12th Biology Chapter 3 Exercise Inheritance and Variation Solutions Maharashtra Board

Inheritance and Variation Class 12 Exercise Question Answers Solutions Maharashtra Board

Balbharti Maharashtra State Board 12th Biology Textbook Solutions Chapter 3 Inheritance and Variation Textbook Exercise Questions and Answers.

Class 12 Biology Chapter 3 Exercise Solutions Maharashtra Board

Biology Class 12 Chapter 3 Exercise Solutions

1. Multiple Choice Questions

Question 1.
Phenotypic ratio of incomplete dominance in Mirabilis jalapa.
(a) 2 : 1 : 1
(b) 1 : 2 : 1
(c) 3 : 1
(d) 2 : 2
Answer:
(b) 1 : 2 : 1

Question 2.
In dihybrid cross, F2 generation offspring show four different phenotypes while the genotypes are ……………….
(a) six
(b) nine
(c) eight
(d) sixteen
Answer:
(b) nine

Maharashtra Board Class 12 Biology Solutions Chapter 3 Inheritance and Variation

Question 3.
A cross between an individual with unknown genotype for a trait with recessive plant for that trait is ……………….
(a) back cross
(b) reciprocal cross
(C) monohybrid cross
(d) test cross
Answer:
(d) test cross

Question 4.
When phenotypic and genotypic ratios are the same, then it is an example of ……………….
(a) incomplete dominance
(b) complete dominance
(c) multiple alleles
(d) cytoplasmic inheritance
Answer:
(a) incomplete dominance

Question 5.
If the centromere is situated near the end of the chromosome, the chromosome is called ……………….
(a) Metacentric
(b) Acrocentric
(c) Sub-Metacentric
(d) Telocentric
Answer:
(d) Telocentric

Question 6.
Chromosomal theory of inheritance was proposed by ……………….
(a) Sutton and Boveri
(b) Watson and Crick
(c) Miller and Urey
(d) Oparin and Halden
Answer:
(a) Sutton and Boveri

Question 7.
If the genes are located in a chromosome as p-q-r-s-t, which of the following gene pairs will have least probability of being inherited together ?
(a) p and q
(b) r and s
(c) s and t
(d) p and s
Answer:
(d) p and s

Question 8.
Find the mismatched pair:
(a) Down’s syndrome = 44 + XY
(b) Turner’s syndrome = 44 + XO
(c) Klinefelter’s syndrome = 44 + XXY
(d) Super female = 44 + XXX
Answer:
(a) Down’s syndrome = 44 + XY

Question 9.
A colourblind man marries a woman, who is homozygous for normal colour vision, the probability of their son being colour blind is ……………….
(a) 0%
(b) 25%
(c) 50%
(d) 100%
Answer:
(a) 0%

2. Very Short Answer Questions

Question 1.
Explain the statements
a. Test cross is back cross but back cross is not necessarily a test cross.
b. Law of dominance is not universal.
Answer:
a. (1) Test cross is the cross between F1 hybrid and its homozygous recessive parent.
(2) Back cross is the cross of offspring with any one of the parents, either dominant or recessive.
(3) Therefore, test cross can be a back cross – but back cross cannot be a test cross.

b. (1) There are many traits in many organisms which show dominance. For example, widow’s peak in human beings is a dominant trait. Yellow seed colour and round seed shape are dominant traits in pea plant.
(2) However, there are characters which are either co-dominant, such as genes for human blood group A and B or incompletely dominant as in flower colour of Mirabilis jalapa.
(3) Therefore the law of dominance is not universally applicable.

Question 2.
Define the following terms:
a. Dihybrid cross
b. Homozygous
c. Heterozygous
d. Test cross
Answer:
a. A cross between parents differing in two heritable traits is called dihybrid cross.
b. An individual possessing identical alleles for a particular trait is called homozygous or pure for that trait. E.g. TT for tallness and tt for dwarfness.
c. An individual possessing contrasting allele for a particular trait is called heterozygous. E.g. Tt showing tallness.
d. The cross of F1 progeny with homozygous recessive parent is called a test cross.

Maharashtra Board Class 12 Biology Solutions Chapter 3 Inheritance and Variation

Question 3.
What are allosomes?
Answer:
Allosomes are the chromosomes which decide the sex of an organism.

Question 4.
What is crossing over?
Answer:
Crossing over is the process of forming new recombinations by interchanging and exchanging non-sister chromatid arms of the homologous chromosomes.

Question 5.
Give one example of autosomal recessive disorder.
Answer:
Thalassemia is an example of autosomal recessive disorder.

Question 6.
What are X-linked genes?
Answer:
Genes located on the non-homologous region of X chromosome are called X-linked genes.

Question 7.
What are holandric traits?
Answer:
Genes located on the non-homologous region of Y chromosome are called Y-linked genes. The traits due to such genes are called holandric traits which are seen only in male sex.

Question 8.
Give an example of chromosomal disorder caused due to non-disjunction of autosomes.
Answer:
Down’s syndrome is an example of chromosomal disorder caused due to non-disjunction of autosomes.

Question 9.
Give one example of complete sex linkage.
Answer:
Sex linkage can be complete X linkage and complete Y linkage. X linkage is haemophilia and Y linkage is hypertrichosis.

3. Short Answer Questions

Question 1.
Enlist seven traits of pea plant selected / studied by Mendel.
Answer:
Seven traits in pea selected by Mendel:

  1. Tall habit versus dwarf habit (Height of the plant).
  2. Purple flowers versus white flowers. (Colour of flowers)
  3. Yellow seeds versus green seeds. (Colour of seeds)
  4. Round seeds versus wrinkled seeds. (Shape of seeds)
  5. Green pods versus yellow pods. (Colour of pods)
  6. Inflated pods versus constricted pods. (Shape of pods)
  7. Axial flower versus terminal flower. (Position of a flower)

Question 2.
Why law of segregation is also called the law of purity of gametes?
Answer:
(1) Mendel’s law of segregation is also called Law of purity of gametes because, during formation of gametes, the alleles separate/ segregate from each other and only one allele enters a gamete.

(2) The separation of one allele does not affect other. Since single allele enters a gamete means gametes will be pure for a trait.
E.g. The contrasting characters such as tall (T) and dwarf (t) present in F1 hybrid (Tt) segregate during the formation of gametes.

(3) Owing to this, two types of gametes i.e. T and t are formed which are pure for the characters which they carry.
(4) Thus for example:
Maharashtra Board Class 12 Biology Solutions Chapter 3 Inheritance and Variation 1

Question 3.
Pleiotropy.
Answer:

  1. When a single gene controls two or more different traits, it is called a pleiotropic gene and the phenomenon is known as pleiotropy or pleiotropism.
  2. The pleiotropic ratio is always 1 : 2 instead . of normal 3 : 1.
  3. Sickle-cell anaemia is caused by the gene HbS. The healthy or normal gene which is dominant is HbA. The heterozygotes or carriers i.e., HbA/Hbs show anaemia as there is deficiency of haemoglobin due to sickling of RBCs. Abnormally low concentration of oxygen can cause sickling of RBCs.
  4. The homozygotes possessing the recessive gene HbS die because of fatal anaemia because the gene for sickle-cell anaemia is lethal in homozygous condition and causes sickle-cell trait in heterozygous carrier.
  5. Thus a single gene produces two different expressions.
  6. When two carriers are married they will produce normal carriers and Sickle-cell anaemic children in the ratio of 1 : 2 : 1. Out of these three children sickle-cell anaemic child will die leaving the ratio 1 : 2 instead of 3 : 1.

Maharashtra Board Class 12 Biology Solutions Chapter 3 Inheritance and Variation

Question 4.
What are the reasons of Mendel’s success?
Answer:
Reasons for Mendel’s success:

  1. Mendel planned his experiments carefully and these experiments consisted of large sample.
  2. He always recorded the results of number of plants of each type and their ratios.
  3. The contrasting characters that he chose were easily recognizable.
  4. The seven pairs of contrasting characters that he selected were under control of a single factor each. They were present on separate chromosomes and were transmitted from one generation to the next.
  5. Mendel studied and introduced concept of dominance and recessiveness.

Question 5.
“Father is responsible for determination of sex of child and not the mother”. Justify.
Answer:

  1. Human made is heterogame tic, i.e. he produces two different types of sperms. One is bearing X chromosome along with 22 autosomes and the other is Y bearing sperm with 22 autosomes.
  2. Mother, on the other hand, is homogametic, producing all similar types of ova, i.e 22 + X chromosomal combination.
  3. If 22+X bearing sperm fertilise an egg, female child is formed while if Y bearing sperm fertilizes an egg, male child is formed.
  4. Thus the sex of the child is dependent upon type of sperm that father gives, therefore, it is said that father is responsible for determination of sex of a child and not the mother.

Question 6.
What is linkage? How many linkage groups do occur in human being and maize?
Answer:

  1. Linkage is defined as the tendency of the genes to be inherited together because they are present in the same chromosome. Linkage group is group of genes situated on a chromosome.
  2. Humans have 23 linkage groups because they have 23 pairs of chromosomes.
  3. Maize plant has 10 linkage groups because they have 10 pairs of chromosomes.

Question 7.
PKU.
Answer:

  1. PKU means phenylketonuria which is an autosomal recessive inborn error.
  2. In this disorder the metabolism of phenylalanine does not occur due to deficiency of phenylalanine hydroxylase (PAH) enzyme.
  3. This enzyme is necessary to metabolize the amino acid phenylalanine to the amino acid tyrosine.
  4. When PAH activity is reduced, phenylalanine accumulates in blood and cerebrospinal fluid and is converted into phenylpyruvate or phenyl-ketone which is a toxic compound. This may cause mental retardation. Excess phenylalanine is excreted in urine, hence this disease is called phenylketonuria.
  5. PKU is caused by mutations in the PAH gene on chromosome no. 12.
  6. Untreated PKU causes abnormal phenotype which includes growth failure, poor skin pigmentation, microcephaly, seizures, global developmental delay and severe intellectual impairment. However, at birth if an infant is checked for PKU, the further abnormalities can be avoided.

Question 8.
Compare X-chromosome and Y-chromosome.
Answer:

X-chromosomeY-chromosome
1. X-chromosome is straight, rod like and longer 1. than Y chromosome. It is metacentric.1. Y-chromosome is shorter chromosome which is acrocentric.
2. X-chromosome has large amount of euchromatin and small amount of heterochromatin.2. Y-chromosome has small amount of euchromatin and large amount of heterochromatin.
3. X-chromosome has large amount of DNA, hence it is genetically active due to more genes.3. Y-chromosome has less amount of DNA, hence it is genetically less active or inert due to lesser genes.
4. Non-homologous region of X-chromosome is longer and contains more genes.4. Non-homologous region of Y-chromosome is shorter and contains lesser genes.
5. Contains X-linked genes on non-homologous region.5. Contains Y-linked genes on non-homologous region.
6. X-chromosome is present in men as well as women.6. Y-chromosome is present only in men.

Question 9.
Explain the chromosomal theory of inheritance.
Answer:
Chromosomal theory of inheritance was put forth by Sutton and Boveri after studying paraillel behaviour of genes and chromosomes during meiotic division. This theory states following points:

  1. Chromosomal theory identifies chromosomes as the carrier of genetic material.
  2. All the hereditary characters are transmitted by gametes. Nucleus of gametes, i.e. sperms and ova of the parents contain chromosomes which transmit the heredity to offspring.
  3. Chromosomes are found in pairs in somatic or diploid cells.
  4. During gamete formation, homologous chromosomes pair and segregate independently at meiosis. The diploid condition is converted into haploid condition. Thus each gamete contains only one chromosome of a pair.
  5. During fertilization, the union of sperm and egg restores the diploid number of chromosomes.

Question 10.
Observe the given pedigree chart and answer the following questions
Maharashtra Board Class 12 Biology Solutions Chapter 3 Inheritance and Variation 2
(a) Identify whether the trait is sex-linked or autosomal.
(b) Give an example of a trait in human beings which shows such a pattern of inheritance.
Answer:
Pedigree given above shows:

  1. First Generation : Carrier woman marrying a sufferer man. Their three children are in following birth order.
  2. Second generation : First son is normal, second daughter is carrier and third daughter is sufferer.
  3. Third generation : The sufferer daughter marries a normal man. Her children are normal daughter and sufferer son.

(a) The above pedigree show sex-linked (X-linked) trait. Since criss-cross inheritance is seen in the trait, it must be sex-linked inheritance.
(b) Such trait and its inheritance can be seen in colour blindness.

4. Match the Columns

rewrite the matching pairs.

Column IColumn II
(1) 21 trisomy(a) Turner’s syndrome
(2) X-monosomy(b) Klinefelter’s syndrome
(3) Holandric traits(c) Down’s syndrome
(4) Feminized male(d) Hypertrichosis

Answer:

Column IColumn II
(1) 21 trisomy(c) Down’s syndrome
(2) X-monosomy(a) Turner’s syndrome
(3) Holandric traits(d) Hypertrichosis
(4) Feminized male(b) Klinefelter’s syndrome

Maharashtra Board Class 12 Biology Solutions Chapter 3 Inheritance and Variation

5. Long Answer Questions

Question 1.
What is dihybrid cross? Explain with suitable example and checker board method.
Answer:
1. A cross which involves two pairs of alleles is called a dihybrid cross. A phenotypic ratio of 9 : 3 : 3 : 1 obtained in the F2 generation of a dihybrid cross is called a dihybrid ratio.

(2) Thus for example, when we cross a true breeding pea plant bearing round and yellow seeds with a true breeding pea plant bearing wrinkled and green seeds we get pea plants bearing round and yellow seeds in the F1 generation.

(3) When F1 plants are selfed, we get a ratio of 9 : 3 : 3 : 1 in the F2 generation, where 9 plants bear yellow round seeds, 3 plants bear yellow wrinkled seeds, 3 plants bear green round seeds and 1 plant bears green wrinkled seeds.

(4) Parents (P1) : RRYY × rryy
Gametes of P1 RY and ry
F1 generation : RrYy(Yellow round)
On selfing F1 : RrYy × RrYy
Gametes of F1 : RY, Ry, rY, ry

P2 generation:
Maharashtra Board Class 12 Biology Solutions Chapter 3 Inheritance and Variation 3
Round Yellow : 9 Round green : 3 Wrinkled yellow : 3 Wrinkled green : 1
Phenotypic ratio : 9 : 3 : 3 : 1
Genotypic ratio : 1 : 2 : 1 : 2 : 4 : 2 : 1 : 2 : 1

Question 2.
Explain with suitable example an independent assortment.
Answer:
(1) The law of independent assortment states that when hybrid possessing two or more pairs of contrasting characters bearing alleles form gametes, the alleles in each pair segregate independently of the other pair. Therefore, the inheritance of one pair of characters is independent of that of the other pair of characters.
(2) For example, when we cross a pea plant which is tall and having purple flowers with dwarf plant having white flowers we obtain all tall plants with purple flowers in F1 generation. When F1 generation are selfed, 9 : 3 : 3 : 1 ratio was obtained in F2 generation with 9 tall and purple flower, 3 tall with white flowers, 3 dwarf with purple flowers and 1 which was dwarf and white. Tallness and purple colour are dominant traits while dwarfness and white colour are recessive traits.

(i) Homozygous tall purple – TTPP
(ii) Homozygous dwarf white – ttpp
Maharashtra Board Class 12 Biology Solutions Chapter 3 Inheritance and Variation 4
Tall purple = 9. Tall white = 3
Dwarf purple = 3, Dwarf white = 1,
Phenotypic ratio = 9 : 3 : 3 : 1
Results : The offspring of F1 generation will be in the proportion of 9 : 3 : 3 : 1, where 9 are tall purple, 3 are tall white, 3 are dwarf purple and 1 is dwarf white.

Question 3.
Define test cross and explain its significance.
Answer:
1. Definition of test cross : A cross between F1 offspring and its homozygous recessive parent is called a test cross.
2. Significance of test cross:

  • Test cross can be used to find out the genotype of any plant which shows dominant characters.
  • Whether the plant is homozygous or heterozygous can be understood by performing test cross.
  • Test cross is used to introduce useful recessive traits in the hybrids of self- pollinated plants.
  • Test cross is quicker method to improve the variety of crop plants and thus it is useful for breeders and geneticists.
  • Test cross can be used for verifying the laws of inheritance.

Maharashtra Board Class 12 Biology Solutions Chapter 3 Inheritance and Variation

Question 4.
What is parthenogenesis? Explain the haplodiploid method of sex determination in honey bee.
Answer:
I. Parthenogenesis is a natural form of asexual reproduction in which growth and development of embryos occur without fertilization by sperm. In some insects like honey bees, parthenogenesis means development of an embryo from an unfertilized egg cell.

II. In honey bee:

  1. Sex determination is by haplodiploid system.
  2. Sex is determined by the number of sets of chromosomes received by an individual.
  3. The egg which is fertilized by sperm, becomes diploid and develops into female.
  4. The egg which is not fertilized develops by parthenogenesis and develops into a male.
  5. The queen and worker bee therefore contain 32 chromosomes. The drone, i.e. male bears 16 chromosomes.
  6. The sperms are produced by mitosis while eggs are produced by meiosis.

Maharashtra Board Class 12 Biology Solutions Chapter 3 Inheritance and Variation 5

Question 5.
In the answer for inheritance of X-linked. genes, Madhav had shown carrier male. His answer was marked incorrect. Madhav was wondering why his marks were cut. Explain the reason.
Answer:
Males can never be carriers. They have single X and other Y chromosome. In X linked inheritance, the genes are present on the non-homologous region of X chromosome. Males do not have other X and hence if the genes are present on his X chromosome, they will not be suppressed in them. The Y chromosome does not have dominant gene to hide this expression as there is no homolorous region too. But in case of females, there are double X chromosomes and hence if X-linked gene is recessive, the other X can hide the expression of such X-linked gene.

Thus she becomes a carrier without showing any physical characters. She is physically normal and does not suffer from such X-linked recessive disorder. Thus, Madhav will get his answer wrong due to incorrect concept.

Question 6.
With the help of neat labelled diagram, describe the structure of chromosome.
Answer:
Maharashtra Board Class 12 Biology Solutions Chapter 3 Inheritance and Variation 6
(1) A chromosome is best visible during metaphase, when it is highly condensed.

(2) Chromosome shows two identical halves, called sister chromatids. Chromatids are held together at centromere which is also called primary constriction.

(3) Primary constriction has disc shaped plate called kinetochore. This plate is useful for attachment of spindle fibres at the time of cell division.

(4) Additional narrow areas called secondary constrictions are seen in some chromosomes which are known as nucleolar organizers. They help in the formation of nucleolus. At secondary constriction (i) there is nucleolar organising region. Secondary constriction (ii) shows attachment of satellite body or SAT body.

(5) Each chromatid is made up of sub¬chromatids called chromonemata. Each chromonema consists of a long, unbranched, slender, highly coiled DNA thread. This double stranded DNA molecule extends throughout the length of the chromosome.

(6) The ends of the chromatid arms are called telomeres.

Question 7.
What is criss-cross inheritance? Explain with suitable example.
Answer:
Criss-cross inheritance is the type of inheritance in which the genes are passed on from father to daughter and then to her son, i.e. from male to female and from female to male (grandson). In other words, it is also said that the transmission is from the grandfather to his grandson through his daughter.

I. Inheritance of Colour blindness show criss-cross pattern.
(1) Colour blindness is a sex-linked disorder in which the person concerned cannot distinguish between red and green colours.

(2) It is recessively X-linked disorder, which is expressed in males. It is rarely seen in females.

(3) The genes for normal vision are dominant whereas those for colour blindness are recessive.

(4)

  • Gene for normal vision : XC
  • Gene for colour blindness : Xc
  • Normal female : XCXC
  • Normal male : XCY
  • Colour blind female : XcXc
  • Carrier female : XCXc
  • Colour blind male : Xc Y

II. Crosses showing the inheritance of colour blindness:
(i) A cross between normal female and colour-blind male.
Maharashtra Board Class 12 Biology Solutions Chapter 3 Inheritance and Variation 7

(ii) A cross of carrier female with normal male.
Maharashtra Board Class 12 Biology Solutions Chapter 3 Inheritance and Variation 8

(1) Normal female with Colour blind male. Such cross produces 50% carrier daughters and 50% normal sons.

(2) Carrier female with normal male. Such a cross produces 25% normal daughters, 25% normal sons, 25% carrier daughters and 25% colour blind sons.

(3) Colour blind father transmits the disorder to his grandson through his carrier daughter. The inheritance of characters from the father to his grandson through his daughter is called criss-cross inheritance.

Maharashtra Board Class 12 Biology Solutions Chapter 3 Inheritance and Variation

Question 8.
Describe the different types of chromosomes.
Answer:
I. Chromosomes are classified into the following four types according to the position of the centromere in them:
(1) Metacentric : In metacentric chromosome, the centromere is situated in the middle of the chromosome. The two arms of the chromosome are nearly equal. It appears ‘V’-shaped during anaphase.

(2) Sub-metacentric : In sub-metacentric chromosome, the centromere is situated some distance away from the middle. Due to this, one arm of the chromosome is shorter than the other. It appears T-shaped during anaphase.

(3) Acrocentric : In acrocentric chromosome, the centromere is situated near the end of the chromosome. One arm of the acrocentric chromosome is very short while the other is long making it appear like ‘J’-shaped during anaphase.

(4) Telocentric : In telocentric chromosome, the centromere is situated at the tip of the chromosome. Telocentric chromosome has only one arm thus it appears rod-shaped.

II. Based on the functions, chromosomes are divided into autosomes and allosomes. Autosomes are somatic chromosomes which decide the body characters. Allosomes are sex chromosomes which decide the sex of the individual.

Maharashtra State Board 12th Std Biology Textbook Solutions

12th Biology Chapter 2 Exercise Reproduction in Lower and Higher Animals Solutions Maharashtra Board

Reproduction in Lower and Higher Animals Class 12 Exercise Question Answers Solutions Maharashtra Board

Balbharti Maharashtra State Board 12th Biology Textbook Solutions Chapter 2 Reproduction in Lower and Higher Animals Textbook Exercise Questions and Answers.

Class 12 Biology Chapter 2 Exercise Solutions Maharashtra Board

Biology Class 12 Chapter 2 Exercise Solutions

1. Multiple choice questions

Question 1.
The number of nuclei present in a zygote is ……………….
(a) two
(b) one
(c) four
(d) eight
Answer:
(b) one

Question 2.
Which of these is the male reproductive organ in human?
(a) Sperm
(b) Seminal fluid
(c) Testes
(d) Ovary
Answer:
(c) Testes

Maharashtra Board Class 12 Biology Solutions Chapter 2 Reproduction in Lower and Higher Animals

Question 3.
Attachment of embryo to the wall of the uterus is known as ……………….
(a) fertilization
(b) gestation
(c) cleavage
(d) implantation
Answer:
(d) implantation

Question 4.
Rupturing of follicles and discharge of ova is known as ……………….
(a) capacitation
(b) gestation
(c) ovulation
(d) copulation
Answer:
(c) ovulation

Question 5.
In human females, the fertilized egg gets implanted in uterus ……………….
(a) after about 7 days of fertilization
(b) after about 30 days of fertilization
(c) after about two months of fertilization
(d) after about 3 weeks of fertilization
Answer:
(a) after about 7 days of fertilization

Question 6.
Test tube baby technique is called ……………….
(a) In vivo fertilization
(b) In situ fertilization
(c) In Vitro Fertilization
(d) Artificial Insemination
Answer:
(c) In Vitro Fertilization

Question 7.
Maharashtra Board Class 12 Biology Important Questions Chapter 2 Reproduction in Lower and Higher Animals 1
The given figure shows a human sperm. Various parts of it are labelled as A, B, C, and D. Which labelled part represents acrosome?
(a) B.
(b) C
(c) D
(d) A
Answer:
(d) A

Question 8.
Presence of beard in boys is a ……………….
(a) primary sex organ
(b) secondary sexual character
(c) secondary sex organ
(d) primary sexual character
Answer:
(b) secondary sexual character

2. Very short answer questions

Question 1.
What is the difference between a foetus and an embryo?
Answer:
Embryo is a growing egg after fertilization until the main parts of the body and the internal organs have started to take shape while foetus is a stage which has the appearance of a fully developed offspring.

Question 2.
Outline the path of sperm up to the urethra.
Answer:
The path of sperm up to the urethra in male is as follows :
Seminiferous tubules → Rete testis → Vasa efferentia → Epididymis → Vas deferens → Ejaculatory ducts Urethra.

Question 3.
Which glands contribute fluids to the semen?
Answer:
The glands which contribute fluids to the semen are seminal vesicles, prostate gland.

Maharashtra Board Class 12 Biology Solutions Chapter 2 Reproduction in Lower and Higher Animals

Question 4.
Name the endocrine glands involved in maintaining the sexual characteristics of males.
Answer:
Interstitial cells of Leydig which lie in between the seminiferous tubules are involved in maintaining the sexual characteristics of male by secreting the male hormone androgen or testosterone. Adenohypophysis also regulates this secretion from the testis.

Question 5.
Where does fertilization and implantation occur?
Answer:
Fertilization of ovum takes place in the ampulla region of fallopian tube whereas implantation occur in the endometrium of uterus.

Question 6.
Enlist the external genital organs in female.
Answer:
The external genital organs in female include the following parts such as vestibule, labia minora, clitoris, labia majora and mons Veneris.

Question 8.
What is the difference between embryo and zygote?
Answer:
Zygote is the unicellular diploid structure formed as a result of fusion of sperm and ovum whereas embryo is a multicellular structure formed from zygote in the uterus 3 weeks after fertilization.

3. Fill in the blanks

Question 1.
The primary sex organ in human male is ……………….
Answer:
testis

Question 2.
The ……………… is also called the womb.
Answer:
uterus

Question 3.
Sperm fertilizes ovum in the ……………….. of fallopian tube.
Answer:
ampulla

Question 4.
The disc like structure which helps in the transfer of substances to and from the foetus’s body is called ………………..
Answer:
placenta

Question 5.
Gonorrhoea is caused by ……………….. bacteria.
Answer:
Neisseria gonorrhoeae

Question 6.
The hormone produced by the testis is ……………………
Answer:
testosterone / androgen.

4. Short Answer Questions

Question 1.
Budding in Hydra.
Answer:
Maharashtra Board Class 12 Biology Important Questions Chapter 2 Reproduction in Lower and Higher Animals 2

  1. Budding is a type of asexual reproduction method seen in Hydra.
  2. Budding takes place during favourable period.
  3. Towards the basal end of the body, small outgrowth is produced which is called a bud.
  4. It grows and forms tentacles and gradually forms a new individual.
  5. The young Hydra after complete development detaches from the parent and becomes an independent new organism.

Question 2.
Explain the different methods of reproduction occurring in sponges.
Answer:

  1. Sponges reproduce both asexually and sexually and they also possess the power of regeneration. Their sexual reproduction is similar to higher animals even though their body organization is primitive type.
  2. Asexual reproduction in sponges takes place by regeneration, budding and gemmule formation.
  3. In sponges, during unfavourable period, gemmule is produced. It is an internal bud.
  4. Archaeocytes which are dormant cells are seen in the aggregation in gemmule. These cells are capable of developing into a new organism.
  5. Amoebocytes are other cells which secrete thick resistant layer of secretion which is coated around archaeocytes.
  6. When favourable conditions of water and temperature return back, the gemmules can develop into new individuals by hatching, e.g. Spongilla.

Maharashtra Board Class 12 Biology Solutions Chapter 2 Reproduction in Lower and Higher Animals

Question 3.
IVF.
Answer:

  1. In laboratory under sterile conditions, oocyte and sperms are placed in a test tube or glass plate to form a zygote. This process is called In Vitro Fertilization.
  2. The zygote with 8 blastomeres is then transferred into the fallopian tube for further development.
  3. IVF technique is used when childless couple wants to have a baby, but there are issues of sterility.
  4. IVF is also called test tube baby technique.

Question 4.
Comment on any two mechanical contraceptive methods.
Answer:
Two mechanical contraceptive methods are as follows:
A. Condom or Nirodh:

  1. It is a protective barrier in the form of thin rubber sheath which is used by male partner during the sexual coitus. It covers the penis and does not allow semen to flow during copulation.
  2. Thus the entry of ejaculated semen into the female reproductive tract is obstructed. This can prevent conception. It is a simple and effective method and has no side effects.
  3. “Nirodh” is a condom, most widely used in India as a contraceptive by males.
  4. Condom also protects both the partners against sexually transmitted diseases such as AIDS and others.

B. Diaphragm, cervical caps and vaults:

  1. Diaphragm and cervical caps are to be used by females as mechanical contraceptive measures.
  2. They are made up of rubber. They are fitted on the cervix in vagina so that they prevent the entry of sperms into the uterus.
  3. They are kept at least six hours after sexual intercourse in order to inhibit sperms from entering female genital tract.

Question 5.
Tubectomy.
Answer:

  1. The permanent birth control method in women, is called tubectomy.
  2. It is a surgical method, also called sterilization.
  3. In tubectomy, a small part of the fallopian tube is tied and cut.
  4. Tubectomy blocks transport of oocytes and also blocks sperms, thus preventing fertilization from reaching the oocyte.

Question 6.
Give the name of causal organism of Syphilis and write on its symptoms.
Answer:
1. Syphilis is a sexually transmitted veneral disease caused by a Spirochaete bacterium Treponema pallidum.

2. The site of infection is the mucous membrane in genital, rectal and oral region.

3. Symptoms of syphilis:

  • Primary lesion known as chancre at the site of infection.
  • They are seen on the external genitalia in males and inside the vagina in females.
  • Skin rashes accompanied by fever, inflammed joints and loss of hair.
  • Paralysis
  • Degenerative changes in the heart and brain.

Question 7.
What is colostrum?
Answer:

  1. The fluid secreted by the mammary glands soon after childbirth is called colostrum.
  2. Colostrum is the sticky and yellow fluid. It contains proteins, lactose and mother’s antibodies, e.g. IgA.
  3. The fat content in colostrum is low.
  4. The antibodies present in colostrum helps in developing resistance for the newborn baby at a time when its own immune response is not fully developed.

5. Answer the Following Questions

Question 1.
Describe the phases of menstrual cycle and their hormonal control.
Answer:
Menstrual cycle (Ovarian cycle):
i. Menstrual cycle involves a series of cyclic, changes in the ovary and uterus. The cyclic events are regulated by gonadotropins from pituitary and the hormones from ovary.
ii. The cyclic events in woman are repeated within approximately 28 days.
iii. Menstrual cycle is divided into following phases, viz.

  1. Menstrual phase (Day 1-5)
  2. Follicular phase in ovary that coincides with proliferative phase in uterus. Post menstrual phase (Day 5-14)
  3. Ovulatory phase (Day 14-15)
  4. Luteal phase in ovary which coincides with secretory phase in uterus (Day 16 to 28).

1. Menstrual Phase:

  • Menstrual phase occurs in the absence of fertilization.
  • During menstruation, uterine endometrium is sloughed off. Level of progesterone and estrogen decrease during this phase resulting into release of prostaglandins which cause this rupture.
  • Blood about 45-100 ml, tissue fluid, mucus, endometrial lining and unfertilized oocyte and other cellular debris is discharged through vagina as a menstrual flow. The endometrial lining becomes about 1 mm thin.
  • Fibrinolysin does not allow blood to clot during this period.
  • Pituitary starts secreting FSH, which further makes many primordial follicles to develop into primary and few of them into secondary follicles.

2. Proliferative phase/Follicular phase/Post menstrual phase:

  • During this phase in the ovary the follicles develop while in uterus the endometrium starts proliferating. 6 to 12 secondary follicles start developing but usually only one of them becomes Graafian follicle due to action of FSH.
  • Developing secondary follicles secrete the hormone estrogen.
  • Estrogen brings about regeneration of endometrium. Further proliferation of endometrium causes formation of endothelial cells, endometrial or uterine glands and network of blood vessels. Endometrium’s thickness becomes 3-5 mm.

(3) Ovulatory phase:

  • Ovulation occurs in this phase. Mature Graafian follicle ruptures and secondary oocyte is released into the pelvic region of abdomen.
  • Ovulation occurs due to surging quantity of LH from pituitary.

(4) Luteal phase/Secretary phase :
(i) Since the empty Graafian follicle converts itself into corpus luteum under the influence of LH, this phase is called luteal phase in ovary. At the same time, the uterine endometrium thickens and becomes more secretory and hence it is called secretory phase in uterus.

(ii) Corpus luteum secretes progesterone, some amount of estrogens and inhibin. These hormones stimulate the growth of endometrial glands which later start uterine secretions.

(iii) Endometrium becomes more vascularized becomes 8-10 mm. in thickness. These changes are the preparation for the implantation of the ovum if fertilization occurs.

(iv) In absence of fertilization, corpus luteum can survive for only two weeks and then degenerate into a non-secretory white scar called corpus albicans.

(v) If ovum is fertilized, woman becomes pregnant and hormone hCG (human Chorionic Gonadotropin) is secreted by chorionic membrane of embryo which keeps corpus luteum active till the formation of placenta.

Question 2.
Explain the steps of parturition.
Answer:
Parturition involves the following three steps:
1. Dilation stage:

  • Dilation stage means dilating the birth canal or passage though which baby is pushed out. In the beginning uterine contractions start from top and baby is moved to cervix. Due to compression of blood vessels and movements of flexible joints in pelvic girdle, mother experiences labour pains.
  • Oxytocin is secreted later in more amount causing severe uterine contractions. This pushes baby in a head down position and closer to cervix.
  • Cervix and vagina both are dilated.
  • This stage lasts for about 12 hours.
  • At the end, amniotic sac ruptures and amniotic fluid is passed out.

2. Expulsion stage:

  • During second stage of about 20 to 60 minutes, the uterine and abdominal contractions become stronger.
  • Foetus moves out with head down position through cervix and vagina.
  • The umbilical cord which connects the baby to placenta is tied and cut off close to the baby’s navel.

3. After birth or placental stage : In the last stage of 10 to 45 minutes, once the baby is out then the placenta is also separated from uterine wall and is expelled out as “after birth”. This is accompanied by severe contractions of the uterus.

Maharashtra Board Class 12 Biology Solutions Chapter 2 Reproduction in Lower and Higher Animals

Question 3.
Explain the histological structure of testis.
Answer:
Histological structure of testis:
Maharashtra Board Class 12 Biology Important Questions Chapter 2 Reproduction in Lower and Higher Animals 3

  1. The external covering of testis is a fibrous connective tissue called tunica albuginea.
  2. Then there is an incomplete peritoneal covering called tunica vaginalis.
  3. Interior to this there is a covering called tunica vascularis formed by capillaries.
  4. The testis is composed of many seminiferous tubules that are lined by cuboidal germinal epithelial cells.
  5. In the seminiferous tubules various stages of developing sperms are seen as spermatogenesis takes place here. These stages are spermatogonia, primary and secondary spermatocytes, spermatids and sperms.
  6. Large, pyramidal sub tentacular cells, nurse cells or Sertoli cells are present between germinal epithelium. Sperm bundles remain attached to Sertoli cells with their heads.
  7. Seminiferous tubules form sperms whereas Sertoli cells provide nourishment to the sperms till maturation.
  8. In between the seminiferous tubules there are interstitial cells of Leydig which are endocrine in nature. They secrete testosterone.

Question 4.
Describe the structure of blastocyst or blastulation
Answer:
Maharashtra Board Class 12 Biology Important Questions Chapter 2 Reproduction in Lower and Higher Animals 4

  1. The outer layer of cells of the morula is called trophoblast or trophoectoderm. This layer absorbs the nutritive fluid secreted by uterine endometrial membrane.
  2. As more and more fluid is absorbed by trophoblast cells, the cells become flat and a cavity called blastocyst cavity or blastocoel or segmentation cavity is formed.
  3. This causes trophoblast cells to get separated from inner cell mass except at one side.
  4. The trophoblast cells in contact with embryonal knob are known as cells of Rauber. As the quantity of fluid increases, the morula enlarges rapidly and assumes the shape of a cyst. This stage is called blastocyst.
  5. The side of the blastocyst to which embryonal knob is attached is known as the embryonic or animal pole and the opposite side as abembryonic pole.
  6. The trophoblast produces extra embryonic membranes and does not participate in the formation of embryo proper.
  7. Zona pellucida disappears allowing the blastula to increase in size and volume. The blastocyst stage is reached in about five days after fertilization.
  8. Blastocyst depends on mother for nutrition which it obtained through placenta.

Question 5.
Explain the histological structure of ovary in human.
Answer:
Histological structure of ovary:
(1) Each ovary is a compact structure differentiated into a central part called medulla and the outer part called cortex.

(2) The cortex is covered externally by a layer of germinal epithelium while the medulla contains the stroma or loose connective tissue with blood vessels, lymph vessels and nerve fibres.

(3) Different stages of developing ovarian follicles are seen in the cortex. Each primordial follicle has at its centre a large primary oocyte (2n) surrounded by a single layer of flat follicular cells, then gradually it matures.

(4) In the ovary during each menstrual cycle there is a maturation of primordial follicles into multilayered primary, secondary and Graafian follicles.

(5) Every Graafian follicle has three layers, viz. theca externa, theca interna and membrana granulosa which are from outer to inner side. A space called antrum filled with liquor folliculi is present inside the follicle. There is a small hillock of cells called cumulus oophours or discus proligerus over which the ovum is lodged. The ovum in turn is covered by vitelline membrane, zona pellucida and corona radiata from inner side to outer surface.

(6) Ovarian cortex also shows corpus luteum, or yellow body formed from empty Graafian follicle after ovulation. Corpus luteum is converted into corpus albicans or white body in case of absence of conception.
Maharashtra Board Class 12 Biology Important Questions Chapter 2 Reproduction in Lower and Higher Animals 5

Question 6.
Describe the various methods of birth control to avoid pregnancy.
Answer:
Birth control/Contraceptive methods are of two main types, viz. temporary and permanent.
A. Temporary methods:
(1) Natural method/Safe period/Rhythm method : A week before and a week after menstrual bleeding is considered the safe period for sexual intercourse. It is based on the fact that ovulation occurs on the 14th day of menstrual cycle.

(2) Coitus Interruptus or withdrawal : In this method, the male partner withdraws his penis from the vagina before ejaculation, so as to avoid insemination. This method also has some drawbacks, as the pre-ejaculation fluid may contain sperms and this can cause fertilization.

(3) Lactational amenorrhoea (absence of menstruation) : This method is based on the fact that ovulation does not occur during the period of intense lactation following parturition so chances of conception are almost negligible. However, this method also has high chances of failure.

(4) Chemical means (spermicides) : In this method chemicals like foam, tablets, jellies and creams are introduced into the vagina before sexual intercourse, they adhere to the mucous membrane, immobilize and kill the sperms.

(5) Mechanical means/Barrier methods:
(i) Condom : It is a thin rubber sheath that is used to cover the penis of the male. Condom should be used before starting coital activity. It also prevents STDs and AIDS.

(ii) Diaphragm, cervical caps and vaults : These devices made of rubber are inserted into the female reproductive tract to cover the cervix diming copulation. They prevent conception by blocking the entry of sperms through the cervix.

(iii) Intra-uterine devices (IUDs) : These are plastic or metal objects placed in the uterus by a doctor. These include Lippes loop, copper releasing IUDs (Cu-T, Cu 7, multiload 375) and hormone releasing IUDs (LNG-20, progestasert). They prevent fertilization of the egg or implantation of the embryo.

(6) Physiological (Oral) Devices : Birth control pills (oral contraceptive pills) check ovulation as they inhibit the secretion of follicle stimulating hormone (FSH) and luteinizing hormone (LH) that are necessary for ovulation. The pill ‘Saheli’ is taken weekly.

(7) Other contraceptives : The birth control implant is similar to that of pills in their mode of action. It is implanted under the skin of the upper arm of the female.

B. Permanent methods surgical operations : In men surgical operation is called vasectomy and in women it is called tubectomy. This method blocks gamete transport and prevent pregnancy.

Question 7.
What are the goals of RCH programmes?
Answer:
Goals of RCH programmes are as follows:

  1. Various aspects related to reproduction are made aware to general public.
  2. Facilities are provided to people to understand and build up reproductive health.
  3. Support is given for building up a reproductively healthy society.
  4. Three critical health indicators, i.e. reducing total infertility rate, infant mortality rate and maternal mortality rate are well looked after.

Question 8.
What is parturition? Which hormones are involved in parturition?
Answer:

  1. Parturition is the act of expelling out the mature foetus from the uterus of mother via the vagina.
  2. When the foetus is fully mature, it starts secreting ACTH (Adreno Cortico Trophic Hormone) from its pituitary.
  3. ACTH stimulates adrenal glands of foetus to produce corticosteroids.
  4. These corticosteroids diffuse from foetal blood to mother’s blood across the placenta. Corticosteroids accumulate in mother’s blood that results in decreased amount of progesterone. Corticosteroids also increase secretion of prostaglandins.
  5. Simultaneously estrogen levels rise bringing about initation of contractions of uterine muscular wall.
  6. Reduced progesterone level and increased estrogen level cause secretion of oxytocin from mother’s pituitary. This causes greater stimulation of myometrium of uterus.
  7. Prostaglandins cause increased forceful contraction of uterus which expels the foetus out of the uterus.
  8. Hormone relaxin secreted by the placenta makes the pubic ligaments and sacroiliac joints of the mother loosen. This causes widening of birth canal which facilitates the normal birth of the baby.

Question 9.
What are the functions of male accessory glands?
OR
Write a brief account of accessory sex glands associated with human male reproductive system.
Answer:
Seminal Vesicles, prostate gland and Cowper’s glands are associated with human male reproductive system.
(i) Seminal Vesicles:

  1. Seminal vesicles occur in pair present on the posterior side of urinary bladder. Its secretion consists about 60% of the total volume of the semen. The secretion is an alkaline seminal fluid containing fructose, fibrinogen and prostaglandins.
  2. Fructose helps in the movement of sperms by providing energy to them.
  3. Semen is coagulated in bolus by fibrinogen. This helps in faster movements of sperms in vagina after insemination.
  4. Reverse peristalsis in vagina and uterus for faster movement of sperms towards the egg in the female body is elided by prostaglandins.

(ii) Prostate gland:

  1. It is a single gland located under the urinary bladder. It has about 20 to 30 separate lobes which open separately into the urethra.
  2. Prostatic fluid secreted by this gland is milky white and slightly acidic. It forms 30 % of the semen and is secreted in urethra.
  3. Its contents are citric acid, acid phosphatase and various other enzymes.
  4. The sperms are protected from the acidic environment of vagina by acid phosphatase.

(iii) Cowper’s glands (Bulbo-urethral glands):

  1. Cowper’s glands occur in pair on either side of urethra. They are small and pea shaped.
  2. Cowper’s glands secrete an alkaline, viscous, mucous-like fluid. It helps as lubricant during copulation.

Question 10.
What is capacitation? Give its importance.
Answer:

  1. Capacitation is the process by which the sperms are made capable to swim up to the fallopian tubes. This process takes place in 5-6 hours.
  2. 50% of ejaculated sperms die due to unfavourable vaginal and uterine conditions.
  3. The remaining sperms are capacitated with the help of prostaglandin and vestibular secretions of female tract. It involves the changes in the membrane covering the acrosome.
  4. Due to capacitation, acrosome membrane becomes thin, Calcium ions enters the sperm and their tail begin to show rapid whiplash movements.
  5. Sperms become extra active and then they ascend upwards to reach fallopian tubes.
  6. After capacitation the sperms swim through the vagina and uterus and reach ampulla of fallopian tube within 5 minutes.

Long answer questions

Question 1.
Explain the following parts of male reproductive system along with labelled diagram showing these parts – Testis, vasa deferentia, epididymis, seminal vesicle, prostate gland and penis.
OR
With the help of a neat, labelled diagram, describe the human male reproductive system.
Answer:
Maharashtra Board Class 12 Biology Important Questions Chapter 2 Reproduction in Lower and Higher Animals 6
(i) Testis, the male gonad, the accessory ducts and glands along with external genitalia form the male reproductive system.

(ii) Testes:

  1. Testes are male gonads with dimensions of about 4.5. cm length, 2.5 cm width and 3 cm thickness.
  2. There are about 200 to 300 lobules in each testis in which there are seminiferous tubules that form rete testis.
  3. Testes produce sperms and secrete male sex hormone, androgen or testosterone.

(iii) Accessory ducts : Rete testis, vasa efferentia, epididymis, vas deferens, ejaculatory duct and urethra together form the accessory ducts of male reproductive system.
1. Vasa efferentia : Vasa efferentia are 12-20 fine tubules. They arise from rete testis and end into the epididymis. The sperms from the testis are carried by these ducts to the epididymis.

2. Epididymis : Epididymis are long and coiled tubes having three parts, viz. caput, corpus and cauda epididymis. They are located on the posterior border of each testis. The sperms undergo maturation in epididymis.

3. Vasa deferentia:

  • Vasa deferentia are a pair of 40 cm long tubular structures that arise from cauda epididymis.
  • Each vas deferens enters the abdominal cavity through the inguinal canal and then ascends in the form of spermatic cord.
  • Vas deferens of each side is joined by the duct from seminal vesicle to form ejaculatory duct.

4. Ejaculatory duct : About 2 cm long pair of ducts formed by joining of vas deferens and a duct of seminal vesicle are the ejaculatory ducts. Both ejaculatory ducts open into urethra near the prostate gland. Seminal fluid containing spermatozoa are carried by ejaculatory duct to the urethra.

Maharashtra Board Class 12 Biology Solutions Chapter 2 Reproduction in Lower and Higher Animals

5. Urethra : The male urethra provides a common passage for the urine and semen hence is also called urinogenital duct.

(iv) Accessory glands : Associated with male reproductive system are : (a) Seminal vesicles (b) Prostate gland and (c) Cowper’s or Bulbourethral glands. Every accessory gland has secretion which helps in functions of reproductive system.

(v) External genitalia : External genitalia consists of penis and scrotum.
1. Penis:

  • Penis is the copulatory organ used for insemination or deposition of sperms in female genital tract.
  • It is cylindrical, erectile and pendulous organ through which passes the urethra.
  • It contains three columns of erectile tissues which has abundant blood sinuses.
  • The tip is called glans penis while the retractible fold of skin on penis is called prepuce.

2. Scrotum : The scrotum is a pouch of pigmented skin arising from lower abdominal wall. It protects testes within it. Scrotum acts as thermoregulator. Testis are suspended in scrotum by spermatic cord.

Question 2.
Describe female reproductive system of human
Answer:
Maharashtra Board Class 12 Biology Important Questions Chapter 2 Reproduction in Lower and Higher Animals 7
The female reproductive system consists of internal organs and external genitalia.

Internal organs are pair of ovaries and pair of fallopian ducts or oviducts, single median uterus and vagina. External genitalia is called vulva. There are a pair of vestibular glands in external genitalia. Mammary glands or breasts are also associated with reproductive system of female.

(1) Ovaries:

  • Ovaries are situated in the abdomen in upper lateral part of the pelvis near the kidneys. Their dimensions are about 3 cm in length, 1.5 cm in breadth and 1.0 cm thick. They are solid, oval or almond shaped organs.
  • Ovaries produce ova and they are also endocrine in nature as they produce estrogen, progesterone, relaxin, activin and inhibin.
  • Ovarian hormones bring about secondary sexual characters. They also control menstrual cycle, pregnancy and parturition.

(2) Fallopian tubes/oviducts:
(i) Fallopian tubes lie horizontally over peritoneal cavity. These are about 10 to 12 cm long, narrow, muscular structure lined by ciliated epithelium.
(ii) They transport the ovum after ovulation from the ovary to the uterus.
(iii) Fallopian tube can be subdivided into the following three parts:

  • The infundibulum which bears a number of finger-like processes called fimbriae at its free border.
  • Infundibulum is funnel-shaped having ostium which receives ova released from the ovary.
  • The second part is the ampulla where the fertilization takes place.
  • The last part is short cornua or isthmus which opens into the uterus.

(3) Uterus/Womb:
(i) Uterus is a pear-shaped, highly muscular, thick walled, hollow organ measuring about 8 cm in length, 5 cm in width and 2 cm in thickness.

(ii) Uterus has the following three parts : Fundus, Body or corpus and Cervix.

(iii) The cervix communicates above with the body of the uterus by an aperture, the internal os and with vagina below by an opening the external os.

(iv) Uterus has three-layered wall. These layers are:

  • Perimetrium : An outer serous layer.
  • Myometrium : The middle thick muscular layer of smooth muscles.
  • Endometrium : The inner highly vascular mucosa that has many uterine glands.

(v) Uterus receives the ovum from fallopian tube. It develops placenta during pregnancy for the nourishment of foetus. At the time of parturition, it expels the young one at birth.

(4) Vagina:

  • Vagina is a highly distensible fibro-muscular tube that lies between the cervix and the vestibule.
  • It is about 7 to 9 cm in length and is internally lined by stratified and non- keratinised epithelium. The vaginal wall has inner mucous lining.
  • Vagina acts as a birth canal as well as copulatory passage. It also allows passage of menstrual flow.
  • Vagina opens into vestibule by vaginal orifice which may be covered with hymen which is also a mucous membrane.

(5) External genitalia or vulva or pudendum : The external genitalia consists of five parts; viz. labia majora, labia minora, mons veneris, clitoris and vestibule.

(6) A pair of vestibular glands / Bartholin’s glands : These glands open into the vestibule and release a lubricating fluid.

(7) A pair of mammary glands/breasts : These are the accessory organs of female reproductive system for production and release of milk after parturition.

Question 3.
Describe the process of fertilization.
Answer:
(1) Fertilization is the process of fusion of the haploid male and female gametes which results in the formation of a diploid zygote (2n).

(2) In human beings fertilization is internal. Sperms deposited in vagina, swim across the uterus and fertilize the ovum in ampulla of the fallopian tube.

(3) Fertilization involves the following events:
(i) Insemination : Discharge of semen into the vagina at the time of copulation is called insemination.

(ii) Movement of sperm towards egg : Sperms reaching the vagina undergo capacitation process for 5-6 hours. During capacitation acrosomal membrane of sperm becomes thin and Ca++ enters the sperm making it extra active. Sperms reach up to the ampulla by swimming aided with contraction of uterus and fallopian tubes. These contractions are stimulated by oxytocin of female. By capacitation sperm can reach ampulla within 5 minutes, they remain 5 viable for 24 to 48 hours, whereas ovum remains viable for 24 hours.

(iii) Entry of sperm into the egg : Though many sperms reach the ampulla, only a single sperm fertilizes the ovum. The acrosome of sperm after coming in contact with the ovum, releases lysins; hyaluronidase and corona penetrating enzymes. Due to these enzymes cells of corona radiata are separated and dissolved. The sperm head then passes through zona pellucida of egg. The zona pellucida has glycoprotein fertilizin receptor proteins. These bind to specific acid protein-antifertilizin of sperm. This makes sperm and ovum to come together. Fertilizin-Antifertilizin interaction is species- specific.

(iv) Acrosome reaction : When the sperm head comes in contact with the zona pellucida, its acrosome covering ruptures to release lytic enzymes, acrosin or zona lysin. These enzymes dissolve plasma membrane of egg so that the sperm nucleus and the centrioles enter the egg, while other parts remain outside. Now the vitelline membrane of egg changes into fertilization membrane which prevents any further entry of other sperms into the egg, thus polyspermy is prevented.

(v) Activation of ovum : After the entry of sperm head into ovum, it gets activated to resume and complete its meiosis-II. With this it gives out the second polar body. The germinal vesicle organises into female pronucleus. At this stage, it is true ovum.
Maharashtra Board Class 12 Biology Important Questions Chapter 2 Reproduction in Lower and Higher Animals 8

(vi) Fusion of egg and sperm : The coverings of male and female pronuclei degenerate results in the formation of a synkaryon by a process called syngamy or karyogamy. The zygote is thus formed.

Question 4.
Explain the process by which zygote divides and redivides to form the morula.
Answer:
(1) Cleavage is a rapid mitotic division to form a blastula. These divisions takes place immediately after fertilization. The cells formed by cleavage are called blastomeres.

(2) The type of cleavage in human is holoblastic, i.e. the whole zygote gets divided, radial and indeterminate, i.e. fate of each blastomere is not predetermined.

(3) Cleavage show faster synthesis of DNA and high consumption of oxygen.

Maharashtra Board Class 12 Biology Solutions Chapter 2 Reproduction in Lower and Higher Animals

(4) Since there is no growth phase between the cleavages, the size of blastomeres will be reduced with every successive cleavage.
Maharashtra Board Class 12 Biology Important Questions Chapter 2 Reproduction in Lower and Higher Animals 9

(5) The cleavages occur as follows:
Maharashtra Board Class 12 Biology Important Questions Chapter 2 Reproduction in Lower and Higher Animals 10

(6) Successive divisions produce a solid ball of cells called morula of 16 cells. It consists of an outer layer of smaller clearer cells and an inner mass of larger cells.

(7) Morula reaches the uterus about 4-6 days after fertilization.

Maharashtra State Board 12th Std Biology Textbook Solutions

Introduction to Acid and Base Class 8 Science Chapter 12 Questions And Answers Maharashtra Board

Std 8 Science Chapter 12 Introduction to Acid and Base Question Answer Maharashtra Board

Balbharti Maharashtra State Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base Notes, Textbook Exercise Important Questions and Answers.

Class 8 Science Chapter 12 Introduction to Acid and Base Question Answer Maharashtra Board

Class 8 Science Chapter 12 Introduction to Acid and Base Textbook Questions and Answers

1. Identify the following solutions, whether they are acid or base.

Question a.
Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base 1
Answer:
Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base 2

2. Write chemical names from given formulae.
H2SO4, Ca(OH)2, HCl, NaOH, KOH, NH4OH

Question a.
Write the chemical names from given formulae: H2SO4, Ca(OH)2, HCl, NaOH, KOH, NH4OH
Answer:

  1. H2SO4 – Sulphuric acid
  2. Ca(OH)2 – Calcium hydroxide
  3. HCl – Hydrochloric acid
  4. NaOH – Sodium hydroxide
  5. KOH – Potassium hydroxide
  6. NH4OH – Ammonium hydroxide

Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base

3. Sulphuric acid has highest importance in chemical Industry. Why?

Question a.
Sulphuric acid has highest importance in chemical Industry. Why?
Answer:
Answer:
Sulphuric acid has highest importance in the chemical industry because it is used in the manufacturing of fertilizers like ammonium sulphate and superphosphate of lime. It is used in the manufacturing of hydrochloric acid, nitric acid, phosphoric acid, ether, plastics and metal sulphates. It is also used in the manufacturing of dyes, drugs, perfumes, disinfectants and glue.

4. Give answers.

Question a.
Which acid is used for getting chloride salt?
Answer:
Hydrochloric acid is used for getting chloride salt.

Question b.
By squeezzing lemon on a piece of rock the gas liberated turned lime water milky. Which compound is present in the rock?
Answer:
Metal carbonate is present in the rock.

Question c.
The label on the bottle of chemical is spoiled. How will you find whether the chemical is acidic or not?
Answer:
The chemical is tested with blue litmus paper. If it turns red it is an acidic otherwise tested with red litmus paper, if it turns blue, it is an alkaline.

Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base

5. Answer the following questions. 

Question a.
Explain the difference between acid and base.
Answer:
Acids:

  1. Acids have sour taste.
  2. Acids turn blue litmus red.

Bases:

  1. Bases have bitter taste.
  2. Bases turn red litmus blue.

Question b.
Why indicator does not affect by salt?
Answer:
Mostly indicators are organic compounds which do not react with a salt.

Question c.
Which substances are produced i by neutralization process?
Answer:
Salt and water are produced in the f neutralization process.

Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base

Question d.
Which are the industrial uses of acids?
Answer:
Acids which are used in the industry are:

  1. Sulphuric acid
  2. Hydrochloric acid
  3. Nitric acid.;

1. Sulphuric acid: Sulphuric acid is 5 used (a) in the manufacture of chemical? fertilizers like ammonium sulphate, (b) for cleaning gold and silver articles and (c) in car batteries.

2. Hydrochloric acid: Hydrochloric acid is used (a) to clean toilets and (b) to obtain glucose from starch and also for producing gelatine.

3. Nitric acid: Nitric acid is used (a) in the manufacture of perfumes (b) for engraving on copper, brass or silver and (c) in the manufacture of paints and explosives.

6. Select proper word given in bracket and fill in the blanks.

Question a.
Main constituent of acid is ……………. .
Answer:
Main constituent of acid is H+ ion.

Question b.
Main constituent of alkali is …………….. .
Answer:
Main constituent of alkali is OH ion.

Question c.
Tartaric acid is a …………… acid.
Answer:
Tartaric acid is a weak acid.

Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base

7. Match the pairs. 

Question a.

Group AGroup B
1. Tamarinda. Acetic acid
2. Curdb. Citric acid
3. Lemonc. Tartaric acid
4. Vinegard. Lactic acid

Answer:

Group AGroup B
1. Tamarindc. Tartaric acid
2. Curdd. Lactic acid
3. Lemonb. Citric acid
4. Vinegara. Acetic acid

8. State true or false.

Question a.
Oxides of metals are alkaline in nature.
Answer:
True.

Question b.
Salt is acidic.
Answer:
False. (Salt is neutral)

Question c.
Metal corrodes due to salts.
Answer:
False. (Acids and bases corrode metals)

Question d.
Salts are neutral.
Answer:
True. (Not all salts neutral)

Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base

9. Classify the following substances into acidic, basic and neutral group:
HCl, NaCl, MgO, KCl, CaO, H2SO4, HNO3, H2O and Na2CO3.

Question a.
Classify the following substances into acidic, basic and neutral group:
HCl, NaCl, MgO, KCl, CaO, H2SO4, HNO3, H2O and Na2CO3.
Answer:

GroupSubstances
AcidHCl, H2SO4, HNO3
BaseCaO, MgO, Na2CO3
NeutralH2O, NaCl, KCl.

Project:

Question a.
Write in your own language the uses and importance of neutralization reaction in daily life.

Class 8 Science Chapter 12 Introduction to Acid and Base Important Questions and Answers

Fill in the blanks:

Question 1.
Acid reacts with metal to form …………. gas.
Answer:
Acid reacts with metal to form hydrogen gas.

Question 2.
DNA is an acid present in our body, it decides …………. properties.
Answer:
DNA is an acid present in our body, it decides heredity properties.

Question 3.
The chemical formula of milk of magnesia is ………….
Answer:
The chemical formula of milk of magnesia is Mg (OH)2.

Question 4.
…………. are used to control hyperacidity.
Answer:
Antacids are used to control hyperacidity.

Question 5.
Alkali has …………. taste.
Answer:
Alkali has bitter taste.

Question 6.
Proteins are made up of ………….
Answer:
Proteins are made up of amino acids.

Question 7.
…………. is used in batteries.
Answer:
Dil. H2SO4 is used in batteries.

Rewrite the following statements by selecting the correct options:

Question 1.
The colour of phenolphthalein indicator in alkaline solution is ………….
(a) yellow
(b) green
(c) orange
(d) pink
Answer:
The colour of phenolphthalein indicator in alkaline solution is pink.

Question 2.
…………. is sour to taste.
(a) An acid
(b) An alkali
(c) A salt
(d) Alcohol
Answer:
An acid is sour to taste.

Question 3.
When phenolphthalein is added to NaOH, the colour of the solution will become ……………… .
(a) colourless
(b) red
(c) pink
(d) yellow
Answer:
When phenolphthalein is added to 5 NaOH, the colour of the solution will become pink.

Question 4.
When phenolphthalein is added to HCl, the colour of the solution will be ………….. .
(a) red
(b) pink
(c) green
(d) colourless
Answer:
When phenolphthalein is added to HCl, the colour of the solution will be colourless.

Question 5.
…………. is a natural indicator.
(a) Phenolphthalein
(b) Methyl orange
(c) Litmus
(d) Methyl red
Answer:
Litmus is a natural indicator.

Question 6.
The litmus paper or the litmus solution is obtained from …………. plants.
(a) moss
(b) rose
(c) hibiscus
(d) lichen
Answer:
The litmus paper or the litmus solution is obtained from lichen plants.

Question 7.
…………. is not an alkali.
(a) Sodium hydroxide
(b) Potassium hydroxide
(c) Copper hydroxide
(d) Calcium hydroxide
Answer:
Copper hydroxide is not an alkali.

Question 8.
…………. is a weak acid.
(a) Hydrochloric acid
(b) Nitric acid
(c) Carbonic acid
(d) Sulphuric acid
Answer:
Carbonic acid is a weak acid.

Question 9.
When methyl orange is added to HCl, the colour of the solution will be …………… .
(a) red
(b) pink
(c) yellow
(d) colourless
Answer:
When methyl orange is added to HCl, the colour of the solution will be pink.

Question 10.
When blue litmus paper is added to NaOH, the colour of the litmus paper will be ……………. .
(a) blue
(b) red
(c) pink
(d) yellow
Answer:
When blue litmus paper is added to NaOH, the colour of the litmus paper will be blue.

State whether the following statements are true or false. If a statement is false, correct it and rewrite:

Question 1.
Red cabbage is a natural indicator.
Answer:
True

Question 2.
Fats of our body are formed by fatty acids.
Answer:
True.

Question 3.
Ammonium hydroxide is used in the production of fertilizers.
Answer:
True.

Question 4.
Lime water is a weak acid.
Answer:
False. (Limewater is a weak base)

Question 5.
Orange colour of methyl orange turns yellow in acid.
Answer:
False. (Orange colour of methyl orange turns pink in acid)

Question 6.
Methyl red turns yellow in alkali.
Answer:
True.

Question 7.
Oxalic acid is used in aerated cold drinks.
Answer:
False. (Carbonic acid is used in aerated cold drinks).

Find the odd one out and justify:

Question 1.
Acetic acid, carbonic acid, hydrochloric acid, nitric acid.
Answer:
Acetic acid. (Others are mineral acids.)

Question 2.
Hydrogen chloride, sodium hydroxide, calcium oxide, ammonia.
Answer:
Hydrogen chloride. (Others are bases.)

Question 3.
HCl, CH3COOH, H2SO4, HNO3
Answer:
CH3COOH. (Others are strong acids.)

Question 4.
NaOH, Ca(OH)2, NH4OH, Ba(OH)2
Answer:
NaOH (Others are weak bases.)

Question 5.
H2SO4, H2CO3, HCl, HNO3
Answer:
H2CO3 (Others are strong acids.)

Question 6.
Citric acid, formic acid, lactic acid, nitric acid.
Answer:
Nitric acid. (Others are organic acids.)

Question 7.
Lime, litmus, phenolphthalein, methyl orange.
Answer:
Lime. (Others are indicators.)

Match the following:

Question 1.

Column ‘A’Column ‘B’
1. Strong acida. Magnesium hydroxide
2. Weak alkalib. Carbonic acid
3. Weak acidc. NaOH
4. Strong alkalid. Nitric acid

Answer:

Column ‘A’Column ‘B’
1. Strong acidd. Nitric acid
2. Weak alkalia. Magnesium hydroxide
3. Weak acidb. Carbonic acid
4. Strong alkalic. NaOH

Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base

Question 2.

Column ‘A’Column ‘B’
1. Sodium hydroxidea. Whitewashing
2. Magnesium hydroxideb. Fertilizers
3. Calcium hydroxidec. Washing soap
4. Ammonium hydroxided. Antacid

Answer:

Column ‘A’Column ‘B’
1. Sodium hydroxidec. Washing soap
2. Magnesium hydroxided. Antacid
3. Calcium hydroxidea. Whitewashing
4. Ammonium hydroxideb. Fertilizers

Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base

Define the following:

1. Acid: A substance which gives H+ ions in water is called an acid.
Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base 3

2. Alkali: A substance which gives OH ions in water is called an alkali.
Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base 4

3. Indicator: Substances which change their colours in presence of acid or base are called indicators.

4. Neutralization: The reaction between an acid and an alkali to form the r salt and water is termed as neutralization.

Answer the following questions in one sentence each:

Question 1.
What are natural acids?
Answer:
Acids present in foodstuffs are called natural acids.

Question 2.
State three vegetables from which natural indicators can be prepared.
Answer:
Natural indicators: Red cabbage, radish, tomato.

Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base

Question 3.
State names of any three strong acids.
Answer:

  1. Hydrochloric acid
  2. Sulphuric acid
  3. Nitric acid.

Question 4.
State the names of the acids found in lemon juice, Amla, tamarind water and curd.
Answer:

  1. Lemonuice – citric acid
  2. Amla – ascorbic acid
  3. tamarind water – tartaric acid
  4. curd – lactic acid.

Question 5.
State names of any three alkalis.
Answer:

  1. sodium hydroxide
  2. potassium hydroxide
  3. calcium hydroxide.

Question 6.
State the names of three indicators.
Answer:

  1. Litmus paper
  2. Methyl orange
  3. Phenolphthalein.

Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base

Question 7.
State the names of three weak alkalis.
Answer:

  1. Calcium hydroxide
  2. ammonium hydroxide
  3. magnesium hydroxide.

Question 8.
From which plant is litmus obtained?
Answer:
Litmus is obtained from plants called lichens.

Question 9.
Name the antacid which is used to control the hyper acidity.
Answer:
Milk of magnesia [Mg(OH)2] is used to control the hyper acidity.

Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base

Question 10.
How will you neutralize the excess of acid present in the soil?
Answer:
Lime stone or lime water is mixed in the soil to neutralize the excess of acid.

Question 11.
When lemonuice falls on a marble kitchen counter, which is the gas that bubbled out?
Answer:
Carbon dioxide.

Answer the following questions:

Question 1.
What are indicators?
Answer:
Substances which change their colours in presence of acid or base are called indicators.

Question 2.
State two acid-base indicators and mention their colour change.
Answer:
Phenolphthalein and methyl orange are two acid-base indicators. Phenolphthalein is colourless in an acidic solution while it turns pink in a basic solution. Methyl orange gives orange colour with an acidic solution and yellow colour with a basic solution.

Question 3.
State the colour change for each of the following solutions with red litmus, blue litmus, phenolphthalein and methyl orange solutions.
Answer:
Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base 5

Question 4.
Name the acid present in (1) Orange (2) Vinegar (3) Tamarind (4) Curd (5) Tomato (6) Lemon.
Answer:

SubstanceAcid
OrangeCitric acid
VinegarAcetic acid
TamarindTartaric acid
CurdLactic acid
TomatoOxalic acid
LemonCitric acid

Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base

Question 5.
Classify the following into acidic substances, basic substances and salts.
(1) Lime water, (2) soda water, (3) soap water, (4) sea water, (5) sweet limeuice, (6) sugar caneuice, (7) buttermilk, (8) a mixture of ash in water, (9) tamarind water.
Answer:
a. Acidic substances: (1) Soda water, (2) sweet limeuice, (3) buttermilk, (4) tamarind water.
b. Basic substances: (1) Lime water, (2) Soap water, (3) a mixture of ash in water.
c. Salts: (1) Sea water, (2) sugar caneuice.

Question 6.
What happens when sour substances like limeuice, tamarind water falls on shahabad stones or kitchen platform? Why?
Answer:
When sour substances like limeuice, tamarind water falls on shahabad stones or kitchen platform, citric acid present in limeuice and tartaric acid in tamarind water reacts with metal carbonates present in shahabad stones or kitchen platform, carbon dioxide gas is evolved resulting in the formation of uneven surface.

Question 7.
Collect soil samples from your surroundings and find out whether it is acidic or alkaline or neutral?
Answer:
Soil samples collected from the surroundings are acidic in nature.

Question 8.
Which substances are used to clean greenish stains on copper vessels and to shine blackish silver utensils?
Answer:
Tamarind pulp is used to clean greenish stains on copper vessels. To shine blackish silver utensils, ammoniacal solution or limeuice or detergent is used.

Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base

Question 9.
Why toothpaste is used for brushing teeth?
Answer:

  1. Toothpaste contains fluorides and alkali to neutralize the mouth acid.
  2. Hence, the tooth paste, which is generally alkaline, is used for cleaning the teeth as it can neutralize the excess acid in i the mouth and prevent tooth decay.

Question 10.
State the properties of acids.
Answer:

  1. Acids are sour in taste.
  2. Acid molecules contain hydrogen ion (H+) as a main constituent.
  3. Acid reacts with metal to form hydrogen gas.
  4. Acid reacts with carbonates and liberates CO2 gas.
  5. Blue litmus turns red in acid.

Question 11.
State the uses of acids.
Answer:

  1. Acids are used in the production s of chemical fertilizers.
  2. Acids are used in the production of explosives, oil purification, medicines, dyes and paints.
  3. Hydrochloric acid is used for the preparation of different types of chloride salts.
  4. Dil. H2SO4 acid is used in the batteries (electric cell).
  5. Dil. HCl is used for sterilization of water.
  6. Acid is used for making of white paper from wood pulp.

Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base

Question 12.
The iron knife shines better after cutting the sour fruits like lemon, raw mangoes. Why?
Answer:
Acids present in sour fruits clean and dissolves the salts present on the surface of iron knife as a result iron knife shines better after cutting the sour fruits.

Question 13.
What is meant by neutralization? Give example.
Answer:
When an acid reacts with an alkali to form a salt and water, it is called neutralization.
Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base 6

Give scientific reasons:

Question 1.
When we have stomachache, doctors prescribe medicine containing magnesium hydroxide.
Answer:

  1. There is hydrochloric acid in our stomach which helps in the digestion of food.
  2. Sometimes in the stomach, there is more hydrochloric acid than we need.
  3. This excess acid causes acidity and indigestion resulting in stomachache.
  4. When magnesium hydroxide is administered it neutralizes the extra acid in the stomach.
  5. Therefore, magnesium hydroxide is the best cure for stomachache.
  6. So, when we have stomachache, doctors prescribe medicine containing magnesium hydroxide.

Question 2.
Quicklime or slaked lime is added to the soil.
Answer:

  1. When chemical fertilizers are added to the soil, the soil becomes acidic.
  2. To reduce its acidity quicklime or slaked lime is added to the soil.

Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base

Question 3.
Tarnished and stained copper vessels are brought to a shine by using tamarind pulp.
Answer:
In due course, unus6d copper vessels
are covered with a coating of black copper oxide and other compounds of copper which tarnish the vessel. Tamarind contains tartaric acid. When the vessel is rubbed with tamarind pulp, tartaric acid reacts with copper oxide and removes the layer. Thus, the copper vessel regains its shine.

Question 4.
Copper and brass utensils are tinned.
Answer:
Copper and brass reacts with i organic acids present in food materials and poisonous salts are formed. Tin does not react with organic acids present in food materials. Therefore, copper or brass vessels are tinned.

Distinguish between acid and alkali. OR Distinguish between the following:

Question 1.
Acid and Alkali:
Answer:

AcidAlkali
1. Acid has sour taste.1. Alkali has bitter taste.
2. Acid turns blue litmus red.2. Alkali turns red litmus blue.
3. An acid in an aqueous solution gives H+ ions.3. An alkali in an aqueous solution gives OH+ ions.
4. Oxides of non – metals form acids.4. Oxides of metals form bases.

Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base

Activity-based questions:

Activity 1:
Apparatus: Hibiscus, rose, turmeric, red cabbage leaves, filter paper, etc.
Activity: Rub red petals of hibiscus flower on the white filter paper. This gives hibiscus indicator paper. Similarly rub, rose petals on the white filter paper. Cut strips of this paper, it is a rose indicator paper. Take turmeric powder, add a little water in it. Dip filter paper or ordinary paper in the turmeric water for some time.

After drying make strips of that paper. Prepare turmeric indicator paper in this way. Put leaves of red cabbage in small quantity of water and heat it. Once solution of cabbage leaves cool down, dip papers in it and dry it. Make strips of dried paper. In this way prepare red cabbage indicator paper. Put some drops of following substances on the indicator papers prepared by the above method and write the effect in the following table:

SubstanceEffect on turmeric paperAcidic/basic
1. Lime juiceYellowAcidic
2. Lime water (calcium hydroxide)RedBasic
3.

Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base

Activity 2:
Take baking powder. Add a little water to it. Add this solution on to limeuice, vinegar, orangeuice, appleuice, etc. and note the findings.
What do you observe on addition of baking soda solution in the fruituice? Whether bubbles formed or effervescence came out of fruituice?
From the above first activity we came to know that yellow turmeric indicator paper’s turns red in certain solutions. Similarly on addition of baking soda solution in the acidic solution bubbles come out or effervescence is produced.
By these simple and easy activity we can identify acidic or alkaline substance:
[Note for Activity 1 and Activity 2: Students should perform the experiments under the guidance of school teachers and record their observations.]

Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base

Activity 3:
Under the guidance of teacher take limeuice, ammonium hydroxide (NH4OH), dil. hydrochloric acid (dil. HCl) and nitric acid (HNOs) in different test-tubes. Add drops of following indicators in them. Also dip litmus papers in the solutions. Observe and record in the following table.
Maharashtra Board Class 8 Science Solutions Chapter 12 Introduction to Acid and Base 7

Balbharati Maharashtra State Board 8th Std Science Textbook Solutions

Metals and Nonmetals Class 8 Science Chapter 7 Questions And Answers Maharashtra Board

Std 8 Science Chapter 7 Metals and Nonmetals Question Answer Maharashtra Board

Balbharti Maharashtra State Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals Notes, Textbook Exercise Important Questions and Answers.

Class 8 Science Chapter 7 Metals and Nonmetals Question Answer Maharashtra Board

Class 8 Science Chapter 7 Metals and Nonmetals Textbook Questions and Answers

1. Complete the table:

Question a.
Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals 1
Answer:

Property of metalUse in everyday life
i. Ductilityi. Gold, silver ornaments
ii. Malleabilityii. Aluminium sheets, galvanised sheets
iii. Conduction of heatiii. Stainless steel vessels, copper vessels, boilers
iv. Conduction of electricityiv. Copper wires
v. Sonorityv. Brass articles

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

2. Identify the odd term.

Question a.
Gold, Silver, Iron, Diamond.
Answer:
Diamond. (Others are metals.)

Question b.
Ductility, Brittleness, Sonority, Malleability.
Answer:
Brittleness. (Other properties are metallic properties.)

Question c.
Carbon, Bromine, Sulphur, Phosphorus.
Answer:
Bromine. (Others are solids.)

Question d.
Brass, Bronze, Iron, Steel.
Answer:
Iron. (Others are alloys.)

3. Give scientific reasons:

Question a.
The stainless steel vessels in kitchen have copper coating on the bottom.
Answer:

  1. Stainless steel is an alloy of iron ; with carbon, chromium and nickel.
  2. The conductivity of copper is higher than that of iron in steel. Copper heats uniformly and faster. The time for cooking is reduced, as a result it saves fuel. Hence, the stainless steel vessels in kitchen have copper coating on the bottom.

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question b.
Copper and brass vessels are cleaned with lemon.
Answer:

  1. Copper undergoes oxidation in air to form black copper oxide. Copper oxide reacts slowly with carbon dioxide in air and gains a green coat. This green substance is copper carbonate.
  2. Lemon contains acid. The acid dissolves the green coating of basic copper carbonate present on the surface of a tarnished copper and brass vessels and makes them shiny again.

Question c.
Sodium metal is kept in kerosene.
Answer:

  1. Sodium reacts so vigorously with atmospheric oxygen and water that it catches fire if kept in the open.
  2. It does not react with kerosene and sinks in it. Hence, to protect sodium and to prevent accidental fires it is always kept in kerosene.

4. Answer the following: 

Question a.
What is done to prevent corrosion of metals?
Answer:
By applying a layer of paint, oil, grease or varnish on the surface of a metal to prevent corrosion. Also plating with noncorroding metal is done. Iron is coated with thin layer of zinc. Due to these processes the contact of metal surface with air is lost and corrosion is prevented.

Question b.
What are the metals that make the alloys brass and bronze?
Answer:
The alloy brass is formed from copper and zinc and the alloy bronze is formed from copper and tin.

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question c.
What are the adverse effects of i corrosion?
Answer:

  1. A reddish coloured deposit (rust) is formed on iron by reaction with oxygen gas.
  2. A greenish coloured deposit (copper carbonate) is formed on copper by reaction with carbon dioxide.
  3. A blackish coloured deposit is formed (silver sulphide) on silver.
  4. Corrosion causes damages to car bodies, bridges, iron railings, ships specially those of iron, silver articles and copper vessels.

Question c.
What are the uses of noble metals?
Answer:
Uses of Noble Metals:

  1. Gold, silver and platinum are used to prepare ornaments.
  2. Silver is used in medicines. (It has antibacterial property).
  3. Gold and silver are also used to make metals and few electronic devices.
  4. Platinum, palladium metals are used as catalyst.

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

5. Three experiments to study the process of rusting are given below. Observe the three test tubes and answer the following questions.

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals 2

Question a.
Why the nail in the test tube 2 is not rusted?
Answer:
In the test tube 2, oil cuts the supply of air to nail due to which oxidation of nail is prevented and boiled water is free from gases. Hence, the nail in the test tube 2 is not rusted.

Question b.
Why is the nail in the test tube 1 is rusted highly?
Answer:
The nail in the test tube 1 is highly rusted because nail is in contact with water and air. The oxidation process is fast.

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question c.
Would the nail in the test tube 3 get rusted?
Answer:
No change is observed in the test tube 3. Nail remains as it is because the calcium chloride absorbs moisture, making the air dry, thus preventing rusting of the nail.

Project:

Question a.
How is the Varkha or silver foil used in sweets made? Collect the information about which metals are used to make ‘Varkha’.

Class 8 Science Chapter 7 Metals and Nonmetals Additional Important Questions and Answers

Rewrite the sentences after filling the blanks:

Question 1.
Gold of 100% purity is …………… carat gold.
Answer:
Gold of 100% purity is 24 carat gold.

Question 2.
The stainless steel utensils used at home are made of an alloy of iron with carbon, …………… and ……….. .
Answer:
The stainless steel utensils used at home are made of an alloy of iron with carbon, nickel and chromium.

Question 3.
…………….. is used in medicines.
Answer:
Silver is used in medicines.

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question 4.
To prepare ornaments ………… carat gold is used.
Answer:
To prepare ornaments 22 carat gold is used.

Question 5.
Non-metals are ………… conductors of heat and electricity.
Answer:
Non-metals are bad conductors of heat and electricity.

Question 6.
Non-metals form ………….. oxides.
Answer:
Non-metals form acidic oxides.

Question 7.
Some element can be hammered into thin sheets. This property is called …………….. .
Answer:
Some element can be hammered into thin sheets. This property is called malleability.

Question 8.
Iodine and ……………. are the two non – metals having typical metallic lustre.
Answer:
Iodine and diamond are the two non¬metals having typical metallic lustre.

Question 9.
Non-metals form ………. ions by gain of electrons.
Answer:
Non-metals form negative ions by gain of electrons.

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question 10.
During formation of positively charged ion, atom of metal ………….. .
Answer:
During formation of positively charged ion, atom of metal lose electrons.

Rewrite the following statements by selecting the correct options:

Question 1.
Metalloids have properties of …………. .
(a) metals
(b) non-metals
(c) both metals and non-metals
(d) neither metals nor non-metals
Answer:
(c) both metals and non-metals

Question 2.
………….. is a metal.
(a) Hg
(b) S
(c) P
(d) Br
Answer:
(a) Hg

Question 3.
…………… is a non-metal.
(a) Aug
(b) Ag
(c) Br
(d) Cu
Answer:
(c) Br

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question 4.
……………. is a metalloid.
(a) Aluminium
(b) Antimony
(c) Zinc
(d) Mercury
Answer:
(b) Antimony

Question 5.
……………. is a metal which is in liquid form at ordinary temperature.
(a) Gallium
(b) Magnesium
(c) Sodium
(d) Scandium
Answer:
(a) Gallium

Question 6.
…………….. is an acidic oxide.
(a) Na2O
(b) CO2
(c) FeOs
(d) H2O
Answer:
(b) CO2

Question 7.
The valence electron in …………… atom is 1.
(a) magnesium
(b) sodium
(c) silicon
(d) aluminium
Answer:
(b) sodium

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question 8.
The electronic configuration of oxygen is …………….. .
(a) 2, 5
(b) 2, 6
(c) 2, 4
(d) 2, 8, 6
Answer:
(b) 2, 6

Question 9.
Pure ………… is soft.
(a) aluminium
(b) silver
(c) gold
(d) platinum
Answer:
(c) gold

Question 10.
…………… is a highly malleable metal.
(a) Iron
(b) Nickel
(c) Manganese
(d) Aluminium
Answer:
(d) Aluminium

Question 11.
22 carat gold is gold of …………… purity.
(a) 100%
(b) 91.66%
(c) 75%
(d) 44%
Answer:
(b) 91.66%

State whether the following statements are True or False:

Question 1.
Metals are sonorous.
Answer:
True.

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question 2.
Diamond is the softest natural substance.
Answer:
False. (Diamond is the hardest natural substance.)

Question 3.
The density of lithium is lower than water.
Answer:
True.

Question 4.
Sulphur is brown in colour.
Answer:
False. (Sulphur is yellow in colour.)

Question 5.
Germanium is a metalloid.
Answer:
True.

Question 6.
Ornaments are made from 24 carat gold.
Answer:
False. (Ornaments are made from 22 carat gold.)

Question 7.
A reddish coloured deposit is formed on iron by reaction with oxygen.
Answer:
True.

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question 8.
Paladium and rhodium are noble metals.
Answer:
True.

Question 9.
The metal oxides are acidic in nature.
Answer:
False. (The metal oxides are basic in nature.)

Question 10.
The metal reacts with dilute acids to form a metal salt.
Answer:
True.

Identify the odd term:

Question 1.
Magnesium, Mercury, Sodium, Iron.
Answer:
Mercury. (Others metals are in solid state at normal temperature.)

Question 2.
Magnesium, Aluminium, Sulphur, Copper.
Answer:
Sulphur. (Others are metals.)

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question 3.
Iron, Copper, Graphite, Phosphorus.
Answer:
Phosphorus. (Others are good conductors of electricity.)

Question 4.
Tin, Bronze, Steel, Stainless steel.
Answer:
Tin. (Others are alloys.)

Consider the relation between the items in the first pair and write the correlation for second pair:

Question 1.
Mercury : Metal : : Carbon : …………. .
Answer:
Non-metal

Question 2.
Wood : Bad conductor of electricity : : Copper : ………………… .
Answer:
Good conductor or electricity

Question 3.
Gold : Noble metal : : Copper: ……………. .
Answer:
Metal

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question 4.
Iron and carbon : Steel : : Copper and Tin : ……….. .
Answer:
Bronze

Question 5.
0 : 2, 6 : : Mg : …………….. .
Answer:
2, 8, 2.

Match the columns:

Question 1.

Column ‘A’Column ‘B’
1. Coppera. Low melting point
2. Sodiumb. Liquid
3. Magnesiumc. High melting point
4. Borond. Conduction of heat
e. 2, 8, 2

Answer:

Column ‘A’Column ‘B’
1. Copperd. Conduction of heat
2. Sodiuma. Low melting point
3. Magnesiume. 2, 8, 2
4. Boronc. High melting point

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question 2.

Column ‘A’Column ‘B’
1. Silvera. Copper + tin
2. Mercuryb. Medicines
3. Platinumc. Thermometer
4. Brassd. Catalyst

Answer:

Column ‘A’Column ‘B’
1. Silverb. Medicines
2. Mercuryc. Thermometer
3.Platinumd. Catalyst
4. Brassa. Copper + tin

Define the following:

  1. Ductility: The property due to which a substance can be drawn into a thin wire is called ductility.
  2. Malleability: The property due to which a substance can be hammered into a thin sheet is called malleability.
  3. Metalloids: The element which shows the properties of metals as well as those of non-metals is called a metalloid.
  4. Corrosion: Gases in the air react with metals in presence of moisture to form metal compounds on its surface, this destroys the metal gradually and is called corrosion.
  5. Alloy: A homogeneous mixture of two or more metals or a homogeneous mixture of metal with non-metals is called alloy.

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Answer the following questions in one sentence:

Question 1.
Name an alloy of copper and tin.
Answer:
An alloy of copper and tin is termed as bronze.

Question 2.
Name a metal which is in liquid state at ordinary temperature.
Answer:
Mercury is in liquid state at ordinary temperature.

Question 3.
Name two metals which are malleable.
Answer:
Iron and aluminium are malleable metals.

Question 4.
Name two metals which are ductile.
Answer:
Gold and silver are ductile metals.

Question 5.
Name two metals which are good conductors of heat.
Answer:
Silver and copper are good conductors of heat.

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question 6.
Name two metals which are good conductors of electricity.
Answer:
Copper and aluminium are good conductors of electricity.

Question 7.
Name two non-metals which are in solid state at room temperature.
Answer:
Carbon and sulphur are solids at room temperature.

Question 8.
Name two non-metals which are in gaseous state at room temperature.
Answer:
Hydrogen and oxygen are in gaseous state at room temperature.

Question 9.
Name the non-metal having electrical conductivity.
Answer:
Graphite has electrical conductivity.

Question 10.
Name two non-metals which are lustrous.
Answer:
Iodine and diamond are lustrous in nature.

Question 11.
Name two non-metals having high melting points.
Answer:
Carbon and boron melt at high temperature.

Question 12.
State two metals which can be cut easily with a knife.
Answer:
Sodium and potassium are soft metals and can be cut easily with a knife.

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question 13.
Which is the hardest natural substance?
Answer:
Diamond, which is a form of carbon is the hardest natural substance.

Question 14.
State the property of the metals for which they can be drawn into wires.
Answer:
The property of the metals due to which they can be drawn into wires is called ductility.

Question 15.
State the property of the metals due to which they can be beaten into thin sheets.
Answer:
The property of the metals due to which they can be beaten into thin sheets is called malleability.

Question 16.
Which of the following metals react with cold water? Sodium, iron, copper, potassium.
Answer:
Sodium and potassium metals react with cold water.

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question 17.
Which of the following metals do not react with cold water or hot water?
Answer:
Aluminium and iron do not react with cold water or hot water.

Question 18.
What are the constituents of stainless steel?
Answer:
Iron with carbon, chromium and nickel are the constituents of stainless steel.

Question 19.
State the term used to express the purity of gold.
Answer:
The purity of gold is expressed in carat.

Question 20.
Name two metals having low melting points and boiling points.
Answer:
Sodium and potassium having low melting points and boiling points.

Question 21.
Name a non-metal which is in liquid state at room temperature.
Answer:
Bromine is in liquid state at room temperature.

Question 22.
State the atomic number and electronic configuration of sodium.
Answer:
Atomic number of sodium: 11.
Electronic configuration of sodium (Na): 2, 8, 1.

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question 23.
State the atomic number and electronic configuration of aluminium.
Answer:
Atomic number of aluminium: 13.
Electronic configuration of aluminium (Al): 2, 8, 3.

Question 24.
Give two example of metalloids.
Answer:
Metalloids: Arsenic (As),
germanium (Ge), antimony (Sb).

Question 25.
State the atomic number and electronic configuration of nitrogen.
Answer:
Atomic number of nitrogen: 7.
Electronic configuration of nitrogen (N): 2, 5.

Answer the following questions:

Question 1.
A metal can be drawn into a wire. Explain why.
Answer:

  1. The property due to which a substance can be draw into a thin wire is called ductility.
  2. Metals are ductile. Thus, a metal can be draw into a wire.

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question 2.
A metal can be hammered into a i thin sheet. Explain why.
Answer:

  1. The property due to which a substance can be hammered (or rolled) into a thin sheet without cracking is called malleability.
  2. Metals are malleable. Thus, a metal can be hammered to form a thin sheet.

Question 3.
State the properties of metals.
Answer:

  1. Metals have a lustre.
  2. Metals are malleable. They can be beaten into thin sheets.
  3. Metals are ductile. They can be drawn into wires.
  4. They are good conductors of heat and electricity.
  5. At ordinary temperature, metals are generally solid. (Exception: Mercury is liquid.)
  6. Metals usually have high density.

Question 4.
State the properties of non-metals.
Answer:

  1. Non-metals lack lustre.
  2. As non-metals are brittle, they are not malleable.
  3. They are not ductile.
  4. Non-metals are poor conductors of heat and electricity.
  5. At ordinary temperature, non-metals are in the solid or gaseous state. (Exception: Bromine is liquid.)
  6. Non-metals have low density in the solid state.

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question 5.
How are metal ions formed? Give two examples.
Answer:
Metals have a tendency to lose their valence electrons to form positively charged ions, called cations.
Examples:
Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals 3
Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals 4

Question 6.
Classify the following elements into metals and non-metals :
Silicon, gold, silver, sulphur, carbon, aluminium, copper and phosphorus.
Answer:
Metals: Gold, silver, aluminium and copper.
Non-metals: Silicon, sulphur, carbon and phosphorus.

Question 7.
How are metal oxides formed? Explain with an example.
Answer:
Metals combine with oxygen in the ’ air to form their oxides.
Metal + Oxygen → Metal oxide
[Note: Reaction/explanation given in the screen are for better understanding of students. The same are not given in the textbook.]
When magnesium burns in air, it combines with oxygen to form magnesium oxide.
2Mg + O2 → 2MgO
Magnesium Oxygen Magnesium oxide

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question 8.
How will you show that metal oxides are basic in nature?
Answer:
1. Take magnesium oxide in a test S tube. Add water in the test-tube. Shake the test-tube. Test the solution with red and blue litmus paper. Blue litmus paper remains as it is while red litmus paper turns blue. This shows that metal oxides are basic in nature.

2. Metal oxides react with an acid to form salt and water. Therefore, metal oxides are basic in nature.
Metal oxide + Acid → + Water
Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals 5

Question 9.
How do metals react with acid? Explain with an example.
Answer:
The metals react with dilute acids to form metal salts. Metals liberate hydrogen gas from dilute acids.
Metal + Dilute acid → Metal salt + Hydrogen gas.
Magnesium reacts with dilute HCl to form magnesium chloride and hydrogen gas.
Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals 6

Question 10.
How do metals react with water? Explain with an example.
Answer:
Most metals do not react with cold water. But some metals like sodium and potassium react with cold water to form their hydroxides and hydrogen gas.
Sodium reacts with water to form sodium hydroxide.
Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals 7

Question 11.
How do non-metals react with oxygen? Explain with an example.
Answer:
Non-metals combine with oxyen to form their oxides.
Non-metal + Oxygen → Non-metal oxide
When carbon burns in air, it combines with oxygen to form carbon dioxide.
Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals 8

Question 12.
How will you show that non- metal oxides are acidic in nature?
Answer:
1. Take non-metal oxide in a test tube. Add water in the test tube. Test the solution with blue and red litmus paper. Red litmus paper remains as it is while blue litmus paper turns red. This shows that non¬metal oxides are acidic in nature.

2. The oxides of non-metals are acidic in nature. They react with bases to form soluble salt and water. Therefore, non-metal oxides are acidic in nature.
C + O2 → CO2
CO2 + 2NaOH → Na2CO3 + H2O

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question 13.
How are non-metal ions formed? Give two examples.
Answer: Non-metals have a tendency to accept electrons in their valence shell to form negatively charged ions called anions.
Examples:
Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals 9

Question 14.
What is meant by noble metals? Give two examples.
Answer:
Some metals like gold, silver, platinum, paladium and rhodium are found in nature in the form of elements. They are not affected by air, water, acids and heat etc. Hence, they are called noble metals.

Give scientific reasons:

Question 1.
Ornaments are generally not made from 24-carat gold.
Answer:

  1. 24-carat gold is considered as gold of 100% purity.
  2. 24-carat pure gold is very soft. 100% pure gold breaks due to pressure or gets bent easily. Therefore, ornaments are generally not made from 24-carat gold.

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetalsc

Question 2.
Ships are painted at frequent intervals.
Answer:
1. The metal sheets of ships are made from iron.
2. Due to salty seawater, the metal sheets of ships get rusted and corroded. Paints contain metals like zinc or magnesium. This prevents the metal surface of the ship coming into direct contact with salty seawater. Therefore, ships are painted at frequent intervals.

Question 3.
Gold and platinum are called noble elements.
Answer:

  1. The metals such as gold and platinum are found in nature in the form of elements.
  2. They are not affected by water, air, acids, heat and also do not take part in chemical reactions. Hence, they are called noble metals.

Explain the following reactions with the help of balanced equations:

Question 1.
Magnesium combines with oxygen.
Answer:
Magnesium combines with oxygen to form magnesium oxide.
Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals 10

Question 2.
Magnesium oxide reacts with dilute HCl.
Answer:
When magnesium oxide reacts with dilute HCl, magnesium chloride (salt) and water are formed.
Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals 11

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question 3.
Magnesium reacts with dilute HCl.
Answer:
When magnesium reacts with dil.
hydrochloric acid, magnesium chloride is formed and hydrogen gas is evolved.
Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals 12

Question 4.
Sodium reacts with water.
Answer:
When sodium reacts with water, sodium hydroxide and hydrogen gas are formed.
Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals 13

Question 5.
Carbon burns in air.
Answer:
When carbon burns in air, carbon dioxide is formed.
Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals 14

Question 6.
Carbon dioxide reacts with sodium hydroxide.
Answer:
When carbon dioxide reacts with sodium hydroxide, soluble salt sodium ; carbonate and water are formed.
Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals 15

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question 7.
Carbon dioxide reacts with water.
Answer:
When carbon dioxide reacts with water, carbonic acid is formed.
Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals 16

Question 8.
Sulphur dioxide reacts with water.
Answer:
When sulphur dioxide reacts with water, sulphurous acid is formed.
Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals 17

Question 9.
Sulphur trioxide reacts with water.
Answer:
When sulphur trioxide reacts with water, sulphuric acid is formed.
Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals 18

Write short notes:

Question 1.
The noble metals.
Answer:
Some metals like gold, silver, platinum, paladium and rhodium are found in nature in the form of elements. They are not affected by air, water, acids and heat etc. Hence, they are called noble metals.

Uses of Nobel Metals:

  1. Gold, silver and platinum are used to prepare ornaments.
  2. Silver is used in medicines. (It has antibacterial property).
  3. Gold and silver are also used to make metals and few electronic devices.
  4. Platinum, palladium metals are used as catalyst. .

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question 2.
The purity of gold.
Answer:
1. The purity of gold is measured in carats.
2. Twenty-four carat gold is considered as gold of 100% purity.
3. 24-carat pure gold is very soft. 100% pure gold bends easily or breaks due to pressure. Therefore, copper or silver is added to gold in the necessary proportion (while making ornaments).
4. Generally, 22-carat gold is used in making ornaments.

Percentage of goldCarat
100%24
91.66%22
75%18
58.33%14
50%12
41.66%10

Question 3.
Corrosion.
Answer:
Corrosion: Gases in the air react with metals in presence of moisture to form metal compounds on its surface, this destroys the metal gradually and is called corrosion.

By applying a layer of paint, oil, grease or varnish on the surface of a metal to prevent corrosion. Also plating with noncorroding metal is done. Iron is coated with thin layer of zinc. Due to these processes, the contact of a metal surface with air is lost and corrosion is prevented.

  1. A reddish coloured deposit (rust) is formed on iron by reaction with oxygen gas.
  2. A greenish coloured deposit (copper carbonate) is formed on copper by reaction with carbon dioxide.
  3. A blackish coloured deposit is formed (silver sulphide) on silver.
  4. Corrosion causes damages to car bodies, bridges, iron railings, ships specially those of iron, silver articles and copper vessels.

Maharashtra Board Class 8 Science Solutions Chapter 7 Metals and Nonmetals

Question 4.
Alloys.
Answer:

  1. A homogeneous mixture of two or more metals or of metals and non-metals is called an alloy.
  2. They contain metals in specific proportions.
  3. The physical properties of an alloy are different from those of its constituents, but chemical properties remain the same.
  4. Copper and tin are used to make an alloy called bronze. It is hard and corrosion resistant.
  5. When iron and carbon are mixed, an alloy steel is formed. It is a stronger material.
  6. The alloy, stainless steel is made from iron, carbon, nickel and chromium. It is more durable, clean and does not rust.

Distinguish between the following:

Question 1.
Metals and Non-metals
Answer:

MetalsNon-metals
1. Metals have lustre.1. Non-metals do not have lustre.
2. Metals are malleable.2. Non-metals are not malleable.
3. Metals are ductile.3. Non-metals are not ductile.
4. Metals are good conductors of heat and electricity.4. Non-metals are poor conductors of heat and electricity.
5. At room temperature, metals are in the solid state. (Exception : Mercury is liquid.)5. At room temperature, non-metals are in the solid, or gaseous state. (Exception Bromine. It is in liquid state.)
6. Generally, metals have high densities.6. Generally, non-metals have lower densities.

Balbharati Maharashtra State Board 8th Std Science Textbook Solutions 

Ecosystems Class 8 Science Chapter 18 Questions And Answers Maharashtra Board

Std 8 Science Chapter 18 Ecosystems Question Answer Maharashtra Board

Balbharti Maharashtra State Board Class 8 Science Solutions Chapter 18 Ecosystems Notes, Textbook Exercise Important Questions and Answers.

Class 8 Science Chapter 18 Ecosystems Question Answer Maharashtra Board

Class 8 Science Chapter 18 Ecosystems Textbook Questions and Answers

1. Complete the following by using the correct option:

Question a.
Air, water, minerals, soil are ………….. factors of an ecosystem. (physical, organic, inorganic)
Answer:
Air, water, minerals, soil are physical factors of an ecosystem.

Question b.
River, ponds, ocean are …………. ecosystems, (land, aquatic, synthetic)
Answer:
River, ponds, ocean are aquatic ecosystems.

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Question c.
Man is ………….. in an ecosystem. (producer, consumer, decomposer)
Answer:
Man is consumer in an ecosystem.

2. Match the following:

Question a.

ProducerEcosystem
1. Cactusa. Forest
2. Aquatic plantsb. Creek
3. Mangrovesc. Aquatic
4. Pined. Desert

Answer:

ProducerEcosystem
1. Cactusd. Desert
2. Aquatic plantsc. Aquatic
3. Mangrovesb. Creek
4. Pine a. Forest

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

3. Give my information:

Question a.
Ecosystem.
Answer:
Ecosystem is the structure formed by the interrelationships between the living organisms and non-living components in their surrounding habitats. Living organisms are also called biotic factors while the non-living components are called abiotic factors. The abiotic and biotic factors have a reciprocal relationship with each other. The ecosystem has plants as producers, animals as consumers and microbes as decomposers.

The decomposers return the substances back to the nature by process of decomposition in which the organic complex molecules are reduced to their inorganic constituents. Thus the dead remains of plants and animals are once again recycled back to the nature in any healthy ecosystem.

Question b.
Biome.
Answer:
Biomes are a larger collection of small ecosystems which are similar in their structure. In a particular biome there are same climatic, abiotic factors and similar living organisms. Biomes are of two main types, land biomes and aquatic biomes. The land biomes exist only on land. Land biomes are of following subtypes based on the abiotic factors. E.g. Grasslands, evergreen forests, deserts, Tundra ecosystem, ecosystems in Taiga, tropical rainforests, etc. Aquatic biomes include freshwater ecosystem, marine ecosystem and brackish water ecosystem found in the creeks.

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Question c.
Food web.
Answer:
The complex feeding relationships form a food web. In nature in any ecosystem, the food chains are not straight and linear. But these are quite complex. A prey is consumed by a predator but this predator can itself be a prey to some other predator. E.g. Frog is a predator for variety of insects but frog is preyed upon by snake and the snake can be eaten by a bird. The same bird can also feed on insects or frog. The interrelationships between different biotic components of any ecosystem thus form the complicated food web.

4. Give scientific reasons: 

Question a.
Plants in an ecosystem are called producers.
Answer:
are cut down causing deforestation. The wild animals lose their habitat. Many of them become extinct. There is great loss of flora and fauna due to construction of large dams. There is undue pressure on the land surface caused due to stored water column. This may cause earthquakes. The human settlements are removed as their houses and farms are immersed under water. In all the above ways large dams destroy the ecosystems.

Question b.
Large dams destroy ecosystems.
Answer:
When a large dam is constructed, the original landscape is changed. The trees are cut down causing deforestation. The wild animals lose their habitat. Many of them become extinct. There is great loss of flora and fauna due to construction of large dams. There is undue pressure on the land surface caused due to stored water column. This may cause earthquakes. The human settlements are removed as their houses and farms are immersed under water. In all the above ways large dams destroy the ecosystems.

Question c.
Rhinos were restored in Dudhwa forest.
Answer:
Long ago in last century, Dudhwa forest was the natural habitat of the one-horned Rhino. However, due to hunting and poaching, the Rhino became almost extinct. In order to restore it back the breeding in captivity was attempted and the young ones were released in the natural habitat. Saving the precious wildlife is important and hence these efforts were done.

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

5. Answer the following:

Question a.
What are the effects of increased population (of human beings) on ecosystems?
Answer:

  1. Human population growth rate is very big as compared to other animals.
  2. Moreover, they are apex consumers in an ecosystem. Just like any other organisms, ecosystems provide all the basic needs to humans, too.
  3. However, man demands much more due to excessive population. The natural resources are utilized on the large scale only by man.
  4. Changing lifestyles, consumerism, degradation of nature and pollution are certain aspects which are created only by human beings.
  5. All these cause increased stress on the ecosystems. Large human population also produces large-scale solid wastes.

Question b.
How is urbanization responsible for destruction of ecosystems?
Answer:
When people do not get sufficient food and other amenities, they migrate to the cities. The cities provide employment for many people due to industries, factories and other facilities. Every day many people migrate to cities. This causes urbanization. Due to increased population in cities, there is more need for housing. This results in loss of agricultural lands, marshlands, wetlands, forests and grasslands, etc.

The natural ecosystems are lost in an attempt to have developmental work. Human interference causes changes in the ecosystems. When land usage is changed many naturally occurring species of plants and animals are exterminated. Animal- human conflicts are very common in newly established urban areas which are near the natural forests.

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Question c.
What are the reasons for war?
Answer:
There are difference of opinions and competition over land, water, mineral resources, etc. among neighbouring countries. Moreover, there can be economic and political causes which lead to war among different countries. Many times the l religions and ethnicity are also caused for dispute. Due to international conflicts, the peace is disturbed and it results in war.

Question d.
Explain the interactions among the factors of an ecosystem.
Answer:

  1. The abiotic factors such as air, water, soil, sunlight, temperature, humidity, etc. affect the biotic factors, i.e. the surviving plants, animals and microbes in the ecosystem.
  2. The type of abiotic factors in an ecosystem determine the survival of biotic factors. The population of these biotic factors is also dependent on the quality of abiotic factors.
  3. The proportion of abiotic factors in an ecosystem fluctuates as biotic factors use up or release particular abiotic factors.
  4. Every biotic factor also interacts with its necessary abiotic factors as well as other biotic factors around it.

Question e.
Differentiate between evergreen forests and grasslands.
Answer:

Evergreen forestsGrasslands
1. About seven percent of the Earth’s surface is occupied by evergreen forests.1. About 30 percent of the Earth’s surface is covered by grasslands.
2.  More than half of the earth’s terrestrial plants and animals are seen in evergreen forests.2. Grazing animals are seen in grasslands.
3. Tropical evergreen forests are dense, multi-layered.3. Grasslands consist of tall grass. There are wild grasses and there may be some trees.
4. These forests are found in the areas receiving more than 200 cm annual rainfall i.e. very heavy rainfall.4. There is an average of 20 – 35 inches of rainfall a year in grasslands.
5. Tropical regions show evergreen forests.5. Several parts of the world have grasslands.

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

6. Describe the following pictures:

Question a.
Describe the following pictures
Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems 1
Answer:
The picture no. 1 is showing desert ecosystem, while the picture no. 2 is showing a forest ecosystem where a wetland (a lake) is also shown. In desert ecosystem, the producers are green cactus and a palm tree. Since in desert there are scanty rains, the vegetation is very less. The soil is sandy soil. The consumers of the desert are also limited.

In the above picture camel is shown which is a primary consumer in the desert ecosystem. Camel is very well adapted for desert life. There is also the scarcity of water in desert and hence cactus shows xerophytic (suitable to survive in desert) adaptations.

In second picture, the forest ecosystem is shown because we can see elephant and tiger in the picture. Also, giant hornbill is sitting on the tree. This forest must be tropical evergreen forest. The rainfall is heavy in such areas and hence different types of wetlands can be seen in forests. Wetlands support variety of life. A separate aquatic ecosystem does exist here which is closely interconnected with the terrestrial ecosystems through food chains and food web.

The birds utilize the fish as their prey. The wild animals come to wetlands to quench their thirst. In this picture the plants, grass, etc. are producers, small fishes in the lake are primary consumers. They will be eaten by larger fishes which are secondary consumer in the aquatic ecosystem. The elephant is herbivorous animal and hence it is primary consumer. Snake is the secondary consumer while the birds of prey (eagle that is flying) and tiger are tertiary consumers.

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Can you recall?

Question 1.
Which factors do you find in your surroundings?
Answer:
In our surroundings there are abiotic and biotic factors. The biotic factors are animals and plants in the surroundings. The invisible bacteria and fungi also have important role in the ecosystem as decomposers. Important abiotic factors are air, water, land, sunlight, etc.

Question 2.
Are these factors directly or indirectly related to you?
Answer:
We are directly or indirectly connected to every single factor in the surrounding in which we reside. For the requirement of food, we are dependent on plants and animals. For our survival we continuously need oxygen, water and other minerals, etc.

Classify:

Question 1.
Classify the following into living and non-living factors. Sunlight, Sunflower, Elephant, Lotus, Algae, Stone, Grass, Water, Ant, Soil, Cat, Fern, Air, Lion.
Answer:

Living FactorsNon-living Factors
Sunflower, Elephant, Lotus, Algae, Grass, Ant, Cat, Fern, Air, Lion.Sunlight, Stone, Water, Soil, Air.

Can you tell?

Question 1.
What is the role of microbes in above interaction?
Answer:
Microbes play the role of decomposers in the above interactions.

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Question 2.
How do producers obtain abiotic factors?
Answer:
Producers obtain solar energy from sunlight. The other nutrients are obtained from soil, water and air.

Question 3.
From where do the consumers get their food?
Answer:
Consumers get their food from producers and other consumers.

Project:

Question 1.
Visit an ecosystem nearby, List the biotic and abiotic factors in it. Show with pictures or sketches, how they are dependant on each other.

Question 2.
With the help of internet find out the loss of ecosystems due to wars or atomic explosions. Describe in your words.

Class 8 Science Chapter 18 Ecosystems Important Questions and Answers

Complete the following by using the correct option:

Question 1.
Biotic community is another name for ………. (ecology, ecosystem, population)
Answer:
Biotic community is another name Biotic for ecosystem.

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Question 2.
Microbes in an ecosystem are ………… (producers, consumers, decomposers)
Answer:
Microbes in an ecosystem are decomposers.

Question 3.
Many types of ecosystems are found in ………… (oceans, deserts, biosphere)
Answer:
Many types of ecosystems are found in biosphere.

Question 4.
………….. is a type of grassland ecosystem. (Taiga, Tundra, Desert)
Answer:
Taiga is a type of grassland ecosystem.

Question 5.
Gir forest in Gujarat is the only habitat/shelter for the spectacular ………….. (Asiatic lion, Royal Bengal tiger, One-horned rhino)
Answer:
Gir forest in Gujarat is the only habitat shelter for the spectacular Asiatic lion.

Correct the following statements by changing one or two words:

Question 1.
Primary, secondary, tertiary consumers are the abiotic factors of the ecosystem.
Answer:
Primary, secondary, tertiary consumers are the biotic factors of the ecosystem.

Question 2.
Most of the ecosystems are simple.
Answer:
Most of the ecosystems are complex.

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Question 3.
The word ecosystem was brought in the use by Ray Claffam.
Answer:
The word ecosystem was brought in the use by A.G. Tansle.

Question 4.
Specific ecosystem developed in a vast area is called a biosphere.
Answer:
Specific ecosystem developed in a vast area is called a biomes.

Question 5.
Longer summer and limited rain develop very tall plants in the grassland ecosystem.
Answer:
Longer summer and limited rain develop dwarf plants in the grassland ecosystem.

Question 6.
29 % of the earth surface is covered by water and only 71 % has land on it.
Answer:
71 % of the earth surface is covered by water and only 29 % has land on it.

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Question 7.
Dams increase the water current in lower area.
Answer:
Dams lessen the water current in lower area.

Match the following:

Question 1.

Column ‘A’Column ‘B’
1. The Great Himalayan National Parka. Asiatic lion
2. Kazirangab. Tigers
3. Bharatpurc. Aquatic birds
4. Ranthambored. One-horned Rhino
5. Gir foreste. White panther

Answer:

Column ‘A’Column ‘B’
1. The Great Himalayan National Parke. White panther
2. Kazirangad. One-horned Rhino
3. Bharatpurc. Aquatic birds
4. Ranthamboreb. Tigers
5. Gir foresta. Asiatic lion

Find the odd one out:

Question 1.
Typha, Pistia, Eichhornia, Dipterocarpus
Answer:
Dipterocarpus. (All others are aquatic plants.)

Question 2.
Teak, Parthenium, Pine, Sandalwood
Answer:
Parthenium. (All others are forest trees.)

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Question 3.
Giraffe, Zebra, Cheetah, Elephant
Answer:
Cheetah.. (All others are surviving grassland animals, Cheetah is a forest animal that is extinct from Asia.)

Question 4.
Hyena, Cow, Deer, Rabbit
Answer:
Hyena. (All others are primary consumers, Hyena is tertiary consumer.)

Question 5.
Fusarium, Leptocorsia, Aspergillus, Polycarpus
Answer:
Leptocorsia. (All others are decomposers, Leptocorsia is primary consumer.)

Taking into consideration the relationship in the first pair, complete the second pair :

Question 1.
Plants : Producers : : ……… : Consumers
Answer:
Animals

Question 2.
Secondary consumers : Jackals : : Tertiary consumer : ………..
Answer:
Kite/Lion/Hyena

Question 3.
Goat, sheep : Grassland ecosystem : : Tigers : …………..
Answer:
Forest ecosystem

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Question 4.
Desert : Land biome : : Creek : …………….
Answer:
Aquatic biome

Question 5.
Limited rain : Grassland ecosystem : : ……….. : Tropical rainforests
Answer:
Excessive rain.

Answer in one sentence:

Question 1.
What is an ecosystem?
Answer:
The structure which is formed due to interactions between abiotic and biotic factors is called an ecosystem.

Question 2.
What is an ecological niche?
Answer:
The position of any living organism with reference to other living organisms and the role played by that organism is called ecological niche.

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Question 3.
How are types of ecosystems formed?
Answer:
Types of ecosystems are formed according to size, place, climate, types of plants and animals that survive in that ecosystem.

Question 4.
Give examples of land biomes.
Answer:
Grasslands, evergreen forests, deserts, Tundra or polar ecosystem, ecosystems in Taiga, tropical rainforests, etc. are land biomes.

Question 5.
What are the reasons for tourism among the people?
Answer:
Tourism is mainly because people like to visit scenic places, undertake nature watch, wish to visit to sacred places and for entertainment purpose.

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Question 6.
Why we should protect natural ecosystems?
Answer:
Natural ecosystems must be protected as they maintain balance in the biosphere.

Give my information Write short notes:

Question 1.
Dudhwa forest.
Answer:
Dudhwa forest is in Uttar Pradesh. About a century back, Dudhwa forest was the habitat for one-horned Rhino. However, due to hunting and poaching in 20th century, this animal became endangered. Thus to restore their populations, on 1st April 1984 rhino were introduced there again. Rhinos can were bred in captivity followed by releasing them back into natural ecosystem.

For this purpose at first the land was selected. This was 27 square km grassland and forest with continuous water supply through natural resources. Two observatories were established for making these efforts successful. Now Dudhwa is known for one¬horned Rhino population.

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Question 2.
Aquatic ecosystems.
Answer:
Earth’s 71 % of surface is covered over by aquatic ecosystems. They are of three main types, viz. fresh water ecosystem, marine ecosystem and brackish water ecosystem. Rivers, lakes and ponds and streams are some of the fresh water ecosystem. Fresh water contains less salt and hence it is potable. Marine water has more salinity, i.e. its salt content is high. Brackish water ecosystem is present in the creeks. Here the saline and fresh water mix together. Hence salinity here is lesser than that of the marine water.

Give scientific reasons:

Question 1.
Microbes are called decomposers.
Answer:
Decomposition is the process in which the organic compounds are broken down to their inorganic constituents. The organic substances such as carbohydrates, proteins and lipids which are locked in the dead remains of plants and animals are converted into hydrogen, oxygen, calcium, iron, sodium, potassium, etc. by microbes. Therefore, microbes are called decomposers.

Use your brain power:

Question 1.
Which biotic factors get affected due to a dam?
Answer:
The biotic factors include plants, animals and humans. Lot of vegetation is submerged from the place where dam is constructed. The forests are wiped out. Large scale deforestation takes place in the proposed dam area. Wildlife is destroyed completely. The resident animals whose habitat are there either migrate away or are killed due to lack of their food and shelter. Many instances of animal-human conflicts arise when the wild animals drift to the neighbouring human settlements.

If human settlements are shifted, people are displaced. They lose their houses and agricultural land. Though compensation is given to them, there is great change for the people. Water current in lower area of the dam is reduced due to construction of dam-walls. Therefore, the original lotic (running 5 water) ecosystems that were present are destroyed after the construction of dam.

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Question 2.
What will be the effects on biotic factors in the running water of river?
Answer:
The aquatic flora (plants) and fauna (animals) are well adapted to their habitats. The running water ecosystems are known as lotic ecosystems. The non-moving waters on the contrary create lentic ecosystems. Lotic ecosystems provide special adaptations to the plants and animals living therein. Plants are mostly in the form of freely floating algae and phytoplankton. Animals are well adapted for swimming in the currents of water. The fishes especially show a stream-lined body, fins for swimming, and gills to take up dissolved oxygen in the water. The other animals are also well adapted to the currents of water.

Think about it:

Question 1.
Can we call a tree an independent ecosystem?
Answer:
The huge tree can be an independent ecosystem. On one such tree there may be different habitats. Variety of insects thrive on huge tree by making their habitats in cracks and crevices on the tree. Many birds visit the tree to feed on such insects. There are many bird species that live in the hollow of the tree. Garden lizards, chameleons, snakes are the different reptiles seen associated with the tree ecosystem.

Squirrels, rabbits, bats are the mammals which take shelter in and around the trees, also inhabit a tree variety of fungi, lichens, mosses and epiphytic plants like orchids survive on the huge trees. Many food chains and complicated food webs are formed with the support of the tree. Thus one can say that a tree is an independent ecosystem.

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Question 2.
Today Divija visited a hill. Honey: bees were hovering on flowers. One of them stung Divijia’s hand. Divija was hurt due to that sting and said with anger that all the honey-bees from the whole world must get destroyed. Afterwards, she thought what will happen if all honey-bees are destroyed? We will get honey, nothing more. What would be your explanation to Divija?
Answer:
Honey bees provide us with honey and bee-wax. Both of these are commercial products. But more than that the role played by honey bees in the pollination of flowers is very important. Due to their nectar collecting behaviour, they bring about pollination of the flowers.

Presence of honey bees is thus very essential for the agriculture and horticulture. Without honey bees, the growth of fruits and grains will not be possible, if pollination and subsequent fertilization does not take place in nature. This will create famine-like conditions. Therefore, honey bees’ position in the nature is very important.

Chart based questions:

Question 1.
Complete the following chart in context to a grassland.
Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems 2
Answer:
Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems 3

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Question 2.
Write the information about various components of forest.
Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems 4
Answer:
Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems 5

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Question 3.
Observe such ecosystems around you and complete the following chart.
Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems 6
Answer:
Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems 7

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Question 4.
Complete the table.
Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems 8
Answer:

National Park/SanctuaryState
1. GirGujarat
2. DachigamJammu-Kashmir
3. RanthamboreRajasthan
4. DajipurMaharashtra
5. KazirangaAssam
6. SunderbansBengal
7. MelghatMaharashtra
8. PeriyarKerala

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Question 5.
Complete the following chart:
Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems 9
Answer:
Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems 10

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Diagram based questions:

Question 1.
Correct the following diagram:
Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems 12
Answer:
Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems 11

MCQs based on experiment:

Question 1.
Which one out of the following is not biotic factor?
(a) Humidity
(b) Rabbit
(c) Snake
(d) Bacteria
Answer:
(a) Humidity

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Question 2.
Which climatic factor is causing migration of the birds in certain regions of the earth?
(a) Humidity and rainfall
(b) Ambient temperature
(c) Amount of carbon dioxide
(d) Amount of plant matter
Answer:
(b) Ambient temperature

Question 3.
Which abiotic factor mainly distinguishes marine water from the fresh water?
(a) Temperature
(b) Dissolved oxygen:
(c) Salinity
(d) Surface tension
Answer:
(c) Salinity

Question 4.
Why is creek water different from the river water?
(a) Creek water is more polluted than the river water.
(b) Creek water is less salty than the river water.
(c) Creek water is more saline than the river water.
(d) Creek water is less turbulent than the river water.
Answer:
(b) Creek water is less salty than the river water.

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Question 5.
Which land biome shows presence of cacti plants more?
(a) Polar regions
(b) Grasslands
(c) Rainforest
(d) Desert
Answer:
(d) Desert

Projects:

Collect information

Question 1.
What are the possible threats to grasslands?
Answer:
Man tries to use grasslands for agricultural purpose. This transformation causes loss of natural ecosystem. Many animals from grasslands are killed by hunting and poaching. Though now Wildlife Act has protected these animals, many wildlife species are already extinct. There are chances of forest fires which is the greatest threat to grasslands. The global warming may also cause grasslands to become a desert.

Question 2.
Why did Asian Cheetah become extinct in last century?
Answer:
When British ruled India, Asian Cheetah was hunted to a great extent. The kings and British rulers did rampant hunting. The forest lands were also reduced due to encroachment by humans to build their settlements. Dams were constructed. Mega highways, bridges and roads caused loss of habitat for Asian Cheetah. Cheetah needs large thickly forested territory. This was lost due to all man-made activities. All these reasons made Asian Cheetah extinct in last century.

Maharashtra Board Class 8 Science Solutions Chapter 18 Ecosystems

Question 3.
Observe Asian Cheetah on internet. Describe it.
Answer:
Cheetah is the fastest running feline animal on the earth. Though from Asian regions it is said to be extinct, in African grasslands, its occurrence is still there. But it is endangered animal. By 2016, the global cheetah population is estimated at approximately 7,100 individuals in the wild. Several African countries have taken steps to improve cheetah conservation measures.

Cheetah has a slender body, deep chest, spotted coat. Its head is small rounded and on the face there is black tear-like streaks. It has long thin legs and a long spotted tail. Cheetah in India were tamed during Moghul period for assisting in hunting. Stories about such episodes are commonly told. However, the last Cheetah in India was spotted in Bastar, M.P. in 1948.

Balbharati Maharashtra State Board 8th Std Science Textbook Solutions

Static Electricity Class 7 Questions And Answers Maharashtra Board

Std 7 Science Chapter 8 Static Electricity Question Answer Maharashtra Board

Balbharti Maharashtra State Board Class 7 Science Solutions Chapter 8 Static Electricity Notes, Textbook Exercise Important Questions and Answers.

Class 7 Science Chapter 8 Static Electricity Question Answer Maharashtra Board

1. Choose the correct option and fill in the blanks.
(always repulsion, always attraction, displacement of negative charge, displacement of positive charge, atom, molecule, steel, copper, plastic, inflated balloon, charged object, gold)

Question a.
There is ………….. between like charges.
Answer:
always repulsion

Question b.
…………. is responsible for generation of electric charge in an object.
Answer:
displacement of negative charge

Maharashtra Board Class 7 Science Solutions Chapter 8 Static Electricity

Question c.
A lightning conductor is made of a ……………… strip.
Answer:
copper

Question d.
……………… does not get electrically charged easily by rubbing.
Answer:
Steel

Question e.
There is …………………. when opposite electric charges come near each other.
Answer:
always attraction

Question f.
A ……………… canbe detected with an electroscope.
Answer:
charged object

Maharashtra Board Class 7 Science Solutions Chapter 8 Static Electricity

2. Explain why it is not safe to go out with an umbrella when there is heavy raine lightning or thunder.

Question a.
Explain why it is not safe to go out with an umbrella when there is heavy raine lightning or thunder.
Answer:
Large amount of charges get built up in the clouds in rainy and stormy weather.

  1. Sometimes these charges are transferred to the earth in the form of a bolt of lightning.
  2. Wire of umbrella is made up of metal and cloth is made up of synthetic material.
  3. If lightning strikes, then umbrella catches it and there are chances of fire and it would be dangerous.
  4. So it is not safe to go out with an umbrella when there is heavy rain.

3. Answer in your own words.

Question a.
How will you protect yourself from lightning?
Answer:

  1. To protect from the lightning, we have to put lightning conductor on high rise buildings,
  2. we should not stand under a tree in rainy and stormy weather.
  3. We should not go out with an umbrella in heavy rain, lightning or thunder.

Question b.
How are charges generated?
Answer:

  1. Friction causes a charge to develop, because on rubbing, some negative particles are transferred from one substance to the other and the later develops a negative charge.
  2. The substance from which particles are removed lose negative charge and hence, it develops a positive charge.

Maharashtra Board Class 7 Science Solutions Chapter 8 Static Electricity

Question c.
In the lightning conductor, what provision is made for spreading the electricity into the ground?
Answer:

  1. The lightning conductor, consists of a long i copper strip with one end forked. This end is ‘ at the highest part of the building.
  2. The other end of the strip is connected to a plate of cast iron.
  3. A pit is dug in the ground, coal and salt are filled into the pit and the iron plate is placed upright in the pit.
  4. There is also a provision for pouring water into it.
  5. This helps to spread the electric charge quickly into the ground.

Question d.
Why do farmers stick an iron staff into the ground while working in the field in rainy conditions?
Answer:

  1. Large amount of charges get built up in the clouds in rainy and stormy weather.
  2. Sometimes these charges are transferred to the earth in the form of a bolt of lightning.
  3. Due to iron staff, the charges will be conducted to the earth through iron metal and spread quickly into the ground.
  4. This way farmers are saved from lighting strike.

Question e.
Why is lightning not seen every day during the rainy season?
Answer:

  1. When air and clouds rub against each other in the sky the upper part of some clouds becomes positively charged and the lower side become negatively charged.
  2. When this negative charge at the bottom of the cloud becomes much larger than the charge on the ground, it starts flowing towards the ground in stages, but this doesn’t happen every day. So lightning is not seen every day during the rainy season.

4. What are the characteristics of a static electric charge?

Question a.
What are the characteristics of a static electric charge?
Answer:
Following are the characteristics of a static electric charge.

  1. The electric charge generated by friction is called frictional electricity. This charge is produced only at the place of friction, hence it is called static electricity.
  2. It remains on the object for a short duration.
  3. The charges of static electricity are absorbed in moist air.
  4. An electrically charged object attracts another object which has no electric charge.
  5. Like charges repel each other.
  6. Unlike charges attract each other.
  7. Repulsion is the sure test of the existence of a static charge.

Maharashtra Board Class 7 Science Solutions Chapter 8 Static Electricity

5. What is the damage caused by lightning? How will you ereate awareness to prevent it?

Question a.
What is the damage caused by lightning? How will you ereate awareness to prevent it?
Answer:
Due to lightning great damage can occur.

  1. It may cause fire.
  2. Person on whom lightning strikes may die also.
  3. It causes more temperature than sun.

Awareness to prevent it:

  1. Guide the people to install lightning conductor on tall buildings.
  2. Do not stand on open ground, below a tree, or on a high location during the thunder storms.
  3. Do not use plugged in electrical appliances.
  4. Do not stand near an electric pole, telephone pole or a tower.
  5. Stay in pucca house made of brick and cement.
  6. Stand on only wood, a plastic sheet or sack of jute.

Maharashtra Board Class 7 Science Solutions Chapter 8 Static Electricity

Project:

Question a.
Make an electroscope yourself by using a thin aluminium foil and check which substances become electrically charged.

Class 7 Science Chapter 8 Static Electricity Important Questions and Answers

1. Choose the correct option and fill in the blanks.
(always repulsion, always attraction, displacement of negative charge, displacement of positive charge, atom, molecule, steel, copper, plastic, inflated balloon, charged object, gold)

Question 1.
named the electric charges as positive charge and negative charge.
Answer:
Benjamin Franklin

Question 2.
Each atom contains a stationary charge and moving charges.
Answer:
positive, negative

Question 3.
Each atom is electrically
Answer:
neutral

Maharashtra Board Class 7 Science Solutions Chapter 8 Static Electricity

Question 4.
Amber is called in the Greek language.
Answer:
electron

Question 5.
The charges of electricity are absorbed in moist air.
Answer:
static

Question 6.
Electrically charged objects uncharged objects.
Answer:
attract

Question 7.
is used as a test for identifying an electrically charged object.
Answer:
Repulsion

Question 8.
The property of amber to attract things was named electricity by in 1646 AD.
Answer:
Thomas Brown

Maharashtra Board Class 7 Science Solutions Chapter 8 Static Electricity

Question 9.
The electric charge generated by stays only as long as the charged object is near to it.
Answer:
induction

Question 10.
A simple device is used to detect the electric charge on an object.
Answer:
gold leaf electroscope

Question 11.
Lightning is a form of
Answer:
electric charge

Question 12.
The gas protects us from the harmful ultra violet rays coming from the sun.
Answer:
ozone

Question 13.
The is a device used for protection from a lightning strike.
Answer:
lightning conductor

Maharashtra Board Class 7 Science Solutions Chapter 8 Static Electricity

Question 14.
Due to the energy of the lightning, the oxygen in the air is converted into
Answer:
ozone

2. Match the columns:

Question a.

Column ‘A’Column ‘B’
1. Like chargesa. gold leaf electroscope
2. Unlike chargesb. lightning conductor
3. Copper stripc. attraction
4. Gold leaves.d. repulsion

Answer:

Column ‘A’Column ‘B’
1. Like chargesd. repulsion
2. Unlike chargesc. attraction
3. Copper stripb. lightning conductor
4. Gold leaves.a. gold leaf electroscope

Say whether true or false, correct and rewrite the false statement:

Question 1.
Charges cannot be transferred from one body to another.
Answer:
False. Charges can be transferred from one body to another

Maharashtra Board Class 7 Science Solutions Chapter 8 Static Electricity

Question 2.
The word ‘electricity.’ came from the word ‘Elektron’.
Answer:
True

Question 3.
When an inflated balloon is rubbed on silk, it develops a charge.
Answer:
True

Question 4.
An ebonite rod rubbed on woollen cloth develops a positive charge.
Answer:
False. An ebonite rod rubbed on woollen cloth develops a negative charge

Question 5.
A glass rod rubbed on woollen cloth develops a negative charge.
Answer:
False. A glass rod rubbed on woollen cloth develops a positive charge

Maharashtra Board Class 7 Science Solutions Chapter 8 Static Electricity

Question 6.
If the leaves of the electroscope spread only a little, the charge on them is less.
Answer:
True

Question 7.
An atom may have either a positive or a negative charge.
Answer:
False. An atom does not have any charge

Question 8.
When two substances are rubbed on each other, like charges are developed on each.
Answer:
False. When two substances are rubbed on each other unlike charges are developed on each

Question 9.
High rise buildings have lightning conductors.
Answer:
True

Maharashtra Board Class 7 Science Solutions Chapter 8 Static Electricity

Question 10.
It is dangerous to stand under a tree in rainy and stormy weather.
Answer:
True

Give scientific reasons:

Question 1.
Ordinarily, an atom does not have any charge.
Answer:

  1. Every atom contains smaller particles with either positive or negative charge.
  2. As the number of positively and negatively charged particles in an atom is equal, they neutralize each other.
  3. As a result the atom has no charge.

Question 2.
Charge cannot be developed on a copper rod.
Answer:
Charge cannot be developed on a copper rod because only certain pairs of substances give rise to electric charge, on rubbing.

Maharashtra Board Class 7 Science Solutions Chapter 8 Static Electricity

Question 3.
High rise buildings have lightning conductors.
Answer:

  1. High rise buildings are prone to lightning strikes during the monsoon.
  2. When lightning strikes, a tremendous electric charge is transferred to the earth, which may damage the tall buildings.
  3. To prevent this, high rise buildings have a forked metal rod, called a lightning conductor fitted on the top of the building.
  4. The lower end of this rod is buried inside the earth.
  5. If lightening strikes, the electric charge passes through this conductor and goes in to the earth. In this way the building is saved from damage.

Question 4.
It is dangerous to stand under a tree in rainy and stormy weather.
Answer:

  1. Large amount of charges get built up in the clouds in rainy and storming weather.
  2. Sometimes these charges are transferred to the earth in the form of a bolt of lightning.
  3. Generally lightning strikes tall buildings and trees. If lightning strikes a tree then either the tree may fall or it may catch fire.
  4. In both cases this would be dangerous for anyone standing under the tree, hence it is dangerous to stand under a tree in rainy and stormy weather.

Maharashtra Board Class 7 Science Solutions Chapter 8 Static Electricity

Question 5.
Repulsion is a test used for identifying an electrically charged object.
Answer:

  1. When a charged object is brought near a neutral object, it gets attracted when two oppositely charged objects are brought close, they get attracted. Therefore, attraction is not a test.
  2. But when two like charges are brought close only then repulsion takes place.
  3. Therefore, repulsion is the sure test for identifying an electrically charged object.

Question 6.
Mustard seeds when shaken vigorously in a glass bottle stick to the sides of the bottle.
Answer:
When seeds are shaken they get electrically charged and therefore they stick to the neutral walls of the glass.

Answer the following:

Question 1.
Why is the charge developed due to friction called static electric charge?
Answer:
The charge developed due to friction is called 1 static electric charge because the charge remains still on the object.

Question 2.
Why does the charge developed by induction disappear quickly?
Answer:
The charge developed by induction disappears quickly because it is very weak.

Maharashtra Board Class 7 Science Solutions Chapter 8 Static Electricity

Question 3.
Why do the leaves of a gold leaf electroscope fly apart when a charged body touches its disc?
Answer:
The leaves of a gold leaf electroscope fly apart when a charged body touches its disc because like charges develop on both the leaves and hence they repel each other.

Draw a neat labelled diagram of Gold leaf electroscope and describe it.

Answer:
Maharashtra Board Class 7 Science Solutions Chapter 8 Static Electricity 1

  1. This is a simple device to detect the electric charge on object.
  2. It consists of a copper rod which has a metal disc at the upper end and two thin gold leaves at the other.
  3. The rod is placed in a bottle so that the disc is above the bottle.
  4. When an uncharged object is taken near the disc, the leaves remain closed.
  5. When a charged object is taken near the disc, both the leaves are charged by the same electric charge, and repel each other.
  6. When we touch the disc with our hand, the leaves collapse because the charge in the leaves goes into the earth through our body, and the leaves get discharged.

Use your brainpower:

Question 1.
Do all the objects get charged by rubbing?
Answer:
No. Only certain pairs of substances get charged on rubbing.

Maharashtra Board Class 7 Science Solutions Chapter 8 Static Electricity

Question 2.
Why does a charged balloon stick to a wall?
Answer:
A charged balloon stick to a wall because there is always attraction between a charged object and an uncharged object.

Question 3.
Can we use leaves of some other metal instead of gold, in the electroscope? Which properties must that metal have?
Answer:
We can use other metals than gold in gold leaf electroscope.

  1. Only thing is that metal should be malleable and good conductor of electricity.
  2. But the best is gold only because we can make extremely thin leaves of gold so even very small charge also can be detected.

Question 4.
What kind of damage is caused by a lightning strike?
Answer:
Due to lightning strike, great damage can occur. It may cause forest fire and burn down things. Person on whom lightning strikes may die. It causes more temperature than sun.

Question 5.
What measures will you take to prevent the damage caused by lightning?
Answer:
Following measures can be taken to prevent the damage caused by lightning:

  1. Always put lightning conductor on tall buildings.
  2. Do not stand on open ground, below a tree or near the electric or telephone pole during rain/ thunder storms.
  3. Do not lean on wired fences.
  4. Do not use plugged in electrical appliances.
  5. Do not swim during thunder storms.
  6. Stay in a pucca house with lightning conductor fitted on it.

Maharashtra Board Class 7 Science Solutions Chapter 8 Static Electricity

Question 6.
Why is the upper end of the lighting conductor pointed?
Answer:

  1. The pointed end makes it possible to increase the electric field near the point. The electric field set up at pointed end is high.
  2. If the discharge of cloud occurs it would be easily passed through the lightening conductor to the ground and damage to the building is averted.

Question 7.
Why is coal and salt added to the pit in the ground?
Answer:
Coal and salt is filled in the pit and also there is a provision for pouring water into it. This helps to spread electric charge quickly into ground and prevent damage.

Observe the given diagram and answer the questions given.

Maharashtra Board Class 7 Science Solutions Chapter 8 Static Electricity 2

Question a.
Name the phenomenon happening in the diagram and define it
Answer:
Phenomenon happening is static electricity.
When certain objects are rubbed against each other, they produce an electric charge on their surface at the place of friction. This is due to electrons which remain for a short time. This is called static electricity.

Maharashtra Board Class 7 Science Solutions Chapter 8 Static Electricity

Question b.
What do you observe in “b” and “c” part of the diagram?
Answer:
In ‘b’, we observe attraction between the charged balloon and the uncharged aluminium ball. In ‘c’, we observe that the charge has been transferred to the aluminium ball and due to the same (like) charge, repulsion is observed.

Maharashtra State Board Class 7 Science Textbook Solutions

Force and Types of Force Class 6 Questions And Answers Maharashtra Board

Std 6 Science Chapter 10 Force and Types of Force Question Answer Maharashtra Board

Balbharti Maharashtra State Board Class 6 Science Solutions Chapter 10 Force and Types of Force Notes, Textbook Exercise Important Questions and Answers.

Class 6 Science Chapter 10 Force and Types of Force Question Answer Maharashtra Board

1. Choose the term and fill in the blanks:

Question a.
……….. has to be applied to change the ……….. of a ……….. object.
(moving, direction, force)
Answer:
force, direction, moving

Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force

Question b.
When an elephant drags a wooden log over the land, the forces that are applied on the log are …………., ………. and …………. .
(muscular force, mechanical force, gravitational force, frictional force)
Answer:
muscular force, gravitationalforce, frictionalforce.

Question c.
A ball was set rolling on a large table. If its …….. has to be changed, a ……….. will have to be applied on it.
(force, motion, gravitation)
Answer:
motion, force

Question d.
The force of friction always acts ……….. the motion.
(along, against)
Answer:
against

Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force

2. Match the following:

Question a.

Column ‘A’Column ‘B’
1. An ox pulling a carta. Magnetic force
2. Lifting heavy iron object with a craneb. Electrostatic force
3. Weighing with a spring balancec. Muscular force
4. Applying brakes to a bicycle.d. Gravitational force
5. Picking up pieces of paper with a plastic scale.e. Frictional force

Answer:

Column ‘A’Column ‘B’
1. An ox pulling a cartc. Muscular force
2. Lifting heavy iron object with a cranea. Magnetic force
3. Weighing with a spring balanced. Gravitational force
4. Applying brakes to a bicycle.e. Frictional force
5. Picking up pieces of paper with a plastic scale.b. Electrostatic force

Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force

3. One or more forces are acting in the following examples. Name them.

Question a.
An object falling from a tall building …………. .
Answer:
Gravitational force

Question b.
An aeroplane flying in the sky. …………. .
Answer:
Mechanical force

Question c.
Sqeezing sugarcane juice with a squeezer. …………. .
Answer:
Muscular or mechanical force

Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force

Question d.
Winnowing foodgrain …………. .
Answer:
Muscular force, gravitational force

4. Explain in your own words giving one example each.
Muscular force, gravitational force, mechanical force, electrostatic force, the force of friction and magnetic force.

Question a.
Muscular force:
Answer:
The force applied with the help of muscles is called muscular force.
e.g. When a bullock pulls the load of a cart with sugarcane, he uses the force of his muscles that is muscular force.

Question b.
Gravitational force:
Answer:
The force applied by the earth to pull the objects towards itself is called gravitational force.
e.g. When a fruit falls from a tree, it is the gravitational force of the earth that pulls the fruit.

Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force

Question c.
Mechanical force:
Answer:
The force applied by means of a machine is called mechanical force. Some machines run by muscular force while some use electricity or fuel.
e.g.Washing machine, electric pump uses electricity to work.

Question d.
Electrostatic force:
Answer:
Static electricity is produced on materials like rubber, plastic and ebonite due to friction. The force exerted by such electrically charged materials is called electrostatic force, e.g. When a plastic comb is rubbed against the dry hair, comb develops electrostatic charge.

Question e.
The force of friction:
Answer:
When two surfaces rub against each other, a force of friction is produced. This force always acts against direction of motion, e.g. A ball rolling over a flat surface stops at certain distance due to friction between the ball and the surface.

Question f.
Magnetic force:
Answer:
The force exerted by a magnet is called magnetic force.
e.g. In a pin holder, the magnet attracts the pins.

Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force

5. Why?

Question a
Machines are oiled from time to time.
Answer:
To reduce the friction between the parts of machines, they are oiled. This will help efficient working of machines.

Question b.
An object thrown upwards comes down after reaching a point.
Answer:
An object is pulled by the gravitational force of the earth. Hence an object thrown upwards comes down after reaching at certain point.

Question c.
Powder is sprinkled on a carrom board.
Answer:
When powder is sprinkled on a carrom board, friction between the coin and the board decreases so that the coin can be pocketed easily.

Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force

Question d.
The ramp at a railway station has a rough surface.
Answer:
The rough surface of the ramp increases the friction between feet and the surface. This helps us to walk on the ramp without skidding or falling.

6. In what way are we different? 

Question a.
Muscular force and Mechanical force
Answer:

Muscular forceMechanical force
1. The force applied with the help of muscles is called muscular force.
e.g. A boy kicking a football.
1. The force applied by means of machine is called mechanical force.
e.g. An electric pump works on electricity.
2. It is created by our muscles.2. It is created by electricity or fuel or muscular force

Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force

Question b.
A force of friction and Gravitational force
Answer:

Force of frictionGravitational force
1. When two surfaces rub against each other, the force of friction comes into force.1. The force applied by the earth to pull an object towards itself, is called a gravitational force.
2. It comes to act between two surfaces.2. It exists between two objects or an object and the earth.

7. Write answers to the following questions in your own words. 

Question a.
What are the things that can be done by applying force?
Answer:
By applying force:

  1. we can set an object in motion.
  2. we can stop a moving object.
  3. we can change the speed or direction or both of a moving object.
  4. we can change the shape of an object.

Question b.
What is meant by weight?
Answer:

  1. The gravitational force acting on an object is called its weight.
  2. Greater force must be applied to lift a greater weight.

Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force

Question c.
Which machines run on muscular force?
Answer:
The machines that run on muscular force are:

  1. Bicycle
  2. Hand cart
  3. Boat
  4. Cycle rickshaw
  5. Stretching of a spring
  6. Ball pen
  7. Vegetable chopper
  8. Sharpener
  9. Pulley
  10. Fruit peeler

8. Solve the following crossword puzzle.

Question a.
Solve the following crossword puzzle.

Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force 1
Down:
1. ………. force is applied to push a scooter that has failed.
2. ………. force can be used to pick up scattered pins.

Across:
3. A ………. pulls iron nails towards itself.
4. ……….. force is used when farm is ploughed with a tractor.
5. It is due to the force of ………… that raindrops fall to the ground.
Answer:
Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force 2

Activity:

Question 1.

Collect more information about the various forces that are used in our day-to-day life.

Question 2.
Make a list of such actions where many forces are applied simultaneously.

Class 6 Science Chapter 10 Force and Types of Force Important Questions and Answers

Choose the term and fill in the blanks:

Question 1.
When powder is sprinkled on a carrom board, friction ……….. .
(increases, decreases)
Answer:
decreases

Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force

Question 2.
Electrostatic force is due to …………. .
(gravitation, friction)
Answer:
friction

Question 3.
Fruits fall on the ground due to ………… force.
(mechanical, gravitational)
Answer:
gravitational

Question 4.
Friction between two rough surfaces is …………. than between two smooth surfaces.
(greater, lesser)
Answer:
greater

Question 5.
The sound created by a stone dropped in a bucket of water from 100 cm height is ………… than that dropped from 20 cm height.
(milder, louder)
Answer:
louder

Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force

Question 6.
A scooter has stopped in the middle of the road as the petrol tank has become empty. So Raju has to use …………. force to take it to petrol pump.
(mechanical, muscular)
Answer:
muscular

One or more forces are acting in the following examples. Name them.

Question 1.
Srikant is playing basketball
Answer:
Muscular force

Question 2.
Raju rubs a peacock feather between pages of his notebook
Answer:
Electrostatic force

Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force

Question 3.
When you rub the palm of your hands, you feel the heat on the palms
Answer:
Frictional force

Question 4.
A blacksmith uses a hammer to beat the hot piece of iron
Answer:
Muscular force

Question 5.
A cricketer hits the ball, but it stops just before the boundary line
Answer:
Frictional force

Question 6.
We can walk on the road without falling down.
Answer:
Frictional force

Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force

Give scientific reasons:

Question 1.
Magnet is used to lift heavy iron bar.
Answer:
A magnet attracts the iron bar. As a result it is easier to lift the heavy iron bar using magnetic force.

Question 2.
An inflated balloon when rubbed against a silk cloth, pulls the hair on our skin.
Answer:
When an inflated balloon is rubbed against a silk cloth, it develops electrostatic force due to friction. This force pulls the hair on our skin.

Question 3.
We are likely to slip when we walk on a oily or wet floor.
Answer:
Wet or oily floor reduces the friction between our feet and surface. Hence we are likely to slip on wet or oily floor.

Distinguish between:

Question 1.
Force of friction and Electrostatic force
Answer:

Force of frictionElectrostatic force
1. It exists between any two surfaces in contact.1. It develops where certain objects are rubbed  against certain material.
2. No electric charge is developed, sometimes heat is developed.
e.g. A brake is applied on a bicycle.
2. Electric charge is developed.
e.g. Thermocol rubbed against silk cloth.

Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force

Answer the following:

Question 1.
Why do planets revolve round the sun in definite orbits?
Answer:

  1. The gravitational force operates between the sun and the planets in the solar system.
  2. Hence, they revolve round the sun in definite orbits.

Question 2.
Which forces are acting upon an aeroplane taking off into the sky?
Answer:
Aeroplane uses mechanical force, Pilot exerts muscular force. Frictional force between aeroplane and air, gravitational force due to weight of an aeroplane.

Question 3.
What happens to the iron nail when the magnet is taken away from it?
Answer:

  1. As we take the magnet away from the iron nail, it does not attract the iron nail as magnetic force decreases.
  2. Magnet is unable to exert force if the nail is not placed in the range of the magnetic field.

Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force

Question 4.
When brakes are applied while riding a bicycle, it stops after running a distance. Why?
Answer:

  1. When brakes are applied while riding a bicycle, frictional force comes to act between the tyres of the bicycle and the surface.
  2. This force opposes the tendency of the bicycle to stop.
  3. Hence, the bicycle has to overcome this force before it stops.

Can you tell?

Question 1.
What happens when you hold the two ends of a spring and pull them apart?
Answer:
Its shape changes due to the force exerted by pull.

Question 2.
What happens when a blacksmith hammers a red hot piece of iron?
Answer:
Shape of iron piece changes.

Observe and discuss:

Observe the figures given and name the force needed for the motion.

Question 1.
Boat with boatman.
Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force 4
Answer:
Muscular force

Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force

Question 2.
Bullock cart.
Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force 5
Answer:
Muscular force

Question 3.
A tractor.
Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force 6
Answer:
Mechanical force

Question 4.
Sewing machine.
Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force 7
Answer:
Mechanical force

Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force

Question 5.
Fruit falling from tree.
Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force 8
Answer:
Gravitational force

Question 6.
A man carrying heavy sac.
Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force 3
Answer:
Gravitational force

Question 7.
A pin holder.
Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force 9
Answer:
Magnetic force

Question 8.
A ramp.
Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force 10
Answer:
Gravitational force

Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force

Question 9.
Carrom board.
Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force 11
Answer:
Frictional force

Question 10.
Mixer grinder.
Maharashtra Board Class 6 Science Solutions Chapter 10 Force and Types of Force 12
Answer:
Mechanical force

Maharashtra State Board Class 6 Science Textbook Solutions

Substances in the Surroundings – Their States and Properties Class 6 Questions And Answers Maharashtra Board

Std 6 Science Chapter 5 Substances in the Surroundings – Their States and Properties Question Answer Maharashtra Board

Balbharti Maharashtra State Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings – Their States and Properties Notes, Textbook Exercise Important Questions and Answers.

Class 6 Science Chapter 5 Substances in the Surroundings – Their States and Properties Question Answer Maharashtra Board

1. In the paragraph below write ‘solid’, ‘liquid’ or ‘gas’ in each of the blank (brackets) depending on the substance referred to just before.

Question a.
On a bright sunny day, Riya and Gargi are playing with a ball (…..) in the park. Gargi feels thirsty. So, Riya brings tender coconut water (…..) for her. At the same time, a strong breeze (…..) starts blowing and it also begins to rain (…..). They run back into the house (…..), change their clothes (…..) and then their mother gives them a cup (…..) of hot milk (…..) to drink.
Answer:
solid, liquid, gas, liquid, solid, solid, solid, liquid.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

2. Discuss.

Question a.
Riya pours some water from her bottle into another bottle. Does it change the shape of the water?
Answer:
Yes, the shape of water changes as water is in liquid state. Liquids do not have a shape of its own. They take the shape of the container.

Question b.
Halima picks up a small stone from the ground and puts it in the water in a dish. Does the shape of the stone change?
Answer:
No, the shape of the stone does not change. Stone is a solid, hence retains its shape.

3. Write the properties of these substances.
(water, glass, chalk, iron ball, sugar, salt, flour, coal, soil, pen, ink, soap)

Question a.
Write the properties of these substances.
(water, glass, chalk, iron ball, sugar, salt, flour, coal, soil, pen, ink, soap)
Answer:
Properties of substances:

SubstanceStateProperties
1. WaterLiquidFluidity, density, solubility, transparency, thermal conductivity.
2. GlassSolidBrittleness, hardness, density, transparency.
3. ChalkSolidBrittleness, density.
4. Iron ballSolidHardness, density, malleability, ductility, electrical ductility, conductivity, thermal conductivity, luster, sonority.
5. SugarSolidBrittleness, density, solubility.
6. SaltSolidBrittleness, density, solubility.
7. FlourSolidDensity, solubility.
8. CoalSolidBrittleness, density, thermal conductivity.
9. SoilSolidBrittleness, density.
10. PenSolidHardness, density.
11. InkLiquidFluidity, density, solubility.
12. SoapSolidBrittleness, hardness, density, solubility.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

4. What is sublimation? Write the names of everyday substances that sublimate.

Question a.
What is sublimation? Write the names of everyday substances that sublimate.
Answer:

  1. The change of a solid substance directly into a gas or vapour without first changing into liquid is called sublimation.
  2. Substances that sublimate: Camphor, napthalene balls, ammonium chloride, iodine.

5. What is made from? Why? 
a. A sickle to cut sugarcane.
b. The sheets used for roofing.
c. A screwdriver
d. A pair of tongs.
e. Electric cables.
f. Ornaments.
g. Pots and pans.

Question a.
A sickle to cut sugarcane.
Answer:
A sickle is made of iron. An iron sickle is hard and malleable. When sharpened it will be able to cut the hard sugarcane.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question b.
The sheets used for roofing:
Answer:

  1. The sheets used for roofing are made of plastic, aluminium.
  2. Plastic is hard, hence, protects against weather conditions.
  3. Plastic is transparent, hence, sunlight can pass through it.
  4. Aluminium is hard, light weight and durable, hence, protects against all weather conditions.
  5. Malleable hence formed into thin sheets.

Question c.
A screwdriver:
Answer:

  1. A screwdriver is made up of iron, steel, aluminium.
  2. A screwdriver possesses property of hardness hence, it easily pierces a screw in piece of wood, wall, metals etc.

Question d.
A pair of tongs:
Answer:

  1. A pair of tongs are made up of iron, steel aluminium etc. Tongs are used to lift hot, boiling utensils or vessels.
  2. Tongs are hard, ductile and malleable.
  3. Hence, have strong grip to hold utensils.
  4. Rubbers fitted on the ends will protect from thermal conduction, from bums.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question e.
Electric cables:
Answer:

  1. Electric cables are metal wires (thin) wound in plastic.
  2. Metal wires possess the property of hardness, ductility, electrical conductivity.
  3. Plastic /rubber covering possesses the property of hardness, elasticity and are bad conductors of heat and electricity.

Question f.
Ornaments:
Answer:

  1. They are made up of metals like gold and silver.
  2. They possess the property of hardness, ductility, malleability, lustre.

Question g.
Pots and pans: Answer:

  1. They are used to cook food, hence metals like aluminium, steel are used.
  2. They possess the property of hardness, ductility, malleability, thermal conductivity, electrical conductivity, (microwave ovens)

6. What will happen if ….? And why?

Question a.
Nails are made of plastic
Answer:
If nails are made of plastic, they will not be able to pierce through other substances on being pushed or forced by a hammer. Plastic lacks the property of hardness.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question b.
A bell is made of wood.
Answer:

  1. If a bell is made of wood it will never make a ringing sound. A wooden bell does not have the property of being sonorous.
  2. Sonority is the property of metals to produce a ringing sound.

Question c.
Rubber is not fitted on a pair of tongs.
Answer:

  1. Rubber is a bad conductor of heat and electricity. It will not allow heat to pass to the hands/handle of the tongs, thus protecting us.
  2. Pair of tongs are made up of metals which conduct heat and electricity. They have file property of thermal conduction and electrical conduction.
  3. If rubber is not fitted on a pair of tongs, we will not be able to lift hot objects with it.

Question d.
A knife is made of wood.
Answer:
Wood does not have the property of malleability. Therefore, the edge of wooden knife will be blunt. Hence, we will not be able to cut anything with it.

Question e.
An axe is made of rubber.
Answer:

  1. If an axe is made of rubber, it will not be used to cut wood or tree.
  2. Rubber does not have the property of hardness that is required to push through to cut it.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

7. Who am I?

Question a.
I’m found in a thermometer, I measure your temperature.
Answer:
Mercury

Question b.
I make things hot or cold.
Answer:
Heat

Question c.
I have no shape whatsoever!
Answer:
Liquid, gases

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question d.
I dissolve in water, but not in kerosene.
Answer:
Salt

8. Why does this happen? 

Question a.
Coconut oil thickens in winter.
Answer:
Coconut oil is in liquid state. In winter the surrounding temperature / atmospheric temperature starts decreasing. Coconut oil starts cooling or losing heat, it changes to solid state.
Thus coconut oil thickens in winter.

Question b.
Kerosene left open in a dish disappears.
Answer:
When kerosene is left open in a dish, it is exposed to surrounding temperature. As the temperature is more, kerosene starts continuously evaporating and finally disappears.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question c.
The fragrance of incense sticks lighted in one corner of a room spreads to the other corner.
Answer:
The fragrance of incense sticks is given out in the form of scented vapours. As vapours are in gaseous state, the gas molecules spread out in the room. The molecules of gas move very fast and there are no forces to stop them from going apart. Therefore the fragrance of incense sticks lighted in one corner of room spreads to the other corner.

Question d.
What you see in the picture.
Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties 1
Answer:
The mass of plastic ball is less than an apple. This difference is because of their densities. Since an apple has greater density, it will sink to the bottom on other hand the plastic ball has lesser density, it will float over water surface.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Activity: 

Question 1.
Find out how the big statues of wax are made.

Question 2.
Visit a jeweller’s shop and find out how ornaments are made.

Class 6 Science Chapter 5 Substances in the Surroundings – Their States and Properties Important Questions and Answers

Fill in the blanks:

Question 1.
The state of a substance changes if it is …………… or …………… .
Answer:
heated, cooled

Question 2.
Every substance in our surroundings is found in either the ……………, …………… or gaseous state.
Answer:
solid, liquid

Question 3.
On …………… heat, the substance changes from solid to liquid and liquid to gas.
Answer:
gaining

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question 4.
When the substance cools, or …………… heat, it changes from gaseous to liquid and liquid to solid state.
Answer:
loses

Question 5.
A …………… amount of heat must be gained or lost before the state of a substance can change.
Answer:
specific

Question 6.
When a substance gets heat, it becomes …………… and then …………… .
Answer:
warm, hot

Question 7.
If the substance is very hot, we could get …………… .
Answer:
scalded

Question 8.
A thermometer is used to measure …………… .
Answer:
temperature

Question 9.
…………… is the unit of measuring temperature.
Answer:
Degree Celsius (°C)

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question 10.
Nowadays, …………… thermometers are frequently used.
Answer:
digital

Question 11.
Solids have a shape of its …………… .
Answer:
own

Question 12.
Solids have a …………… volume.
Answer:
definite

Question 13.
Liquids take the shape of the …………… .
Answer:
container

Question 14.
Liquids have a …………… volume.
Answer:
specific

Question 15.
Air occupies all the available …………… .
Answer:
space

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question 16.
Evaporation occurs from the …………… of the water.
Answer:
surface

Question 17.
At sea-level, pure water boils at …………… .
Answer:
100°C

Question 18.
Condensation of steam takes place at …………… .
Answer:
100°C

Question 19.
The temperature of a substance can fall below …………… .
Answer:
0°C

Question 20.
Ice melts at …………… .
Answer:
0°C

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question 21.
Each substance has a specific boiling point which is also its …………… point.
Answer:
condensation

Question 22.
Each substance has a specific melting point which is the same as its …………… point.
Answer:
freezing

Question 23.
Candles are made by melting …………… wax.
Answer:
paraffin

Question 24.
Solid carbon-dioxide is …………… .
Answer:
dry ice

Question 25.
Liquid …………… is used in animal husbandry.
Answer:
nitrogen

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question 26.
Sand is melted to make …………… .
Answer:
glass

Question 27.
Iron is melted to make …………… .
Answer:
tools

Question 28.
Substances can be identified by studying their …………… .
Answer:
properties

Question 29.
Substances that break into small particles are said to be …………… .
Answer:
brittle

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question 30.
The …………… of any liquid is determined by how easily it flows.
Answer:
fluidity

Question 31.
Between substances of the same volume, the ones with greater density are …………… than those of lesser density.
Answer:
heavier

Question 32.
The property of a substance of getting …………… is called its solubility.
Answer:
dissolved

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question 33.
Minerals from the earth’s crust are …………… to obtain metals.
Answer:
processed

Question 34.
Metals can be converted into …………… by hammering.
Answer:
sheets

Question 35.
Metals can be stretched and drawn into …………… .
Answer:
wires

Question 36.
All metals are …………… of electricity to a greater or lesser extent.
Answer:
conductors

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question 37.
Every metal has a …………… colour by which it can be identified.
Answer:
specific

Question 38.
Metals produce …………… sound.
Answer:
ringing

Question 39.
Metals form a …………… group of substances.
Answer:
separate

Question 40.
Heat is the cause of the change of the state of …………… .
Answer:
substances

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Match the columns:

Question 1.

Column ‘A’Column ‘B’
1. Boiling watera. > 35° C
2. Body temperatureb. 0° C
3. Freezing waterc. < 5° C
4. Air (summer afternoon)d. < 15° C
5. Inside a fridgee. < -18° C
6. Air (winter night)f. 100° C
7. Inside the freezerg. 37°C

Answer:

Column ‘A’Column ‘B’
1. Boiling waterf. 100° C
2. Body temperatureg. 37°C
3. Freezing waterb. 0° C
4. Air (summer afternoon)a. > 35° C
5. Inside a fridgec. < 5° C
6. Air (winter night)d. < 15° C
7. Inside the freezere. < -18° C

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Answer in one sentence:

Question 1.
What is change of state of substances?
Answer:
When a substance changes from one state to another, the process is called change of state of the substance.

Question 2.
When does state of substance change?
Answer:
State of substance changes when it is heated or cooled.

Question 3.
In which state do substances exist in our surroundings?
Answer:
The substances exist in solid, liquid and gaseous form in our surroundings.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question 4.
What happens when a substance gains heat?
Answer:
When a substance gains heat, it changes its state i.e. from solid to liquid and liquid to gas.

Question 5.
What happens when a substance loses heat?
Answer:
When a substance loses heat, it changes its state from gaseous to liquid and liquid to solid state.

Question 6.
How do we tell how hot or cold a substance is?
Answer:
The temperature on the thermometer will tell us how hot or cold a substance is.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question 7.
What is the unit of measuring temperature.
Answer:
Degrees Celsius (°C) is the unit of measuring temperature.

Question 8.
What is the boiling point of water?
Answer:
The boiling point of water is 100° C.

Question 9.
What is condensation?
Answer:
When vapour cools, it is converted into liquid again. This process is condensation.

Question 10.
At what temperature condensation of steam takes place?
Answer:
Condensation of steam takes place at 100° C.

Question 11.
What is the freezing point of water?
Answer:
0° C is the freezing point of water.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question 12.
What is the temperature of air in the freezer of a refrigerator?
Answer:
-18° C is the temperature of air in the freezer of a refrigerator.

Question 13.
At what temperature ice melts?
Answer:
Ice melts at 0° C.

Question 14.
How are candles made?
Answer:
Candles are made by melting paraffin wax.

Question 15.
What is the use of solid carbon-dioxide?
Answer:
Solid carbon-dioxide (dry ice) is used to make ice cream and to keep it frozen.

Question 16.
What is the use of liquid nitrogen?
Answer:
Liquid nitrogen is used in animal husbandry.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question 17.
What is sublimation?
Answer:
The change of a solid substance directly into gas or vapour without changing into a liquid is called sublimation.

Question 18.
Define brittleness / What is brittleness?
Answer:
Some substances break into small pieces or particles. Such substances are said to be brittle. This property of substances is called brittleness.

Question 19.
Define hardness / What is hardness?
Answer:
The hardness of a substance is determined by how much resistance it offers to the substances being pushed through it.

Question 20.
Define elasticity / What is elasticity?
Answer:
Some substances change their shape when a force is applied on them but return to their original shape and size when the force is removed. This property is called elasticity.

Question 21.
Define fluidity / What is fluidity?
Answer:
Liquids flow downward on a sloping surface. This property is called fluidity.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question 22.
How is fluidity of any liquid determined?
Answer:
Fluidity of any liquid is determined by how easily it flows.

Question 23.
Define density / What is density?
Answer:
The mass of different substances having the same volume can be different. This difference is because of the difference in their densities. Between substances of the same volume, the ones with greater density are heavier than those of lesser density.

Question 24.
Define solubility / What is solubility?
Answer:
The property of a substance of getting dissolved is called its solubility.

Question 25.
Define transparency / What is transparency?
Answer:
When we can look through a substance and see things on the other side, then that substance is said to be transparent. This property of the substances is called transparency.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question 26.
List some transparent substances.
Answer:
Glass, air, clean water and some types of plastic are transparent substances.

Question 27.
What are metals?
Answer:
Metals are substances like copper, gold, iron, aluminium. They are found in the form of minerals deep inside the earth. Minerals from the earth’s crust are processed to obtain metals.

Question 28.
Define malleability. / What is malleability?
Answer:
Metals can be converted into sheets by hammering. This property of metals is called malleability.

Question 29.
Define ductility. / What is ductility?
Answer:
Metals can be stretched and drawn into thin wires. This property of metals is called ductility

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question 30.
Name some ductile metals.
Answer:
Metals like silver, gold, platinum can be drawn into fine wires.

Question 31.
Define electrical conductivity. / What is electrical conduction?
Answer:
Electricity flows through metals. All metals are conductors of electricity to a greater or lesser extent.

Question 32.
Define thermal conductivity. / What is thermal conductivity?
Answer:
Metals allow heat to flow through them. This property is called thermal conductivity

Question 33.
What is lustre?
Answer:
The typical shine or characteristic colour by which metal can be identified is called lustre.

Question 34.
What is sonority of metals? / Define sonority.
Answer;
Metals produce a ringing sound. This property is called the sonority of metals.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Give scientific reasons for following:

Question 1.
Metals are used to make musical instruments.
Answer:
Metals possess the property of being sonorous, i.e. produce a ringing sound. Hence, they are used to make musical instruments.

Question 2.
Ornaments are made up of metals.
Answer:
Metals have the property of being malleable, ductile, lustrous. Hence, ornaments are made up of metals.

Question 3.
Why should we not put our hand or finger in the water to judge the hotness of water?
Answer:
We should never put our hand or finger in the water to judge how hot it is because that is not an accurate measure. Besides if the substance is very hot, we could get scalded.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Can you tell?

Question 1.
Why are electric boards fitted on the wall made of plastic or wood?
Answer:
Plastic or wood are bad conductors of heat and electricity. Electric boards are made up of plastic or wood. So that while touching we will not get electric shock.

Question 2.
The handle of cooker is made of plastic. Why?
Answer:
Cooker is made of metal. When food is cooked in it, it gets heated and the whole of its body becomes hot due to thermal conductivity. Hence with the plastic handle we can easily lift the hot cooker as plastic is a bad conductor of heat.

Question 3.
Use your brain power!
On opening a box of camphor, its smell spreads all around. Why does this happen?
Answer:

  1. Camphor is a sublimate substance.
  2. When a box of camphor is opened it changes its state from solid to gas or vapour state.
  3. This change takes due to the process of sublimation where camphor absorbs heat from surrounding to change from solid to gaseous state.
  4. Camphor particles in gaseous state start spreading all around.
  5. Hence on opening a box of camphor its smell spreads all around.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question 4.
Identify the objects shown in fig. 5.14. From which substances are they made? What are these substances called as a group?
Answer:
In fig 5.14, the metallic bars are shown, these bars are made up of shiny solid. These substances are called metals.

Question 5.
Name the solid, liquid and gaseous states of water.
Answer:

  • Solid- Ice
  • Liquid – water
  • Gas – water vapour.

Question 6.
Read this list of substances:
spirit, camphor, petrol, ghee, coconut oil, naphthalene balls, ammonium chloride (navsagar).

Question a.
Which one freezes in winter?
Answer:
Coconut oil, ghee.

Question b.
Which liquids have you seen change into a vapour?
Answer:
Spirit, petrol.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question c.
Which solid directly changes into gaseous state?
Answer:
Camphor, naphthalene balls, ammonium chloride.

Question 7.
The chart given below shows the boiling point and freezing point of some substances. State whether these substances are solid, liquid or gaseous at room temperature.

SubstanceFreezing PointBoiling Point
Candle60 °C350 °C
Plastic> 250 °C954 °C
Iron1535 °C2862 °C

Answer:
Candle, plastic and iron are in solid state at room temperature.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Distinguish between solids, liquids and gases.
Answer:

SolidsLiquid                                                  Gases
e.g.: A piece of irone.g.: Water, spirit, oile.g.: Air
Has a shape of its own, Retains shape, no matter how it is kept.Does not have a shape of its own. Takes the shape of the container.Does not have a shape of its own. Occupies all the available space.
Has a definite volume. Solids like sugar, sand when poured on a flat surface, form a heap.It has a specific volume. Occupies definite portion of a container. Spreads on a flat surface on pouring. Flows downwards along a slope. Takes the shape of the surface.Does not have a definite volume. On changing the pressure on a gas in a closed container, its volume also changes.

Distinguish between Boiling and Melting.
Answer:

BoilingMelting
1. When heat is supplied to liquids, they boil.1. When heat is supplied to solids, they melt.
2. Boiling leads liquids to vapour/gaseous state.2. Melting leads solids to liquid state.
3. The temparature at which liquid starts boiling continuously is called boiling point.3. The temperature at which solid turns to liquid completely is called melting point.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Answer the following briefly:

Question 1.
List properties of solids
Answer:

  1. Solids have its own shape i.e. Retains shape, no matter how it is kept.
  2. Solids have definite volume.
  3. e.g. Sand when poured on a flat surface form a heap.

Question 2.
List properties of liquids.
Answer:

  1. Liquid does not have a shape of its own. Takes the shape of the container.
  2. A liquid has a specific volume i.e. occupies definite portion of a container.
  3. Liquids: e.g. water, milk, kerosene.

Question 3.
List properties of gases.
Answer:

  1. Gases does not have a shape of its own.
  2. Occupies all the available space.
  3. Does not have a definite volume.
  4. e.g. Air.

Question 4.
Explain with example how liquids take the shape of the surface.
Answer:
Liquids have a specific volume. They occupy definite portion of a container. Liquids spreads on a flat surface on pouring. Liquids flow downwards along a slope.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question 5.
Explain Ebullition.
Answer:

  1. As the water gets heated, its temperature increases and it evaporates at a faster and faster rate.
  2. When water kept on a stove attains a particular temperature or level of heat, then evaporation takes place in all parts of the body of water.
  3. Then we see water bubbles rising at a faster and faster rate to the surface and steam mixing in the air.
  4. This is called boiling of water or Ebullition.

Question 6.
Explain: Boiling point and condensation point of water are one and the same.
Answer:
Water boils at 100°C. i.e. boiling point of water is 100°C. Condensation of steam also takes place at 100° C. Thus boiling point and condensation point of water are one and the same.

Question 7.
Explain freezing point of water.
Answer:

  1. Water kept in a fridge or on ice becomes cooler and cooler i.e. its temperature falls.
  2. At a certain temperature water does not cool further but starts freezing and forms ice.
  3. The temperature at which this happens is called the freezing point of water. (0° C)

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question 8.
Explain: Freezing point and melting point of water are same.
Answer:

  1. The temperature at which water does not get any cooler but starts freezing and forming ice is 0° C.
  2. When ice gets heat, it starts melting or changes into liquid state at 0° C.
  3. Thus, freezing point and melting point of water are one and the same.

Question 9.
List various uses of changes in physical state.
Answer:

  1. Candles are made by melting paraffin wax.
  2. Solid carbon-dioxide (dry ice) is used to make ice-cream and to keep it frozen.
  3. Liquid nitrogen is used in animal husbandry.
  4. Sand (silica) is melted to make glass.
  5. Metals like gold and silver are melted to make ornaments.
  6. Iron is melted to make tools.

Question 10.
List the properties of substances:
Answer:
The properties of substances are

  1. Brittleness
  2. Hardness
  3. Elasticity
  4. Fluidity
  5. Density
  6. Solubility
  7. Transparency

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question 11.
List properties of metals:
Answer:
The properties of metals are

  1. Malleability
  2. Ductility
  3. Electrical conductivity
  4. Thermal conductivity
  5. Lustre
  6. Sonority

Question 12.
How can we change the volume of a gas?
Answer:
On changing the pressure on a gas in a closed container we can change its volume.

Can you tell?

Question 1.
Does water change into vapour the moment we place the vessel on a stove? Does water kept in fridge change at once into ice?
Answer:
No, it doesn’t. Water slowly changes from one state to another.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question 2.
How do we tell how hot or cold a substance is?
Answer:
A thermometer is used to measure the temperature of the subatance which tell us hot or cold it is.

Question 3.
How will you identify the following
Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties 2

Question i.
A glass: Is it made of plastic, steel or glass?
Answer:
Glass is made of glass as it is transparent.

Question ii.
A rod: Iron or aluminium.
Answer:
A rod is made of iron as it is heavy.

Maharashtra Board Class 6 Science Solutions Chapter 5 Substances in the Surroundings - Their States and Properties

Question iii.
A door: Wooden or glass?
Answer:
A door is wooden as it is opaque.

Question iv.
A white powder: Salt or chalk powder?
Answer:
If powder dissloves in water it is salt and if it does not dissolves in water it is chalk.

Maharashtra State Board Class 6 Science Textbook Solutions

Sound Class 8 Science Chapter 15 Questions And Answers Maharashtra Board

Std 8 Science Chapter 15 Sound Question Answer Maharashtra Board

Balbharti Maharashtra State Board Class 8 Science Solutions Chapter 15 Sound Notes, Textbook Exercise Important Questions and Answers.

Class 8 Science Chapter 15 Sound Question Answer Maharashtra Board

Class 8 Science Chapter 15 Sound Textbook Questions and Answers

1. Fill in the blank with appropriate word:

Question a.
The region in a sound wave, with higher pressure and density is called ………….. and that with low pressure and density is called ……….. .
Answer:
The region in a sound wave, with higher pressure and density is called compression and that with low pressure and density is called rarefaction.

Maharashtra Board Class 8 Science Solutions Chapter 15 Sound

Question b.
Medium is …………… for generation of sound.
Answer:
Medium is needed (or necessary) for generation of sound.

Question c.
The total number of compressions and rarefactions produced per second in a sound wave is 1000. The frequency of the sound wave is ………… .
Answer:
The total number of compressions and rarefactions produced per second in a sound wave is 1000. The frequency of the sound wave is 500 Hz.
[Note: Total number: 100. ∴ 500 compressions and 500 rarefactions are produced per second.]

Question d.
Different sound notes have different ………………. .
Answer:
Different sound notes have different frequencies.

Maharashtra Board Class 8 Science Solutions Chapter 15 Sound

Question e.
In a loudspeaker, …………… energy is converted into ………….. energy.
Answer:
In a loudspeaker, mechanical energy is converted into sound energy.

2. Give scientific reasons:

Question a.
It is essential to change the tension in the vocal cords, as we produce different sound notes from our larynx.
Answer:
Different sound notes correspond to different frequencies. The frequency of sound depends on the tension in the vocal cords. Hence, it is essential to change the tension in the vocal cords, as we produce different sound notes our larynx.

Question b.
Astronauts on the moon cannot hear each other directly.
Answer:
Two astronauts on the moon talking to each other directly, will be unable to listen to each other, even if they are very close to each other. The moon does not have atmosphere. Since there is no medium which is necessary for generation and propagation of sound, between the astronauts, direct sound propagation between them is not possible. Therefore, the astronauts use some technology like the one used in our cell-phones to communicate with each other. The waves used in cell-phone do not need any medium for propagation.

Question c.
As the sound wave propagates from one place to the other in air, the air itself is not required to move from one place to the other.
Answer:
Propagation of sound through air occurs due to energy transfer by vibrating air molecules in one region to those in the adjacent region away from the source. The molecules simply vibrate about their mean positions. Hence, the air itself is not required to move from one place to the other.

Maharashtra Board Class 8 Science Solutions Chapter 15 Sound

3. How are different sound notes generated in musical instruments like guitar, which uses strings for sound generation, and flute, which uses blown air for sound generation?

Question a.
How are different sound notes generated in musical instruments like guitar, which uses strings for sound generation, and flute, which uses blown air for sound generation?
Answer:
1. Guitar: It is a string based, flat- backed instrument. It has usually six strings, the strings are plucked or strummed with the fingers or a small piece of plastic, wood, etc. It has a flat sounding board with a circular sound hole in the centre. Also it has a fretted fingerboard. Its frequency range is more than three octaves. The frequency of vibration of the string is changed by changing the tension in the string or changing the vibrating length of the string. As the tension is increased, the frequency increases. As the vibrating length is increased, the frequency decreases. This is how different sound notes are generated.
[Note: The acoustic guitar has hollow body and six or twelve strings while the electric guitar usually has solid body and six strings. The electric bass guitar has four strings.]

2. Flute: It is a wind instrument where air is blown against the edge or rim of the blowing hole. The frequency of the sound produced depends upon the length of the vibrating air column in the tube. The greater the length of the vibrating air column, the less is the frequency of the sound produced. This is how different sound notes are produced. The flute has six or seven or eight holes to generate sounds of different frequencies. Different notes can be generated also by changing the way of air-blowing.

Maharashtra Board Class 8 Science Solutions Chapter 15 Sound

4. How is sound produced in the human larynx and a loudspeaker?

Question a.
How is sound produced in the human larynx and a loudspeaker?
Answer:
1. Sound production in the human larynx:
In the humans, sound is produced in the voice box called the larynx. It is located at the upper end of the windpipe. Two vocal cords (chords) are stretched across it with a narrow slit between them for the passage of air (Fig. 15.5). When the lungs force air through the slit, the cords start vibrating.

The frequency of the sound produced depends upon the length and thickness of the cords, and the tension in the chords. The frequency increases with the increase in tension and the more the length or the thickness of the cord, the less is the frequency. Muscles attached to the cords can make the cords tight (more tension) or loose (less tension).
Maharashtra Board Class 8 Science Solutions Chapter 15 Sound 1
2. Sound produced in a loudspeaker:
Figure shows the internal construction of a loudspeaker. Here, a coil is wound around a permanent magnet. The conical screen of the loudspeaker is attached to the coil.
Maharashtra Board Class 8 Science Solutions Chapter 15 Sound 2
When a current is passed through the coil, a magnetic field is produced. Its interaction with the permanent magnet results in the back and forth motion of the coil. The frequency and the amplitude of the motion of the coil depends on the variation in the current through the coil.

As the coil moves, the conical screen also moves back and forth. The vibrations of the screen produce sound waves in air. Very loud sound can be produced by changing the current.
[Note: If you gently touch the vibrating screen, you can feel the vibrations.]

Maharashtra Board Class 8 Science Solutions Chapter 15 Sound

5. Explain the experiment, with0 a neat diagram, to prove the following:
‘Sound needs a material medium for propagation.’

Question a.
Explain the experiment, with0 a neat diagram, to prove the following:
‘Sound needs a material medium for propagation.’
Answer:
Maharashtra Board Class 8 Science Solutions Chapter 15 Sound 3
Figure shows part of the set up used in this experiment. What is not shown is the electric circuit in which the electric bell is connected. A vacuum tight bell jar contains an electric bell connected to a power supply through the lid of the jar. The jar is placed on a smooth horizontal surface such as that of glass.

Initially the vacuum pump is off and the jar contains air. The circuit containing the bell is completed using the key or the switch so that the bell starts ringing. This can be heard outside the jar.

Then the vacuum pump is switched on so that it starts removing the air from the jar. We find that the level of ringing sound heard goes on decreasing as the quantity of air in the jar becomes less and less.

When the pump is operated for a sufficiently long time interval, the quantity of air in the jar becomes so less that the level of ringing sound becomes very low; sound is hardly audible. But we can see the striker in the bell hitting the gong. By extrapolation, we conclude that sound generation and propagation needs a medium.

Maharashtra Board Class 8 Science Solutions Chapter 15 Sound

6. Match the following:

Question a.
Maharashtra Board Class 8 Science Solutions Chapter 15 Sound 4
Answer:

Column IColumn II
Human larynxVibrations in vocal cords
LoudspeakerVibrations of screen
JaltarangVibrations in air column
Tuning forkVibrations of metal arms
SitarVibrations in strings

Can you recall?

Question a.
How is sound produced?
Answer:
Sound is produced by the vibrations of an object such as a stretched membrane or a string under tension.

Maharashtra Board Class 8 Science Solutions Chapter 15 Sound

Project:

Question 1.
Take two plastic glasses and tie a thread between them to make a toy phone. Does the voice of your friend reach you through the thread? Take metal wire instead of the thread and also change the length of the thread wire and repeat the activity. Discuss with your friends and teacher about your conclusions.

Question 2.
Take a plastic or tin can or a plastic glass. Remove its bottom. Stretch a piece of rubber balloon across one end and fix it with a rubber band. Put a few grains of say ragi or bajra on the stretched rubber. Now ask your friend to shout ‘Hoorrey ……… Hoorrey ………… ‘ from the open end of the glass. Observe the dancing of the grains up and down. Discuss the reason behind this.

Class 8 Science Chapter 15 Sound Important Questions and Answers

Select the correct option and write the completed statements:

Question 1.
Sound waves cannot travel through a ………… .
(a) solid
(b) liquid
(c) gas
(d) vacuum
Answer:
Sound waves cannot travel through a vacuum.

Question 2.
If the frequency of a sound wave is 512 Hz, the number of rarefactions produced per second is ……………… .
(a) 256
(b) 512
(c) 1024
(d) 128
Answer:
If the frequency of a sound wave is 512 Hz, the number of rarefactions produced per second is 512.

Maharashtra Board Class 8 Science Solutions Chapter 15 Sound

Question 3.
In the experiment to show that a medium is necessary for propagation of sound, as the quantity of air inside the bell jar decreases, the level of ringing sound heard outside ……………… .
(a) increases
(b) decreases
(c) fluctuates randomly
(d) changes at regular intervals
Answer:
In the experiment to show that a medium is necessary for propagation of , sound, as the quantity of air inside the bell jar decreases, the level of ringing sound heard outside decreases.

Find the odd one out and give the reason:

Question 1.
Sound waves, Waves on the surface of water, Waves on a stretched string, Light waves
Answer:
Light waves. Light waves can travel in a vacuum. Other waves need a medium for propagation.

Question 2.
Sitar, Violin, Guitar, Flute.
Answer:
Flute. It is not a string based instrument. Others are string based instruments.

State whether the following statements are True or False. (If a statement is false, correct it and rewrite it.)

Question 1.
If the vibrating length of a stretched string is kept constant and the tension in the string is increased, the frequency of the sound produced increases.
Answer:
True.

Maharashtra Board Class 8 Science Solutions Chapter 15 Sound

Question 2.
In Jaltarang, the frequency of sound produced is independent of the height of the air column inside the glass cup.
Answer:
False. (In Jaltarang, the frequency of sound produced depends on the height of the air column inside the glass cup; the more the height of the air column, the less is the frequency of the sound produced.)

Answer the following questions in one sentence each:

Question 1.
What is sound?
Answer:
Sound is a form of energy which produces sensation of hearing in our ears.

Question 2.
What is vibration?
Answer:
Vibration is a rapid, to and from periodic motion of an object about its mean position.

Question 3.
What is compression?
Answer:
As a sound wave travels through air, the region in which air is at high pressure and high density is called compression.

Question 4.
What is rarefaction?
Answer:
As a sound wave travels through air, the region in which air is at low pressure and low density is called rarefaction.

Maharashtra Board Class 8 Science Solutions Chapter 15 Sound

Question 5.
What is the relation between the frequency of vibration and the vibrating length (or height) of the air column?
Answer:
The greater the vibrating length (or height) of the air column, the less is the frequency of vibration of the column.

Question 6.
For a particular string (given material and radius), what are the factors on which its frequency of vibration depends?
Answer:
For a particular string (given material and radius), the frequency of vibration of the string depends upon its vibrating length and the tension in the string.
[Note: in the above case, frequency is proportional to the square root of the tension and inversely proportional to the length.]

Question 7.
Name an instrument in which a stretched skin is used to produce musical sound.
Answer:
Tabla.

Maharashtra Board Class 8 Science Solutions Chapter 15 Sound

Answer the following questions:

Question 1.
Explain the production and propagation of sound in air.
Answer:
Let us consider production of sound by using a tuning fork. A tuning fork is made of a metal. It has a stem and two prongs (Fig). Figure (a) shows the state of air in the absence of propagation sound through it. Equally spaced vertical lines show that the average distance between the air molecules is the same everywhere. It means average pressure and average density in the regions A, B and C are the same.
Maharashtra Board Class 8 Science Solutions Chapter 15 Sound 5

Maharashtra Board Class 8 Science Solutions Chapter 15 Sound 6

Suppose the tuning fork is held vertical, its stem is fixed in a stand (not shown in the figure) and its prongs are struck lightly using a light hammer with a piece of rubber at the top. The prongs then start vibrating.
Figure (b) shows what happens when the prongs move away from each other. The air outside the prongs is compressed (layers in the region A). The pressure and density increase in this region.

Figure (c) shows what happens when the prongs move close to each other. The air molecules near the prongs move away from each other resulting in lower pressure and lower density.

This region is called rarefaction. Meanwhile, the compression produced earlier moves forward, i.e., away from the prongs because the air molecules in this region transfer their energy to the air molecules in the region B producing a compression there. The periodic formation of compression and rarefaction results in propagation of sound waves away from the prongs.

Eventually, these sound waves reach our ears, the ear-drum vibrates, and we get a sense of hearing a sound as the specific signals reach the brain.

Maharashtra Board Class 8 Science Solutions Chapter 15 Sound

Use your brain power:

Question a.
If sound waves are generated in air, what moves away from the source? Is it the air itself or the state of compression and rarefaction created in the air?
Answer:
If sound waves are generated in air, the state of compression and rarefaction created in the air moves away from the source.
[Note: The air does not move away from the source because air is elastic and the force due to the tuning fork varies periodically with time.]

Question 2.
Explain the term frequency of a sound wave.
Answer:
Sound travels in the form of waves. A wave consists of cycles of alternate compression and rarefaction. The number of cycles produced in the air (or any other medium) per second is called the frequency of the sound wave. It is expressed in hertz (Hz). 1 hertz = 1 cycle per second or 1 vibration per second or 1 oscillation per second.

Maharashtra Board Class 8 Science Solutions Chapter 15 Sound 7

[Note: The SI unit of frequency, the hertz, is named in honour of Heinrich Hertz (1857-94), German physicist.]

Maharashtra Board Class 8 Science Solutions Chapter 15 Sound

Question 3.
State the factors on which the frequency of a tuning fork depends.
Answer:
The frequency of a tuning fork depends on the dimensions of the prongs, i.e., length and thickness, and the material used for making the fork.

Try this:

Question a.
Take 6 – 7 glass cups. Arrange them in a line and fill them with water with gradually increasing water level from one end to other. Take a pencil and strike the cups sequentially. The sound generated by each cup will be different. Why is it so?
Use of ICT:
Download videos of Jaltarang from youtube and send them to your friends by email.

Maharashtra Board Class 8 Science Solutions Chapter 15 Sound 8

Answer:
When a cup is struck, waves are set up in the air column above the water level in the cup. The frequency of the generated wave depends on the height of the air column inside the glass cup. Since the water level in each glass is different, the height of the air column in each glass is also different. Therefore, the frequency of sound generated by each glass cup will also be different. So, the sound generated is different.

Question b.
An ‘app’ for measurement of sound frequency may be available on cellphones. With the help of your teacher, use the app to measure the frequency of the sound generated from each glass cup. Do you observe any relation between the frequency of generated sound and the height of the air column in the glass cup?
Answer:
Yes. The greater the height of the air column in the glass cup, the less is the frequency of the sound produced.

Question c.
This is your simple ‘Jaltarang’! Can this experiment be performed with stainless steel pots of different size?
Answer:
Do it. See what happens as the stainless steel pot itself starts vibrating producing a sound. Also see how this sound is damped by water.

Maharashtra Board Class 8 Science Solutions Chapter 15 Sound

Do you know?

Question a.
What are the frequencies of musical notes ‘sa’, ’re’, ‘ga’, ‘ma’, ‘pa’, ‘dha’, ‘ni’ in the ‘madhya saptak’?
Answer:
Maharashtra Board Class 8 Science Solutions Chapter 15 Sound 9

[Note: The diatonic scale:
Maharashtra Board Class 8 Science Solutions Chapter 15 Sound 10.1
Maharashtra Board Class 8 Science Solutions Chapter 15 Sound 11.1
Such a simple fraction is pleasing to the ear and is called a musical interval. Frequency ratios 2 : 1, 3 : 2, 4 : 3 are examples of musical interval.

Observe and discuss:

Question 1.
Identify the instruments and discuss sound production in them. [Students should see these musical instruments.]
Maharashtra Board Class 8 Science Solutions Chapter 15 Sound 12
Answer:
Maharashtra Board Class 8 Science Solutions Chapter 15 Sound 13

  1. Sitar
  2. Shehnai
  3. Flute
  4. Tabla
  5. Santoor
  6. Bugle
  7. Mandoline or Mandolin
  8. Saxophone.

Question i.
Sitar, Santoor and Mandoline or mandoline (String instruments):
Answer:
Vibrating strings produce the sound. The greater the tension in the string, the higher is the frequency of the sound. The greater the vibrating length and the diameter of the string, the lower is the frequency of the sound.

Question ii.
Flute, Saxophone and Shehnai (Wind instruments):
Answer:
Vibrating air column produces the sound. The greater the length of the column, the lower is the frequency of the sound.

Maharashtra Board Class 8 Science Solutions Chapter 15 Sound

Question iii.
Tabla (Percussion instrument):
Answer:
Vibrating skin produces the sound. The greater the tension in the skin, the higher is the frequency of the sound. The greater the thickness of the skin, the lower is the frequency of the sound.

Try this:
‘Apps’ for generation of different sound notes (sound note generator app) may be available on cellphones. With the help of your teacher, using such an app, generate sound notes listed in the table.

Maharashtra Board Class 8 Science Solutions Chapter 15 Sound 9

Vocal cords are 20 cm in length in male, about 15 cm in female and even smaller in children. Therefore the voice of male, female and children are different.
[Note: Vocal cords are 20 mm in length in male, about 15 mm in female and even smaller in children. Reference NCERT textbook Std. VIII, published in 2017.]

Question 1.
Produce a sound ‘bho … bho …’ just like a dog-barking and ‘meow … meow…’ just like a mewing cat. Carefully notice the tension on the vocal cords, when you produce these sounds. Do you feel that the tension on the vocal cords changes when you produce these two different sounds?
Answer:
Yes.

Maharashtra Board Class 8 Science Solutions Chapter 15 Sound

Question 2.
An ‘app’ may be available on cell-phones to measure the loudness of sound in decibel. With the help of your teacher, use the app to measure the sound level of a sound from a loudspeaker at some public place. Measure the sound level at different distances from the loudspeaker. Do you observe some relation between the distance from the loudspeaker and the sound level?
Answer:
Yes. As the distance increases, the sound level decreases.

Always remember:

We should take care that others are not disturbed when we study sound and its production. Sound pollution is a major cause affecting the environment and social health. Hence we should find ways to avoid sound pollution.

Balbharati Maharashtra State Board 8th Std Science Textbook Solutions

The Living World: Adaptations and Classification Class 7 Questions And Answers Maharashtra Board

Std 7 Science Chapter 1 The Living World: Adaptations and Classification Question Answer Maharashtra Board

Balbharti Maharashtra State Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification Notes, Textbook Exercise Important Questions and Answers.

Class 7 Science Chapter 1 The Living World: Adaptations and Classification Question Answer Maharashtra Board

1. Find my match!

Question a.

Column ‘A’Column ‘B’
1. Lotusa. Flower and leaves attract insects
2. Aloeb. Haustorial roots for absoption of food
3. Cuscutac. Adapted to live in deserts
4. Venus fly trapd. Adapted to live in water

Answer:

Column ‘A’Column ‘B’
1. Lotusd. Adapted to live in water
2. Aloec. Adapted to live in deserts
3. Cuscutab. Haustorial roots for absoption of food
4. Venus fly trapa. Flower and leaves attract insects

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

2. Read the paragraph and answer the following questions:

I am a penguin. I live in polar region covered by snow. My abdomen is white. My skin is thick with a layer of fat underneath. My body is spindle-shaped. My wings are small. My toes are webbed. We live in flocks.

Question a.
Why is my skin white and thick and why is there a thick layer of fat underneath?
Answer:

  1. White skin colour camouflage with the snow so penguins cannot be easily spotted and they get protected from enemies.
  2. Thick skin and thick layer of fat underneath gives them protection from severe cold.

Question b.
Why do we live in flocks sticking close to each other?
Answer:
Penguins live in flocks sticking close to each other because sticking close to each other reduce the relative area so there is least loss of heat and they get protection from cold.

Question c.
Which geographical region do I inhabit? Why?
Answer:

  1. Penguins inhabit Antarctica region. Antarctica is surrounded by ocean. Climate is colder, drier and windier.
  2. It does not have human population. This climate is suitable for penguins, so they inhabit Antarctica.

Question d.
Which adaptations should you have to enable you to live permanently in the polar region? Why?
Answer:

  1. I should be a warm blooded animal. This should allow me to permanently live in polar region.
  2. My body has to be covered with thick fur or scale so that loss of heat will be very less and I can survive in severe cold.

3. Who is lying?

Question a.
Cockroach – I have five legs.
Answer:
Cockroach is lying. It has six legs.

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question b.
Hen – My toes are webbed.
Answer:
Hen is lying because hen’s toes are not webbed. Duck has webbed toes.

Question c.
Cactus – My fleshy, green part is a leaf.
Answer:
Cactus is lying. It’s fleshy, green part is a stem not a leaf.

4. Read each of the following statements. Write a paragraph about adaptation with reference to each statement.

Question a.
There is extreme heat in deserts.
Answer:

  1. Plant’s stem is fleshy, leaves get modified into thorns to reduce loss of water. Steam perform photosynthesis in the absence of leaves.
  2. Animals have cushioned soles, hump, long legs and nostrils are protected by folds of skin. Eyelashes are long and thick.

Question b.
Grasslands are lush green.
Answer:
Insects like grasshoppers have green colour so they can be camouflaged amidst grasses.

Question c.
We hide.
Answer:
In equatorial region grasses are very tall, so to protect themselves animals like tiger, elephants and deer remain hidden in these tall grasses.

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question d.
We have long ears.
Answer:
It helps the animals to receive sounds from long distance, and they can protect themselves from predators.

5. Answer the following:

Question a.
Why is the camel called the ‘ship of the desert’?
Answer:

  1. Camel lives in a desert easily due to following adaptations. It has long legs and cushioned soles which keep the body of camel above the sand and cushioned soles do not allow to sink in sand while walking.
  2. The nostrils are protected by folds of skin.
  3. The eyelashes are long and thick.
  4. It has hump which stores fats so it helps camel to survive in desert for many days without food and water.

Due to above adaptations camel is used to carry people and transport goods from one place to another place in the desert. Therefore, camel is called the ship of the desert.

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question b.
How can the plants like cactus and acacia live in deserts with scarce water?
Answer:
The plants like cactus and acacia live in deserts with scarce water due to the following adaptations.

  1. Leaves are like small needles or have been modified into thorns, as a result they lose very little water by evaporation.
  2. The stem stores water and food so it is fleshy.
  3. The stems are green as they perform photosynthesis in the absence of leaves.
  4. Their roots penetrate deep into the soil in search of water.
  5. There is a thick layer of a waxy substance on the stems.

Question c.
What is the inter-relationship between adaptations of organisms and their surroundings?
Answer:
1. Adaptations of organisms depend on the changes in the surroundings.

2. To adjust with those changes in the surroundings adaptation takes place gradually and continuously in organisms.

3. Changes that take place in the various organs and life processes of organisms, enable them to live, feed, reproduce to perpetuate themselves and to protect themselves from their enemies in specific surroundings, depending upon the habitat and its geographical conditions, are called adaptations.

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question d.
How are organisms classified?
Answer:

  1. Different scientists have used different criteria and independently classified plants and animals.
  2. A hierarchy is formed in the classification that starts with kingdom Animalia or kingdom Plantae, further groups and sub-groups are formed depending upon basic similarities and differences.
  3. This is called the ‘hierarchy of classification’.
  4. Binomial nomenclature is used to identify each organism. Accordingly, a scientific name has been assigned to each organism.
  5. It consists of two parts – first part is ‘genus’ and second ‘species’.
  6. All identified organisms have been assigned a binomial name as per the guidelines of the International code of Nomenclature. For e.g.
GenusSpecies
MangoMangiferaIndica
HumanHomoSapiens

Activity:

Question 1.
Find out how the gradual adaptation from primitive man to modern man must have taken place.

Class 7 Science Chapter 1 The Living World: Adaptations and Classification Important Questions and Answers

Fill in the blanks.

Question 1.
Leaves of some aquatic plants are …………. and …………. ike a ribbon.
Answer:
thin, slender

Question 2.
…………. in stems and …………. of aquatic plants are useful for floating in water.
Answer:
Air spaces, petioles

Question 3.
Leaves of desert plants are modified into …………. .
Answer:
thorns

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question 4.
The stems of desert plants are green as they perform …………. in the absence of leaves.
Answer:
photosynthesis

Question 5.
…………. roots of grasses prevent soil erosion.
Answer:
Fibrous

Question 6.
Grasses in the …………. region are very tall.
Answer:
equatorial

Question 7.
…………. are found in hilly areas as well as plains.
Answer:
Vast meadows

Question 8.
Plants need …………., …………. and …………. for growth.
Answer:
nitrogen, phosphorus, potassium

Question 9.
Dodder has …………. roots for absorbing nutrients from the host plant.
Answer:
haustorial (sucking)

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question 10.
Fungi do not have …………. so cannot perform photosynthesis.
Answer:
chlorophyll

Question 11.
Fish breathe with …………. instead of a nose.
Answer:
gills

Question 12.
Fish have …………. within the body to help them to float.
Answer:
air bladders

Question 13.
Frog and duck have …………. toes.
Answer:
webbed

Question 14.
Tigers have …………. paws.
Answer:
padded

Question 15.
Bats can fly with the help of …………. .
Answer:
patagium.

Question 16.
Desert plants are either leafless or their leaves are like …………. or modified into …………. .
Answer:
needles, thorns

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question 17.
Spring like …………. on the stems of some climbers are examples of their adaptation.
Answer:
Tendrils

Question 18.
…………. is not a sudden process, it is gradual and continuous.
Answer:
Adaptation

Question 19.
…………. proposed the theory of the survival of the fittest.
Answer:
Charles Darwin

Match the columns:

Question 1.

Column ‘A’Column ‘B’
1. Cactusa. Herbivorous animal
2. Pineb. Carnivorous animal
3. Tigerc. Snowy region plant
4. Blackbuckd. Desert plant

Answer:

Column ‘A’Column ‘B’
1. Cactusd. Desert plant
2. Pinec. Snowy region plant
3. Tigerb. Carnivorous animal
4. Blackbucka. Herbivorous animal

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question 2.

Column ‘A’Column B’
1. Doga. Hibiscus roso sinensis
2. Cowb. Sorghum bicolor
3. Hibiscusc. Bos taurus
4. Joward. Canis lupus familiarise

Answer:

Column ‘A’Column B’
1. Dogd. Canis lupus familiarise
2. Cowc. Bos taurus
3. Hibiscusa. Hibiscus roso sinensis
4. Jowarb. Sorghum bicolor

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Name the following:

Question 1.
Animals which live in desert in deep burrows.
Answer:
Rats, snakes, spiders, lizards

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question 2.
Animals which have webbed feet.
Answer:
Frog, duck

Question 3.
Plants of snowy regions.
Answer:
Deodar, pine

Question 4.
Plants that eat insects.
Answer:
Drosera, venus flytrap, pitcher plant

Question 5.
World Frog Protection Day.
Answer:
29th April

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question 6.
2 parts of bionomial nomenclature.
Answer:
genus and species.

Who am I?

Question 1.
My leaves trap insects.
Answer:
Venus fly trap or pitcher plant.

Question 2.
I have waxy feathers and webbed feet.
Answer:
Duck

Question 3.
I breath through skin in water and through lungs on land.
Answer:
Frog

Question 4.
I have sucking roots through which I take nutrition from my host plant.
Answer:
Dodder (cuscuta)

Question 5.
I have silvery white body with thick long hair
Answer:
Snow animals like polar bear.

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question 6.
I have waxy broad leaves and air spaces in my stem.
Answer:
Lotus (or aquatic plants)

Question 7.
My Scientific name is Bos taurus.
Answer:
Cow

Question 8.
I discovered Binomial nomenclature.
Answer:
Carl Linnaeus

Question 9.
I have special thin folds in between my forelegs and hind legs called patagium.
Answer:
Bat

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question 10.
I am mango, my genus is?
Answer:
Mangifera

Say whether true or false, correct and rewrite the false statements:

Question 1.
Killing or harming frogs is prohibited by the Wild Life Protection Act.
Answer:
True

Question 2.
Scientific name of jowar is Bos taurus.
Answer:
False. Scientific name of jowar is Sorghum bicolor

Question 3.
Theory of natural selection was found by Charles Darwin.
Answer:
True

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question 4.
T.V. Channels like National Geographic, Wild and Discovery show about the feeding habits of animals.
Answer:
True

Question 5.
The spindle shaped body of birds maximizes the resistance of air while flying.
Answer:
False. The spindle shaped body of birds minimises the resistance of air while flying.

Question 6.
House lizard and monitor lizards have webbed toes.
Answer:
False. House lizard and monitor lizards have clawed toes.

Question 7.
Crocodiles use their muscles for creeping.
Answer:
True

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question 8.
The eyes of predatory carnivores are located on either side of the head.
Answer:
False. The eyes of predatory carnivores are located in the front of their head.

Question 9.
A frog is an amphibian.
Answer:
True

Question 10.
Diverse types of bushes and grasses are found in the grasslands.
Answer:
True.

Complete the given table:

Question 1.
Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World Adaptations and Classification 1

Question 2.
Give one special adaptation or features of the following plant or animal to suit its habitat surrounding
Answer:

Plant/animalSpecial adaptation/features
1. FishStream lined body
2. BirdHollow bones, feathers
3. CamelThick skin, folds in skin near nosetrils
4. Deerlong and tapering legs with strong hooves
5. TigerPadded paws, sharp canine teeth
6. Duckwaxy feathers, webbed toes
7. FungiRoot like fibers
8. CuscutaLeafless, yellow thread like stem with haustorial (sucking) roots
9. Venus fly trapTrigger hair inside their traps
10. Deodar treeConical shape and needle shaped leaves
11. Grape vineTendrils for support
12. AcaciaFleshy thick green stem with leaves turned into thorns.

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Who is lying?

Question 1.
Camel has thin skin and short eyelashes.
Answer:
Camel is lying – It has thick skin and long and thick eyelashes.

Answer in one or two sentences:

Question 1.
What is called ‘hierarchy of classification’?
Answer:

  1. A hierarchy is formed in the classification that starts with kingdom Animalia or Kingdom Plantae, further groups and sub-groups are formed depending upon basic similarities and differences.
  2. This is called the ‘hierarchy of classification’.

Question 2.
What theories were proprosed by Charles Darwin
Answer:
The theories of Charles Darwin are Theory of natural selection and theory of survival of the fittest.

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question 3.
Explain the terms Autotrophic and Parasitic
Answer:
1. Plants which are able to produce their own food with the help of the process of photosynthesis are called autotrophic plants eg. All green plants.

2. Plants which are not able to produce their own food but depend upon other plants for their nutrition are called parasitic plants They are leafless and non green in colour eg. Dodder (cuscuta). They have haustorial (sucking) roots for absorbing nutrients from the host plant.

Give scientific reasons:

Question 1.
Leaves of some aquatic plants are thin and slender like a ribbon.
Answer:
Leaves of some aquatic plants are thin and slender like a ribbon because this shape helps them to withstand fast currents of water.

Question 2.
Some aquatic plants have air spaces in stems.
Answer:
Some aquatic plants have air spaces in stems because air spaces help the plants to float on water.

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question 3.
Desert plants have thorns.
Answer:

  1. Desert plants have thorns because in deserts, due to scarcity of water these plants are either leafless or their leaves are like small needles or modified into thorns.
  2. They lose very little water by evaporation due to little surface area. This helps plants to survive in desert.

Question 4.
Desert plants have green stem.
Answer:
Desert plants have green stem because green stem performs photosynthesis in the absence of leaves.

Question 5.
Desert plants have strong roots.
Answer:
Desert plants have strong roots so they can penetrate deep into the soil in search of water.

Question 6.
Deodar tree is conical in shape.
Answer:
Deodar tree grows in snowy region and conical shape of the tree doesn’t allow snow to accumulate on the tree and thus protect the tree from snow.

Question 7.
Pine tree has thick bark.
Answer:
Pine tree grows in snowy region where it is extremely cold and its thick bark helps the tree to withstand the cold.

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question 8.
Plants in forest grow tall.
Answer:
In forest region variety of trees, shrubs and herbs are found. These plants compete amongst themselves for sunlight. Hence trees grow tall to get sunlight.

Question 9.
Cuscuta has haustorial roots.
Answer:

  1. Cuscuta is a parasitic plant. It is leafless and cannot prepare food on its own.
  2. So to get food haustorial (sucking) roots penetrate up to the conducting vessels of the host plant to absorb water and food, the Cuscuta has haustorial roots.

Question 10.
Fungi have root-like fibers.
Answer:

  1. Fungi are parasitic.
  2. They do not have chlorophyll and cannot perform photosynthesis.
  3. So these root-like fibers help to absorb the food from the starchy foodstuffs like bhakri and bread.

Question 11.
Pitcher plant eats insects.
Answer:

  1. Pitcher plant grows in a soil where nitrogen, phosphorous and potassium are very less. But the plant needs these for the growth.
  2. So to fulfill the need for nitrogen, pitcher plant consumes insects.

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question 12.
Duck and frog have webbed feet.
Answer:
When duck and frog are in water at that time the webbed feet act as oars and help them to swim in water.

Question 13.
Frogs can swim easily in water.
Answer:
Frogs have webbed toes, slippery, smooth skin and triangular head. This helps the frog to swim easily through water.

Question 14.
Tiger has sharp and pointed canine teeth.
Answer:
Tiger is a carnivorous animal. So the sharp and pointed canine teeth help the tiger to tear the prey and eat.

Question 15.
Blackbuck has eyes on either side of the head.
Answer:
Blackbuck is a herbivore animal and eyes on either side of the head gives them wide angle vision which helps to protect themselves from predators.

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question 16.
Tigers have padded paws.
Answer:
Tigers are carnivorous animals. So these padded paws enable them to silently stalk their prey and capture it easily.

Question 17.
The eyes of predatory carnivores are located in the front of their head.
Answer:
The eyes of predatory carnivores are located in the front of their head because it helps them to spot their prey from a long distance.

Question 18.
Camel can live in desert.
Answer:

  1. Camel can live in desert because it has thick skin to prevent loss of water from the body. Their legs are long with flat and cushioned soles.
  2. The nostrils are protected by folds of skin. The eyelashes are long and thick so these adaptations enable Camels to live in desert easily.

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question 19.
White fox has white body colour.
Answer:

  1. White fox lives in snowy region which throughout the year is covered with snow.
  2. White colour of fox matches with the snow so it gets camouflaged in snow and it can save itself from predators.

Question 20.
Birds can fly in the air.
Answer:

  1. Birds can fly in the air because the spindle shaped body minimises the resistance of air while flying.
  2. Their hollow bones, body covering of feathers and forelegs being modified into wings, their body being light in weight, all these factors make the birds adapted to fly in the air.

Can you tell?

Answer the following questions:

Question 1.
Arc the plants and animals from Kashmir and Rajasthan of the same type? Can you elaborate on any differences between the two?
Answer:
Plants and animals from Kashmir and Rajasthan are of different types.
Differences in plants:

  1. Plants of Kashmir, which is a snowy region, are conical in shape due to their sloping branches.
  2. This shape prevents the snow accumulation on the tree and the thick bark helps the tree to withstand the cold.
  3. But the plants of Rajasthan, which is a desert region, are either leafless or their leaves are small, needle shaped or have been modified into thorns. So the loss of water can be reduced
  4. The stem stores water and food so they are fleshy. The stem performs photosynthesis in the absence of leaves.

Differences in animals:

  1. Animals of Kashmir have thick hair and white or silver body colour camouflaged with snow. This helps them to get protection in snowy region.
  2. The animals of Rajasthan have long legs with flat and cushioned soles.
  3. The nostrils are protected by folds of skin. The eyelashes are long and thick. It gives protection from sand and heat.

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question 2.
In what way are sloping branches useful to plants in a snowy region?
Answer:
In a snowy region sloping branches of a plant gives conical shape to the tree and it doesn’t allow snow to accumulate on tree inspite of heavy snowfall and thus protect the tree from severe cold and snow.

Question 3.
What is the main difference between vehicles on the road and aeroplanes?
Answer:
The two main differences between vehicles on the road and aeroplanes are:

  1. aeroplanes have wings whereas vehicles on the road do not have wings.
  2. The body of aeroplanes are spindle shaped and the body of vehicles on the road depends on the number of wheels they have.

Use your brain power!

Answer the following questions:

Question 1.
Why does water trickle off lotus leaves?
Answer:

  1. Water trickles off lotus leaves because it is coated with waxy covering on it.
  2. It is one of the adaptations of aquatic plants to survive in water without getting wet and rot or sink to the bottom.

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question 2.
Why don’t the leaves of lotus plants rotinwatei?
Answer:
leaves of these plants do not rot in water because it is covered with waxy coating on it so that they do not get wet.

Question 3.
Why are roots of lotus plants short and fibrous?
Answer: –

  1. These plants grow in water so the roots do not need to go deep down in search of water. Their roots are not anchored in the soil.
  2. So their roots are short and fibrous.

Question 4.
The lotus stalk has holes or air spaces?
Answer:

  1. The air spaces in stems and petioles of aquatic plants are useful for making them float in water and also to prevent them from rotting
  2. Hence, the lotus stalk has holes or air spaces.

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Answer in detail:

Question 1.
Explain the Darwin’s theory of evolution.
Answer:
Charles Darwin, a biologist suggested two principles in his theory of evolution.

  1. Theory of survival of the fittest: He said that only those organisms are likely to survive which can best adapt themselves to a changing environment. This is called the theory of survival of the fittest.
  2. Theory of ‘Natural selection’: If an organism is bom with a new beneficial characteristic and is able to survive, this change is preserved in the next generation. This is called the theory of ‘natural selection’.

Diagram based questions:

Draw a neat labelled diagram of fish and answer the following questions.
Answer:
Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World Adaptations and Classification 2

Question a.
Why do fish have a body tapering towards both its ends?
Answer:
Fish have its body tapering towards its ends, to allow them to swim with least resistance in water.

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question b.
Why do Fish have transparent eyelids.
Answer:
The transparent eyelids of fish protect the eyes from the substance in the water

Question c.
How are they able to float?
Answer:
Fish have air bladders within their body which help them to float.

Observe the diagram and answer the questions.
Answer:
Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World Adaptations and Classification 3

Question a.
What habitat does this camel live in?
Answer:
Camel lives in desert habitats or in areas where there is scarcity of water.

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question b.
State any 2 of its body adaptations to survive in desert?
Answer:

  1. Thick skin to prevent loss of water from the body
  2. The eyelashes are long and thin
  3. Their legs are long and flat with cushioned soles

Question c.
How does a camel protect itself from sand storms or winds carrying sand?
Answer:
Camels have nostrils protected by folds of skin and long thick eyelashes to prevent entry of fir dust and sand into its nose and eyes.

Paragraph based questions:

Compare and contrast:

Question 1.
Compare the lotus plant to the Acacia plant and Hibiscus plant.
Answer:

Lotus plantHibiscus plantAcacia plant
I. Stem have air spaces in themStem do not have air spaces and do not store too much of water and foodStem is fleshy and stores water and food
ii. Leaves have a waxy coatingLeaves do not have a waxy coating and have thin laminaLeaves are not present and if present are very tiny or modified into thorns

Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World: Adaptations and Classification

Question 2.
What is the difference between the plants given in the pictures. Give 2 points of difference taking into consideration their adaptations with their surroundings.
Maharashtra Board Class 7 Science Solutions Chapter 1 The Living World Adaptations and Classification 4
Answer:

A. CactusB. LotusC. Deodar tree
i. Stem is green and fleshyStem is with air spaceShape of tree is conical
ii. leaves are reduced or absent and replaced by thornsLeaves are broad and with a waxy coatingLeaves are needle shaped

Maharashtra State Board Class 7 Science Textbook Solutions