  • High temperatures do not affect Teflon as its melting point is 327 °C.
  • Teflon coated non-stickware are easy to clean.

Answer the following questions:

Question 1.
What is the strip shown below? What is it used for?
Answer:
The strip shown is pH metre scale. It is used to determined pH of solutions.

Question 2.
Prepare saturated solutions of given salts and put 2-3 drops of the universal indicator in them and note your observations in the table below:
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 1

Class 9 Science Chapter 14 Substances in Common Use Additional Important Questions and Answers

Select the correct option:

Question 1.
Baking soda is ………………………… .
(a) non-metallic
(b) metallic
(c) acidic
(d) basic
Answer:
(d) basic

Question 2.
During electrolysis of NaCl in the fused state ………………………… is formed at cathode.
(a) sodium
(b) oxygen
(c) oxalic acid
(d) butyric acid
Answer:
(a) sodium

Question 3.
………………………… is known as chloride of lime.
(a) Calcium carbonate
(b) Sodium bicarbonate
(c) Sodium chloride
(d) Bleaching powder
Answer:
(d) Bleaching powder

Question 4.
Salt obtained from certain type of rock is called ………………………… .
(a) hard salt
(b) rock salt
(c) stone salt
(d) pure salt
Answer:
(b) rock salt

Question 5.
The ………………………… % aqueous solution of salt is called brine.
(a) 25
(b) 60
(c) 30
(d) 50
Answer:
(a) 25

Question 6.
The molecular formula for baking soda is ………………………… .
(a) Na2CO3
(b) NaHCO3
(c) Na2SO4
(d) NaNO3
Answer:
(b) NaHCO3

Question 7.
Bleaching powder is also called ………………………… .
(a) Calcium oxygen chlorine
(b) Calcium oxychloride
(c) Calcium hydroxide
(d) Calcium oxalate
Answer:
(b) Calcium oxychloride

Question 8.
NaHCO3 is also called as ………………………… .
(a) Sodium carbonate
(b) Sodium bicarbonate
(c) Sodium carbon oxide
(d) Sodium chloride
Answer:
(b) sodium bicarbonate

Question 9.
Molecular formula for Magnesium bromide is ………………………… .
(a) MgBr
(b) Mg2Br
(c) Mg2Br2
(d) MgBr2
Answer:
(d) MgBr2

Question 10.
The molten state of NaCl is also called as ………………………… .
(a) solid state
(b) semi-solid
(c) gaseous state
(d) fused state
Answer:
(d) fused state

Question 11.
Substance used to make hard water soft is ………………………… .
(a) Na2CO3.10H2O
(b) Na2CO3.H2O
(c) NaCO3.10H2O
(d) NaCO3.H2O
Answer:
(a) Na2CO3.10H2O

Question 12.
The fixed number of molecules of water in alum is ………………………… .
(a) 24
(b) 10
(c) 7
(d) 2
Answer:
(a) 24

Question 13.
Chlorine gas is a strong ………………………… agent.
(a) reducing
(b) oxidising
(c) neutral
(d) acidic
Answer:
(b) oxidising

Question 14.
Bleaching powder is ………………………… in colour.
(a) brownish red
(b) yellowish-white
(c) pinkish brown
(d) greenish blue
Answer:
(b) yellowish-white

Question 15.
Soap is ………………………… in nature.
(a) acidic
(b) basic
(c) neutral
(d) fuming
Answer:
(b) basic

Question 16.
Melting point of NaCl is ………………………… .
(a) 400°C
(b) 100°C
(c) 800°C
(d) 600°C
Answer:
(c) 800°C

Question 17.
Rock salt is ………………………… in colour.
(a) black
(b) white
(c) brown
(d) blue
Answer:
(c) brown

Question 18.
Strong odour in swimming pool is due to ………………………… .
(a) chlorine gas
(b) impurities
(c) calcium carbonate
(d) calcium hydroxide
Answer:
(a) chlorine gas

Question 19.
Molecular formula of sodium bicarbonate is ………………………… .
(a) NaHCO3
(b) Na2HCO3
(c) Na2HCO2
(d) NaHCO2
Answer:
(a) NaHCO3

Question 20.
Soap is ………………………… in nature.
(a) radioactive
(b) natural
(c) acidic
(d) basic
Answer:
(d) basic

Question 21.
The molecular formula for Magnesium bromide is ………………………… .
(а) MgBr
(b) MgBr2
(c) Mg2Br2
(d) Mg2Br
Answer:
(b) MgBr2

Fill in the blanks and rewrite the complete statements:

(1) 25% of NaCl is known as
(2) gas is released when bleaching powder is added to water.
(3) Washing soda is as it absorbs moisture if left exposed to air.
(4) is used to make hard water soft.
(5) Molecular formula for Alum is
(6) is used in blood test for diagnosing anaemia.
(7) High grade of and are used as raw material to manufacture bathing soap.
(8) Pickles, jams and sauce contain small quantities of and
(9) Excessive consumption of foods with added food colours leads to diseases like
(10) Melting point of Teflon is
(11) Anodizing is done by
(12) The red blood cell count increases in the disease
(13) Magnesium sulphate (MgS04.7H20) is also called
Answer:
(1) Brine
(2) Chlorine
(3) hygroscopic
(4) Na2CO3 (Washing soda)
(5) K2SO4.Al2(SO)3.24H2O
(6) Blue Vitriol
(7) fats, oils
(8) lead, mercury
(9) ADHD (Attention Deficit Hyperactivity Disorder)
(10) 327°C
(11) Electrolysis
(12) Polycythemia
(13) Epsom salt
(14) Soap

State whether the following statements are true or false. Correct the false statements.
(1) Bleaching powder is used in preparation of chloroform which is used as an anaesthetic.
(2) On addition of universal indicator the colour of table salt changes to pink.
(3) Borax is Na2B4O7.9H2O.
(4) Boron -10 is used to cure bone cancer.
(5) Clinical deo contains 20 to 25% of aluminium.
(6) NaHCO3 is sodium carbonate.
(7) Soap is acidic in nature.
(8) Baking powder is neutral in nature.
(9) POP is crystalline in nature.
(10) pH value of universal indicator is 0 – 7.
(11) Sodium chloride is formed by neutralization reaction between sodium hydroxide and calcium carbonate.
(12) Boiling point of NaCl is 800 °C.
(13) Molten state of NaCl is also called as solid state.
(14) Mineral halite is an example of Rock Salt.
(15) Sodium bicarbonate is used to reduce acidity.
(16) Bleaching powder is also called as chloride of lime.
(17) Bleaching powder is obtained by reaction of chlorine gas with slaked lime.
(18) Bleaching powder available in market is classified on the basis of colour.
(19) The hard water becomes soft on adding baking soda (NaHCO3)
Answer:
(1) True
(2) False. On addition of universal indicator the colour of table salt changes to green.
(3) False. Borax is Na2B4O7.9H2O
(4) False. Boron – 10 is used in treatment of brain tumour.
(5) True
(6) False. NaHCO3 is sodium bicarbonate.
(7) False. Soap is basic in nature.
(8) False. Baking powder is basic in nature.
(9) False. POP is amorphous in nature.
(10) False. pH value of universal indicator is 0 -14.
(11) False. Sodium chloride is formed by a neutralization reaction between sodium hydroxide and hydrochloric acid.
(12) False. Melting point of NaCl is 800°C.
(13) False. Molten state of NaCl is also called as fused state.
(14) True
(15) True
(16) True
(17) True
(18) False. Bleaching powder available in market is classified on the basis of percentage of chlorine present in it.
(19) False. Hard water becomes soft on adding washing soda (Na2CO3.10H2O)

Name the following:

Question 1.
Important salts found in sea water.
Answer:
Magnesium chloride, Potassium chloride

Question 2.
Chemical used in preparation of breads and cakes to make them soft.
Answer:
Sodium bicarbonate

Question 3.
Gas liberated when bleaching powder is added to CO2 gas.
Answer:
Chlorine (Cl2) gas.

Question 4.
Salt used in refining petroleum
Answer:
Sodium carbonate (Na2CO3)

Question 5.
Chemical formula of bleaching powder
Answer:
CaOCl2

Question 6.
The chemical formula of Sodium hydrogen carbonate.
Answer:
NaHCO3

Question 7.
Nature of soap.
Answer:
Basic

Question 8.
Molecular formula for Magnesium bromide
Answer:
MgBr2

Question 9.
Melting point of NaCl
Answer:
800 °C

Question 10.
Two examples of Rock Salt
Answer:
Mineral halite and Himalayan rock salt.

Question 11.
Uses of sodium bicarbonate
Answer:
To prepare breads, cakes and dhokla

Question 12.
Constituents of baking powder.
Answer:
Baking soda and mild acid (tartaric acid)

Question 13.
Substance used to make hard water soft.
Answer:
Washing soda i.e. Na2CO3.10H2O.

Question 14.
Radioactive isotopes used in treatment of bone cancer.
Answer:
Strontium – 89, Strontium – 90, Samarium -153, Radium – 223

Question 15.
Use of Strontium 89 and strontium 90.
Answer:
Treatment of bone cancer.

Select the odd man out:

Question 1.
Sodium sulphate, Barium chloride, Magnesium sulphate, Bleaching powder.
Answer:
Bleaching powder, all others are crystalline salt with water of crystallization while bleaching powder is not.

Question 2.
Strontium – 89, Strontium – 90, Radium – 223, Iodine -123.
Answer:
Iodine -123, it is used to cure hyperthyroidism while others are used to cure bone cancer.

Question 3.
Soap, Toothpaste, Baking soda, Curd.
Answer:
Curd, it is acidic in nature while others are basic in nature.

Question 4.
Na2CO3.10H2O, Na2SO4.10H2O, BaCl2.2H2O, CaOCl2
Answer:
CaOCl2, it is amorphous in nature while rest are crystalline in nature.

Question 5.
Boron-10, Iodine – 131, Cobalt – 60, Iodine – 123.
Answer:
Iodine -123, it is used in hyperthyroidism while rest are used in treatment of brain tumour.

Question 6.
Na2SO4, K3PO4, MgBr2, HCl.
Answer:
HCl, rest all are salts but HCl is an acid.

Write the correlated terms:

(1) Washing Powder : Basic :: Milk : ……………………………
(2) Na2SO4: Sodium sulphate :: K3PO4 : ……………………………
(3) CaOCl2: Calcium Oxychloride : : NaHCO3 : ……………………………
(4) Borax : 10H2O : : Alum : ……………………………
(5) Sodium Sulphate : Na2SO4.10H2O : : Magnesium Sulphate : ……………………………
(6) Bathing soap : High grades fats and oils :: Washing soap : ……………………………
(7) Radium – 23 : Bone cancer :: Phosphorus – 32 : ……………………………
(8) Iodine -123 : Hyperthyroidism :: Iodine -131 : ……………………………
(9) Clinical deo : 20-25% of aluminium : : Antiperspirant deo : of aluminium chlorohydrate : ……………………………
(10) Sodium carbonate : Na2CO3 : : Sodium bicarbonate : ……………………………
(11) Curd : Acidic : : Soap : ……………………………
(12) Calcium Carbonate : CaCO3 : : Magnesium bromide : ……………………………
(13) Baking Soda : NaHCO3 : : Washing Soda : ……………………………
(14) Baking Soda : Breads and Cakes : : Washing Soda : ……………………………
(15) Borax : Na2B4O7.10H2O : : Alum : ……………………………
Answer:
(1) Acidic
(2) Potassium phosphate
(3) Sodium hydrogen carbonate
(4) 24H2O
(5) MgSO4.7H2O
(6) Low-grade fats and oils
(7) Polycythemia
(8) Tumour detection
(9) 15%
(10) NaHCO.
(11) Basic
(12) MgBr2
(13) Na2CO3.10H2O
(14) Hard water soft
(15) K2SO4.Al2(SO4)3.24H2O

Match the columns:

Question 1.

Column ‘A’Column ‘B’
(1) Barium chloride(a)24H2O
(2) Sodium sulphate(b)7H2O
(3) Magnesium sulphate(c)2H2O
(4) Alum(d)10H2O

Answer:
(1 – c),
(2 – d),
(3 – b),
(4 – a)

Question 2.

Column ‘A’Column ‘B’
(1) Strontium – 90(a) Brain tumour
(2) Cobalt – 60(b) Hyperthyroidism
(3) Iodine – 131(c) Polycythemia
(4) Phosphorus – 32(d) Bone cancer

Answer:
(1 – d),
(2 – a),
(3 – b),
(4 -c)

Give scientific reasons:

Question 1.
Baking soda is used while making cakes.
Answer:

  • Baking soda is chemically known as sodium bicarbonate.
  • On heating, sodium bicarbonate decomposes to form sodium carbonate, water and carbon dioxide (CO,).
  • The carbon dioxide produced is released due to which the cake becomes soft and spongy.
  • Hence, baking soda is used to make cake spongy and soft.

Question 2.
Baking soda is used to reduce acidity in the stomach.
Answer:

  • Baking soda is used as a medicine (antacid). When it is taken, it undergoes hydrolysis to give sodium hydroxide in the stomach. Thus, sodium hydroxide neutralizes the hydrochloric acid produced by gastric juice and gives relief to the patient from acidity.
    Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 4

Question 3.
Tap water and water in swimming pool has a typical strong odour in the rainy season.
Answer:

  • Tap water and water in swimming pool has a typical strong odour in the rainy season, it is the odour of the chlorine gas that is used to destroy the microbes in the water.
  • Chlorine gas is a strong oxidizing agent and therefore, it has a strong disinfecting as well as bleaching action.
  • Chlorine is inconvenient to handle because of its gaseous state. Instead, the solid bleaching powder which has the same effect is more convenient to use.
  • Bleaching powder undergoes slow decomposition due to the carbon dioxide in air and chlorine gas is released. Bleaching powder gets its property because of this release of chlorine gas.
    Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 5

Question 4.
Sodium carbonate is added to hard water to make it soft.
Answer:

  • The hardness of water is due to the presence of chlorides and sulphates of calcium and magnesium in it.
  • Na2CO3 is added to it to soften such water and make it suitable for use.
  • The reaction with Na2CO3 causes the formation of insoluble carbonate salts of magnesium and calcium thus making the water soft.
    Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 6

Question 5.
Alum is used in the process of water purification.
Answer:

  • Alum is used in the process of water purification because of property of coagulation.
  • The solid impurities in water come together, become heavy and settle to the bottom.
  • As a result, the water above becomes clear.

Question 6.
Overconsumption of artificial food colours should be avoided?
Answer:

  • The overconsumption of artificial food colours should be avoided because they can be detrimental to health.
  • Food colours added to pickles, jam and sauce contain small quantities of lead and mercury. These can be harmful for those who consume these products on a regular basis.
  • Diseases like ADHD (Attention Deficit Hyperactivity Disorder) can affect children due to excessive consumption of foods with added food colours.

Question 7.
Artificial colours in Rang Panchami should be used cautiously.
Answer:

  • We regularly use artificial colours on Rang Panchami.
  • The red colour used on Rang Panchami is very dangerous. It contains a high proportion of mercury in it.
  • This poses risks like blindness, skin cancer, asthma, itching of the skin, permanent blocking of sweat pores etc.
  • Therefore, it is necessary that artificial colours are used cautiously.

Question 8.
There are various brands of bleaching powder in the market.
Answer:

  • When bleaching powder comes in contact with air, it reacts with carbon dioxide to form calcium carbonate and releases chlorine gas. CaOCl2 + CO2 → CaCO3 + Cl2 ↑ (from air)
  • This generated chlorine is known as “available chlorine.”
  • On the basis of the percentage of “available chlorine” various brands of bleaching powder are available in the market.

Question 9.
We use anodized cooking utensils like griddles and cookers.
Answer:

  • Anodizing is process of forming a protective rayer of hydrated aluminium oxide on utensils.
  • Due to anodizing, the surface of the cooking utensils become non-standing, non-toxic and non-reactive with the ingredients of the foot.
  • These utensils get heated faster and withstand high heat.
  • Also the amount of butter, ghee or oil used to cook food in these type of utensils is neglible.
  • These utensils are tough, durable and resistant to corrosion.
  • Hence, we use anodized cooking utensils like gridders and cookers.

Explain the following chemical reactions with the help of balanced equations :

Question 1.
Sodium hydroxide reacts with dilute Hydrochloric acid.
Answer:
When Sodium hydroxide reacts with dilute Hydrochloric acid, it forms sodium chloride and water.
This is a neutralization reaction.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 8

Question 2.
When an electric current is passed through a saturated solution of sodium chloride (brine)
Answer:
When an electric current is passed through a saturated solution of sodium chloride (brine) it is electrolysed and hydrogen gas is released at the cathode while chlorine gas is released at the anode. Also, an important basic compound NaOH is formed in the cell.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 9

Question 3.
Baking soda (Sodium hydrogen carbonate) reacts with dilute hydrochloric acid.
Answer:
When Sodium bicarbonate (Sodium hydrogen carbonate) reacts with dilute hydrochloric acid, it gives sodium chloride, water and carbon dioxide gas is liberated.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 10

Question 4.
Bleaching powder is exposed to air.
Answer:
When bleaching powder is exposed to air, it undergoes slow decomposition due to the carbon dioxide in air and chlorine gas is released.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 11

Question 5.
When dry slaked lime reacts with chlorine gas.
Answer:
When dry slaked lime reacts with chlorine gas, it gives bleaching powder.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 12

Question 6.
Bleaching powder reacts with dilute sulphuric acid.
Answer:
Dilute sulphuric acid reacts rapidly with bleaching powder to form calcium sulphate and release chlorine gas completely.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 13

Question 7.
Bleaching powder reacts with dilute hydrochloric acid.
Answer:
Dilute hydrochloric acid reacts rapidly with bleaching powder to form Calcium chloride and release chlorine gas completely.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 16

Question 8.
Sodium carbonate reacts with magnesium chloride.
Answer:
When Sodium carbonate reacts with magnesium chloride, it forms insoluble magnesium carbonate and sodium chloride. This reaction is used to make hard water soft.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 15

Question 9.
Crystalline sodium carbonate is exposed to air.
Answer:
When crystalline sodium carbonate is exposed to air it loses its water of crystallization readily and a white powder is obtained. This powder is called washing soda.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 14

Question 10.
Sodium carbonate reacts with sulphuric acid.
Answer:
When sodium carbonate reacts with sulphuric acid it forms sodium sulphate, water and carbon dioxide gas is liberated.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 17

Distinguish between;

Question 1.
Washing soda and Baking soda
Answer:

Washing sodaBaking soda
(i) Chemical name is sodium carbonate.(i)    Chemical name is sodium bicarbonate or sodium hydrogen carbonate.
(ii) Its molecular formula is Na2CO3.10H2O(ii) Its molecular formula is NaHCO3
(iii) It is a crystalline substance.(iii) It is an amorphous powder.
(iv) It is used in manufacturing soaps and detergents.(iv) It is used in bakery for making cakes and bread lighter and spongy.

Question 2.
Bathing soap and Washing soap
Answer:

Bathing soapWashing soap
(i) High-grade fats and oils are used as the raw material.(i) Low-grade fats and oils are used as the raw material.
(ii) Expensive perfumes added.(ii) Cheaper perfumes added.
(iii) No free alkali content present to prevent injuries to skin.(iii) Free alkali present for cleaning action.

Answer the following:

Question 1.
Give the properties and uses of Sodium bicarbonate.
Answer:
Properties and uses of sodium bicarbonate

  • (i) NaHCO2 reacts with moist litmus paper and red litmus turns blue which means that it is basic in nature.
  • (ii) It is used to make bread, cake, dhokla.
  • (iii) Being basic in nature it is used to reduce acidity in the stomach.
  • (iv) NaHCO3 is used to make the active substance CO2 in the fire extinguisher.
  • (v) Baking soda is used to clean an oven.

Question 2.
Give the properties and uses of washing soda.
Answer:
Properties and uses of washing soda :

  • Washing soda is a whitish and odourless powder at room temperature.
  • Litmus has a blue colour in its aqueous solution.
  • It is hygroscopic, that is, it absorbs moisture if left exposed to air.
  • It is used mainly for washing clothes.
  • Sodium carbonate is used in the glass and paper industry and also in refining of petrol.

Question 3.
Name some substances in our daily use which contain water of crystallization.
Answer:

  • Alum (Potash alum – K2SO4.Al2(SO4)3.24H2O)
  • Borax (Na2B4O7.10H2O)
  • Epsom salt (Magnesium sulphate MgSO4.7H2O)
  • Barium chloride (BaCl2.2H2O)
  • Sodium sulphate (Glauber’s salt Na2SO4.10H2O)

Question 4.
Give the uses of radioactive isotopes in the measurement of thickness, density and level.
Answer:
Measurement of thickness, density and level:

  • It is necessary to maintain the required thickness in the manufacture of aluminium, plastic, iron sheets of differing thickness.
  • In the manufacturing process, a radioactive substance is placed on one side and an instrument to measure radiation on the other.
  • The radiation read by the measuring instrument varies with the thickness of the sheet.
  • Material inside a packing can also be examined by the same technique.

Question 5.
Give the uses of radioactive isotopes in Luminescent paint and radioluminescence.
Answer:
Luminescent paint and radioluminescence:

  • The radioactive substances radium, promethium, tritium with some phosphour are used to make certain objects visible in the dark, for example, the hands of a clock, and certain other objects.
  • Krypton-85 is used in HID (High Intensity Discharge) lamps while promethium-147 is used in portable X-ray units as the source of beta rays.

Question 6.
Give the uses of radioactive isotopes in Field of agriculture.
Answer:
Field of agriculture:

  • The genes and chromosomes that give seeds properties like fast growth, higher productivity, etc. can be modified by means of radiation.
  • The radioactive isotope cobalt-60 is used for food preservation.
  • Onions, potatoes are irradiated with gamma rays from cobalt-60 to prevent their sprouting.
  • Strontium-90 is used as a tracer in the research on various crops.

Question 7.
Give the uses of dyes.
Answer:
Uses of dyes :

  • They are used for colouring cloth and hair.
  • Fluorescent colours are used to make street boards that are visible at night.
  • Dyes are used to polish leather shoes, purses and chappals.

Question 8.
What are the adverse effects of dyes?
Answer:
Adverse effects dyes :

  • Dyeing hair can have adverse effects like hair fall, damage to hair texture, burning of skin, adverse effect on eyes, etc.
  • Lipstick contains a dye named carmine. It does not affect lips but causes stomach disorders.
  • Excessive use of plants for making natural dyes results in deterioration of the environment.

Question 9.
Give the uses of teflon.
Answer:
Uses of teflon :

  • Teflon is a poor conductor of electricity. Therefore, Teflon clad wires and parts are used in high technology electronic instruments.
  • It is used for making non-stick kitchenware.
  • The coloured metal sheets of two-wheelers and four-wheelers are given a Teflon coating to protect them from damage due to high temperature and rain.

Question 10.
What is ceramic? Give examples.
Answer:

  • Ceramic is a heat resistant substance formed by kneading an inorganic substance in water and then shaping it and hardening it by heating.
  • Pots made by a potter, Mangalore roofing tiles, construction bricks, pottery, terracotta articles are some examples of common ceramic articles that we see around.

Question 11.
Give the uses of ceramics.
Answer:

  • Ceramics can withstand high temperatures without decomposing. Ceramic is brittle, water-resistant and an electrical insulator.
  • Therefore, it is used in electrical instruments, for coating the interior of a kiln, the outer surfaces of ships and blades of jet engines.
  • A certain type of ceramic tiles are fixed on the outer layer of a space shuttle. Some types of ceramics are used as superconductors.

Question 12.
What is brine? What happens when ^th of this solution is evaporated?
Answer:

  • The 25% aqueous solution of salt is called saturated brine.
  • When th of this solution is evaporated the dissolved salt gets crystallized and salt gets separated from the solution.

Question 13.
What is baking soda? Give its chemical name and molecular formula.
Answer:

  • Baking soda is a white non-crystalline powder.
  • Its chemical name is sodium hydrogen carbonate or sodium bicarbonate and its molecular formula is NaHC03.

Question 14.
Give two uses of Blue vitriol.
Answer:

  • Blue vitriol is used in the blood test for diagnosing anaemia.
  • Bordeaux mixture which is a mixture of slaked lime and blue vitriol is used as a fungicide on fruits like grapes and musk melon.

Question 15.
What is radioactivity and what are radioactive substances?
Answer:

  • Elements with a high atomic number such as uranium, thorium, radium have a property of spontaneously emitting invisible, highly penetrating and high energy radiation. This property is called radioactivity.
  • A substance having this property is called a radioactive substance.

Question 16.
What can you say about the uses of radioactive isotopes?
Answer:

  • It is a misconception that radioactive elements are used only for making an atom bomb.
  • Radioactive isotopes are used in various fields such as scientific research, agriculture, industry, medicine, etc.
  • Radioactive substances are used in two ways.
  • By using the radiation alone.
  • By using the radioactive element itself.

Question 17.
Give the uses of radioactive isotopes in Radiography.
Answer:

  • Internal cracks and voids in cast iron articles and iron solder can be detected with the help of gamma rays.
  • For this purpose, isotopes like cobalt-60, iridium-192 are used in the radiography camera.
  • This technique is used for detecting flaws in metalwork.

Question 18.
Give the uses of radioactive isotopes in ceramic articles.
Answer:

  • Luminous colours are used to decorate ceramic tiles, utensils, plates, etc.
  • Earlier uranium oxide was used in these paints.

Question 19.
What is a dye?
Answer:
The coloured substance which on applying to an article, imparts that colour to the article, is called a dye

Question 20.
What is done to fix a dye on the cloth ?
Answer:

  • A mordant is to be used to fix the colour after dyeing a cloth.
  • A mordant is a chemical binding agent that adheres well to both the fibers and the dye.

Question 21.
What is Teflon? Give its chemical name.
Answer:

  • Teflon is the polymer of tetrafluoroethylene.
  • Its chemical name is polytetrafluoroethylene (C2F4)n

Question 22.
What is powder coating? Why is it done?
Answer:

  • Powder coating is a method of applying a layer harder than paint on the surface of plastic, medium density fibre (MDF).
  • Board and iron object to make them attractive, durable and to prevent rustihg respectively.

Question 23.
Give the properties of ceramics.
Answer:

  • Ceramics can withstand high temperatures without decomposing.
  • Ceramic is brittle, water resistant and an electrical insulator.

Question 24.
How is bone china made? How is it different from porcelain?
Answer:

  • Bone china is made by adding some ash of animal bones in the mixture of china clay, feldspar and fine silica while making porcelain.
  • This ceramic is harder than porcelain.

Question 25.
What compounds are used instead of clay for making advanced ceramic?
Answer:
Oxides like Alumina (Al2O3), Zirconia (ZrO2) Silica (SiO2) and some other compounds like silicon carbide (SiC), boron carbide (B4C) are used instead of clay for making advanced ceramic.

Question 26.

What is sintering?
Answer:

  • Advanced ceramics requires a temperature of 1600 to 1800 °C and an oxygen-free atmosphere for firing.
  • This process is called sintering.

Write short notes on :

Question 1.
Chernobyl disaster.
Answer:

  • On 26th April 1986, the graphite reactor in the Chernobyl atomic power plant exploded, and suddenly the radioactive isotopes and radiation came out.
  • Due to this episode, radioactive isotopes entered the human body through water and land and caused genetic disorders.
  • These got carried further into the next generation.
  • Thyroid disorders increased in children as well as adults.
  • As a result, the incidence of throat diseases is greater there than in other places.

Question 2.
Food colours.
Answer:

  • Food colours are mixed in most soft drinks and foodstuffs available in the market.
  • These food colours are in the form of powders, gels and pastes.
  • Food colours are used in domestic as well as commercial products.
  • Certain colours and essences are added to ice cream, ice candies, sauces, fruit juices, cold drinks, pickles, jams and jellies.
  • Food colours are often found to be added to packaged meat (chicken, mutton), chilli powder, turmeric, sweets and other similar substances so as to give them a good colour.
  • Food colours are natural as well as artificial.
  • The food colours prepared from seeds, beetroot, flowers and fruit concentrate are natural.
  • Tetrazene, sunset yellow are artificial food colours used extensively.
  • However, over-consumption of artificial food colours can be detrimental to health. Therefore, usage of natural food colours is always good.

Question 3.
Anodizing.
Answer:

  • A protective layer is formed naturally on the surface of aluminium metal by reaction with oxygen in air.
  • In the anodizing process, this layer can be made of the desired thickness.
  • Anodizing is done by electrolysis.
  • Dilute sulphuric acid is taken in the electrolytic cell and the aluminium article is dipped in it as the anode.
  • When an electric current is passed, hydrogen gas is released at the cathode and oxygen gas at the anode.
  • A reaction with oxygen occurs and a layer of hydrated aluminium oxide is formed on the anode, i.e. the aluminium article.
  • This layer can be made attractive by adding colour in the cell during electrolysis.

Answer the following questions:

Question 1.
What are salts? Give their source.
Answer:

  • The ionic compounds which do not contain H+ and OH ions and contain only one kind of cation and anion are called simple salts.
  • For example, Na2SO4, K3PO4, CaCl2.
  • The sea is said to be a rich source of salts of various elements such as chlorine, sodium, magnesium, potassium, calcium, bromine.
  • The important salts found in sea water are:
    (a) Sodium chloride
    (b) Magnesium chloride
    (c) Magnesium sulphate
    (d) Potassium chloride
    (e) Calcium carbonate
    (f) Magnesium bromide

Question 2.
Which are the three kinds of salts depending on their pH value? How are they formed?
Answer:
The three kinds of salts depending on their pH value are:

Neutral salts:
Salt is neutral when its pH value is 7. Such a salt is made from a strong acid and a strong base.

Acidic salts:
The pH value of a salt made from a strong acid and a weak base is less than 7 and it is acidic.

Basic salts:
The pH value of a salt made from a weak acid and strong base is more than 7 and it is basic.

Question 3.
Which is the most used salt? What is its chemical name? How is it formed?
Answer:

  • Table salt, or common salt, which gives a salty taste to food, is the most used of all salts.
  • Its chemical name is Sodium chloride.
  • Sodium chloride is formed by a neutralization reaction between sodium hydroxide and hydrochloric acid.
  • Chemical reaction
  • This is a neutral salt and the pH value of its aqueous solution is 7.

Question 4.
How is bleaching powder obtained?
Answer:

  • Bleaching powder is obtained by the reaction of chlorine gas with slaked lime.
  • Chemical reaction

Question 5.
How is hard water from well converted to soft water?
Answer:

  • The hard water from a well or a bore-well becomes soft on adding washing soda and we come to know this from the lather formed on it.
  • The hardness of water is due to the presence of chlorides and sulphates of calcium and magnesium in it.
  • Na2CO3 is added to it to soften such water and make it suitable for use.
  • The reaction with Na2CO3 causes the formation of insoluble carbonate salts of magnesium and calcium.
  • Chemical reaction
    MgCl2(aq) + Na2CO3(s) → MgCO3(s) + 2NaCl(s) Magnesium Sodium Magnesium Sodium chloride carbonate carbonate chloride

Question 6.
How is washing soda obtained from sodium carbonate?
Answer:

  • Sodium carbonate is a water soluble salt of sodium.
  • Crystalline sodium carbonate, on keeping, loses its water of crystallization readily and a white powder is obtained.
  • This powder is called washing soda.
  • Chemical reaction

Question 7.
How is soap prepared? Why it does not form lather with hard water?
Answer:

  • When oil or animal fat is boiled with an aqueous solution of sodium or potassium hydroxide, sodium or potassium salts of carboxylic acids (fatty acids) are formed.
  • These salts are called soap.
  • When soap is mixed with hard water, calcium and magnesium salts of fatty acids are formed.
  • These being water insoluble, they form a precipitate and that is why lather is not formed.

Question 8.
What are the harmful effects of artificial food colours?
Answer:

  • Food colours added to pickles, jams and sauces contain small quantities of lead and mercury. These can be harmful for those who consume these products on a regular basis.
  • Diseases like ADHD (Attention Deficit Hyperactivity Disorder) can affect children due to excessive consumption of foods with added food colours.

Question 9.
Which is the main source of colour for preparing a natural dye?
Answer:

  • Plants are the main source of colour for preparing a natural dye.
  • Roots, leaves, flowers, bark, fruits, seeds, fungus and pistils are used for making dyes.
  • In Kashmir a very good dye is made from saffron, which is used to dye fibers from which saris, shawls and dresses are made.
  • These are very costly. The use of henna leaves to colour hair is safe for health.

Question 10.
How are artificial colours harmful to us?
Answer:

  • We regularly use artificial colours on Rang Panchami.
  • The red colour used on Rang Panchami is very dangerous.
  • It contains a high proportion of mercury in it.
  • This poses risks like blindness, skin cancer, asthma, itching of the skin, permanent blocking of sweat pores, etc.
  • Therefore, it is necessary that artificial colours are used cautiously.

Question 11.
What are the harmful effects of deodorants?
Answer:

  • Aluminium – Zirconium compounds are the most harmful chemicals in deodorants. Disorders like headache, asthma, respiratory disorders, heart disease are likely to occur without our knowledge.
  • There is a possibility of various skin disorders and also skin cancer due to the aluminium chlorohydrates.

Question 12.
How is a ceramic article made?
Answer:

  • When clay is kneaded in water, shaped and then fired in a kiln at a temperature of 1000 to 1150 °C, a porous ceramic is formed.
  • To overcome the porosity, the fired object is covered with finely ground glass powder suspended in water (glaze) and is then fired again. As a result, the surface of the ceramic becomes shiny and its porosity disappears.

Question 13.
What is porcelain? How is it made?
Answer:

  1. Porcelain is a hard, translucent and white coloured ceramic. It is made by using the white clay called kaolin, found in China. Glass, granite and the mineral feldspar is mixed with kaolin and kneaded with water.
  2. The resulting mixture is shaped and fired in a kiln at a temperature of 1200 to 1450 °C. On firing again after glazing, beautiful articles of porcelain are obtained.

Answer the following questions:

Question 1.
What are the constituents of baking powder? Where is the baking powder used?
Answer:

  • Baking powder consist of 30% sodium bicarbonate, 5-12% monocalcium phosphate and 21-26% sodium aluminium sulphate.
  • Baking powder is a leavening agent and is used for increasing the volume and lightening the texture of baked goods.

Question 2.
Take a piece of coloured cloth. Put some saturated solution of bleaching powder on a small part and observe what changes take place in the colour of the cloth.
Answer:
When bleaching powder is added to a piece of coloured cloth, the fabric looses its colour due to the oxidising reaction of the chlorine present in the bleaching powder.

Answer in detail:

Question 1.
Give the properties and uses of Sodium chloride.
Answer:
Properties and uses of sodium chloride:

  • Common salt is a colourless and crystalline ionic compound. There is no water of crystallization in its crystalline structure.
  • It is a neutral salt, salty in taste.
  • This compound is used for the production of salts like Na2CO3, NaHCO3.
  • When an electric current is passed through a saturated solution of sodium chloride (brine), it is electrolysed and hydrogen gas is released at the cathode while chlorine gas is released at the anode.
  • This method is used for production of chlorine gas. In this method an important basic compound NaOH is formed in the cell.
    2NaCl + 2H2O → 2NaOH + Cl2↑ + H2
  • When salt is heated to a high temperature (about 800 °C), it melts. This is called the fused state of the salt.
  • When fused salt is electrolysed, chlorine gas is released at the anode and liquid sodium metal, at the cathode.

Question 2.
Give the properties and uses of Bleaching Powder.
Answer:
Properties and uses bleaching powder:

  • Bleaching powder is a yellowish-white coloured solid substance.
  • Its chemical name is Calcium oxychloride.
  • It has a strong odour of chlorine gas.
  • It is used for disinfection of drinking water at the water works and the water in the swimming pool.
  • It is used for bleaching of cloth.
  • It is used for disinfection by the road side and garbage sites.
  • Dilute sulphuric acid and dilute hydrochloric acid react rapidly with bleaching powder to release chlorine gas completely.
    CaOCl2 + H2SO4 → CaSO4 + Cl2 ↑ + H2O CaOCl2 + 2HCl → CaCl2 + Cl2 ↑ + H2O
  • Calcium oxychloride reacts slowly with carbon dioxide to form calcium carbonate and chlorine.
    CaOCl2 + CO2 → CaCOs + Cl2

Question 3.
Explain with neat labelled diagram the nature of radioactive radiation.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 2
Answer:

  • When radioactive radiations are allowed to pass through two oppositely charged plates they get separated. This method was introduced by Rutherford in 1902.
  • Rutherford and Willard studied the radiation emitted by radioactive substances.
  • For this purpose, the rays were allowed to pass through an electrical field and a photographic plate was held in their path.
  • It was found that the radiation was divided into three types.
  • One type of radiation deviated slightly towards the negatively charged plate, while the second type of radiation deviated substantially towards the positively charged plate.
  • However, the third type of radiation did not deviate at all in the electrical field.
  • The rays which deviated slightly toward negatively charged plate are called alpha rays.
  • Those which deviate substantially towards the positively charged plate are called beta rays and those which did not deviate at all are called gamma rays.

Question 4.
Give the characteristics of alpha, beta and gamma rays.
Answer:
Characteristics of alpha, beta and gamma rays are as given in the table.
Maharashtra Board Class 9 Science Solutions Chapter 14 Substances in Common Use 3

Question 5.
Give the uses of radioactive isotopes in Medical science.
Answer:
Medical science:

  • Polycythemia: The red blood cell count increases in the disease polycythemia. Phosphorus- 32 is used in its treatment.
  • Bone cancer: Strontium-89, strontium-90, samarium-153 and radium-223 are used in the treatment of bone cancer.
  • Hyperthyroidism: Enlargement of thyroid gland, weight loss in spite of appetite, insomnia are the symptoms of hyperthyroidism.
  • It occurs due to overproduction of hormones by the thyroid gland. Iodine-123 is used in the treatment of hyperthyroidism.
  • Tumour detection: Boron-10, iodine-131, cobalt-60 are used in the treatment of brain tumour, while arsenic-74 is used in detection of small tumours in the body.

Question 6.
What are the hazards of radioactive substances and radiation?
Answer:

  • The central nervous system is affected by radioactive radiations.
  • Hereditary defects are generated by bombardment of radiation on D.N.A in the body.
  • Radioactive radiation can penetrate the skin, and causes diseases like skin cancer, leukemia.
  • The radiative pollutants created due to explosions enter the body through air and it is difficult to control them.
  • The radioactive pollutants released in the sea enter the bodies of fishes and through them enter the human body.
  • The radioactive paint on the watch can cause cancer.
  • The radioactive isotopes strontium-90 can enter the body through plants, fruits, flowers, cereals, milk, etc. and cause diseases like bone cancer, leukemia.

Question 7.
Why are deodorant used? Give their types and content.
Answer:

  • Body odour is caused by the bacterial decomposition of the sweat. A deodorant is used to prevent this odour.
  • Deodorants contain parabens (methyl, ethyl, propyl, benzyl and butyl) and also alcohol in large proportions. Aluminium compounds and silica are also used.
  • Types of deodorants are :
    (a) Ordinary deo: It contains a smaller proportion of aluminium. It decreases the odour of the sweat.
    (b) Antiperspirant deo : This decreases the extent of sweating. It contains about 15% of aluminium chlorohydrate. It clogs the sweat pores on the skin.
    (c) Clinical deo : Some people sweat heavily and it has harmful effects on the skin. Clinical deo is meant for such people. It contains 20 to 25% aluminium. It is used during the night.

Question 8.
Explain how powder coating is done.
Answer:

  • Powder coating is a method of applying a layer harder than paint on the surface of an iron object to prevent rusting.
  • In this method, a polymer resin, a pigment and some other ingredients are melt, mixed, cooled and ground into a uniform powder.
  • This powder is sprayed on the polished metal surface by electrostatic spray deposition (ESD).
  • In this method, the particles of the powder are given an electrostatic charge due to which a uniform layer of the powder sticks to the metal surface.
  • Then the object is heated in the oven along with the coating.
  • A chemical reaction occurs in the layer, resulting in the formation of long cross-linked polymeric chains.
  • This powder coating is highly durable, hard and attractive.
  • Powder coating can be done on plastic and medium density fibre (MDF) board in day to day use as well.

Balbharati Maharashtra State Board 9th Std Science Textbook Solutions 

Laws of Motion Class 9 Science Chapter 1 Questions And Answers Maharashtra Board

Std 9 Science Chapter 1 Laws of Motion Question Answer Maharashtra Board

Balbharti Maharashtra State Board Class 9 Science Solutions Chapter 1 Laws of Motion Notes, Textbook Exercise Important Questions and Answers.

Class 9 Science Chapter 1 Laws of Motion Question Answer Maharashtra Board

Class 9 Science Chapter 1 Laws of Motion Textbook Questions and Answers

1. Match the first column with appropriate entries in the second and third columns and remake the table.
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 1

2. Clarify the differences

A. Distance and displacement
Answer:

DistanceDisplacement
(i) Distance is the length of the actual path travelled by an object.
(ii) It is a scalar quantity.
(iii) It is either equal to or greater than displacement.
(iv) Distance travelled is always positive.
(i) Displacement is the minimum distance between the starting and finishing points.
(ii) It is a vector quantity.
(iii) It is either equal to or less than distance.
(iv) Displacement may be positive or negative or zero.

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

B. Uniform and non-uniform motion.
Answer:

Uniform motionNon-uniform motion
(i) If an object covers equal distances in equal intervals of time it is said to be in uniform motion.
(ii) Distance – time graph for uniform motion is a straight line.
(iii) In uniform motion, acceleration is zero.
(i) If an object moves unequal distances in equal intervals of time, its motion is said to be non­uniform.
(ii) Distance – time graph for non-uniform motion is not a straight line.
(iii) In non-uniform motion acceleration is non-zero.

3. Complete the following table.
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 2

4. Complete the sentences and explain them.

a. The minimum distance between the start and finish points of the motion of an object is called the ……….. of the object.
b. Deceleration is ………………………. acceleration
c. When an object is in uniform circular motion, its ………………………. changes at every point.
d. During collision ………………………. remains constant.
e. The working of a rocket depends on Newton’s ………………………. law of motion.

5. Give scientific reasons.

a. When an object falls freely to the ground, its acceleration is uniform.
Answer:

  • When the body falls freely to the ground, there are equal changes in velocity of the body in equal intervals of time.
  • Thus the acceleration of the body is constant, and it possesses uniform acceleration.

b. Even though the magnitudes of action force and reaction force are equal and their directions are opposite, their effects do not get cancelled.
Answer:

  • Action and reaction forces act on different bodies.
  • They don’t act on the same body, hence they cannot cancel each other’s effect.
  • Hence, even though the magnitudes of action force and reaction force are equal, they do not cancel each other.

c. It is easier to stop a tennis ball as compared to a cricket ball, when both are traveling with the same velocity.
Answer:

  • Momentum of an object depends on its mass as well as its velocity.
  • Cricket ball is heavier than a tennis ball. Although they are thrown with the same velocity, cricket ball has more momentum than a tennis ball.
  • The force required to stop a cricket ball is more than a tennis ball.
  • Hence it is easier to stop a tennis ball than a cricket ball moving with same velocity.

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

d. The velocity of an object at rest is considered to be uniform.
Answer:

  • When a body is at rest there is no change in velocity.
  • A body with constant velocity is said to be in uniform motion.
  • Hence, the state of rest is an example of uniform motion.

6. Take 5 examples from your surroundings and give an explanation based on Newton’s laws of motion.

7. Solve the following examples.

a) An object moves 18 m in the first 3 s, 22 m in the next 3 s and 14 m in the last 3 s. What is its average speed? (Ans: 6 m/s)
Answer:
Given:
Total distance (d) = 18 + 22 + 14 = 54 m
Total time taken (t) = 3 + 3 + 3 = 9 sec
To find:
Average speed = ?
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 3

The object moves with an average speed of 6 m/s.

b) An object of mass 16 kg is moving with an acceleration of 3 m/s2. Calculate the applied force. If the same force is applied on an object of mass 24 kg, how much will be the acceleration? (Ans: 48 N, 2 m/s2)
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 4

The force acting on the 1 body is 48 N and the acceleration of the 2” body is 2 m/s2

c) A bullet having a mass of 10 g and moving with a speed of 1.5 m/s, penetrates a thick wooden plank of mass 90 g. The plank was initially at rest. The bullet gets embedded in the plank and both move together. Determine their velocity. (Ans: 0.15 m/s)
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 5
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 6
The plank embedded with the bullet moves with a velocity of 0.15 m/s.

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

d) A person swims 100 m in the first 40 s, 80 m in the next 40 s and 45 m in the last 20 s. What is the average speed? (Ans: 2.25 m/s2)

Answer:
Given:
Total distance (d) = 100 + 80 + 45 = 225 m
Total time taken (t) = 40 + 40 + 20 = 100 sec
To find:
Average speed =?
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 7
The person swims with an average speed of 2.25 m/s.

Class 9 Science Chapter 1 Laws of Motion Intext Questions and Answers

(i) Who will take less time to reach the school and why?
Answer:
Prashant will take less time as the path followed by him is the shortest.
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 8

(a) Every morning, Swaralee walks round the edge of a circular field having a radius of 100 m. As shown in figure (a), if she starts from the point A and takes one round, how much distance has she walked and what is her displacement?
Answer:
Radius (r) = 100 m
Distance covered = Circumference of the circle
= 2 nr
= 2 x 3.14 x 100
= 628 m
Displacement = 0 m (Shortest distance between initial and final position is zero)

(b) If a car, starting from point P, goes to point Q (see figure 1.9) and then returns to point P, how much distance has it travelled and what is its displacement?
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 9
Answer:
Distance covered = PQ + QP
= 360 + 360
= 720 m
Displacement = 0 m (The shortest distance between initial and final position is zero)

Class 9 Science Chapter 1 Laws of Motion Additional Important Questions and Answers

(A) Choose and write the correct option:

Laws Of Motion Class 9 Questions And Answers Maharashtra Board Question 1.
The displacement that occurs in unit time is called …………….. .
(a) displacement
(b) distance
(c) velocity
(d) acceleration
Answer:
(c) velocity

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Laws Of Motion Class 9 Maharashtra Board Exercise Answers  Question 2
The unit of velocity in the SI system is …………….. .
(a) cm/s
(b) rn/s2
(c) um/s2
(d) rn/s
Answer:
(d) m/s

Laws Of Motion Class 9 Maharashtra Board  Question 3.
v2 = u2 + 2as is the relation between and …………….. .
(a) speed and velocity
(b) distance and acceleration
(c) displacement and velocity
(d) speed and distance
Answer:
(c) displacement and velocity

Class 9 Science Notes Chapter 1 Laws Of Motion Question 4.
…………….. is the relation between displacement and time.
(a) v = u + at
(b) v2 = u2 + 2as
(c) s = ut + 1/2 at2
(d) v = u + 2as
Answer:
(c) s = ut + 1/2 at2

Class 9 Science Chapter 1 Laws Of Motion Question Answer Question 5.
The force necessary to cause an acceleration of 1 m/s2 in an object of mass 1 kg is called …………….. .
(a) 1 dyne
(b) 1 m/s
(c) 1 Newton
(d) 1 cm/s
Answer:
(c) 1 Newton.

9th Science Chapter 1 Laws Of Motion Question 6.
Even if the displacement of an object is zero, the actual distance traversed by it …………….. .
(a) may not be zero.
(b) will be zero
(c) will be constant
(d) will be infinity
Answer:
(a) may not be zero

Question 7.
If the velocity changes by equal amounts in equal time intervals, the object is said to be in …………….. .
(a) uniform acceleration
(b) uniform velocity
(c) non-uniform acceleration
(d) non-uniform motion
Answer:
(a) uniform acceleration

Question 8.
If an object is moving with a uniform velocity …………….. .
(a) its speed remains the same, but direction of motion changes
(b) its speed changes but direction of motion is same
(c) its speed and direction both change
(d) its speed and direction both remain the same
Answer:
(d) its speed and direction both remain the same

Question 9.
is an example of positive acceleration.
(a) A stone is thrown vertically upwards
(b) A stone falls freely towards the earth
(c) Brakes are applied by the truck driver
(d) The train arriving at the station
Answer:
(b) a stone falls freely towards the earth

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Question 10.
An object continues to remain at rest or in a state of uniform motion along a straight line unless an …………….. acts on it.
(a) internal imbalanced force
(b) external unbalanced force
(c) internal balanced force
(d) external balanced force
Answer:
(b) external unbalanced force

Question 11.
The …………….. is proportional to the applied force and it occurs in the direction of the force.
(a) change of momentum
(b) rate of change of velocity
(c) change of velocity
(d) rate of change of momentum
Answer:
(d) rate of change of momentum

Question 12.
…………….. is a relative concept.
(a) Motion
(b) Direction
(c) Power
(d) Acceleration
Answer:
(a) Motion

Question 13.
A body is said to be in motion if it changes its …………….. with respect to its surroundings.
(a) position
(b) direction
(c) speed
(d) force
Answer:
(a) position

Question 14.
A body is said to be at …………….. if it does not change its position with respect to its surroundings.
(a) Motion
(b) Rest
(c) Gravity
(d) Force
Answer:
(b) Rest

Question 15.
…………….. is the length of the actual path travelled by an object in motion while going from one point to another.
(a) Distance
(b) Displacement
(c) Speed
(d) Velocity
Answer:
(a) Distance

Question 16.
The distance covered by a body in unit time is called its …………….. .
(a) velocity
(b) speed
(c) displacement
(d) rest
Answer:
(b) speed

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Question 17.
S.I. unit of speed is …………….. and in C.G.S unit it is …………….. .
(a) m/s and cm/s
(b) km/s and cm/s
(c) m/s and mm/s
(d) m/s and nm/s
Answer:
(a) m/s , cm/s

Question 18.
The distance travelled in a particular direction by an object in unit time is called its …………….. .
(a) velocity
(b) speed
(c) displacement
(d) rest
Answer:
(a) velocity

Question 19.
Units of speed and velocity are the
(a) Same
(b) Different
(c) Greater than each other
(d) Unequal
Answer:
(a) same

Question 20.
…………….. . is related to distance, while …………….. is related to displacement.
(a) Gravity and magnetism
(b) Speed and force
(c) Speed and velocity
(d) Motion and rest
Answer:
(c) Speed, velocity

Question 21.
If an object covers equal distances in equal time intervals, it is said to be moving with …………….. speed.
(a) Uniform
(b) Non uniform
(c) Changing
(d) Random
Answer:
(a) uniform

Question 22.
If an object covers unequal distances in equal time Intervals, it is said to be moving with speed.
(a) Uniform
(b) Non uniform
(c) Changing
(d) Random
Answer:
(b) non uniform

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Question 23.
The rate of change of velocity is called
(a) Speed
(b) Acceleration
(c) Velocity
(d) Rest
Answer:
(b) acceleration

Question 24.
Speed of light in dry air is …………….. m/s.
(a) 3 x 107
(b) 3 x 108
(c) 3 x 109
(d) 3 x 103
Answer:
(b) 3 x 108

Question 25.
When velocity of a body increases, its acceleration is …………….. .
(a) Negative
(b) Zero
(c) Positive
(d) Equal
Answer:
(c) positive

Question 26.
When velocity of a body decreases, its acceleration is …………….. .
(a) Negative
(b) Zero
(c) Positive
(d) Equal
Answer:
(a) negative

Question 27.
Negative acceleration is also called or
(a) Deceleration or retardation
(b) Deceleration or acceleration
(c) acceleration or retardation
(d) Zero
Answer:
(a) deceleration or retardation

Question 28.
In case of motion, object travels equal …………….. in equal intervals of time.
(a) Uniform, distance
(b) Non-Uniform, distance
(c) Uniform, displacement
(d) Uniform, displacement
Answer:
(a) uniform, distances

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Question 29.
Motion of an object was studied by …………….. .
(a) Sir Albert Einstein
(b) Sir Thomas Edison
(c) Sir Isaac Newton
(d) Sir Ravindranath Tagore
Answer:
(c) Sir Issac Newton

Question 30.
When an object moves in a circular path with uniform speed, its motion is …………….. motion.
(a) Non uniform circular
(b) Random circular
(c) Uniform circular
(d) Uniform linear
Answer:
(c) uniform circular

Question 31.
When a coin moves along a circular path, the direction of its motion at every point is …………….. .
(a) Circular
(b) Concave
(c) Tangential
(d) Convex
Answer:
(c) tangential

Question 32.
For all uniformly accelerated motions, the velocity-time graph is a …………….. .
(a) Curved line
(b) Straight line
(c) Negative line
(d) Positive line
Answer:
(b) straight line

Question 33.
In the distance-time graph, the slope of the straight line indicates …………….. .
(a) Acceleration
(b) Velocity
(c) Speed
(d) Rest
Answer:
(b) velocity

Question 34.
The first equation of motion gives relation between …………….. and time.
(a) Acceleration
(b) Velocity
(c) Speed
(d) Rest
Answer:
(b) velocity

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Question 35.
Newton’s first law explains the phenomenon of
(a) Rest
(b) Inertia
(c) Speed
(d) Velocity
Answer:
(b) inertia

Question 36.
…………….. cause a change in the state of an object at rest or in uniform motion.
(a) Balanced forces
(b) Zero forces
(c) Unbalanced forces
(d) None of them
Answer:
(c) Unbalanced forces

Question 37.
To describe an object’s momentum, we must specify its …………….. and …………….. .
(a) Mass and displacement
(b) Mass and direction
(c) Mass and velocity
(d) Mass and acceleration
Answer:
(c) mass and velocity

Question 38.
…………….. is the product of mass and velocity of an object.
(a) Speed
(b) Acceleration
(c) Momentum
(d) Force
Answer:
(c) Momentum

Question 39.
The rate of change of momentum is proportional to the applied …………….. .
(a) Balanced force
(b) Unbalanced force
(c) Mass
(d) Velocity
Answer:
(b) unbalanced force

Question 40.
S.I. unit of momentum is
(a) kg cm/s
(b) kg m/s
(c) gm/s
(d) m/s
Answer:
(b) kg m/s

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Question 41.
…………….. is always conserved in a collision.
(a) Force
(b) Power
(c) Speed
(d) Total momentum
Answer:
(d) Total momentum

Question 42.
When a bullet is fired from the gun, the gun moves in backward direction. This motion is called as …………….. .
(a) Momentum
(b) Velocity
(c) Acceleration
(d) Recoil
Answer:
(d) Recoil

Question 43.
In CGS system, the unit of force is …………….. .
(а) Newton
(b) Watt
(c) Horse power
(d) Dyne
Answer:
(d) Dyne.

 (B) 1. Find the odd man out:

Question 1.
Displacement, Force, Momentum, Mass
Answer:
Mass

Question 2.
Speed, Power, Energy, Acceleration
Answer:
Acceleration

Question 3.
Newton’s 1st law, Newton’s 2nd law, Newton’s 3rd law, Kepler’s laws of motion
Answer:
Newton’s 3rd law

(B) 2. Find out the correlation

Question 1.
Speed zero: Body at rest :: Negative acceleration : Retardation
Answer:
Retardation

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Question 2.
Displacement : Vector quantity :: Distance : Scalar quantity
Answer:
Vector quantity

Question 3.
When body comes to rest at the end of the motion : Final velocity is zero :: When body is at rest at the starting of motion : Initial velocity is zero
Answer:
Initial velocity is zero

Question 4.
Uniform circular motion: Displacement is zero :: Uniform velocity : Acceleration is zero
Answer:
Displacement is zero

Question 5.
Inertia : Newton’s 1st law :: Rate of change of momentum : Newton’s 2nd law
Answer:
Newton’s 2nd law

Question 6.
Balanced force : Body at rest :: Force equation : Mass x acceleration
Answer:
Body at rest

(B) 3. Distinguish between:

Question 1.
Positive acceleration and Negative acceleration
Answer:

Positive accelerationNegative acceleration
(i) When the velocity of a body increases, acceleration is said to be positive acceleration.(i) When the velocity of a body decreases, acceleration is said to be negative acceleration.

Question 2.
Scalar quantity and Vector quantity
Answer:

Scalar quantityVector quantity
(i) Scalar quantities are physical quantities having magnitude only.(i) Vector quantities are physical quantities having both magnitude and direction.

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Question 3.
Balanced force and Unbalanced force
Answer:

Balanced forceUnbalanced force
(i) Balanced force keeps the body at rest.(i) Balanced force keeps the body at rest.

(B) 4. State whether the following statements are true or false:

Question 1.
The velocity of a body is given by the distance covered by it in unit time in a given direction.
Answer:
True

Question 2.
Displacement is a scalar quantity.
Answer:
False

Question 3.
Uniform acceleration means that the body is moving with a uniform velocity.
Answer:
False

Question 4.
The direction of acceleration can be opposite to that of velocity.
Answer:
True

Question 5.
Work is a vector quantity.
Answer:
False

Question 6.
Displacement is always greater than distance.
Answer:
False

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Question 7.
The distance and displacement are equal only if, motion is along a straight path.
Answer:
True

Question 8.
If an object experiences acceleration, a force is acting on it.
Answer:
True

Question 9.
A train pulling out from a station is in uniform motion.
Answer:
False

Question 10.
If a bus in motion is suddenly stopped, the passengers fall backwards.
Answer:
False

Question 11.
If a single force is acting on an object, it will always accelerate.
Answer:
True

Question 12.
In circular motion, direction of motion is tangential.
Answer:
True

Question 13.
The inertia of a body is measured in terms of its mass.
Answer:
True

(B) 5. Name the following:

Question 1.
The scientist who summarized motion in a set of equations of motion.
Answer:
Isaac Newton

Question 2.
Motion of an object along a circular path with uniform speed.
Answer:
Uniform circular motion

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Question 3.
What is the backward motion of the gun called?
Answer:
Recoil

Question 4.
The motion in which the object covers equal distance in equal intervals of time.
Answer:
Uniform motion

Question 5.
S. I. unit of acceleration.
Answer:
m/s2

Question 6.
CGS unit of momentum
Answer:
g cm/s

(B) 6. Answer the following in one sentence:

Question 1.
When is acceleration said to be positive?
Answer:
When the velocity of a body increases, acceleration is said to be positive acceleration.

Question 2.
What is negative acceleration?
Answer:
When the velocity of a body decreases, acceleration is said to be negative acceleration.

Question 3.
What is the direction of velocity of an object performing uniform circular motion?
Answer:
The direction of velocity is along the tangential direction to its position.

Question 4.
Give the mathematical expression used to determine velocity of an object moving with uniform circular motion.
Answer:
is the expression used to determine velocity of a body moving with uniform circular motion.

Question 5.
What kind of force keeps the body at rest?
Answer:
Balanced force keeps the body at rest.

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Question 6.
Which law of motion gives the measure of force?
Answer:
Newton’s second law of motion gives the measure of force.

Question 7.
What are vectors and scalars?
Answer:
Scalars are physical quantities having magnitude only whereas, vectors are physical quantities having both magnitude and direction.

Question 8.
Which of the quantities distance, speed, velocity, time and displacement are scalars and which are vectors?
Answer:
Distance, speed and time are scalars displacement and velocity are vectors.

Give formula:

Question 1.
Force =
Answer:
Mass x Acceleration = ma

Question 2.
Final velocity (v) =
Answer:
Initial Velocity + (Acceleration x Time) = u + at

Question 3.
Displacement (s) =
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 10

Question 4.
Final velocity2 (v2) =
Answer:
Initial Velocity2 + 2 x Acceleration x Displacement = u2 + 2as

Question 5.
velocity of an object moving with uniform circular motion =
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 11

Give scientific reasons:

Question 5.
Motion is relative.
Answer:

  • The motion of an object depends on the observer, hence a body may appear moving for one person and at the same time at rest for another one.
  • Hence, motion is relative.

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Question 6.
Newton’s first law of motion is called as law of inertia.
OR
Heavier objects offer more inertia.
Answer:

  • Inertia is related to the mass of the object.
  • As mass is the quantity of matter in a body, we need to exert more force to push a heavier body.
  • Hence heavier objects offer more inertia.
  • As the same property is described by Newton’s first law of motion, it is called as Law of Inertia.

Question 7.
The launching of a rocket is based on Newton’s third law of motion.
Answer:

  • Newton’s third law of motion states that ‘Every action force has an equal and opposite reaction force which acts simultaneously.’
  • When the fuel in a rocket is ignited, it bums as a result of chemical reaction.
  • The exhaust gases escape with a great force in the backward direction.
  • It exerts an equal and opposite reaction force on the rocket, due to which the rocket moves in the forward direction.
  • Thus, the principle of launching of rocket is based on Newton’s third law of motion.

Solve the following numerical:

Question 1.
An athlete is running on a circular track. He runs a distance of 400 m in 25 s before returning to his original position. What is his average speed and velocity?
Answer:
Given:
Total distance travelled = 400 m
Total displacement = 0, as he returns to his original position.
Total time = 25 seconds.
To find:
Average speed = ?
Average velocity = ?
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 12
The athlete runs at an average speed of 16 m/s and velocity 0 m/s.

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Question 2.
An aeroplane taxies on the runway for 30 s with an acceleration of 3.2 m/s2 before taking off. How much distance would it have covered on the runway?
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 13
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 14
The distance covered on the runway is 1440 m.

Question 3.
A kangaroo can jump 2.5 m vertically. What must be the initial velocity of the kangaroo?
Answer:
Given:
a = 9.8 m/s2, s = 2.5 m, v = 0,
To find:
u = ?
Formula:
v2 = u2 + 2as
Solution:
v2 = u2 + 2as
02 = u2 + 2 x (-9.8) (2.5) : (Negative sign is used as the acceleration is in the direction opposite to that of velocity.)
0= u2 – 49 u2
= 49 u
= 7 m/s

The initial velocity of the kangaroo must be 7 m/s.

Question 4.
A motorboat starts from rest and moves with uniform acceleration, if it attains the velocity of 15 m/s in 5s, calculate the acceleration and the distance travelled in that time.
Answer:
Given:
Initial velocity, u = 0
Final velocity, v = 15 m/s time, t = 5 s.
To find:
Acceleration (a) = ?
Distance (s) = ?
Solution:
From the first equation of motion
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 15
From the second equation of motion, the distance covered will be
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 16
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 17

The acceleration is 3 m/s2 and distance travelled is 37.5 m.

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Question 5.
The mass of a cannon is 500 kg and it recoils with a speed of 0.25 m/s. What is the momentum of the cannon?
Answer:
Given:
mass of the cannon = 50 kg
recoil speed = 0.25 m/s
To find:
Momentum = ?
Formula:
Momentum = m x v
Solution:
Momentum = m x v
= 500 x 0.25
= 125 kg m/s

The momentum of cannon is 125 kg m/s

Answer the following in short:

Question 1.
Explain the three different ways to change the velocity.
Answer:
As velocity is related to speed and direction, it can be changed by :

  • Changing the speed while keeping the direction constant.
  • Changing direction while keeping speed constant.
  • Changing both speed as well as direction of motion.

Question 2.
Explain what is positive, negative and zero acceleration.
Answer:

  • Positive Acceleration: When the velocity of an object increases, the acceleration is positive. In this case, the acceleration is in the direction of velocity.
  • Negative Acceleration: When the velocity of an object decreases with time, it has negative acceleration. Negative acceleration is also called deceleration. Its direction is opposite to the direction of velocity.
  • Zero Acceleration: If the velocity of the object does not change with time, it has zero acceleration.

Question 3.
What inference do we draw from the velocity-time graph for a uniformly accelerated motion?
Answer:

  • From velocity-time graph we can infer whether velocity changes by equal amounts in equal intervals of time or not.
  • Thus, for all uniformly accelerated motion, the velocity – time graph is a straight line and slope of the line gives the acceleration.
  • For non-uniformly accelerated motion, velocity-time graph can have any shape according to variation in velocity with respect to time.

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Question 4.
State the three equations of motion and give the relationship explained by them.
Answer:

  • v = u + at: This is the relation between velocity and time.
  • s = ut + 1/2 at2 : This is the relation between displacement and time
  • v2 = u2 + 2as : This is the relation between displacement and velocity.

Question 5.
What are the implications of Newton’s Third Law of motion?
Answer:

  • Action and reaction are terms that express force.
  • These forces act in pairs. One force cannot exist by itself.
  • Action and reaction forces act simultaneously.
  • Action and reaction forces act on different objects. They do not act on the same object and hence cannot cancel each other’s effect.

Question 6.
Explain recoil and recoil velocity. Derive its expression.
Answer:

  • Let us consider the example of a bullet fired from a gun. When a bullet of mass nij is fired from a gun of mass m2, its velocity becomes v2, and its momentum becomes m^. Before firing the bullet, both the gun and the bullet are at rest. Hence, total initial momentum is zero.
  • According to Newton’s third law of motion, the total final momentum also has to be zero. Thus, the forward-moving bullet causes the gun to move backward after firing.
  • This backward motion of the gun is called its recoil. The velocity of recoil, v2 is such that,
    Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 19

Complete the flow chart:

(1) Types of force and their effects
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 20

(2) Newton’s laws
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 21

Distinguish between:

Question 1.
Speed and velocity.
Answer:

SpeedVelocity
(i) Speed is the distance covered by a body in unit time.
(ii) It is a scalar quantity.
(iii) Speed is equal to or greater than velocity.
(iv) Speed = distance/time
(v) It is always positive or zero but never negative.
(i) The displacement that occurs in unit time is called velocity.
(ii) It is a vector quantity.
(iii) Velocity is equal to or less than speed.
(iv) Velocity = displacement/time
(v) It may be positive, Zero or negative.

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Question 2.
Balanced force and unbalanced force.
Answer:

Balanced forceUnbalanced force
(i) Two equal forces applied on a body in the opposite direction.
(ii) This force does not change the state of rest or the state of uniform motion
(i) Two unequal forces applied on a body.
(ii) This force can change the state of rest or the state of uniform motion of a body in a straight line.

Give examples:

Question 1.
Scalar quantities
Answer:
Time, Volume, Speed, Mass, Temperature, Distance, Entropy, Energy, and Work

Question 2.
Vector quantities
Answer:
Acceleration, Velocity, Momentum, Force, and Weight

Answer the following questions:

Observe the figure and answer the questions:

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 22

(a) Measure the distance between points A and B in different ways as shown in figure (I).
Answer:
Distances measured may be of different lengths depending on the path taken.

(b) Now measure the distance along the dotted line. Which distance is correct according to you and why?
Answer:
Dotted line shows the shortest way of reaching from A to B.

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

(c) Observe the following figures. If you increase the number of sides of the polygon and make it infinite, how many times will you have to change the direction? What will be the shape of the path?
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 23
Answer:
If we increase the number of sides of the polygon and make it infinite, then we will have to change the direction an infinite number of times. The shape of the path thus obtained will be a circle.

Observe the figure and answer the questions

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 24

Question 1.
What will be the effect on the velocity of the motorcycle if its speed increases or decreases, but its direction remains unchanged?
Answer:
If the speed is increased the velocity of the motorcycle will increase and if the speed is decreased the velocity of the motorcycle will decrease

Question 2.
In case of a turning on the road, will the velocity and speed be same?
Answer:
As speed is scalar quantity while velocity is vector quantity so by turning velocity will change while speed remains same

Question 3.
If, on a turning, we change the direction as well as the speed of the motorcycle, what will be the effect on its velocity?
Answer:
Its velocity will change because velocity depends on speed as well as direction and here both speed and direction are changed.

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Numerical:

Question 1.
A person travels a distance of 72 km in 4 hours. Calculate average speed in m/s.
Answer:
Given :
Total distance (d)
= 72 km
= 72×1000
= 72000 m

Total time taken (t)
= 4 hours
= 4 x 3600 (v lhr = 3600 sec)
= 14400 s

To find:
Average speed = ?
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 25
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 26
The person travels with average speed of 5 m/s

Question 2.
balls have masses of 50 gm and 100 gm and they are moving along the same line in the same direction with velocities of 3 m/s and 1.5 m/s respectively. They collide with each other and after the collision, the first ball moves with a velocity of 2.5 m/s. Calculate the velocity of the other ball after collision.
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 27
Final velocity of second ball after collision is 1.75 m/s.

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Write laws and explain write implications:

Question 1.
Newton’s third law of motion
Answer:
‘Every action force has an equal and opposite reaction force which acts simultaneously’.

  • Action and reaction are terms that express force.
  • These forces act in pairs. One force cannot exist by itself.
  • Action and reaction forces act simultaneously.
  • Action and reaction forces act on different objects. They do not act on the same object and hence cannot cancel each other’s effect.

Question 2.
Explain Newton’s second law of motion and derive the formula.
Answer:
Newton’s second law explains about change in momentum. It states that The rate of change of momentum is proportional to the applied force and the change of momentum occurs in the direction of the force.

Suppose an object of mass ‘m’ has an initial velocity ‘u. When a force ‘F’ is applied in direction of its velocity for time ‘t’, its velocity becomes ‘y’. Then, the total initial momentum of the body = ‘mu’. Its final momentum after time t = ‘mv’.

So, the rate of change of momentum
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 28

Hence by Newtons second la of motion, 4he rate of change of momentum is proportional to the applied force.
∴ ma ∝ F
∴ F ∝ ma
∴ F ∝ kma (k = Constant of proportionaLity and value is 1).
∴ F = ma

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Question 3.
State the law of conservation of momentum and derive the formula.
Answer:

Let mass of object A and B be m1 and m1 respectively
Let their initial velocity be u1 and u2 Let their final velocity be v1 and v2

We know,
P = mv
Let their initial momentum be m1u1 and m2 u2
Let their final momentum be m1v1 and m2v2

Total initial momentum = (m1u1 + m2u2)
Total final momentum = (m1v1 + m2v2)

If F2 is the force that acts on object B,
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 29

i.e. The magnitude of total of total final momentum = the magnitude of total initial momentum

Complete the paragraph:

Question 1.
Moving Objects
Answer:
‘Distance’ is the length of the actual path travelled by an object in motion while going from one point to another, whereas displacement is the minimum distance between the starting and finishing points. The displacement that occurs in unit time is called velocity. The units of speed and velocity are the same. In the SI system, the unit is m/s while in the CGS system; it is cm/s. Speed is related to distance while velocity is related to the displacement. If the motion is along a straight line, the values of speed and velocity are the same, otherwise they can be different. The first scientist to measure speed as the distance /time was Galileo. The speed of sound in dry air is 343.2 m/s while the speed of light is about 3 x 108 m/s. The speed of revolution of the earth around the sun is about 29770 m/s.

Question 2.
Types of motion
Answer:
If an object covers unequal distances in equal time intervals, it is said to be moving with non-uniform speed. For example the motion of a vehicle being driven through heavy traffic. If an object covers equal distances in equal time intervals, it is said to be moving with uniform speed. The rate of change of velocity is called acceleration. If the velocity changes by equal amounts in equal time intervals, the object is said to be in uniform acceleration. If the velocity changes by unequal amounts in equal time intervals, the object are said to be non-uniform acceleration. The speed of the tip is constant, but the direction of its displacement and therefore, its velocity is constantly changing. As the tip is moving along a circular path, its motion is called uniform circular motion.

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Question 3.
Newton’s laws and conservation of momentum
Answer:
An object continues to remain at rest or in a state of uniform motion along a straight line unless an external unbalanced force acts on it. The rate of change of momentum is proportional to the applied force and the change of momentum occurs in the direction of the force. Momentum has magnitude as well as direction. Its direction is the same as that of velocity. In SI system, the unit of momentum is kg m/s, while in CGS system, it is g cm/s. If an unbalanced force applied on an object causes a change in the velocity of the object, then it also causes a change in its momentum.

The force necessary to cause a change in the momentum of an object depends upon the rate of change of momentum. Every action force has an equal and opposite reaction force which acts simultaneously. As the mass of the gun is much higher than the mass of the bullet, the velocity of the gun is much smaller than the velocity of the bullet. The magnitude of the momentum of the bullet and that of the gun are equal and their directions are opposite. Thus, the total momentum is constant. Total momentum is also constant during the launch of a rocket.

Answer the following in detail:

Question 1.
What is speed? State its units and types. Explain instantaneous speed and average speed.
Answer:

The speed of a body is the distance travelled in unit time. The units of speed in CGS system is cm/s and in SI system is m/s.
There are two types of speed :

    • Uniform speed : When a body covers equal distance in equal intervals of time throughout its motion, it is said to have uniform speed.
    • Non-uniform or variable speed: When a body covers unequal distance in equal intervals of time it is said to have non-uniform speed.

The speed of the body at any instant is called instantaneous speed. Average speed is the ratio of total distance covered to total time taken.

Question 2.
What is velocity? State its units and types.
Answer:

The velocity of a body is the distance travelled by a body in a particular direction in unit time. Thus, rate of change of displacement is called velocity.

v = s/t
where: s = displacement; t = time taken; v = velocity
(MKS unit: m/s CGS unit: cm/s)
There are two types of velocities :

    • Uniform velocity: If there is equal displacement taking place in equal intervals of time, it is uniform velocity.
    • Non-uniform velocity or variable velocity: If there is unequal displacement in equal intervals of time, it is non-uniform velocity.

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Question 3.
What is acceleration? State its units and types.
Answer:
(i) Acceleration is a rate of change in velocity. It is a vector quantity, \(a=\frac{v-u}{t}\)
where : v = final velocity; u = initial velocity;
a = acceleration
Units of acceleration in SI system is m/s2 and CGS system is cm/s2.

(ii) Types of acceleration: .
(a) Uniform acceleration : If the change in velocity is equal in equal intervals of time, the acceleration is uniform acceleration.
(b) Non-uniform acceleration : If the change in velocity is unequal in equal intervals of time, the acceleration is a non-uniform acceleration.

(iii) Kinds of acceleration:
Positive acceleration : When the velocity of an object goes on increasing, it is said to have Positive acceleration.
Negative acceleration : When the velocity of an object goes on decreasing, it is said to have negative acceleration or retardation or deceleration.
Zero acceleration : If the velocity of the object does not change with time, it has zero acceleration.

Question 4.
Explain Newton’s second law of motion and derive the formula.
Answer:
Newton’s second law explains about change in momentum. It states that ‘The rate of change of momentum is proportional to the applied force and the change of momentum occurs in the direction of the force.’

Suppose an object of mass’m’ has an initial velocity ‘u’. When a force ‘F’ is applied in the direction of its velocity for time’t’, its velocity becomes ‘v’. Then, the total initial momentum of the body = ‘mu’. Its final momentum after time t = ‘mv’.

So, the rate of change of momentum
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 30

Hence by Newton’s second law of motion, the rate of change of momentum is proportional to the applied force.
∴ ma ∝ F
∴ F ∝ ma
∴ F = kma (k = Constant of proportionality and value is 1).
∴ F = ma

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

Question 5.
State the law of conservation of momentum and derive the formula.
Answer:
(i) Let mass of objects A and B be and m2 respectively
Let their initial velocity be m1 and u2
Let their final velocity be V1 and v2

(ii) We know,
P = mv
Let their initial momentum be m1u1 and m2u2
Let their final momentum be m1v1 and m2v2

(iii) Total initial momentum = (m1u1 + m2u2)
Total final momentum = (m1v1 + m2v2)

(iv) If F2 is the force that acts on object B,
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 31
i.e. The magnitude of total final momentum = the magnitude of total initial momentum.

Question 6.
Obtain the equations of motion by graphical method:

(a) Equation for velocity-time relation.
Answer:
Velocity-time graph: shows the change in velocity with time of a uniformly accelerated object. The object starts from the point D in the graph with velocity v. Its velocity keeps increasing and after time t it reaches the point B on the graph.

The initial velocity of the object = u = OD
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 32

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

(b) Equation for displacement-time relation.
Answer:
Suppose that an object is in uniform acceleration ‘a’ and it has covered the distance ‘s’ within time’t’. From the graph the distance covered by the object during time’t’ is given by the area of quadrangle DOEB.
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 33

(c) Equation for displacement-velocity relation.
Answer:
We can determine the distance covered by the object in time t from the area of the quadrangle DOEB. DOEB is a trapezium. So we can use the formula for its area.
Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 34
This is Newton’s third equation of motion.

Read the paragraph and answer the questions:

1. Paragraph

(a) When a bat strikes a ball, the ball exerts an equal and opposite force on the bat. The force : acting on the ball projects it with high velocity, Due to the large mass of bat compared to ball, reaction force on the bat slows down the bat’s motion.
(b) When a bullet is fired from a gun, the gun exerts a force on the bullet in the forward direction. This is the action force. The bullet also exerts an equal force on the gun in the backward direction. This is the reaction force. Due to the large mass of the gun, it j moves only a little distance backward. This backward movement of the gun is called the recoil of the gun.
(c) In a rocket, burning fuel creates a push on the front of the rocket pushing it forward. This creates an equal and opposite push on the exhaust gas backwards.

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

(i) Which of Newton’s law examples are given here?
Answer:
Newton’s 3rd law is stated by the above example

(ii) When a rifle is fired it is pushed back this movement is called what?
Answer:
Movement of rifle getting pushed back after firing is called recoil.

(iii) What does the ball acquire after it gets velocity?
Answer:
The ball acquires momentum after it gets velocity.

(iv) State newton’s 1st law of motion
Answer:
An object continues to remain at rest or in a state of uniform motion along a straight line unless an external unbalanced force acts on it.

(v) Which force is required to produce motion in an object?
Answer:
Unbalanced force is required to produce motion in an object.

2. Paragraph 2
constant velocity. If that velocity is zero, then the object remains at rest. If an external force is applied, the velocity will change because of the force. The second law explains how the velocity of an object changes when it is subjected to an external force. The law defines a force to be equal to changes in momentum (mass times velocity) per change in time. Newton also developed the calculus of mathematics, and the “changes” “expressed in j the second law are most accurately defined in differential forms. (Calculus can also be used to determine the velocity and location variations experienced by an object subjected to an external force.) For an object with a constant mass the second law states that the force F is the product of an objects mass and its acceleration a:
F = m * a
For an external applied force the change in velocity depends on the mass of the object.

A force will cause in velocity; and likewise, a change in velocity will generate a force. The equation works both ways.
The third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal force on object: A. Notice that the forces are exerted on different objects. The third law can be used to explain the generation of lift by a wing and the production of thrust by a jet engine

(i) A chalk kept on the table remains in the position of rest until moved by the teacher. Which law of motion is followed in this situation?
Answer:
Newton’s 1st law is followed in this situation e

(ii) What will happen to momentum if the mass and acceleration both are doubled?
Answer:
If the mass and acceleration both are doubled then the momentum will be increased four times

(iii) What will happen to momentum if the mass and acceleration both are halved?
Answer:
If the mass and acceleration both are doubled then the momentum will be decreased one four times

(iv) A moving stone filled truck collides with a moving car coming from opposite direction. Why is it observed that only the car is pushed backward?
Answer:
A stone filled truck as more mass than a car hence it has more momentum thus it is observed that only the car is pushed backward

Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion

(v) What will happen to the force if the jet engines do not produce enough thrust to push the aeroplane in mid-air?
Answer:
If the jet engines do not produce enough thrust to push the aeroplane in mid-air the force of aeroplane and resistance of air will become balanced thus putting the aeroplane at rest which will result in a crash.

Balbharati Maharashtra State Board 9th Std Science Textbook Solutions

Carbon: An Important Element Class 9 Science Chapter 13 Questions And Answers Maharashtra Board

Std 9 Science Chapter 13 Carbon: An Important Element Question Answer Maharashtra Board

Balbharti Maharashtra State Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element Notes, Textbook Exercise Important Questions and Answers.

Class 9 Science Chapter 13 Carbon: An Important Element Question Answer Maharashtra Board

Class 9 Science Chapter 13 Carbon: An Important Element Textbook Questions and Answers

1. Select the proper option and complete the statements
(single, all, double, ionic, carbon, give and take, hydrogen, multiple, share, most, covalent)

a. A carbon atom forms a ….……………. bond with other atoms. In this bond the two atoms ….electrons.
Answer:
covalent, share

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

b. All the carbon bonds in a saturated hydrocarbon ….……………. electrons.
Answer:
share

c. At least one carbon bond in an unsaturated hydrocarbon is ….…………… .
Answer:
multiple

d. ….……………. is the essential element in all the organic compounds.
Answer:
Carbon

e. The element hydrogen is present in ….. organic compound.
Answer:
all

2. Answer the following questions

a. Why are carbon and its compounds used as fuels?

Answer:
(i) The name ‘carbon’ is derived from Latin word ‘carbo’meaning coal. In the earth’s crust, carbon is present to an extent of approximately 0.27% in the form of carbonate, coal and petroleum. One of the non-crystalline and amorphous form of carbon is coal. Coal is a fossil fuel.

(ii) Peat, lignite, bituminous and anthracite are the four types of coal in the increasing order of their carbon content and heat produced respectively. Charcoal and coke are the other amorphous forms of carbon used as fuel.

(iii) Compounds of carbon such as hydrocarbons consist of carbon and hydrogen and they are easily combustible. For example, methane (CH4) which occurs in natural gas is highly inflammable. It bums by reacting with oxygen to give a bluish flame. In this reaction, 213 Kcal/mol of heat is given out. Methane bums completely.

Chemical reaction:
CH4 + 2O2 → CO2 + 2H2O + Heat

(iv) Thus when hydrocarbons are burnt in air, large amount of heat is evolved with formation of carbon dioxide (CO2) and water (H2O). Due to evolution of heat on combustion, carbon and its compounds are used as fuels.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

b. In which compound forms does carbon occur?
Answer:
Carbon in its combined state exists as various compounds such as:

  • Carbon dioxide and in the form of carbonates such as calcium carbonate, marble, calamine (ZnCO3).
  • Fossil fuel – coal, petroleum, natural gas.
  • Carbonaceous nutrients – carbohydrates, proteins, fats.
  • Natural fibres – cotton, wool, silk.
  • Hydrocarbons – compound of carbon and hydrogen.

c. Write the uses of the diamond.
Answer:
Uses of diamonds are:

  • Diamonds are used in glass cutting and rock drilling machines.
  • Diamonds are used in ornaments.
  • Diamond knives are used in the eye surgery.
  • Diamond dust is used for polishing other diamonds.
  • Diamond is used to make windows giving protection from radiation in space and in artificial satellites.

3. Explain the difference:

a. Diamond and graphite.

Answer:

Diamond Graphite
(i) Diamond is a brilliant, hard and crystalline allotrope of carbon.(i) Graphite is a black, soft, brittle and slippery crystalline allotrope of carbon.
(ii) In diamonds, every carbon atom is bonded to four neighbouring atoms by covalent bonds forming tetragonal three dimensional structure which makes it very hard.(ii) In graphite, every carbon atom is bonded to three other carbon atoms by covalent bonds in such a way that a hexagonal layered structure is formed. A graphite crystal is made of many such layers of carbon atoms. These layers slip over each other on applying pressure.
(iii) Density of diamond is 3.5 g/cm3.(iii) Density of graphite is 1.9 to 2.3 g/cm3.
(iv) Diamond is a bad conductor of electricity as it does not have free electrons.(iv) Inside each layer of graphite, free electrons move continuously within the entire layer. Hence, graphite is a good conductor of electricity.

b. Crystalline and non-crystalline forms of carbon.
Answer:

Crystalline forms of carbonNon-crystalline forms of carbon
(i) A crystalline form has a regular and definite arrangement of atoms.
(ii) They have high melting points and boiling points.
(iii) A crystalline form has a definite geometrical shape, sharp edges and plane surfaces.
(iv) Diamond, graphite and fullerene are different crystalline forms of carbon.
(i) A non-crystalline form does not have a regular and definite arrangement of atoms.
(ii) They have low melting points and boiling points.
(iii) They are amorphous, hence, they do not have definite geometrical shape.
(iv) Coal, charcoal and coke are different non­crystalline/amorphous forms of carbon.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

4. Write scientific reasons

a. Graphite is a conductor of electricity.
Answer:

  • In graphite, each carbon is bonded to three other carbon atoms in such a way that a hexagonal layered structure is formed.
  • Due to this structure, graphite has free electrons available.
  • These free electrons move continuously within the entire layer.
  • Hence, graphite is a good conductor of electricity.

b. Graphite is not used in ornaments.
Answer:

  • Graphite is a black, soft, brittle and dull form of carbon.
  • It is neither malleable nor ductile.
  • These properties of graphite make it unsuitable for making of ornaments.
  • Hence, graphite is not used for making ornaments.

c. Limewater turns milky when CO2 is passed through it.
Answer:

  • Limewater traditionally means a weak solution of the alkali calcium hydroxide Ca(OH)2.
  • When CO2 is passed through limewater, it reacts with calcium hydroxide to form insoluble particulates (precipitate) of Calcium carbonate (CaCO3).
  • Calcium carbonate is weak basic salt and this gives a milky white precipitate.
  • Hence, lime water turns milky when CO2 gas is passed through it.

d. Biogas is an eco-friendly fuel.
Answer:

  • Biogas is formed by the decomposition of animal dung, dry leaves, wet garbage in a biogas plant.
  • This produces methane gas also called biogas.
  • Biogas is a very cheap fuel option which meets the demand for cooking gas.
  • Biogas is eco-friendly as it contains about 55% to 60% of methane and rest is carbon dioxide, hence, on combustion it does not produce harmful gases which cause pollution.
  • Biogas is a fuel which is convenient to use and in addition to this it produces a very good manure as a side product of the process.
  • Hence, biogas is an eco-friendly fuel.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

5. Explain the following.

a. Diamond, graphite and fullerenes are crystalline forms of carbon.
Answer:

  • Carbon exhibits a property of allotropy in which an element exists in more than one form in nature.
  • The chemical properties of these different forms are the same but their physical properties are different.
  • Carbon exists in crystalline as well as non-crystalline (amorphous form).
  • Crystalline form has a regular and definite arrangement of atoms. They have high melting points and boiling points.
  • A crystalline form has a definite geometrical shape, sharp edges and plane surfaces.
  • Carbon has three crystalline allotropes such as diamond, graphite and fullerene.
  • In the structure of diamond, every carbon atom is bonded to four neighbouring atoms by covalent bonds.
  • Therefore, diamond has a tetragonal three dimensional structure which makes it very hard.
  • Brilliant and pure diamond is the hardest natural substance.
  •  In the structure of graphite, every carbon atom in graphite is bonded to three other carbon atoms in such a way that a hexagonal layered structure is formed.
  • A graphite crystal is made of many sheets or layers of carbon atoms.
  • These layers slip over each other on applying pressure. One layer of graphite is called graphene.
  • Fullerene is rarely found in nature. It is found in soot and in interstellar space.
  • The first example of fullerene is Buckminster fullerene (C60).
  • This allotrope of carbon is named fullerene after the architect.
  • Richard Buckminster Fuller because the structure of C60 resembles the structure of the geodesic dome he designed.
  • (xi) Molecules of fullerenes are found in the form of buckyballs and buckytubes.
  • (xii) There are 30 to 900 carbon atoms in one molecule of a fullerene. , C60, C70, C76, C82 and C86 are other examples of fullerene. Their molecules occur in small numbers in soot.

b. Methane is called marsh gas.
Answer:

  • Methane is formed by the decomposition of plant and animal matter in swamps or marshy areas.
  • As methane gas bubbles out from marshy area, it is called as marsh gas.

c. Petrol, diesel, coal are fossil fuels.
Answer:
(i) A fossil fuel is a fuel formed by natural processes, such as anaerobic decomposition of buried dead organisms. Fossil fuels contain high percentage of carbon. The word carbon is derived from the Latin word ‘Carbo’ meaning coal.

(ii) Coal is formed from the remains of trees and other vegetation. Approximately 350 million years ago, these remains were trapped on the bottom of swamps, accumulating layer after layer and creating a dense material called peat. As this peat was buried under more and more ground, the high temperature and pressure transformed it into coal.

(iii) Petrol and diesel are obtained from mineral oil. Mineral oil also called as crude oil or petroleum oil is formed from the remains of plants and animals that lived in the seas millions of years ago. This plant and animal matter has been drawn down and subjected to extremes of temperature and pressure over millions of years ago.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

(iv) Mineral oil is commonly formed in rocks under the sea bed. The word petroleum is derived from Latin word ‘Rock oil’. Petrol and Diesel are obtained from mineral oil by the process called as fractional distillation.
Thus petrol, diesel and coal are fossil fuels.

d. Uses of various allotropes of carbon.

e. Use of CO2 in fire extinguisher.
Answer:

  • CO2 based fire extinguishers do not cause corrosion and are non-conductors of electricity.
  • It is beyond their capacity to extinguish a big fire.
  • Therefore these fire extinguishers are used to extinguish small scale fire of electrical and electronic equipments.

f. Practical uses of CO2.
Answer:
Practical uses of CO2 are:

  • CO2 is used to make aerated drinks.
  • CO2 obtained by chemical reaction or kept under pressure is used in fire extinguishers. Liquified CO2 is used to remove caffeine from coffee.
  • Liquid CO2 is used as solvent in modem eco-friendly dry cleaning.
  • Solid carbon dioxide is used in cold storage and to keep milk and milk products and frozen substances cool during transport. It is also used for getting special effects of a mist in dramas and movies.

6. Write two physical properties each.

a. Diamond
Answer:
Properties of diamond are:

  • Brilliant and pure diamond is the hardest natural substance.
  • The density of diamond is 3.5 g/cm3.
  • The melting point of diamond is 3500 °C.
  • When a diamond is heated at 800 °C in the presence of oxygen, CO2 is given away. In this process no other product besides CO2 is formed.
  • Diamond does not dissolve in any solvent.
  • Acids/bases have no effect on diamond.
  • Diamond is a bad conductor of electricity as it does not have free electrons.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

b. Charcoal
Answer:

  • The charcoal that is made from animals is made from their bones, horns, etc.
  • On the other hand, the charcoal made from plants is formed by combustion of wood in an insufficient supply of air.

c. Fullerene
Answer:
Properties of fullerenes are:

  • Molecules of fullerenes are found in the form of buckyballs and buckytubes.
  • There are 30 to 900 carbon atoms in one molecule of a fullerene.
  • Fullerenes are soluble in organic solvents such as carbon disulphide, chlorobenzene.

7. Complete the following Chemical reactions.

1. ………………..+………………..→ CO + 2H2O + Heat
2. ………………..+………………..→ HCl + Cl + HCl
3. 2 NaOH + CO2 →………………..+………………..
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 1

8. Write answers to the following in detail.

a. What are the different types of coal? What are their uses?
Answer:
Coal is a fossil fuel. It contains carbon, hydrogen and oxygen. It also contains nitrogen, phosphorus and sulphur. It occurs in the solid state. It is of four types.

  • Peat: Formation of peat is the first step in the formation of coal. It contains a high proportion
    of water and less than 60% of carbon. Therefore, not much heat can be obtained from peat.
  • Lignite: Peat was transformed into Lignite due to increased pressure and temperature inside the earth. It contains 60 to 70% of carbon.- Lignite is the second step of the formation of coal.
  • Bituminous coal: Bituminous coal was formed as the third step of formation of coal. It contains 70 to 90% of carbon.
  • Anthracite: Anthracite is known as the pure form of coal. This coal is hard and contains about 95% of carbon.

Uses of coal:

  • Coal is used as fuel in factories and homes.
  • Coal is used to obtain coke, coal gas and coal tar.
  • Coal is used in thermal power plants for generation of electricity.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

b. How will you prove experimentally that graphite is good conductor of electricity?
Answer:
Apparatus required: Lead pendi, electrical wires, battery/cell, small bulb, etc.

Step-I: Remove the lead from a pencil and assemble the apparatus as shown in the diagram.
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 28

Step-II:

  • Start the electric current in the circuit, the moment the electric current is passed through the circuit, the bulb glows.
  • This experiment proves that graphite is a good conductor of electricity as graphite has free electrons moving continuously within the entire layer and these free electrons conduct electricity in the lead of the pencil.

c. Explain the properties of carbon.
Answer:
Allotropic nature of Carbon: Some elements occur in nature in more than one form. The chemical properties of these different forms are the same but their physical properties are different. This property of elements is called allotropy. Carbon shows the property of allotropy.

Carbon allotropes are of two types:
(A) Crystalline forms:
Carbon has three crystalline allotropes: Diamond, Graphite and Fullerene. Properties of crystalline forms of carbon are as follows:

  • A crystalline form has a regular and definite arrangement of atoms.
  • They are made up of only carbon atoms.
  • They have high melting points and boiling points.
  • A crystalline form has a definite geometrical shape, sharp edges and plane surfaces.

(B) Amorphous forms or non-crystalline forms: Coal, charcoal, coke are the non-crystalline forms of carbon.
Properties of non-crystalline forms of carbon are as follows:

  • The arrangement of carbon atoms in this form is not regular.
  • Apart from carbon atoms, they also contain hydrogen, oxygen, nitrogen, phosphorus and sulfur atoms.
  • Compared to a crystalline form, they have low melting and boiling points.
  • Most of them are used as fuels.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

d. Classify carbon.
Answer:
Carbon is classified as follows:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 2

9. How will you verify the properties of carbon dioxide?
Answer:
Properties of carbon dioxide can be verified in the following ways:

  • When a burning candle is placed in a gas jar of carbon dioxide, it extinguishes indicating that carbon dioxide is a non-combustible gas and does not support combustion.
  • When carbon dioxide gas is passed through lime water, it turns lime water milky due to the formation of insoluble calcium carbonate.
  • Moist blue litmus turns red in a gas jar of carbon dioxide indicating, it is acidic in nature.
  • Carbon dioxide is fairly soluble in water, it dissolves in water forming carbonic acid.

Class 9 Science Chapter 13 Carbon: An Important Element Intext Questions and Answers

Can you recall?

Question 1.
Whatremains behind on complete combustion of any organic compound?
Answer:
A black colour substance ‘Carbon’ remains behind on complete combustion of any organic compound.

Question 2.
What type of element is carbon? Give some information about it.
Answer:

  • Carbon is a non-metallic element. It is available ‘ abundantly in the nature and occurs in free as well as combined state.
  • Carbon in free state is found as diamond and graphite and in combined state it is present to the extent of approximately 0.27% in the form of carbonate, coal, petroleum.
  • In atmosphere, the proportion of carbon in the form of carbon dioxide is approximately 0.03%.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 3.
What is an element? What are the different types of elements.
Answer:

  • A substance which cannot be decomposed into simple substances by any physical or simple chemical method is called as an Element.
  • An element is composed of atoms of only one kind.
  • The different types of elements are:
    (a) Metals – Examples: Gold, Silver, etc.
    (b) Non-metals – Examples: Carbon, Sulphur, etc.
    (c) Metalloids – Examples: Silicon, Antimony, etc.

Answer the following questions:

Question 1.
Does an electric charge form on atoms when a covalent bond is formed between them? Why is a single bond between two carbon atoms strong and stable?
Answer:

  • No, electric charge is not formed on atoms when a covalent bond is formed between them. This is because covalent bond is formed by sharing of electrons.
  • Therefore, there is no change in number of electrons and protons in these atoms and they remain electrically neutral.
  • Covalent bonds occur when electrons are shared between two atoms. A single covalent bond is formed when only one pair of electrons is shared between atoms.
  • In this sharing, the atomic orbitals directly overlap between the nuclei of two atoms forming the strongest type of covalent bond called as sigma bond.
  • Hence, a single covalent bond between two carbon atoms is strong and stable.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 2.
In which of the solvents – water, kerosene and cooking oil does the coal powder dissolve?
Answer:
Solvents such as water, kerosene and cooking oil do not dissolve coal powder in them.

Question 3.
What inference will you draw about the solubility of carbon?
Answer:
Carbon is insoluble in water, kerosene and cooking oil.

Question 4.
Is the density of CO2 more or less than that of air?
Answer:

  1. Density is defined as mass per unit volume of a substance, expressed as kilograms per cubic meter.
  2. At standard temperature and pressure, the density of air is 1.29 kg/m3. While that of carbon dioxide (CO2) is 1.79 kg/m3. Hence, density of CO2 is more than that of air.

Question 5.
What is a compound? How are compounds formed?
Answer:

  • A compound is a substance formed when two or more elements are chemically bonded with each other in definite proportion by weight.
  • When atoms or two or more different elements chemically react with each other in a definite proportion by weight, a compound is formed. Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element
  • The properties of a compound are altogether different from its constituent elements.
  • Example: Pure water is a compound made up of two elements Hydrogen and Oxygen. Hydrogen (H) atoms and oxygen (O) atoms have chemically reacted with each other in definite proportion to form a compound-water (H2O). The proportion of hydrogen and oxygen in water by volume is 2 : 1 and by weight is 1 :8 respectively.
  • The properties of water are altogether different from the properties of its constituent elements, hydrogen and oxygen.

Class 9 Science Chapter 13 Carbon: An Important Element Additional Important Questions and Answers

Choose and write the correct option:

Question 1.
The organic compound having double or triple bond in them is termed as
(a) unsaturated
(b) inorganic
(c) saturated
(d) complete
Answer:
(a) Unsaturated hydrocarbon

Question 2.
Covalent compounds are generally soluble in solvents.
(a) inorganic
(b) organic
(c) mixed
(d) mineral
Answer:
(b) organic

Question 3.
Methane is also called as
(a) maha gas
(b) mar’s gas
(c) Anthracite
(d) marsh gas
Answer:
(d) Marsh gas

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 4.
is an alio trope of carbon used to make ornaments.
Answer:
Diamond

Question 5.
The number of valence electrons in carbon is
(a) 4
(b) 5
(c) 6
(d) 3
Answer:
(a) 4

Question 6.
In saturated hydrocarbons, two carbon atoms are linked by
(a) double bond
(b) triple bond
(c) multiple bond
(d) single bond
Answer:
(d) single bond

Question 7.
Carbon has 4 valence electrons in its outermost shell, hence, it is
(a) divalent
(b) tetravalent
(c) trivalent
(d) pentavalent
Answer:
(b) tetravalent

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 8.
Methanogenic bacteria act on the organic acids to produce
(a) oxygen gas
(b) nitrogen gas
(c) methane gas
(d) carbon dioxide gas
Answer:
(c) Methane gas

Question 9.
is used to remove caffeine from coffee.
(a) liquefied O2
(b) liquefied N2
(c) liquefied CO2
(d) liquefied CH4
Answer:
(c) Liquified CO2

Question 10.
Exhaled air contains about CO2.
(a) 4%
(b) 3%
(c) 5%
(d) 6%
Answer:
(a) 4%

Question 11.
Electronic configuration of carbon is
(a) (2, 2)
(b) (2,4)
(c) (2, 5,4)
(d) (2, 6)
Answer:
(b) 2, 4

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 12.
Molecular formula of ethane is
(a) C3H4
(b) C2H4
(c) C2H6
(d) C2H2
Answer:
(c) C2H6

Question 13.
Molecular mass of carbon dioxide is
(a) 28
(b) 22
(c) 56
(d) 44
Answer:
(d) 44

Question 14.
On heating a mixture of hydrogen and carbon monoxide gases at 300°C in the presence of nickel (catalyst) is formed.
(a) carbon dioxide gas
(b) oxygen gas
(c) methane gas
(d) ethylene gas
Answer:
(c) methane gas

Question 15.
Ethane with molecular formula C2H6 has covalent bonds.
(a) six
(b) seven
(c) eight
(d) nine
Answer:
(b) seven

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 15.
Weight of Kohinoor Diamond was
(a) 186 carats
(b) 27 carats
(c) 252 carats
(d) 23 carats
Answer:
(a) 186 carats

Question 16.
Covalent compounds have
(a) high melting point
(b) low melting point
(c) moderate melting point
(d) very high melting point
Answer:
(b) low melting point

Question 17.
Methane is
(a) C2H6
(b) C3H8
(C) CH2
(d) CH4
Answer:
(d) CH4

Question 18.
Wohler, a German scientist synthesized the compound from an inorganic compound ammonium cyanate.
(a) methane
(b) ethylene
(c) urea
(d) acetic acid
Answer:
(c) urea

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 19.
Molecular mass of methane is
(a) 19
(b) 16
(c) 17
(d) 18
Answer:
(b) 16

Question 20.
coal contains highest percentage of carbon.
(a) Bituminous
(b) Peat
(c) Anthracite
(d) Lignite
Answer:
(c) Anthracite

Question 21.
H2C = CH2 is ……………………… .
(a) Propane
(b) Ethyne
(c) Ethane
(d) Ethene
Answer:
(d) Ethene

Question 22.
CH3 – C = CH is ……………………… .
(a) Propene
(b) Propyne
(c) Ethyne
(d) Ethene
Answer:
(b) Propyne

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 23.
Carbon dioxide gas is not used in
(a) photosynthesis
(b) aerated drinks
(c) glass cutting
(d) fire extinguishers
Answer:
(c) glass cutting

Question 24.
Melting point of diamond is
(a) 3700 °C
(b) 3500 °C
(c) 4000 °C
(d) 2500 °C
Answer:
(b) 3500 °C

Question 25.
Melting point of C02 is
(a) 26 °C
(b) 56 °C
(c)-56.6°C
(d)-98°C
Answer:
(c) -56.6 °C

Question 26.
Melting point o* methane is
(a) -182.5 °C
(b) -161.5 °C
(c) 182.5 °C
(d) 161.5 °C
Answer:
(a) -182.5 °C

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 27.
Biogas contains about methane.
(a) 55% to 60%
(b) 20% to 25%
(c) 90% to 95%
(d) 40% to 45%
Answer:
(a) 55% to 60%

Question 28.
is not a property of carbon dioxide gas.
(a) Supporting combustion
(b) Odourless
(c) Colourless
(d) Turns blue litmus red
Answer:
(a) Supporting combustion

Name the following:

Question 1.
Industries that use methane in the form of natural gas.
Answer:
Fabric mills, paper mills, food processing industry, petrol purification.

Question 2.
Organic compounds prepared from methane.
Answer:
Ethanol, methyl chloride, methylene chloride, acetylene.

Question 3.
Chemicals used in regular fire extinguisher.
Answer:
Sodium bicarbonate and dilute sulphuric acid.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 4.
Components of biogas
Answer:
Methane, carbon dioxide

Question 5.
Organic solvents is which fullerenes are soluble.
Answer:
Carbon disulfide, chlorobenzene.

Question 6.
Use of carbon dioxide is dramas and movies
Answer:
The special effect of mist.

Match the columns:

Question 1.

Column ‘A’Column ‘B’
(1) Diamond
(2) Fullerenes
(3) Graphite
(a) Hexagonal layered structure
(b) Tetragonal three-dimensional structure
(c) Geodesic dome

Answer:
(1-b),
(2- c),
(3 – a)

Question 2.

Column ‘A’Column ‘B’
(1) Peat
(2) Lignite
(3) Bituminous
(4) Anthracite
(a) 60-70% of Carbon
(b) 95% of Carbon
(c) less than 60% of Carbon
(d) 70 – 90% of Carbon

Answer:
(1 – c),
(2 – a),
(3 – d),
(4 – b)

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 3.

Column ‘A’Column ‘B’
(1) Propyne
(2) Propene
(3) Propane
(a) CH3 – CH2 – CH3
(b) CH3 – C = CH
(c) CH3 – CH = CH2

Answer:
(1 – b),
(2 – c),
(3 – a)

Question 4.

Column ‘A’Column ‘B’
(1) Fullerene
(2) Diamond
(3) Graphite
(a) Lubricants
(b) Insulator
(c) Ornaments

Answer:
(1 – b),
(2 – c),
(3 – a)

Question 5.

Column ‘AColumn ‘B’
(1) Water gas
(2) Methane gas
(3) Producer gas
(4) Carbon dioxide gas
(a) CH4
(b) CO + H2
(c) CO2
(d) CO + H2 + CO2 + N2

Answer:
(1 – b),
(2 – a),
(3 – d),
(4 – c)

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

State whether the following statements are true or false. Correct the false statement.

(1) Study of organic compounds is called as organic chemistry.
(2) Hydrocarbons with double bonds are called as saturated hydrocarbons.
(3) Ethene is saturated hydrocarbon.
(4) Covalent compounds are good conductor of electricity.
(5) Methane is a covalent compound.
(6) Covalent compounds are soluble in organic solvents.
(7) Graphite is used in making lubricants and lead pencils.
(8) The density of diamond is 9.8 g/cm3.
(9) Diamond knives are used in eye surgery.
(10) Fullerenes are used as insulators.
(11) Coke is used in production of water gas i.e. (CO2 + H2O).
(12) Structural formula of propyne is CH3 – C = CH.
(13) COz is used to make aerated drinks.
(14) Methane gas is black in colour.
(15) Production of biogas is aerobic process.
Answer:
(1) True
(2) False. Hydrocarbons with double bonds are called as Unsaturated hydrocarbons.
(3) False. Ethene is Unsaturated hydrocarbon.
(4) False. Covalent compounds are bad conductor of electricity.
(5) True
(6) True
(7) True
(8) False: The density of diamond is 3.5 g/cm3.
(9) True
(10) True
(11) False. Coke is used in production of water gas i.e. (CO + H2).
(12) False. Structural formula of propyne is CH3 – C = CH.
(13) True
(14) False. Methane gas is colourless.
(15) False. Production of biogas is anaerobic process.

Find the odd man out:

Question 1.
Propane, Methane, Ethene, Pentane.
Answer:
Ethene. It is an unsaturated hydrocarbon with double bond between two carbon atoms while rest are saturated hydrocarbons with single bond between two carbon atoms.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 2.
CH4, C2H6, C3H8, CaCO3.
Answer:
CaCO3. It is a salt which is an inorganic’ compound, while rest are hydrocarbon compounds, i.e. organic compounds.

Question 3.
C2H2, C3H8, C2H6, CH4.
Answer:
C2H2. It is an unsaturated hydrocarbon with triple bonds while rest are saturated hydrocarbons with single bonds between two carbon atoms.

Question 4.
Diamond, Fullerene, Graphite, Methane.
Answer:
Methane. It is a marsh gas while rest are allotropes of carbon.

Question 5.
Coal, Petroleum, Natural gas, Cotton
Answer:
Cotton. Cotton is a natural fibre while rest all are fossil fuels.

Question 6.
Cotton, Silk, Proteins, Wool
Answer:
Proteins. Proteins are carbonaceous nutrients while rest all are natural fibres.

Question 7.
Carbohydrates, Coal, Proteins, Fats
Answer:
Coal. Coal is a fossil fuel while rest all are carbonaceous nutrients.

Question 8.
Peat, Charcoal, Lignite, Bituminous
Answer:
Charcoal. Charcoal is a non-crystalline form of carbon while rest all are types of coal.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 9.
Lubricants, Electrodes, Ornaments, Arc Lamps
Answer:
Ornaments. Ornaments are made from diamonds while rest all are made from graphite.

Write the correlated terms:

(1) Propene : Double bond :: Propyne : ……………………. .
(2) Ethane : CH3 – CH3 :: Ethene : ……………………. .
(3) Hydrogen : Monovalent :: Carbon : ……………………. .
(4) Methane : Low melting point i.e. -182.5°C Diamond : ……………………. .
(5) Graphite : Hexagonal structure :: Diamond : ……………………. .
(6) Density of Diamond : 3.5 g/cm3 :: Density of Graphite : ……………………. .
(7) Peat: 60% of carbon :: Anthracite : ……………………. .
(8) Melting point of CO2: -56.6°C :: Melting point of CH4: ……………………. .
Answer:
(1) Triple Bond
(2) CH2 = CH2
(3) Tetravalent
(4) High melting point i.e. 3500°C
(5) Tetragonal structure
(6) 1.9 to 2.3 g/cm3
(7) 95% of carbon
(8) -182.5 °C

Give scientific reasons:

Question 1.
Covalent compounds have low melting and boiling points.
Answer:

  • When substances melt or boil, bonds between the molecules are broken due to heat supplied.
  • On covalent compounds, the intermolecular forces of attraction are weak.
  • Hence, intermolecular forces in covalent compounds are broken easily due to which they have low melting and boiling points.

Question 2.
Graphite is a good conductor of electricity whereas diamond is a non-conductor of electricity.
Answer:

  • In diamond, each carbon atom uses all its four electronic to get bonded to another carbon atom, whereas in graphite each carbon uses there out of four electrons during bonding.
  • Hence in diamond no free electrons are left whereas in graphite free electrons are available.
  • Due to the presence of electron which are free to flow graphite is a good conductor of electricity, whereas due to the absence of free electrons diamond is a non-conductor of electricity.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 3.
Graphite is used as a lubricant.
Answer:

  • Lubricants are used to reduce friction and wear and tear of mechanical parts.
  • Graphite is smooth and slippery and hence is useful in reducing friction. Hence, graphite is used as a lubricant.

Question 4.
Methane is used as a domestic fuel.
Answer:

  • Methane is highly inflammable.
  • It burns by reacting with oxygen to give a bluish flame.
  • It burns completely and producers 213 Kcal/ mol of heat.
  • Being the smallest hydrocarbon, the proportion of CO2 released in the combustion of methane is small.
  • Therefore methane is used as a domestic fuel.

Answer in short:

Question 1.
What was the contribution of chemist Wohier in organic chemistry?
Answer:

  • The German chemist Wohier synthesized an organic compound urca from an inorganic compound ammonium cyanate,
  • Ever since then, many organic compounds have been made from inorganic compounds.
  • Carbon was found to he the main element in all these compounds.
  • Hence, organic chemistry is also referred to as chem is try of carbon corn pounds.

Question 2.
With neat diagram explain the structure of diamond.
Ans.

  • In diamond, every carbon atom is bonded to four neighbouring atoms by covalent bonds.
  • Therefore, diamond has a tetragonal three dimensional structure which makes it very hard.
    Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 29

Question 3.
With neat diagram explain the structure of graphite?
Answer:

  • Every carbon atom in graphite is bonded to three other carbon atoms in such a way that a hexagonal layered structure is formed.
  • A graphite crystal is made of many sheets or layers of carbon atoms.
  • These layers slip over each other on applying pressure.
  • One layer of graphite is called graphene.
    Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 30

Question 4.
Give the properties of graphite.
Answer:
Properties of graphite are:

  • Graphite found in nature is black, soft, brittle and slippery.
  • Inside each layer of graphite, free electrons move continuously within the entire layer. That is why graphite is a good conductor of electricity. Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element
  • Due to the layered structure graphite can be used for writing on paper.
  • The density of graphite is 1.9 to 2.3 g/cm3.
  • Graphite does not dissolve in most solvents.

Question 5.
Give the uses of graphite.
Answer:
Uses of graphite are:

  • Graphite is used for making lubricants.
  • Graphite is used for making carbon electrodes.
  • Graphite is used in pencils for writing.
  • Graphite is used in paints and polish.
  • Graphite is used in arc lamps which gives a very bright light.

Question 6.
Give the uses of fullerenes.
Answer:
Uses of Fullerenes are:

  • Fullerenes are used as insulators.
  • Fullerenes are used as a catalyst in water purification.
  • At a certain temperature, fullerene exhibits superconductivity.

Question 7.
What is Coal?
Answer:

  • Coal is a fossil fuel. It contains carbon, hydrogen and oxygen.
  • It also contains nitrogen, phosphorus and sulphur.
  • It occurs in the solid state. It is of four types – peat, lignite, bituminous and anthracite.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 8.
What is Coke?
Answer:
The pure coal that remains when coal gas has been taken away from coal, is called coke.

Question 9.
Give the uses of Coal.
Answer:
Uses of Coal are:

  • Coal is used as fuel in factories and homes.
  • Coal is used to obtain coke, coal gas and coal tar.
  • Coal is used in thermal power plants for generation of electricity.

Question 10.
Give the uses of Coke.
Answer:
Uses of Coke are:

  • Used as domestic fuel.
  • Coke is used as a reducing agent.
  • Coke is used in production of water gas (CO + H2) and producer gas (CO + H2 + CO2 + N2)

Question 11.
Name the types of coal and give the differences in them.
Answer:
The four types of coal are Peat, Lignite, Bituminous and Anthracite.
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 3

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 12.
Give the properties of covalent compounds.
Answer:
Properties of covalent compounds:

  • Covalent compounds have low melting points and boiling points.
  • Generally they are insoluble in water and soluble in organic solvents.
  • They are poor conductors of heat and electricity.

Question 13.
What are saturated hydrocarbons? Give examples.
Answer:

  • The hydrocarbons having only single bonds between carbon atoms are called saturated hydrocarbons.
  • For example, ethane (C2H6) which is (CH3 – CH3), propane (C3H8) which is (CH3 – CH2 – CH3).

Question 14.
What are unsaturated hydrocarbons? Give examples.
Answer:

  • Some hydrocarbons have a multiple bond between two carbon atoms.
  • A multiple bond can be a double bond or a triple bond.
  • Hydrocarbons having at least one multiple bond are called unsaturated hydrocarbons.
  • For example, ethene (H2C = CH2), ethyne (HC = CH), propene (CH3 – CH = CH2), propyne (CH3 – C = CH).

Question 15.
Give the following information of carbon dioxide: Molecular formula, Molecular mass, Melting point, Percentage occurrence in air.
Answer:
Molecular formula – CO2, Molecular mass – 44, Melting point -56.6 °C Percentage occurrence in air – 0.03%.

Question 16.
Give the physical and chemical properties of carbon dioxide.
Answer:
Physical properties of carbon dioxide are:

  • It is an odourless gas.
  • It is a colourless gas.

Chemical properties of carbon dioxide are:

  • It is non-combustible and does not support combustion.
  • It turns lime water milky.
  • It is fairly soluble in water and dissolves in water forming carbonic acid.
  • It turns blue litmus red indicating it is acidic in nature.
  • The colour of universal indicator turns orange/ yellow in C02 indicating its pH value between 4 and 6, i.e. acidic in nature.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 17.
Give the uses of Carbon dioxide.
Answer:
Uses of Carbon dioxide are:

  • CO2 is used to make aerated drinks
  • Solid carbon dioxide is used in cold storage and also to keep milk and milk products and frozen substances cool during transport. It is also used for getting special effects of a mist in dramas and movies.
  • CO2 obtained by chemical reaction or kept under pressure is used in fire extinguishers.
  • Liquified CO2 is used to remove caffeine from coffee.
  • Liquid CO2 is used as solvent in modern eco-friendly dry cleaning.
  • Plants use CO2 in air for photosynthesis.

Question 18.
Give the occurrence of methane.
Answer:
The occurrence of methane is as follows:

  • Methane occurs in natural gas to the extent of 87%.
  • Decomposition of organic matter in the absence of air (anaerobic) produces methane.
  • Methane is present in biogas.
  • Methane is found in coal mines.
  • Methane is found at the surface of marshy places which is why it is also called marsh gas.
  • On heating a mixture of hydrogen and carbon monoxide gases at 300 °C in the presence of nickel (catalyst), methane gas is formed.
  • Fractional distillation of natural gas gives methane in pure form.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 19.
Give the physical properties of methane.
Answer:
Physical properties of methane are:

  • Melting point of methane is (-182.5 °C).
  • Boiling point of methane is (-161.5 °C).
  • It is a colourless gas.
  • The density of liquid methane is less than that of water.
  • Methane is sparingly soluble in water. It is highly soluble in organic solvents like gasoline, ether and alcohol.
  • Methane is in gaseous state at room temperature.

Question 20.
Give the uses of methane.
Answer:
Uses of methane are:

  • Methane in the form of natural gas is used in industries such as fabric mills, paper mills, food processing industry, petrol purification.
  • Being the smallest hydrocarbon, the proportion of CO2 released in the combustion of methane is small and, therefore, it is used as a domestic fuel.
  • Methane is used for production of organic compounds such as ethanol, methyl chloride, methylene chloride and acetylene.

Question 21.
How is methane formed? Give structural formula and electron dot model of methane.
Answer:

  • Atomic number of carbon is 6. The electronic configuration of carbon is (2, 4). The valency of carbon is 4.
  • Carbon atom can form four covalent bonds with other carbon atoms or atoms of different elements.
  • When a carbon atom shares one electron each with four hydrogen atoms and forms four C-H bonds, a methane (CH4) molecule is formed.
    Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 4

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 22.
What are organic and inorganic compounds?
Answer:
Compounds obtained directly or indirectly from plants and animals are called organic compounds and compounds obtained from minerals are called inorganic compounds.

Question 23.
What is allotropy?
Answer:

  • Allotropy – Some elements occur in nature in more than one form.
  • The chemical properties of these different forms are the same but their physical properties are different.
  • This property of elements is called allotropy.

Question 24.
What are basic organic compounds? What are they also called as?
Answer:

  • The compounds formed from only carbon and hydrogen are called basic organic compounds.
  • These are also called hydrocarbons.

Write a balanced chemical equation and explain the following chemical reactions.

Question 1.
Preparation of urea from Ammonium cyanate:
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 5
Organic compound Urea can be synthesized from an inorganic compound Ammonium cyanate.

Question 2.
Coal when burnt in air
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 6
When coal is burnt in air, the carbon present in coal combines with oxygen present in air to form carbon dioxide gas.

Question 3.
Calcium carbonate reacts with dilute hydrochloric acid:
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 7
When Calcium carbonate reacts with dilute hydrochloric add it forms Caldum chloride, water and Carbon dioxide gas is evolved.

Question 4.
Carbon dioxide is passed through an aqueous solution of Sodium hydroxide:
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 8
When Carbon dioxide gas is passed through an aqueous solution of Sodium hydroxide it forms Sodium carbonate and Water.

Question 5.
Carbon dioxide is passed through an aqueous solution of Sodium carbonate:
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 9
When carbon dioxide is passed through an aqueous solution of Sodium carbonate, it forms Sodium bicarbonate.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 6.
Carbon dioxide is passed through freshly prepared lime water for a short duration and then for longer duration:
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 10
When Carbon dioxide is passed through freshly prepared lime water, it forms water and white precipitate of Calcium carbonate because of which lime water turns milky.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 11
When Carbon dioxide is continuously passed through milky lime water, it forms Calcium bicarbonate which is soluble in water and therefore, water once again turns colourless.

Question 7.
Carbon dioxide gas is dissolved in water.
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 12
Carboh dioxide gas is fairly soluble in water, it dissolves in water under pressure to form Carbonic acid.

Question 8.
Sodium bicarbonate reacts with dilute Sulphuric acid, (reaction in fire extinguisher):
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 13
When Sodium bicarbonate reacts with dilute Sulphuric acid it forms Sodium sulphate, water and Carbon dioxide gas.

Question 9.
Methane gas is burnt in air:
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 14
Methane is highly inflammable, it burns in air with a bluish flame and combines with oxygen present in air to form Carbon dioxide and water. In these reaction 213 kcal/mol of heat is given out.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Question 10.
Methane and Chlorine gases react with each other.
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 15
Methane and chlorine gases react with each other at the temperature of 250 °C to 400 °C in presence of ultra voilet light and form mainly Methyl chloride (Chloromethane and ‘ Hydrogen chloride)
This reaction is called Chlorination of methane.

Question 11.
Production of methane gas in biogas plant.
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 16
In biogas plant, microbes act on the bio-degradable complex organic compounds and produce organic acids.

The methanogenic bacteria act on the organic acids to produce Methane gas and Carbon dioxide gas.

Question 12.
Production of water gas:
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 17
When super heated steam is passed over red hot coke at high temperature, it forms carbon monoxide gas and hydrogen gas.

This gaseous product of carbon monoxide gas and hydrogen gas together is called as water gas.

With the help of ne abelled diagram explain the following:

Question 1.
Regular fire extinguisher.
Answer:

  • A fire extinguisher contains Sodium bicarbonate powder. There is also dilute sulphuric acid placed in a glass capsule.
  • On pressing the knob, the capsule breaks and sulphuric acid comes in contact with the sodium bicarbonate. These two react chemically to release CO2 which comes out.
  • CO2 based fire extinguishers do not cause corrosion and are non-conductors of electricity. Therefore, they are used when electrical or electronic equipment catches fire. Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element
  • CO2 based fire extinguishers are used to extinguish small scale fire. It is beyond their capacity to extinguish a big fire.
  • In modern fire extinguishers liquid and solid CO2 is filled under pressure. On reducing the pressure, it becomes gaseous and comes out forcefully through the horn-like hose pipe.
  • Chemical reaction:
    Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 18

Question 2.
Biogas plant.
Answer:

  • Animal dung, dry leaves, wet garbage get decomposed by anaerobic microbes in a biogas plant.
  • This produces methane gas, also called biogas.
  • Biogas is a very cheap fuel option which meets the demand for cooking gas. It is also used for the production of electricity.
  • Biogas contains about 55% to 60% methane and the rest is carbon dioxide.
  • Biogas is a fuel which is convenient to use and, in addition to this, a very good manure is also produced as a side product of the process.
  • Biogas production process – Production of biogas is an anaerobic process. It takes place in two stages.
    (a) Production of acids – The microbes act on the biodegradable complex organic compound and produce organic acids.
    (b) Methane gas production – The methanogenic bacteria act on the organic acids to produce methane gas.

Chemical reaction:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 19

Answer the following

Question 1.
What happens when substances like milk, sugar, wool, dry leaves, hair and seeds are heated strongly in hard glass test tube?
Answer:
When milk, sugar, wool, dry leaves, hair and seeds are heated strongly in hard glass test tube, they get charred and a black substance is left behind. This black substance is carbon.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Answer the following questions:

Question 1.
Take some milk in an evaporating dish. Heat the evaporating dish on a bunsen burner. What remains behind at the bottom of an evaporating dish on complete evaporation of the milk?
Answer:

  • On complete evaporation of milk, a black residue is left behind.
  • This residue is of carbon.

Question 2.
Take small samples of sugar, wool, dry leaves, hair, seeds, split pulses and plastic in separate test tubes. Heat each test tube and observe the changes taking place in the substances. What does the black substance in each test tube indicate?
Answer:

  • On heating the above samples, they get charred and a black substance is left behind.
  • The black substance is carbon.

Question 3.
Apparatus : Coal, match box, moist litmus paper, etc.

Procedure : Ignite the coal. Hold the moist blue litmus paper over the gas released on igniting the coal. Note the observation.
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 20

(a) With which gas in the air does the coal react on igniting?
Answer:
Coal reacts with oxygen gas present in the air, on igniting.

(b) What is the substance formed?
Answer:
The substance formed is carbon dioxide.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

(c) What change takes place in the litmus paper?
Answer:
The moist blue litmus paper turns red.

(d) Write down the chemical reaction taking place in the above procedure.
Answer:
(i) Carbon combines with oxygen to form Carbon dioxide gas.
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 21
(ii) This C02 combines with water present on moist blue litmus paper to form Carbonic acid which turns blue litmus to red.
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 22

Question 4.
Apparatus : Pencil, electrical wires, battery/ cell, small bulb, water, kerosene, test tube, lead pencils, etc.

Procedure : Remove the lead from a pencil and arrange the apparatus as shown in the above diagram. Note your observations for the following.
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 23

(a) What is the colour of lead in the pencil? .
Answer:
The colour of the lead in the pencil is black as it is made from graphite which is an allotrophic form of carbon.

(b) Try to break lead with your hand.
Answer:
The lead breaks easily as it is made up of graphite which is brittle in nature.

(c) Start the electric current in the circuit and observe. What did you find?
Answer:
When we start the electric current in the circuit, the bulb in the circuit glows, indicating that the lead in the pencil is a good conductor of electricity.

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

(d) Take some water in a test tube. Take some kerosene in another test tube. Put lead dust in both the test tube. What did you observe?
Answer:
(i) Lead dust does not dissolve in water nor in kerosene.
(ii) It remains insoluble in both the test tubes.

Question 5.
Apparatus : Test tube, straw, lime water, etc.

Procedure: Take freshly prepared lime water in a test tube. Blow air in it for some time through the straw and observe the lime water. Note the observation.
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 24

(a) What did you see?
Answer:
When we blow air through the straw in freshly prepared lime water, it turns milky.

(b) What might be the reason behind the change?
Answer:
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 25
Freshly prepared lime water is obtained by dissolving lime (CaO) in water (H2O).

When we blow air through the straw in lime water, carbon dioxide (CO2) present in the air reacts with lime water to form white precipitate (insoluble substance) of Calcium Carbonate (CaCO3) due to which lime water turns milky.
Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 26

Question 6.
With the help of a neat labelled diagram explain the laboratory preparation of Carbon dioxide gas.
Answer:
The laboratory preparation of Carbon dioxide gas is as follows:

Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon: An Important Element

Apparatus : Retort stand, round bottom flask, thistle funnel, gas delivery tube, gas jars.
Chemicals : Calcium carbonate (Pieces of Shahabad tiles/marble pieces/limestone), dilute hydrochloric acid.

Procedure:

  • Assemble the apparatus as shown in the figure. While assembling, place CaCO3 in the round bottom flask.
  • Add dilute HCl in the flask through thistle funnel. See to it that the end of the funnel dips in the acid.
  • CO2 is formed as a result of the reaction between CaCO3 and HCl. Collect this gas in four to five gas jars. The chemical equation of the above reaction is as follows. CaCO3 + 2HCl → CaCl2 + H2O + CO2
    Maharashtra Board Class 9 Science Solutions Chapter 13 Carbon An Important Element 27

Balbharati Maharashtra State Board 9th Std Science Textbook Solutions